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p1 p3 p_2n-1 p2 p4 p_2n Exhaust Stage I Stage n Stage II X l/h Y l/h Volume V l C4F10 Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume is divided into N steps where N=V/X=20 with no diffusion between the steps. The total volume which is rejected at the exhaust is replaced by pure C 4 F 10 . The total volume, DV i , which is pumped out at stage i for one step, is transferred to stage i+1 as one volume and then treated at this membrane in 100 mini steps assuming that the partial pressures do not change significantly during a mini step. (This statement is perhaps overly optimistic, but I checked that there is no real difference between 100 and 1 (I stopped at n=4)

Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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Page 1: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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p1

p3

p_2n-1

p2

p4

p_2nExhaust

Stage I

Stage n

Stage II

X l/h

Y l/h

Volume V l

C4F10

Fun games with membranes and cold traps.

I will assume:The total volume is 4000 l.The circulation speed X l/h = Y l/h = 200 l/h pump speed.The volume is divided into N steps where N=V/X=20 with no diffusion between the steps.The total volume which is rejected at the exhaust is replaced by pure C4F10.The total volume, DVi, which is pumped out at stage i for one step, is transferred to stage i+1 as one volume and then treated at this membrane in 100 mini steps assuming that the partial pressures do not change significantly during a mini step. (This statement is perhaps overly optimistic, but I checked that there is no real difference between 100 and 500.)

(I stopped at n=4)

Page 2: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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NeomechsCO2 0.0762 l/h/mbar p1-p2 6000 mbarAr 0.0155 l/h/mbar p3-p4 1000 mbarO2 0.01485 l/h/mbar p5-p6 300 mbarN2 0.00641 l/h/mbar p7-p8 120 mbarCF4 0.00127 l/h/mbarC4F10 0.000532 l/h/mbar

5% air in the C4F10 volume.

Numbers from an old logbook

Page 3: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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Small losses of C4F10

and reasonable purity. (1 % N2)

but not fast.

Page 4: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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Switch off Stage I and usep3-p4 6000 mbarp5-p6 1000 mbarp7-p8 200 mbar

Still tolerable losses for the same purity.

Page 5: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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Switch off Stage I and II and usep5-p6 6000 mbarp7-p8 500 mbar

Not too surprisingly, the losses are now rather high.

Page 6: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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CO2 is easy. For a 5% admixture usep1-p2 2000 mbarp3-p4 1000 mbarp5-p6 500 mbarp7-p8 50 mbar

Page 7: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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What about a steady state air leak?Try with 0.5 l/h. That is 0.5 l/h C4F10 []and 0.5 l/h air []usep1-p2 6000 mbarp3-p4 1000 mbarp5-p6 500 mbarp7-p8 120 mbar

and start the membranes when there is 2% air in the volume.

Not perhaps the most optimal device for such a state. Still, it will stabilise around 98.5% . The rest being N2.

Page 8: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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The fiddling with the pressures is very depending on the actual (measured) throughput of the membranes. The pressures should probably also be adjusted as a function of the admixture in the gas.Look for another type in my old logbook:

GeneronCO2 1.0152 l/h/mbarAr 0.0904O2 0.174N2 0.0394CF4 0.00370C4F10 0.00534and usep1-p2 2000 mbarp3-p4 500 mbarp5-p6 100 mbarp7-p8 20 mbar

Start out with 5 % air

Page 9: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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Will now have a look at gas scrubbing at low temperature. Have used:

Tables of Physical and Chemical ConstantsPhysical Properties and gas Solubilities, Journal of Chemical and Engineering Data Vol. 18 No. 4 1973 Solubility of gases in fluorocarbons, 3M pubM.F. Costa Gomes et al., Journal of Fluorine Chemistry 125(2004)1325

Ostwald solubility coefficient.Volume of gas dissolved in unit volume at ambient temperature and pressure. In anesthetic practice, these are quoted in tables, assuming a body temperature of 37°C. Note that the volume of gas dissolved is only dependent on temperature, and not pressure (though the number of molecules and the activity of these is pressure-dependent). This differs from Bunsen's solubility coefficient (a) in that the amount of dissolved gas is expressed in terms of its volume at the temperature of the experiment, instead of STPD.

Friedrich Wilhelm Ostwald Nobel Prize in Chemistry in 1909

The moleKingdom: AnimaliaPhylum: ChordataClass: Mammalia Infraclass: Eutheria Order: Soricomorpha Family: Talpidae

Which has taken me through a tour of mole units and Ostwald's coefficient. Just to get (cc gas) in (cc liquid) at a given temperature and partial pressure.

It does indeed require some rather large extrapolations (and faith).

Page 10: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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Water is well known.Compare 3M numbers at one temperature with measurements at many different temperatures.Looks consistent.

and then compare the solubility of the different gases in water and FC80.

water FC80a_N2 1538 1304a_CO2 2625 2269a_O2 1691 977Known that the odd man out, O2 , has a relative high solubility in fluorocarbons.As I know nothing about the temperature dependence of He in FC80, I will just use the a from water and fit to the 3M point.Solubility is nearly independent of the type of fluorocarbons. I will therefore assume that these curves holds for C4F10.

Page 11: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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Molecularsieve H2O

Burp

Pressure stabilizinggas Ar, N2, He

lN2

C4F10

Use the same set-up as for the membranes.That isTotal volume: 4000 lCirculation: 200 l/h → 20 stepsNo diffusion and no compressibility.

Total volume of the scrubber: 2 l3 bar < scrubber pressure <3.5 barPressure stabilizing gas : He at 5 l/h

Each step split in 500 mini steps.Checked that there is no real difference between 500 and 1000 steps (apart from time used on my PC).

Page 12: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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Time (h) C4F10 N2 O2 He0 95 4 1 020 98.69 1.02 0.22 0.0740 99.35 0.43 0.09 0.1360 99.61 0.2 0.04 0.1580 99.73 0.09 0.02 0.16100 99.78 0.04 0.01 0.17Composition (%)

Start with 5 % airand the cold trap at - 60 degC

Page 13: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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N2 will also work fine, but will end up with some 2.5 %. This is less than what I would have expected from some measurements at COMPASS and could indicate that the solubility constants that I am using are too low by about a factor of two.

C4F10 N2 O2

0 95 4 120 97.89 1.86 0.2540 97.8 2.08 0.1160 97.8 2.16 0.0580 97.79 2.19 0.02100 97.79 2.2 0.01

Page 14: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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C4F10 N2 O2 He0 95 4 1 020 99.22 0.59 0.14 0.0540 99.67 0.18 0.04 0.1160 99.8 0.06 0.01 0.1280 99.85 0.02 0 0.13100 99.86 0.01 0 0.13

C4F10 N2 O2 He0 95 4 1 020 99.56 0.32 0.09 0.0340 99.84 0.07 0.02 0.0860 99.89 0.01 0 0.0980 99.9 0 0 0.09100 99.91 0 0 0.09

No real change in purity, but a rather dramatic increase in losses.CO2 will not work in a cold trap.

Page 15: Fun games with membranes and cold traps. I will assume: The total volume is 4000 l. The circulation speed X l/h = Y l/h = 200 l/h pump speed. The volume

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Some sort of a Conclusion.

Gas scrubbing, cold trap at (at least) -60 degC, is the best choice if the aim of the game is to get air content in the range of ppm.

The triple membrane contraption will give oxygen content of about 0.1 %nitrogen of <1 %

without any excessive loss of C4F10

A steady state leak, would be better handled with a cold trap.

The principle of Gas Scrubbing can easily be understood from one clear sketch found in freepatents.com