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Footings. Acknowledgement. This Powerpoint presentation was prepared by Dr. Terry Weigel, University of Louisville. This work and other contributions to the text by Dr. Weigel are gratefully acknowledged . Footings. Support structural members and transfer loads to the soil. - PowerPoint PPT Presentation

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Page 1: Footings

FootingsFootings

1

Page 2: Footings

Acknowledgement

This Powerpoint presentation was prepared by Dr. Terry Weigel, University of Louisville. This work and other contributions to the text by Dr. Weigel are gratefully acknowledged.

2

Page 3: Footings

FootingsFootings

3

Design for load transfer to soil uses unfactored loads

Support structural members and transfer loads to the soil

Structural members are usually columns or walls

Structural design of footing is done with factored loads

Page 4: Footings

FootingsFootings

4

Typically, bottom of footing must be located below frost line

Footings must be designed to prevent bearing failure, sliding and overturning

Footings must be designed to prevent excessive settlement or tilting

Excavation may be required to reach a depth where satisfactory bearing material is located

Page 5: Footings

Wall FootingWall Footing

5

Wall footings – enlargement of the bottom of the wall

Page 6: Footings

Isolated Square FootingIsolated Square Footing

6

Isolated or single column square footing – loads relatively light and columns not closely spaced

Page 7: Footings

Combined FootingCombined Footing

7

Combined footings – support two or more columns – heavily loaded columns; closely spaced columns; columns near property line

Page 8: Footings

Mat FootingMat Footing

8

Mat or raft foundation – continuous concrete slab supporting many columns; soil strength relatively low; large column loads; isolated spread footings would cover more than 50 percent of area; reduce differential settlement

Page 9: Footings

Pile CapPile Cap

9

Pile caps – distribute column loads to groups of piles

Page 10: Footings

Soil PressureSoil Pressure

10

Soil pressure is assumed to be uniformly distributed beneath footing if column load is applied at the center of gravity of the footing

Footings supported by sandy soils

Footings supported by clayey soils

Footings supported eccentric loads

Page 11: Footings

Assumed Soil PressureAssumed Soil Pressure

11

Page 12: Footings

Soil Pressure - Sandy SoilSoil Pressure - Sandy Soil

12

Page 13: Footings

Soil Pressure - Clayey SoilSoil Pressure - Clayey Soil

13

Page 14: Footings

Allowable Soil PressureAllowable Soil Pressure

14

Actual soil pressure is based on unfactored loads

Allowable soil pressure may be determined by a geotechnical engineer

When soil exploration is not feasible, values provided by building codes may be used

Factor of safety is typically 3

Page 15: Footings

Allowable Soil Pressure (Table Allowable Soil Pressure (Table 12.1)12.1)

15

Maximum Allowable Soil PressureMaterial Allowable Pressure, ksf

Rock 20% of ultimate strength

Compact coarse or fine sand, hard clay or sand clay

8

Medium stiff clay or sandy clay 6

Compact inorganic sand and silt mixtures

4

Loose sand 3

Soft sand clay or clay 2

Loose inorganic sand-silt mixtures 1

Loose organic sand-silt mixtures, muck or bay mud

0

Page 16: Footings

Design of Wall FootingsDesign of Wall Footings

16

Generally, beam design theory is used

Shear strength almost always controls footing depth

Compute moment at the face of the wall (concrete wall) or halfway between wall face and its centerline (masonry walls)

Page 17: Footings

Design of Wall FootingsDesign of Wall Footings

17

Page 18: Footings

Design of Wall FootingsDesign of Wall Footings

18

Page 19: Footings

Design of Wall FootingsDesign of Wall Footings

19

Page 20: Footings

Design of Wall FootingsDesign of Wall Footings

20

Page 21: Footings

Design of Wall FootingsDesign of Wall Footings

21

Shear may be calculated at distance d from face of the wall

Use of stirrups is not economical – set d so that concrete carries all the shear

'

'

2

2

c c w

u

c w

V f b d

Vdf b

Page 22: Footings

Design of Wall FootingsDesign of Wall Footings

22

Design a 12-in wide stripSection 15.7 of ACI Code:

Depth of footing above bottom reinforcement not less than 6 in for footings on soil and not less than 12 in for footings on piles

Minimum practical depth of footing is 10 in and 16 in for pile caps

Page 23: Footings

Wall Footing Design Wall Footing Design ExamplesExamples

23

Page 24: Footings

Example 12.1Example 12.1

24

Design a wall footing to support a 12-in. wide reinforced concrete wall with a dead load of 20 k/ft and a live load of 15 k/ft. The bottom of the footing is to be 4 foot below final grade, the soil weighs 100 lb/ft3 the allowable soil pressure is 4 ksf. The concrete strength is 3,000 psi and the steel is Grade 60.

Page 25: Footings

Example 12.1Example 12.1

25

Page 26: Footings

Example 12.1Example 12.1

26

Assume a footing thickness of 12 in. With a minimum cover of 3 in., this gives a d value of about 8.5 in. Compute the footing weight and

soil weight:

Footing weight12 in 150 150 psf

12 in/ftSoil weight

36 in 100 300 psf12 in/ft

Page 27: Footings

Example 12.1Example 12.1

27

Effective soil pressure and required width of footing:

4000 psf 150 psf 300 psf 3550 psfWidth of footing required20 k/ft 15 k/ft 9.86 ft

3.55 ksfUse 10 ft

eq

Page 28: Footings

Example 12.1Example 12.1

28

Factored bearing pressure for design of concrete:

1.2 20 k/ft 1.6 15 k/ft4.80 ksf

10 ftuq

Page 29: Footings

Example 12.1Example 12.1

29

Compute design shear (at distance d from face of wall):

10 ft 6 in 8.5 in 4.80 ksf 18.2 k2 12 in/ft 12 in/ft

18, 200 lb 18.46 in0.75(1.0) 2 3000 ksi 12 in

Much larger than orginal assumptionTry a thicker footing - say 20 in thick

16.5 in

uV

d

d

Page 30: Footings

Example 12.1Example 12.1

30

20 in4000 psf 150 psf12 in/ft

28 in 100 psf 3517 psf12 in/ft

Width of footing required20 k/ft 15 k/ft 9.95 ft

3.517 ksfUse 10 ft

eq

Page 31: Footings

Example 12.1Example 12.1

31

10 ft 6 in 16.5 in 4.80 ksf 15.0 k2 12 in/ft 12 in/ft

15,000 lb 15.21 in0.75 2 3000 ksi 12 in/ft

15.21 in 3.5 in 18.71 inUse a 20 in thick footing

uV

d

h

Page 32: Footings

Example 12.1Example 12.1

32

22

22

10 ft 6 in 4.5 ft2 12 in/ft

Compute moment on a one-foot-long strip

4.80 k/ft 4.5 ft48.6 k-ft/ft

2 212 in/ft 48,600 lb-ft/ft

198.3 psi0.9 12 in 16.5 in

u

u

wLM

Mbd

Page 33: Footings

Example 12.1Example 12.1

33

Appendix Table 4.12, = 0.00345 < 0.0136, section is tension controlled; = 0.9

2in0.00345 12 in 16.5 in 0.68

ftsA

Use No 7 at 10 in (As = 0.72 in2 / ft from Table A.6)

Page 34: Footings

Example 12.1Example 12.1

34

Development length:1

5 in side cover0.875c 3 3 3.4375 3.5

2 210 in 5 in one-half c-c spacing of bars

23.5 in 0 4.0 Use 2.50.875 in

t e s

b

bb b

b

b tr

b

cd use c in

c

c Kd

Page 35: Footings

Example 12.1Example 12.1

35

'

2,

2,

340

3 60,000 psi 1 32.86 diameters40 2.53000 psi

0.68 in /ft32.86 31.03 diameters0.72 in /ft

31.03 0.875 in 27.15 in

yd t e s

b trb c

b

s requiredd

b s provided

d

fc Kd f

d

Ad A

Page 36: Footings

Example 12.1Example 12.1

36

10 ft 12 in/ft6 in 3 in 51 in 27.15 in

2

Available length for development

Page 37: Footings

Example 12.1Example 12.1

37

20.0018 12 in 20 in 0.432 in / ftsA

Temperature and shrinkage steel

Use No 5 at 8 in (As = 0.465 in2 / ft)

Page 38: Footings

Design of Isolated Square Design of Isolated Square FootingsFootings

38

Most isolated square footings have a constant thickness

For very thick footings, it may be economical to step or taper footing

Two types of shear must be considered – one-way shear and two-way shear

Page 39: Footings

Design of Isolated Square Design of Isolated Square FootingsFootings

39

Constant thickness

Page 40: Footings

Design of Isolated Square Design of Isolated Square FootingsFootings

40

Stepped

Page 41: Footings

Design of Isolated Square Design of Isolated Square FootingsFootings

41

Tapered

Page 42: Footings

One-way ShearOne-way Shear

42

'2u

c w

Vd

f bSame as for wall footings

Page 43: Footings

One-way ShearOne-way Shear

43

Page 44: Footings

Two-way ShearTwo-way Shear

44

ACI Code Section 11.11.1.2 states that critical section is at a distance d/2 from face of support

Page 45: Footings

Two-way ShearTwo-way Shear

45

Page 46: Footings

Two-way ShearTwo-way Shear

46

Page 47: Footings

Two-way ShearTwo-way Shear

47

'

'

'

4

42

ratio of the length of the long side of the column to the length of the short side of the column bearing on the footing

2

c c o

c c oc

c

sc c o

o

V f b d

V f b d

dV f b db

<- ACI Code Equation 11-33

<- ACI Code Equation 11-35

<- ACI Code Equation 11-34

Page 48: Footings

Two-way ShearTwo-way Shear

48

s = 40 for interior columns

s = 30 for exterior columns

s = 20 for corner columns

Page 49: Footings

Flexural Design – Isolated Flexural Design – Isolated Square FootingsSquare Footings

49

Flexural reinforcement is required in two directions

The values of d for the layers of steel in the two directions will be different

For square footings, design using the value of d for the upper layer is typical

For square footings supporting non-square columns, moments are larger in the shorter direction of the column

Page 50: Footings

Flexural Design – Isolated Flexural Design – Isolated Square FootingsSquare Footings

50

Reinforcing steel areas required to resist moment are often less than minimum required steel:

Code Section 10.5.4 states that minimum area and maximum spacing need only be equal to values required for temperature and shrinkage steel

,min

'

,min

200

3

s wy

cs w

y

A b df

fA b d

f

Page 51: Footings

Flexural Design – Isolated Flexural Design – Isolated Square FootingsSquare Footings

51

Maximum steel spacing may not exceed three times the footing thickness or 18 in.

Page 52: Footings

Load Transfer from Column Load Transfer from Column to Footingto Footing

52

All forces at the base of the column must be transferred to the footing

Compressive forces must be transferred by bearing

Tensile forces may be transferred by reinforcement or mechanical connectors

Page 53: Footings

Load Transfer from Column Load Transfer from Column to Footingto Footing

53

Columns transfer loads directly over the area of the column

Load transfer into the footing may by assumed to occur over an effective area which may be larger than the column area

For the same strength of concrete, the footing can support more bearing load than can the column

Page 54: Footings

Load Transfer from Column Load Transfer from Column to Footingto Footing

54

Bearing strength permitted at the base of the column ->

Bearing strength permitted on the footing is the same value multiplied by ->

See ACI Code Section 10.14.1

'10.85 cf A

2

1

2AA

Page 55: Footings

Definition of ADefinition of A11 and A and A22

55

A2 is the area of footing geometrically similar to and concentric with the column

A1 is the area of the column

Page 56: Footings

Column DowelsColumn Dowels

56

Page 57: Footings

Excess Bearing LoadExcess Bearing Load

57

Excess bearing load can be carried by dowels or column bars extended into footing

ACI Code Section 15.8.2 requires that the dowel area not be less than 0.005 times the gross cross-sectional area of the column

Page 58: Footings

Development Length for Development Length for DowelsDowels

58

Development length of dowels must be sufficient to transfer column force to footing

Development length of dowels may not be less than the length required if bearing stress was not exceeded

Page 59: Footings

Splice Length for DowelsSplice Length for Dowels

59

ACI Code does not permit splicing of No 14 or No 18 bars

ACI Code Section 15.8.2.3 does permit No 14 or No 18 bars to be spliced to No 11 (or larger) dowels in footings

These dowels must extend into the column not less than the development length for the No 14 or No 18 bar, or the compression lap splice length for the dowels, whichever is larger

Page 60: Footings

Splice Length for DowelsSplice Length for Dowels

60

These dowels must extend into the footing for a distance not less than the development length for dowels

Page 61: Footings

Insufficient Development or Insufficient Development or Splice LengthSplice Length

61

Use a larger number of smaller dowels

Use a deeper footing

Add a cap or pedestal to the footing

Page 62: Footings

Column UpliftColumn Uplift

62

Development length must be those for tension

Splice requirements are those found in ACI Code Section 12.17

Page 63: Footings

Isolated Rectangular Isolated Rectangular FootingsFootings

63

Square footings are more econonical than rectangular footings

Long direction steel is uniformly distributed along short direction

Short direction steel is non uniformly distributed along long direction

Page 64: Footings

Isolated Rectangular Isolated Rectangular FootingsFootings

64

ACI Code Section 15.4.4.2Reinforcement in band width 2

Reinforcement in short direction 1

is the ratio of the length of the footing in the long direction to the length in the short direction

Remaining steel is distributed uniformly throughout the two portions of the footing outside the band

Page 65: Footings

Isolated Rectangular Isolated Rectangular FootingsFootings

65

Page 66: Footings

Footing Design ExamplesFooting Design Examples

66

Page 67: Footings

Example 12.2Example 12.2

67

Design a square column footing for a 16-in. square tied interior column that supports loads of D = 200 k and L = 160 k. The column is reinforced with eight No 8 bars, the bottom of the footing is 5 foot below final grade, the soil weighs 100 lb/ft3 the allowable soil pressure is 5 ksf. The concrete strength is 3,000 psi and the steel is Grade 60.

Page 68: Footings

Example 12.2Example 12.2

68

Assume a footing thickness of 24 in. with a minimum cover of 3 in., this gives a d value of about 19.5 in. Compute the footing weight and

soil weight:

Footing weight24 in 150 300 psf

12 in/ftSoil weight

36 in 100 300 psf12 in/ft

Page 69: Footings

Example 12.2Example 12.2

69

Effective soil pressure and required area of footing:

2

5000 psf 300 psf 300 psf 4400 psf200 k 160 k 81.82 ft

4.40 ksfUse 9 ft x 9 ft

eq

A

Page 70: Footings

Example 12.2Example 12.2

70

Factored bearing pressure for design of concrete:

2

1.2 200 k 1.6 160 k6.12 ksf

81 ftuq

Page 71: Footings

Example 12.2Example 12.2

71

Depth required to resist punching shear:

222

4(16 19.5) 142 in

81.0 ft 2.96 ft 6.12 442.09 k

442,090 lb 18.95 in 19.5 in Ok0.75 4 3000 psi 142 in

442,090 lb40 19.5 in0.75 2 3000 psi 142 in

142 in 10.12 in 19.5 in Ok

o

u

b

V

d

d

Page 72: Footings

Example 12.2Example 12.2

72

Page 73: Footings

Example 12.2Example 12.2

73

Depth required to resist one-way shear:

1 9 ft 2.208 ft 6.12 ksf 121.62 k

121,620 lb 13.71 in 19.5 in Ok0.75 2 3000 psi 108 in

uV

d

Page 74: Footings

Example 12.2Example 12.2

74

22

22

6.12 ksf 9 ft 3.83 ft404 k-ft

2 212 in/ft 404,000 lb-ft

131.2 psi0.9 108 in 19.5 in

u

u

wLM

Mbd

Flexural design

Page 75: Footings

Example 12.2Example 12.2

75

Appendix Table 4.12, = 0.00225 < min

2

200 0.003360,000 psi

3 3000 psi0.00274

60,000 psi0.0033 108 in 19.5 in 6.95 insA

Use nine No 8 (As = 7.07 in2)

Page 76: Footings

Example 12.2Example 12.2

76

Development length:

1 bottom cover 3.5 in one-half center-to-center bar spacing 6 in

3.5 in 0 3.5 Use 2.51.0 in

t e s

b

b

b tr

b

ccc K

d

Page 77: Footings

Example 12.2Example 12.2

77

'

2,

2,

340

3 60,000 1 32.86 diameters40 2.53000

6.95 in32.86 32.30 diameters7.07 in

32.30 1.0 in 32.30 in

yd t e s

b trb c

b

s requiredd

b s provided

d

fc Kd f

d

Ad A

Page 78: Footings

Example 12.2Example 12.2

78

9 ft 12 in/ft 16 in 3 in 43 in 32.30 in2 2

Available length for development

Page 79: Footings

Example 12.3Example 12.3

79

Design for load transfer for the column and footing in Example 12.2. The strength of the sand-lightweight concrete (different from Example 12.2) in the column is 4 ksi.

Page 80: Footings

Example 12.3Example 12.3

80

Bearing force at the column base: 1.2 200 k 1.6 160 k 496 k

Design bearing force at the column base:

2'10.85 0.65 0.85 4 ksi 16 in

566 k 496 k Okcf A

Page 81: Footings

Example 12.3Example 12.3

81

Design bearing force in the footing concrete:

2

2

' 21

1

2

108 in6.75 Use 2

16 in

0.85

0.65 0.85 3 ksi 16 in 2 848.6 k 496 k Ok

cAf AA

Minimum dowel area: 2 20.005 16 in 1.28 in

Page 82: Footings

Example 12.3Example 12.3

82

'

0.02 0.02 0.75 in 60,000 psi16.74 in

0.85 4000 psib y

d

c

d f

f

Dowel development length into the column

'

0.02 0.02 0.75 in 60,000 psi16.43 in

1.0 3000 psib y

d

c

d f

f

Dowel development length into the footing

Page 83: Footings

Example 12.3Example 12.3

83

0.0003 0.0003 0.75 in 60,000 ksi

13.50 in8.0 in

d b y

d

d f

Development length must not be less than:

Page 84: Footings

Example 12.4Example 12.4

84

Design for load transfer for a 14-in. square column to a 13 ft square footing if Pu = 800 k. Normal weight concrete is used in both the column and the footing. The concrete in the column is 5 ksi and in the footing is 3 ksi. The column is reinforced with eight No 8 bars.

Page 85: Footings

Example 12.4Example 12.4

85

Bearing force at the column base = 800 k

Design bearing force at the column base:

2'10.85 0.65 0.85 5 ksi 14 in

541.5 k 800 k No goodcf A

Page 86: Footings

Example 12.4Example 12.4

86

Design bearing force in the footing concrete:

2

22

1

' 21

1

2

156 in11.14 Use 2

14 in

0.85

0.65 0.85 3 ksi 14 in 2

649.7 k 800 k No good

c

AA

Af AA

Page 87: Footings

Example 12.4Example 12.4

87

Design dowels to resist excess bearing force:

2

2 2

800 k 541.5 k 258.5 k258.5 k 4.79 in

0.9 60 k

0.005 14 in 0.98 in

sA

Use eight No 7 bars (As = 4.80 in2)

Page 88: Footings

Example 12.4Example 12.4

88

'

0.02 0.02 0.875 in 60,000 psi14.85 in

1 5000 psi

0.0003 0.0003 0.875 in 60,000 ksi

15.75 in8.0 in

b yd

c

d b y

d

d f

f

d f

Dowel development length into the column

Page 89: Footings

Example 12.4Example 12.4

89

'

0.02 0.02 0.875 in 60,000 psi19.42 in

1.0 3000 psi

0.0003 0.0003 0.875 in 60,000 ksi

15.75 in8.0 in

b yd

c

d b y

d

d f

f

d f

Dowel development length into the footing

Page 90: Footings

Example 12.5Example 12.5

90

Design a rectangular footing for an 18-in. interior square column for D = 185 k and L = 150 k. The long side of the footing should be twice the length of the short side. The normal weight concrete strength for both the column and the footing is 4 ksi. The allowable soil pressure is 4000 psf and the bottom of the footing is 5 ft below grade.

Page 91: Footings

Example 12.5Example 12.5

91

Assume a footing thickness of 24 in. with a minimum cover of 3 in., this gives a d value of about 19.5 in. Compute the footing weight and

soil weight:

Footing weight24 in 150 300 psf

12 in/ftSoil weight

60-24 in 100 300 psf12 in/ft

Page 92: Footings

Example 12.5Example 12.5

92

Effective soil pressure and required area of footing:

2

2

2

4000 psf 300 psf 300 psf 3400 psf185 k 150 k 98.5 ft

3.40 ksfUse a footing 7'-0" x 14'-0" 98.0 ft

1.2 185 k 1.6 150 k4.71 ksf

98.0 ft

e

u

q

A

A

q

Page 93: Footings

Example 12.5Example 12.5

93

Depth required to resist one-way shear. Take b = 7 ft.

1 7 ft 4.625 ft 4.71 ksf 152.49 k

152,490 lb 19.14 in0.75 1 2 4000 psi 84 in

19.14 4.5 in 23.64 in

uV

d

h

Page 94: Footings

Example 12.5Example 12.5

94

Page 95: Footings

Example 12.5Example 12.5

95

Depth required to resist punching shear:

222

4 18 19.5 in 150 in

98.0 ft 3.125 ft 4.71 ksf 415.58 k

415,580 lb 14.60 in 19.5 in Ok0.75 1 4 4000 psi 150 in

415,580 lb40 19.5 in0.75 2 4000 psi 150 in

150 in 8.11 in 19.5 in Ok

o

u

b

V

d

d

Page 96: Footings

Example 12.5Example 12.5

96

Page 97: Footings

Example 12.5Example 12.5

97

22

14 ft 9 in 6.25 ft2 12 in/ft

6.25 ft6.25 ft 7 ft 4.71 ksf 643.9 k-ft2

12 in/ft 643,900 lb-ft268.8 psi

0.9 84 in 19.5 in

u

u

M

Mbd

Flexural design (steel in long direction)

Page 98: Footings

Example 12.5Example 12.5

98

Appendix Table 4.13, = 0.00467

20.00467 84 in 19.5 in 7.65 insA

Use ten No 8 (As = 7.85 in2)

Page 99: Footings

Example 12.5Example 12.5

99

22

7 ft 9 in 2.75 ft2 12 in/ft

2.75 ft2.75 ft 14 ft 4.71 ksf 249.3 k-ft2

12 in/ft 249,300 lb-ft52.0 psi

0.9 168 in 19.5 in

u

u

M

Mbd

Flexural design (steel in short direction)

Too low for Table A.13

Page 100: Footings

Example 12.5Example 12.5

100

2

200 0.003360,000 psi

3 4000 psi0.00316

60,000 psi0.0033 168 in 19.5 in 10.81 insA

Use 18 No 7 (As = 10.82 in2)

Page 101: Footings

Example 12.5Example 12.5

101

Reinforcement in band width 2 2 2Reinforcement in short direction 1 2 1 3

Use 2/3 x 18 = 12 bars in band width

Page 102: Footings

Example 12.5Example 12.5

102