Footing Design.pdf

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    Isolated Footing Design

    Isolated Footing F2Input Values

    Concrete and Rebar Properties

    Unit Weight of Concrete : 23.000 kN/m3

    Strength of Concrete : 20.000 MPa

    Yield Strength of Steel : 415.000 MPa

    Minimum Bar Size : # 3

    Maximum Bar Size : # 8

    Minimum Bar Spacing : 2.20 in

    Maximum Bar Spacing : 18.00 in

    Concrete Covers

    Pedestal Clear Cover (P, CL) : 1.50 in

    Footing Clear Cover (F, CL) : 3.00 in

    Soil Properties

    Unit Weight : 22.00 kN/m3

    Soil Bearing Capacity : 150.00 kN/m2

    Soil Surcharge : 0.00 ksi

    Depth of Soil above Footing : 4.00 ft

    GeometryInitial Footing Dimensions

    Thickness (Ft) : 6.00 inLength - X (Fl) : 60.00 in

    Width - Z (Fw) : 60.00 in

    Eccentricity along X (Oxd) : 0.00 in

    Eccentricity along Z (Ozd) : 0.00 in

    Pedestal

    Include Pedestal? Yes

    Pedestal Shape : Rectangular

    Pedestal Height (Ph) : 48.00 in

    Pedestal Length - X (Pl) : 30.00 in

    Pedestal Width - Z (Pw) : 30.00 in

    Footing Design CalculationsFooting Size

    Initial Length (Lo) = 60.00 in

    Initial Width (Wo) = 60.00 in

    Min. area required frombearing pressure, Amin =

    P / qmax = 1786.491in

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    Area from initial length andwidth, Ao =

    Lo * Wo = 3600.00in

    Final dimensions for design.

    Length (L2) = 94.00 in Governing Load Case : # 13

    Width (W2) = 94.00 in Governing Load Case : # 13

    Area (A2) = 8836.00 in

    Calculated pressures at 4 corners.

    Load CasePressure atcorner 1 (q1)

    (kip/in^2)

    Pressure atcorner 2 (q2)

    (kip/in^2)

    Pressure atcorner 3 (q3)

    (kip/in^2)

    Pressure atcorner 4 (q4)

    (kip/in^2)

    Area of footing inuplift (Au)

    (in2)

    11 0.01 0.01 0.01 0.01 0.00

    11 0.01 0.01 0.01 0.01 0.00

    20 0.01 0.01 0.01 0.01 0.00

    20 0.01 0.01 0.01 0.01 0.00

    If Au is zero, there is no uplift and no pressure adjustment is necessary. Otherwise, to account for uplift, areas of negative pressube set to zero and the pressure will be redistributed to remaining corners.Summary of adjusted pressures at 4 corners.

    Load Case

    Pressure atcorner 1 (q1)

    (kip/in^2)

    Pressure atcorner 2 (q2)

    (kip/in^2)

    Pressure atcorner 3 (q3)

    (kip/in^2)

    Pressure atcorner 4 (q4)

    (kip/in^2)

    11 0.01 0.01 0.01 0.01

    11 0.01 0.01 0.01 0.01

    20 0.01 0.01 0.01 0.01

    20 0.01 0.01 0.01 0.01

    Adjust footing size if necessary.

    Check for stability against overturning and sliding:-

    Factor of safety againstsliding

    Factor of safety againstoverturning

    LoadCase No.

    Along X-Direction

    Along Z-Direction

    About X-Direction

    About Z-Direction

    11 121.193 107.604 111.150 148.385

    13 46.724 1.565 1.533 55.321

    16 130.762 31.290 31.232 160.723

    17 116.466 50.879 49.044 142.188

    20 135.012 19.604 19.462 166.334

    21 108.496 21.356 20.853 132.006

    Critical load case and the governing factor of safety for overturning and sliding

    Critical Load Case for Sliding along X-Direction : 13

    Governing Disturbing Force : 0.257 kip

    Governing Restoring Force : 12.016 kip

    Minimum Sliding Ratio for the Critical Load Case : 46.724

    Critical Load Case for Overturning about X-Direction : 13

    Governing Overturning Moment : 783.718 kip-in

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    Governing Resisting Moment : 1201.604 kip-in

    Minimum Overturning Ratio for the Critical Load Case : 1.533

    Critical load case and the governing factor of safety for overturning and sliding

    Critical Load Case for Sliding along Z-Direction : 13

    Governing Disturbing Force : 7.677 kip

    Governing Restoring Force : 12.016 kip

    Minimum Sliding Ratio for the Critical Load Case : 1.565

    Critical Load Case for Overturning about Z-Direction : 13

    Governing Overturning Moment : -21.721 kip-in

    Governing Resisting Moment : 1201.604 kip-in

    Minimum Overturning Ratio for the Critical Load Case : 55.321

    Check Trial Depth against Punching Shear strength, Vc

    Calculated Effective Depth, deff= D - Ccover- 1.0 = 4.00 in

    For rectangular column, = Bcol / Dcol = 1.00

    Effective depth, deff, increased until 0.75*Vc Punching Shear ForcePunching Shear Force, Pu = 0.00 kip, Load Case # 13

    From ACI Cl.11.12.2.1, for column = 136.00 in

    Equation 11-33, Vc1 = 175.79 kip

    Equation 11-34, Vc2 = 93.07 kip

    Equation 11-35, Vc3 = 117.20 kip

    Punching shear strength, Vc = 0.75 * minimum of (Vc1, Vc2, Vc3) = 69.80 kip

    0.75 * Vc > Vu hence, OK

    Check Trial Depth against One-Way Shear strength, VcShear along the Z-Z axis.

    From ACI Cl.11.3.1.1, Vc = 43.09 kip

    Distance along Z to design for shear, Dz = 0.00 in

    Check that 0.75 * Vc > Vux where Vux is the shear force for the critical load cases at a distance deff from the face of the column caby bending about the X axis.

    From above calculations, 0.75 * Vc = 0.00 kip

    Critical load case for Vux is # 13 0.00 kip

    0.75 * Vc > Vux hence, OK

    Shear along the X-X axis.

    From ACI Cl.11.3.1.1, Vc = 43.09 kip

    Distance along X to design for shear, Dx = 0.00 in

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    Check that 0.75 * Vc > Vuz where Vuz is the shear force for the critical load cases at a distance deff from the face of the column caby bending about the Z axis.

    From above calculations, 0.75 * Vc = 0.00 kip

    Critical load case for Vuz is # 13 0.00 kip

    0.75 * Vc > Vuz hence, OK

    Design for Flexure about Z axisCalculate the flexural reinforcement along the X direction of the footing. Find the area of steel required, A, as per Sectioof Reinforced Concrete Design (5th ed.) by Salmon and Wang (Ref. 1) Critical Load Case # 20The strength values of steel and concrete used in the formulae are in ksi

    Factor from ACI Cl.10.2.7.3 for Fc' 4 ksi, 0.85

    From ACI Cl. 10.3.2, = 0.02058

    From ACI Cl. 10.3.3, = 0.01544

    From ACI Cl. 7.12.2, = 0.00180

    From Ref. 1, Eq. 3.8.4a, constant m = 24.41

    Calculate reinforcement ratio for critical load case

    Design for flexure about Z axis is performedat the face of the column at a distance, Dx =

    35.00 in

    Ultimate moment, 167.98 kip-in

    Nominal moment capacity, Mn = 186.65 kip-in

    Required = 0.00199

    Since OK

    Area of Steel Required, As =0.79 sq.in

    Find suitable bar arrangement between minimum and maximum rebar sizes

    Available development length for bars, DL = 32.00 in

    Try bar size # 3 Area of one bar = 0.11 sq.in

    Number of bars required, Nbar= 8

    Because the number of bars is rounded up, make sure new reinforcement ratio

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    Design for Flexure about X axisCalculate the flexural reinforcement along the Z direction of the footing. Find the area of steel required, A, as per Sectioof Reinforced Concrete Design (5th ed.) by Salmon and Wang (Ref. 1) Critical Load Case # 11The strength values of steel and concrete used in the formulae are in ksi

    Factor from ACI Cl.10.2.7.3 for Fc' 4 ksi, 0.85

    From ACI Cl. 10.3.2, = 0.02058

    From ACI Cl. 10.3.3, = 0.01544

    From ACI Cl.7.12.2, = 0.00180

    From Ref. 1, Eq. 3.8.4a, constant m = 24.41

    Calculate reinforcement ratio for critical load case

    Design for flexure about X axis is performedat the face of the column at a distance, Dz =

    65.00 in

    Ultimate moment, 138.47 kip-in

    Nominal moment capacity, Mn = 153.85 kip-in

    Required = 0.00389

    Since OK

    Area of Steel Required, As =1.02 sq.in

    Find suitable bar arrangement between minimum and maximum rebar sizes

    Available development length for bars, DL = 32.00 in

    Try bar size # 3 Area of one bar = 0.11 sq.in

    Number of bars required, Nbar= 10

    Because the number of bars is rounded up, make sure new reinforcement ratio

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    Calculate the flexural reinforcement along the X direction of the footing. Find the area of steel required The strength values of steel and concrete used in the formulae are in ksi

    Factor from ACI Cl.10.2.7.3 for Fc' 4 ksi, 0.85

    From ACI Cl. 10.3.2, = 0.02058

    From ACI Cl. 10.3.3, = 0.01544

    From ACI Cl. 7.12.2, = 0.00180

    From Ref. 1, Eq. 3.8.4a, constant m = 24.41

    Calculate reinforcement ratio for critical load case

    Design for flexure about A axis is performedat the face of the column at a distance, Dx =

    35.00 in

    Ultimate moment, 279.79 kip-in

    Nominal moment capacity, Mn = 310.87 kip-in

    Required = 0.00446

    Since OK

    Area of Steel Required, As =1.56 sq.in

    Find suitable bar arrangement between minimum and maximum rebar sizes

    Design for top reinforcement about X axis

    First load case to be in pure uplift # 13Calculate the flexural reinforcement along the Z direction of the footing. Find the area of steel required The strength values of steel and concrete used in the formulae are in ksi

    Factor from ACI Cl.10.2.7.3 for Fc' 4 ksi, 0.85

    From ACI Cl. 10.3.2, = 0.02058

    From ACI Cl. 10.3.3, = 0.01544

    From ACI Cl.7.12.2, = 0.00180

    From Ref. 1, Eq. 3.8.4a, constant m = 24.41

    Calculate reinforcement ratio for critical load case

    Design for flexure about A axis is performedat the face of the column at a distance, Dx =

    35.00 in

    Ultimate moment, 279.79 kip-in

    Nominal moment capacity, Mn = 310.87 kip-in

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    Required = 0.00337

    Since OK

    Area of Steel Required, As =1.35 sq.in

    Find suitable bar arrangement between minimum and maximum rebar sizes

    Pedestal Design CalculationsCritical Load Case: 11

    Strength and Moment Along Reinforcement in X direction

    Bar size : # 8

    Number of Bars : 12

    Steel Area : 9.0000 sq.in

    Neutral Axis Depth (Xb): 4.3826 in

    Strength and Moment from Concrete

    Cc = 275.55 kip

    Mc = 3620.00 kip-in

    Calculate strength and moment from one bar.

    Distance between extreme fiber and bar, db 2.00 in

    Strain in bar, = 0.0016

    Maximum Strain, = 0.0021

    as

    47.30 kip/in^2

    0.0016

    as

    2.47 kip/in^2

    35.42 kip

    460.42 kip-in

    Total Bar Capacity, Cs = -238.74 kip

    Capacity of Column = Cc + Cs = 36.81 kip

    Total Bar Moment, Ms = 4314.31 kip-in

    Total Moment = Mc + Ms = 7934.31 kip-in

    Strength and Moment Along Reinforcement in Z direction

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    Bar size : # 8

    Number of Bars : 12

    Steel Area : 9.0000 sq.in

    Neutral Axis Depth (Xb): 4.3826 in

    Strength and Moment from Concrete

    Cc

    = 275.55 kip

    Mc = 3620.00 kip-in

    Calculate strength and moment from one bar.

    Distance between extreme fiber and bar, db 2.00 in

    Strain in bar, = 0.0016

    Maximum Strain, = 0.0021

    as

    47.30 kip/in^2

    0.0016

    as

    2.47 kip/in^2

    35.42 kip

    460.42 kip-in

    Total Bar Capacity, Cs = -238.74 kip

    Capacity of Column = Cc + Cs = 36.81 kip

    Total Bar Moment, Ms = 4314.31 kip-in

    Total Moment = Mc + Ms = 7934.31 kip-in

    Check for bi-axial bending, 0.003

    Design Moment Mnx= 33.652 kip-in

    Design Moment Mnz= 39.656 kip-in

    Total Moment Mox= 7934.310 kip-in

    Total Moment Moz= 7934.310 kip-in

    if Mnx or Mnz = 0, then = 1.0

    otherwise, = 1.24

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    Isolated Footing F5Input Values

    Concrete and Rebar Properties

    Unit Weight of Concrete : 23.000 kN/m3

    Strength of Concrete : 20.000 MPa

    Yield Strength of Steel : 415.000 MPa

    Minimum Bar Size : # 3

    Maximum Bar Size : # 8

    Minimum Bar Spacing : 2.20 in

    Maximum Bar Spacing : 18.00 in

    Concrete Covers

    Pedestal Clear Cover (P, CL) : 1.50 in

    Footing Clear Cover (F, CL) : 3.00 in

    Soil Properties

    Unit Weight : 22.00 kN/m3

    Soil Bearing Capacity : 150.00 kN/m2

    Soil Surcharge : 0.00 ksi

    Depth of Soil above Footing : 4.00 ft

    GeometryInitial Footing Dimensions

    Thickness (Ft) : 6.00 in

    Length - X (Fl) : 60.00 in

    Width - Z (Fw) : 60.00 in

    Eccentricity along X (Oxd) : 0.00 in

    Eccentricity along Z (Ozd) : 0.00 in

    Pedestal

    Include Pedestal? Yes

    Pedestal Shape : Rectangular

    Pedestal Height (Ph) : 48.00 in

    Pedestal Length - X (Pl) : 30.00 in

    Pedestal Width - Z (Pw) : 30.00 in

    Footing Design CalculationsFooting Size

    Initial Length (Lo) = 60.00 in

    Initial Width (Wo) = 60.00 in

    Min. area required frombearing pressure, Amin =

    P / qmax = 6751.470in

    Area from initial length andwidth, Ao =

    Lo * Wo = 3600.00in

    Final dimensions for design.

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    Minimum Overturning Ratio for the Critical Load Case : 5.149

    Critical load case and the governing factor of safety for overturning and sliding

    Critical Load Case for Sliding along Z-Direction : 13

    Governing Disturbing Force : 21.908 kip

    Governing Restoring Force : 103.743 kip

    Minimum Sliding Ratio for the Critical Load Case : 4.735

    Critical Load Case for Overturning about Z-Direction : 13

    Governing Overturning Moment : 96.169 kip-in

    Governing Resisting Moment : 11930.502 kip-in

    Minimum Overturning Ratio for the Critical Load Case : 124.058

    Check Trial Depth against Punching Shear strength, Vc

    Calculated Effective Depth, deff= D - Ccover- 1.0 = 7.00 in

    For rectangular column, = Bcol / Dcol = 1.00Effective depth, deff, increased until 0.75*Vc Punching Shear ForcePunching Shear Force, Pu = 106.82 kip, Load Case # 13

    From ACI Cl.11.12.2.1, for column = 148.00 in

    Equation 11-33, Vc1 = 334.79 kip

    Equation 11-34, Vc2 = 217.16 kip

    Equation 11-35, Vc3 = 223.19 kip

    Punching shear strength, Vc = 0.75 * minimum of (Vc1, Vc2, Vc3) = 162.87 kip

    0.75 * Vc > Vu hence, OK

    Check Trial Depth against One-Way Shear strength, VcShear along the Z-Z axis.

    From ACI Cl.11.3.1.1, Vc = 86.71 kip

    Distance along Z to design for shear, Dz = 79.50 in

    Check that 0.75 * Vc > Vux where Vux is the shear force for the critical load cases at a distance deff from the face of the column caby bending about the X axis.

    From above calculations, 0.75 * Vc = 65.03 kip

    Critical load case for Vux is # 13 58.19 kip

    0.75 * Vc > Vux hence, OK

    Shear along the X-X axis.

    From ACI Cl.11.3.1.1, Vc = 86.71 kip

    Distance along X to design for shear, Dx = 35.50 in

    Check that 0.75 * Vc > Vuz where Vuz is the shear force for the critical load cases at a distance deff from the face of the column caby bending about the Z axis.

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    From above calculations, 0.75 * Vc = 65.03 kip

    Critical load case for Vuz is # 13 37.67 kip

    0.75 * Vc > Vuz hence, OK

    Design for Flexure about Z axisCalculate the flexural reinforcement along the X direction of the footing. Find the area of steel required, A, as per Sectioof Reinforced Concrete Design (5th ed.) by Salmon and Wang (Ref. 1)

    Critical Load Case # 11The strength values of steel and concrete used in the formulae are in ksi

    Factor from ACI Cl.10.2.7.3 for Fc' 4 ksi, 0.85

    From ACI Cl. 10.3.2, = 0.02058

    From ACI Cl. 10.3.3, = 0.01544

    From ACI Cl. 7.12.2, = 0.00180

    From Ref. 1, Eq. 3.8.4a, constant m = 24.41

    Calculate reinforcement ratio for critical load case

    Design for flexure about Z axis is performedat the face of the column at a distance, Dx =

    42.50 in

    Ultimate moment, 1059.07 kip-in

    Nominal moment capacity, Mn = 1176.75 kip-in

    Required = 0.00503

    Since OK

    Area of Steel Required, As =3.47 sq.in

    Find suitable bar arrangement between minimum and maximum rebar sizes

    Available development length for bars, DL = 39.50 in

    Try bar size # 6 Area of one bar = 0.44 sq.in

    Number of bars required, Nbar= 8

    Because the number of bars is rounded up, make sure new reinforcement ratio

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    Calculate the flexural reinforcement along the Z direction of the footing. Find the area of steel required, A, as per Sectioof Reinforced Concrete Design (5th ed.) by Salmon and Wang (Ref. 1) Critical Load Case # 11The strength values of steel and concrete used in the formulae are in ksi

    Factor from ACI Cl.10.2.7.3 for Fc' 4 ksi, 0.85

    From ACI Cl. 10.3.2, = 0.02058

    From ACI Cl. 10.3.3, = 0.01544

    From ACI Cl.7.12.2, = 0.00180

    From Ref. 1, Eq. 3.8.4a, constant m = 24.41

    Calculate reinforcement ratio for critical load case

    Design for flexure about X axis is performedat the face of the column at a distance, Dz =

    72.50 in

    Ultimate moment, 1225.44 kip-in

    Nominal moment capacity, Mn = 1361.60 kip-in

    Required = 0.00790

    Since OK

    Area of Steel Required, As =4.77 sq.in

    Find suitable bar arrangement between minimum and maximum rebar sizes

    Available development length for bars, DL = 39.50 in

    Try bar size # 7 Area of one bar = 0.60 sq.in

    Number of bars required, Nbar= 8

    Because the number of bars is rounded up, make sure new reinforcement ratio

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    Steel Area : 9.0000 sq.in

    Neutral Axis Depth (Xb): 6.6437 in

    Strength and Moment from Concrete

    Cc = 417.71 kip

    Mc = 5086.25 kip-in

    Calculate strength and moment from one bar.

    Distance between extreme fiber and bar, db 2.00 in

    Strain in bar, = 0.0021

    Maximum Strain, = 0.0021

    as

    60.19 kip/in^2

    0.0016

    as

    2.47 kip/in^2

    45.60 kip

    592.84 kip-in

    Total Bar Capacity, Cs = -186.13 kip

    Capacity of Column = Cc + Cs = 231.58 kip

    Total Bar Moment, Ms = 4895.38 kip-in

    Total Moment = Mc + Ms = 9981.64 kip-in

    Strength and Moment Along Reinforcement in Z direction

    Bar size : # 8

    Number of Bars : 12

    Steel Area : 9.0000 sq.in

    Neutral Axis Depth (Xb): 6.6437 inStrength and Moment from Concrete

    Cc = 417.71 kip

    Mc = 5086.25 kip-in

    Calculate strength and moment from one bar.

    Distance between extreme fiber and bar, db 2.00 in

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    Strain in bar, = 0.0021

    Maximum Strain, = 0.0021

    as

    60.19 kip/in^2

    0.0016

    as

    2.47 kip/in^2

    45.60 kip

    592.84 kip-in

    Total Bar Capacity, Cs = -186.13 kip

    Capacity of Column = Cc + Cs = 231.58 kip

    Total Bar Moment, Ms = 4895.38 kip-in

    Total Moment = Mc + Ms = 9981.64 kip-in

    Check for bi-axial bending, 0.040

    Design Moment Mnx= 571.916 kip-in

    Design Moment Mnz= 261.643 kip-in

    Total Moment Mox= 9981.636 kip-in

    Total Moment Moz= 9981.636 kip-in

    if Mnx or Mnz = 0, then = 1.0

    otherwise, = 1.24