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First derivative: y is positive Curve is rising. y is negative Curve is falling. y is zero Possible local maximum or minimum. Second derivative: y is positive Curve is concave up. y is negative Curve is concave down. y is zero Possible inflection point (where concavity

First derivative:

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is positive. is negative. is zero. is positive. is negative. is zero. First derivative:. Curve is rising. Curve is falling. Possible local maximum or minimum. Second derivative:. Curve is concave up. Curve is concave down. Possible inflection point (where concavity changes). - PowerPoint PPT Presentation

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Page 1: First derivative:

First derivative:

y is positive Curve is rising.

y is negative Curve is falling.

y is zero Possible local maximum or minimum.

Second derivative:

y is positive Curve is concave up.

y is negative Curve is concave down.

y is zero Possible inflection point(where concavity changes).

Page 2: First derivative:

Example:Graph 23 23 4 1 2y x x x x

There are roots at and .1x 2x

23 6y x x

0ySet

20 3 6x x

20 2x x

0 2x x

0, 2x

First derivative test:

y0 2

0 0

21 3 1 6 1 3y negative

21 3 1 6 1 9y positive

23 3 3 6 3 9y positive

Possible extreme at .0, 2x

We can use a chart to organize our thoughts.

Page 3: First derivative:

Example:Graph 23 23 4 1 2y x x x x

There are roots at and .1x 2x

23 6y x x

0ySet

20 3 6x x

20 2x x

0 2x x

0, 2x

First derivative test:

y0 2

0 0

maximum at 0x

minimum at 2x

Possible extreme at .0, 2x

Page 4: First derivative:

Example:Graph 23 23 4 1 2y x x x x

23 6y x x First derivative test:

y0 2

0 0

There is a local maximum at (0,4) because for all x in and for all x in (0,2) .

0y( ,0) 0y

There is a local minimum at (2,0) because for all x in(0,2) and for all x in .

0y(2, )0y

Page 5: First derivative:

Because the second derivative atx = 0 is negative, the graph is concave down and therefore (0,4) is a local maximum.

Example:Graph 23 23 4 1 2y x x x x

There are roots at and .1x 2x

23 6y x x Possible extreme at .0, 2x

Or you could use the second derivative test:

6 6y x

0 6 0 6 6y

2 6 2 6 6y Because the second derivative atx = 2 is positive, the graph is concave up and therefore (2,0) is a local minimum.

Page 6: First derivative:

inflection point at 1x There is an inflection point at x = 1 because the second derivative changes from negative to positive.

Example:Graph 23 23 4 1 2y x x x x

6 6y x

We then look for inflection points by setting the second derivative equal to zero.

0 6 6x

6 6x

1 x

Possible inflection point at .1x

y1

0

0 6 0 6 6y negative

2 6 2 6 6y positive

Page 7: First derivative:

Make a summary table:

x y y y

1 0 9 12 rising, concave down

0 4 0 6 local max

1 2 3 0 falling, inflection point

2 0 0 6 local min

3 4 9 12 rising, concave up

p

Page 8: First derivative:

Graph 4 22y x x

Page 9: First derivative:

Graph 4 34y x x

Page 10: First derivative:

Graph 4 33 4y x x

Page 11: First derivative:

Graph 4 23 6y x x

Page 12: First derivative:

Graph 3 3 1y x x

Page 13: First derivative:

Graph 3 41 2y x x

Page 14: First derivative:

Graph 5 45y x x