Upload
chandra-sekhara-babu-asmath
View
219
Download
0
Embed Size (px)
Citation preview
8/6/2019 Fundamental of Trans
1/31
POWER TRANSFORMERS AND SHUNTREACTORS PRINCIPLES
AND CONCEPT
8/6/2019 Fundamental of Trans
2/31
A transformer is an electromagneticdevice used for transfer of energy
from one circuit to another withmagnetic field as coupling device.
The energy is always transferred at thesame frequency but usually withchanges in voltage and current
8/6/2019 Fundamental of Trans
3/31
8/6/2019 Fundamental of Trans
4/31
There are two types of transformers on
the basis of construction of winding andcore
1) Core type
2) Shell type
In core type the windings surround the core.
In shell type the core surrounds the windings
8/6/2019 Fundamental of Trans
5/31
8/6/2019 Fundamental of Trans
6/31
Core of the shell type transformer
8/6/2019 Fundamental of Trans
7/31
Electromotive force (emf) in a transformer
Faradays law states that
1) Whenever there is a change in magnetic field with respectto coil a voltage is induced
2) The magnitude of induced emf in the coil
by electomagnetic induction is directly proportional to the
time rate of change of flux linkage
E = N * (d / dt)
Where N= No of turns in the coil
and
(d / dt ) =Rate of change of flux
8/6/2019 Fundamental of Trans
8/31
8/6/2019 Fundamental of Trans
9/31
Inductance of a transformer coil
a r N
L= -------------------l
Where,
a = area of cross- section of the coil
- 7 = Absolute permeability =4 * * 10 Henry/m
r = Relative permeability
500 1000 for transformer core depending on flux
density
1 for all other space and all non -magnetic material
8/6/2019 Fundamental of Trans
10/31
8/6/2019 Fundamental of Trans
11/31
8/6/2019 Fundamental of Trans
12/31
Emf equation in a transformer
Let,
N1 = No. of turns in primary
N2 = No. of turns in secondarym = Maximum flux in the core (Webers)
f = Frequency of A.C.input.
As shown in Fig.1,flux increases from zero valueto maximum value ( m ) in one quarter of acycle i.e. 1/4* f
m
Average rate of change of flux= --------- = 4 f m
1/4f
8/6/2019 Fundamental of Trans
13/31
Average emf / turn = 4 * f * m
R.M.S. Value
------------------ = 1.1Average Value
RMS emf = 1.1 *4 * f * m
= 4.4 * f * m
If there are N1 turns in primary then
E1= 4.4 * N1* f * m
For Secondary,
E2 = 4.4 * N2* f * m
Thus ,
E1/E2 = N1/N2
8/6/2019 Fundamental of Trans
14/31
Losses in transformer
Losses in transformer
1)No load losses2) Full load losses
No load losses comprise the
i hysteresis lossesii eddy current losses
iii copper losses
When a.c. is applied to the coil a magnetizing current flows in the
coil and hence a magnetizing force H is applied to the magnetic fieldWhen flux density (B) is plotted against (H) a hysteris loop is formed
8/6/2019 Fundamental of Trans
15/31
8/6/2019 Fundamental of Trans
16/31
8/6/2019 Fundamental of Trans
17/31
8/6/2019 Fundamental of Trans
18/31
8/6/2019 Fundamental of Trans
19/31
Copper losses on no load is very small
since it is dependent on the magnetizing current.however at higher load the copper losses in the
winding increases and depends on the square of
the current
2
Losses = I *R
Thus the only increase in losses from no load to
full load is the copper loss
8/6/2019 Fundamental of Trans
20/31
8/6/2019 Fundamental of Trans
21/31
/
R2 =R2 * (N1/N2)
X2 = X2 * (N1/N2)
/Total Res. = R1+R2
/
Total Ind = X1+ X2
8/6/2019 Fundamental of Trans
22/31
8/6/2019 Fundamental of Trans
23/31
8/6/2019 Fundamental of Trans
24/31
8/6/2019 Fundamental of Trans
25/31
,
8/6/2019 Fundamental of Trans
26/31
low
8/6/2019 Fundamental of Trans
27/31
8/6/2019 Fundamental of Trans
28/31
Shunt ReactorsWhy a shunt reactor is required in a power system?
When a line is switched on and is on no- load thereceiving end voltage is higher than sending end .
This phenomena is known as Ferranti effect
This affects the insulation of connected equipmentparticularly the transformer. In order to keep the
receiving end voltage within a specified value whenthe line is on no-load or light load the shunt reactorsare connected
Shunt reactors differ from transformer since it usesone winding per phase and that magnetic circuit has
a gap. The magnetic energy is kept in the reactorAir gap which separates the individual ironpackets.The air gaps are made of stiff material likeceramic.
8/6/2019 Fundamental of Trans
29/31
8/6/2019 Fundamental of Trans
30/31
420 kV class shunt reactors (major Technical param.)
50 MVAR,63 MVAR,80 MVAR and 125 MVAR
System fault level : 40 KAConnection : star with neutral brought
Insulation level:
a) Lightning impulse(1.2 /50 sec) : 1300 kVp
b) Switching surge impulse (20/500 sec) : 1050 kVp
c) Maximum temperature rise at rated load : 50 deg C
d) Neutral Insulation level
Impulse withstand Voltage : 550 kVp
Power frequency voltage : 230 kVp
8/6/2019 Fundamental of Trans
31/31
Thank you for your time