FEBRUARY 10 TH 2012

FEBRUARY 10TH 2012

COACHING CLASSA Humble Initiative to Enlighten the Latent Glow

A Presentation by R.Baburaj jain

MAIN INDEXMENTAL ABILITY

MATHS

LANGUAGE ABILITY

Navodaya at a Glance

Objectives of Navodaya

Facilities

Picture Gallery (Jawahar Navodaya Vidyalaya, South Garo Hills, Meghalaya)

JNVST - 2012

NAVODAYA AT A GLANCE

Total Jawahar Navodaya Vidyalayas

(Residential System)

in India

588Education from class VI to XII (Science, Commerce, Humanities)

GO TO -> Main Index / Mental Ability Sub Index – Navodaya at a Glance , Objectives of Navodaya, Facilities, Picture Gallery, JNVST 1, JNVST 2

OBJECTIVES OF NAVODAYA

1. To provide good quality modern education to the talented children predominantly from the rural areas, without regard to their family's socio-economic condition.

2. To ensure that all students of Jawahar Navodaya Vidyalayas attain a reasonable level of competence in three languages as envisaged in the Three Language Formula.

3. To serve, in each district, as focal points for improvements in quality of school education in general through sharing of experiences and facilities.


FACILITIESAll facilities to the students of JNVs are provided free of cost by Govt. of India.

Free Tuition Fee for Girls, SC and ST BoysFree Meal (Breakfast, Lunch, Snacks, Dinner)Free UniformFree Daily use Items (Oil, Soap, Tooth Paste, etc.)Free Text BooksFree Note BooksFree Bedding itemsFree Regular Medical Check Up and Free First AidWell Equipped DormitoriesWell Equipped Science Labs (Physics, chemistry, Biology)Well Equipped Computer Lab with 50 Computers and 24 Hours Internet ConnectivityWell maintained Library with more than 5000 books on various subjectsWell Equipped facilities for hobby classes (Music, Art, Sports)NCC, Scouts and GuidesSmart Class Room (Teaching with Ultra Modern Facilities)Opportunity to study in United Kingdom under Pestalozzy Scholarship SchemeMedium of instruction is EnglishMigration SystemWell Trained and Educated Teachers Selected through National Level Examination


PICTURE GALLERY


Academic Block

NEXT

PICTURE GALLERY


Boys’ Hostel

Girls’ Hostel

NEXT

PICTURE GALLERY


Smart Class Room with ultra modern facilities

Computer Lab with 50 Computers + 24 Hours Internet

NEXT

PICTURE GALLERY


Extra Curricular Activities + Hobby Classes

Library with more than 5000 Books on various Subjects

NEXT

PICTURE GALLERY


Inside Boys’ Hostel

Staff Quarters

JNVST - 2010Examination Date: - 10th April 2010 (Saturday)

Examination Venue: -1. Baghmara Block –Rengku Memorial Girls’ Hs. School, Baghmara2. Karukol Block - Karukol H. S. School, Karukol3. Chokpot Block – Chokpot UPS, Chokpot4. Gasuapara Block – Gasuapara UPS, Gasuapara5. Rongra Block – Rongra UPS, Rongra

Examination Time: - 09:30 am

Examination Duration: - 02 Hours

Number of Questions: - 100

Total Marks: - 100

Type of Questions: - Objective (Multiple Choice)

Distribution of Marks: - i. Mental Ability – 50ii. Maths – 25iii. Language Ability - 25


JNVST - 2010


Side – 2 (USE ENGLISH NUMBERS/ LETTERS ONLY

Invigilator to put Center Stamp in Blue/ Blank InkTest Booklet Series

ATest Booklet Number

TO BE FILLED BY THE INVIGILATOR ONLY

State Distt. Block Center

Roll Number

Name of Candidate___________

Boy Girl

Gen OBC

Urban Rural

Signature of Invigilator___________

SC ST

Roll NumberTO BE FILLED BY THE CANDIDATE ONLY

Name of the Candidate_________________________

Signature of Candidate_________________________

FILL THE RIGHT RESPONCES IN ENGLISH NUMBERS ONLYIN THE BOXES PROVIDED FOR EACH QUESTIONS (1 – 100)

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GENERAL INSTRUCTIONS

1. Use Blue/ Black ball point pen only to write on answer sheet . Use of pencil is strictly prohibited.

2. Use English numbers only to write on side – 2 of the answer sheet.

3. No changes in the answer once written is allowed.

4. Write your answers only in English numbers (i.e. 1, 2, 3, 4) in the box against the number corresponding to the question.

5. Do not use white/ correction fluid on answer sheet.

6. Overwriting, cutting and Erasing on the answer sheet is not allowed.

7. Rough work must not be done in the answer sheet .

8. Use page number 16 of the test booklet for rough work.

SUB INDEX – Mental AbilityFIND NEXT IN SERIES

ODD MAN OUT

Ratio

Similarity

Fit the Missing Block

Complete the Square

GO TO -> Main Index / Mental Ability Sub Index – Find Next in Series, Odd Man out, Ratio, Similarity, Fit the Missing Block, Complete the Square

Find Next in Series

1 2 3 4 5 6 7 8 9 10

In these type of questions One Incomplete Series of Four Blocks (Problem Figure)

and Four Answer Figures are given.

Three Answer Figures do not complete the series of Four Blocks.

Remaining one option that completes the Series is called COMPLETING FIGURE.

This COMPLETING FIGURE is the correct answer.


1

X

+ X+

X+ ?

X +X +

X

X

+ X+

(a) (b) (c) (d)

+X+

Correct Answer is (b)

1

2


Problem figures

Answer figures

Solution

Find Next in Series

?

(a) (b) (c) (d)

+ Correct Answer is (c)

2

1

2


Problem figures

Answer figures

Solution

Find Next in Series

ODD MAN OUT

1 2 3 4 5 6 7 8 9 10


In these type of questions Four options are given.

Three options belong to same category.

Remaining one option that does not belong to the group is called ODD MAN OUT.

This ODD MAN OUT is the correct answer.

Milk Tea Coffee Petrol

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Odd Man Out

(a) (b) (c) (d)

Correct Answer is (d)

(a) Milk we can Drink.

(b) Tea we can drink.

(c) Coffee we can drink.

(d) Petrol we can not drink.

Bulb

2 Odd Man Out


(a) (b) (c) (d)


(a) Bulb gives the Light.

(b) Candle gives the Light.

(c) Lamp gives the Light.

(d) Plug does not give the Light.

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Candle Lamp Plug

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Odd Man Out

(a) (b) (c) (d)

Correct Answer is (c)

(a) Shirt we can Wear.

(b) Hat we can wear.

(c) Tree we can not Wear.

(d) Pants we can Wear.

Shirt Hat Tree Pants

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Odd Man Out

(a) (b) (c) (d)


(a) Triangle inside Triangle.

(b) Square inside Square.

(c) Circle inside Circle.

(d) Circle inside Hexagon.

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Odd Man Out


(a) (b) (c) (d)

(a) Both Arrows Facing Same Direction.

(b) Both Arrows Facing Same Direction.

(c) Both Arrows Facing Opposite Direction.

(d) Both Arrows Facing Same Direction.

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Odd Man Out

(a) (b) (c) (d)


(a) Two is an Even Number.

(b) Four is an Even Number.

(c) Six is an Even Number.

(d) Five is an Odd Number.

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Monday Tomato Potato Cabbage


Odd Man Out

(a) (b) (c) (d)

Correct Answer is (a)

(a) Monday is part of Week.

(b) Tomato is Vegetable.

(c) Potato is Vegetable.

(d) Cabbage is Vegetable.

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Odd Man Out

(a) (b) (c) (d)


(a) Both Dots outside the Triangle.

(b) One Dot outside the Triangle.

(c) One Dot outside the Triangle.

(d) One Dot outside the Triangle.

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Odd Man Out

(a) (b) (c) (d)


(a) Hexagon is a Closed Shape.

(b) Right Angle is not a Closed Shape.

(c) Square is a Closed Shape.

(d) Circle is a Closed Shape.

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Odd Man Out

(a) (b) (c) (d)


(a) Dot outside the Middle Block.

(b) Dot inside the Middle Block.

(c) Dot outside the Middle Block.

(d) Dot outside the Middle Block.

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RATIO

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In these type of questions Four Problem Figures separated in two groups by “:”

and Four Answer Figures are given.Two items in the First Group of problem are given as hint.

In the second group one item is kept missing which is called MISSING FIGURE.

The item among the Answer Figure which fits the Missing Figure is correct answer.

1 Ratio

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Problem figures

Answer figures

Solution

One square divided into two squares

Similarly


Correct Answer(b)

(a) (b) (c) (d)

One Triangle divided into two Triangles

2 Ratio

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Problem figures

Answer figures

Solution

Two Triangles divided into Four Triangles + One Vertical Line

Similarly


Correct Answer(b)

(a) (b) (c) (d)

Two Half Circles and One Vertical Line divided into Four Half Circles and Two Vertical Lines

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Problem figures

Answer figures


Ratio

Solution

Two opposite non intersecting Half Circles Intersect each other

Correct Answer(b)

(a) (b) (c) (d)

Similarly

Two non intersecting Circles Intersect each other

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Problem figures

Answer figures


Ratio

Solution

Four sided figure changes into Three sided double figure

Correct Answer(c)

(a) (b) (c) (d)

Similarly

Five sided figure changes into Four sided double figure

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Problem figures

Answer figures


Ratio

Solution

Circle inside Triangle changes into Triangle into Circle

Correct Answer(a)

(a) (b) (c) (d)

Similarly

Triangle into square changes into Square into Triangle

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Ass Foal Cat

Kitten Puppy Fawn Cub

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Problem figures

Answer figures


Ratio

Solution

Foal is the baby of Ass

Correct Answer(a)

(a) (b) (c) (d)

SimilarlyAssFoal CatKitten

Kitten is the baby of Cat

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Problem figures

Answer figures


Ratio

Solution

One E changes into two E

Correct Answer(b)

(a) (b) (c) (d)

Similarly

One 3 changes into Two 3

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Tiger Cub Sheep

Lamb Hen Horse Dog

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Problem figures

Answer figures


Ratio

Solution

Cub is the baby of Tiger

Correct Answer(a)

(a) (b) (c) (d)

SimilarlyTigerCub SheepLamb

Lamb is the baby of Sheep

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Problem figures

Answer figures


Ratio

Solution

Three vertical lines change into three circles

Correct Answer(b)

(a) (b) (c) (d)

Similarly

Two vertical lines change into two circles

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Problem figures

Answer figures


Ratio

Solution

One square changes into three squares

Correct Answer(d)

(a) (b) (c) (d)

Similarly

One Triangle changes into Three Triangles

Similarity


In these type of questions One Problem Figure and Four Answer Figures are given .

Three Answer Figures do not match with Problem Figure.

Remaining one option that matches with the Problem Figure is called MATCH

FIGURE.

This MATCH FIGURE is the correct answer.

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(a) (b) (c) (d)

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Problem Figure Answer figures


(a) (b) (c) (d)

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(a) (b) (c) (d)

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(a) (b) (c) (d)

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+=

X

X=

++

=+

=+

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Similarity


(a) (b) (c) (d)

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Similarity


(a) (b) (c) (d)

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(a) (b) (c) (d)

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(a) (b) (c) (d)

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(a) (b) (c) (d)

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(a) (b) (c) (d)

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Similarity



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In these type of questions One Incomplete Block Figure (Problem Figure) and Four

Answer Figures are given.

Three Answer Figures do not complete the Incomplete Block Figure.

Remaining one option that completes the Incomplete Block Figure is called

COMPLETING FIGURE.

This COMPLETING FIGURE is the correct answer.

?

(a) (b) (c) (d)

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(a) (b) (c) (d)

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Correct Answer is (c)?

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(a) (b) (c) (d)

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(a) (b) (c) (d)

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(a) (b) (c) (d)

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X X X X X X

X X X

O O O

O O O

O O O

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(a) (b) (c) (d)

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Complete the Square

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In these type of questions One Incomplete Square (Problem Figure) and Four

Answer Figures are given .

Three Answer Figures do not fit into the figure to make it a Square.

Remaining one option that fits into the figure to make it a Square is called MATCH

FIGURE.

This MATCH FIGURE is the correct answer.


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Complete the Square

(a) (b) (c) (d)


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(a) (b) (c) (d)


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(a) (b) (c) (d)


1 2 3 4

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(a) (b) (c) (d)


1 2 3 4

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(a) (b) (c) (d)


1 2 3 4

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(a) (b) (c) (d)


1 2 3 4

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(a) (b) (c) (d)


1 2 3 4

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(a) (b) (c) (d)


1 2 3 4

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(a) (b) (c) (d)


1 2 3 4

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Complete the Square

(a) (b) (c) (d)


Metric SystemNumber SystemPlace Value and Face ValuePrime Number and DivisibilityFactors and MultiplesFractionSimplificationHCM & LCMPercentageProfit and LossSimple InterestAverageSpeed, Time, DistanceUnity MethodRatio and ProportionCalendarMensuration

SUB INDEX – Maths

GO TO -> Main Index / Maths Sub Index – Metric System/ Number System/ Place Value and Face Value/ Prime Number and Divisibility/ Factors and Multiples/ Fraction/ Simplification/ HCM & LCM/ Percentage/ Profit and Loss/ Simple Interest/ Average/ Speed, Time, Distance/ Unity Method/ Ratio and Proportion/ Calendar/ Mensuration

Metric System

Measures of Length

10 Millimeter (mm) = 1 Centimeter (cm)10 Centimeter (cm) = 1 Decimeter (dm)10 Decimeter (dm) = 1 Meter (m)10 Meters = 1 Decameter (dam)10 Decameters = 1 Hectometer (hm)10 Hectometers = 1 Kilometer (km)

Time

60 Seconds = 1 Minute60 Minutes = 1 Hour24 Hours = 1 Day7 Days = 1 Week30 Days = 1 Month12 Months = 1 Year365 Days = 1 Year366 Days = 1 Leap Year

Articles

12 Articles = 1 Dozen12 Dozen = 1 Gross

Temperature

Fahrenheit to Centigrade

F = (9/5) C + 32

Centigrade to Fahrenheit

C = (5/9) (F – 32)

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Metric System

Convert into Days – 6 Months, 7 Weeks and 16 Days.

(a) 245 (b) 257 (c) 235 (d) 235

Solution: -

6 Months = 6 * 30 = 180 Days7 Weeks = 7 * 7 = 49 Days16 Days = 16 * 1 = 16 Days

Total Days = 180 + 49 + 16 = 245 Days

Correct answer is (a)


2 Metric System

How many Articles are there in 15 gross, 8 dozen and 10 units?

(a) 2256 (b) 2266 (c) 2276 (d) 2286

Solution: -

15 gross = 15 * 144 = 21608 dozen = 8 * 12 = 9610 units = 10 * 1 = 10

Total articles = 2160 + 96 + 10 = 2266

Correct answer is (b)

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Number System

Types of Numbers: -

1. Natural Numbers = The counting numbers such as 1, 2, 3, 4…… are called as Natural Numbers. (Least Natural Number is 1 and 0 is not a Natural Number)

2. Even Numbers = The Natural Numbers which are divisible by 2 are called as Even Numbers. For Example = 2, 4, 6, 8……….

3. Odd Numbers = The Natural Numbers which are not divisible by 2 are called as Odd Numbers. For Example = 1, 3, 5, 7, 9………

4. Prime Numbers = The Natural Numbers greater than 1 which are not divisible by any number except 1 and itself are called Prime Numbers.

For Example = 2, 3, 5, 7……..

1. Successor of a number = It is a number just after the given number. To get the successor of a number we add 1 to it.For Example = Successor of 89 is 90.

2. Predecessor of a number = It is a number just before the given number. To get the predecessor of a number we subtract 1 from it. For Example = Predecessor of 100 is 99

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1The difference between the greatest number of four digits and smallest number of five digits is

(a) 1 (b) 11 (c) 1111 (d) 899

Solution: -

Smallest number of five digits = 10000Greatest number of four digits = 9999

Difference = 10000 – 9999 = 1

Number System


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2The sum of two numbers is 11009. If one number is 9999, the other number is

(a) 1010 (b) 1110 (c) 2110 (d) 21008

Solution: -

Sum of the numbers = 11009

One number = 9999

Then other number = 11009 – 9999 = 1010

Number System


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Place Value and Face Value

Place Value: - It is the value of a digit obtained by its place. It is also known as local value.For Example in a given number

1. Place value of unit digit = Unit Digit * 12. Place value of Tens digit = Tens Digit * 10

3. Place value of Hundreds digit = Hundreds Digit * 1004. Place value of Thousands digit = Thousands Digit * 1000

Face Value: - The face value of a digit in a number is the value of digit itself. It is also known as Natural Value.

For Example in a given number 1. in the number 86754 the face value of 6 is 6.

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1 Place Value and Face Value

The difference between the place values of two 7s in 27307 is

(a) 6993 (b) 7300 (c) 307 (d) 40

Solution: -

Place values of two 7s in 27307 are

7000 (7*1000) and 7 (7*1)

Difference = 7000 – 7 = 6993


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2 Place Value and Face Value

The difference of place value and face value of 4 in number 46890 is

(a) 4 (b) 40000 (c) 39996 (d) 39969

Solution: -

Place value of 4 in 46890 = 40000

Face value of 4 in 46890 = 4

Difference = 40000 – 4 = 39996

Correct answer is (c)

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Prime Number and Divisibility

Rules for divisibility: -

1. Divisibility by 2 = If the last digit of the number is either 2, 4, 6, 8 or 0 the number will be

divisible by 2. Example – 242, 306, 500

2. Divisibility by 3 = If the sum of the digit of a number is divisible by 3, the number is

divisible by 3. Example – 243 (2 + 4 + 3 = 9/3 = 3)

3. Divisibility by 5= If the last digit of a number is either 5 or 0 the number is divisible by 5.

Example – 445, 670

4. Divisibility by 9 = If the sum of the digit of a number is divisible by 9, the number is divisible

by 9. Example – 243 (2 + 4 + 3 = 9/9 = 1)

5. Divisibility by 10 = If the last digit of a number is 0 the number is divisible by 10. Example –

540, 780

6. Divisibility by 11 = If the difference between the sum of digits at even places and sum of

digits at odd places is 0 or divisible by 11 then the number is divisible by 11. Example –

1353 (Here the difference = (1+5) – (3+3) = 6 – 6 = 0

1

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1 Prime Number and Divisibility

Which of the following is the smallest two digit prime number?

(a) 13 (b) 17 (c) 11 (d) 12

Solution: -

Highest number given in the options is 17 and Prime numbers up to 17

are 2, 3, 5, 7, 11, 13, 17. Smallest two digit number among these is 11.


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2 Prime Number and Divisibility

What value must be given to * so that the number 6912* is divisible by 10

(a) 1 (b) 2 (c) 0 (d) 5

Solution: -

A number is divisible by 10 only when its last digit is 0. Therefore in the given question the last digit of the number must be 0.


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Factors and Multiples

Factor: - When two or more numbers are multiplied together to give a product each is called a Factor of the product.

For Example 4 * 5 = 20 Here 4 and 5 are factors of 20.

Multiple: - The product of two or more numbers is said to be a multiple of each of those numbers.

For Example 4 * 5 = 20Here 20 is a multiple of both 4 and 5.

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1 Factors and Multiples

The factors of 30 are:

(a) 2, 3, 5 (b) 1, 2, 3, 5, 10 (c) 1, 2, 3, 10, 15 (d) 1, 2, 3, 5, 6, 10, 15, 30

Solution: -

30 = 1 * 30 = 2* 15 = 3 * 10 = 5 * 6

So factors of 30 are 1, 2, 3, 5, 6, 10, 15, 30

Correct answer is (d)

1

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2 Factors and Multiples

What are the numbers of multiples of 3 which are less than 25

(a) 6 (b) 7 (c) 8 (d) 9

Solution: -

Multiples of 3 less than 25 are

= 3, 6, 9, 12, 15, 18, 21, 24

So the total numbers of multiples are 8


1

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Fraction

Fraction: -

The number of the form a/b where a and b are natural numbers.For Example: - 1/2, 2/3, ¾

Here a is called Numeratorb is called Denominator

Types of Fraction

1. Proper Fraction: - When numerator is less than the denominator. Example – 4/7

2. Improper Fraction: - When numerator is greater than the denominator. Example – 8/3

3. Mixed Fraction: - A fraction with a whole number part and a fractional part. Example – 4 2/3

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1 Fraction

Which of the following fractions is not equal to the other three?

(a) 4/5 (b) 9/15 (c) 3/5 (d) 6/10

Solution: -

Convert all the fractions in their lowest terms – (a) 4/5 = 4/5(b) 9/15 = 3/5(c) 3/5 = 3/5(d) 6/10 = 3/5

Among them 4/5 is not equal to other three.


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2 Fraction

Write in ascending order 5/17, 9/17, 8/17, 10/17

(a) 10/17, 9/17, 5/17, 8/17 (b) 5/17, 8/17, 9/17, 10/17 (c) 9/17, 5/17, 8/17, 10/17 (d) 8/17, 5/17, 9/17, 10/17

Solution: -

Since denominator in all the fractions is same so we should check the

ascending order of numerators only.

Hence - 5/17, 8/17, 9/17, 10/17


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Simplification

BODMAS Rule: -

B – Brackets ( ), { }, [ ]O - OfD - DivisionM - MultiplicationA - AdditionS - Subtraction

Rule for Multiplication : -

+ x + = ++ x - = -- x + = -- x - = +

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1 Simplification

The value of 9 – 6 /3 * 2 + 1

(a) 3 (b) 4 (c) 6 (d) 9

Solution: -

9 – 6 /3 * 2 + 1= 9 – 2 * 2 + 1= 9 – 4 + 1= 9 + 1 – 4= 10 – 4= 6 Correct answer is (c)

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GO TO -> Main Index / Maths Sub Index – Metric System/ Number System/ Place Value and Face Value/ Prime Number and Divisibility/ Factors and Multiples/ Fraction/ Simplification/ HCM & LCM/ Percentage/ Profit and Loss/ Simple Interest/ Average/ Speed, Time, Distance/ Unity Method/ Ratio and Proportion/ Calendar/

Mensuration

2 Simplification

The simplification of 6 – {5 + 3 – (5 – 2) – 5} gives the result

(a) 0 (b) 6 (c) 12 (d) 3

Solution: -

6 – {5 + 3 – (5 – 2) – 5}= 6 – {5 + 3 – 3 – 5 }= 6 – {8 – 3 – 5}= 6 – {5 – 5}= 6 – 0= 6 Correct answer is (b)

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Mensuration

HCM & LCM

Rules: -

1. HCF of numbers * LCM of numbers = Product of numbers

2. HCF of fractions = HCF of numerators/ LCM of denominators

3. LCM of fractions = LCF of numerators/ HCF of denominators

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Mensuration

1The product of two numbers is 216 and their HCF is 3. what is their LCM

(a) 648 (b) 219 (c) 213 (d) 72

Solution: -

Applying the formula –

HCF of numbers * LCM of numbers = Product of numbers

3 * LCM of numbers = 216LCM of numbers = 216/3LCM of numbers = 72


HCM & LCM

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Mensuration

2Find the HCF of 8/9, 32/81 and 10/27

(a) 2/81 (b) 160/9 (c) 10/81 (d) 8/81

Solution: -

Applying the formula –

HCF of fractions = HCF of numerators/ LCM of denominators = HCF of 8, 32, 10/ LCM of 9, 81, 27 = 2/81


HCM & LCM

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Mensuration

Percentage

A fraction with its denominator as 100 is called as Percent.

Rules: -

1. To convert a ratio into percent, we write it as a fraction and multiply it by 100.For Example – 1:2 -> 1/2 -> 1/2 *100

2. To convert a decimal fraction into a percent , we shift the decimal point two places to the right.For Example - 1.2 ->

3. To convert a percentage into fraction, we drop the percent (%) sign and multiply the remaining number with 1/100.

For Example - q

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Mensuration

1Which one of the following is equivalent of 6/20?

(a) 6% (b) 20% (c) 26% (d) 30%

Solution: -

6/20 in percent is ->

6 100 --- * ---- = 30 %20 1


Percentage

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Mensuration

240% of 20% is equal to

(a) 16% (b) 20% (c) 8% (d) 80%

Solution: -

40% = 40/10020% = 20/100

Therefore

40% of 20% = 40/100 * 20/100 = 8/100 = 8 %


Percentage

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Mensuration

Profit & Loss

Cost Price (CP): - It is the price at which it is bought.Selling Price (SP): - It is the amount received by selling the article.

Profit: - If the selling price of an article is greater than the cost price, then there is a net gain or profit.

Gain = SP – CPGain % = (Gain / CP) * 100SP = (100 + Gain %)/100 * CPCP = (100 / 100 +Gain %) * SP

Loss: - If the selling price is less than the cost price than there is a net loss.

Loss = CP – SPLoss % = (Loss * 100) / CPCP = (100/100 – Loss %) * SPSP = (100 – Loss % / 100) * CP

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Mensuration

1A man buys a radio for Rs. 900 and sells it for Rs. 1200. Find the his gain percent.

(a) 20% (b) 25% (c) 30% (d) 100/3%

Solution: -

Cost Price (CP) = 900Selling Price (SP) = 1200Profit (Gain)= 1200 -900 = 300

Applying the formula ->

Gain % = (Gain / CP) * 100

Profit % = (300/900) *100 = 100/3% Correct answer is (d)

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Mensuration

2A man purchased a machine for Rs. 7500 and later sold it at the profit of Rs. 750. How much additional profit he would got if he had sold the machine for Rs. 8500.

(a) 250 (b) 500 (c) 750 (d) 1000

Solution: -

CP of machine = 7500Profit = 750SP = CP + Profit = 7500 + 750

= 8250New SP of the machine = 8500So Additional Profit = 8500 – 8250

= 250Correct answer is (a)

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Mensuration

Simple Interest

Principal (P) = It is the money borrowed from lender.Amount (A) = It is the sum of the Principal and interest.Time (T) = It is the time period for which the money is borrowed.Rate (R) = It is the rate of interest.

Formula: -

Simple Interest = (P x R x T) / 100

Principal = 100 x Simple Interest / Rate x Time

Rate = Simple Interest / Principal x Time

Time = 100 x Simple Interest / Rate x Principal

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Mensuration

1Find the simple interest of Rs. 700 at 4% per year for three years.

(a) Rs. 15 (b) Rs. 36 (c) Rs. 54 (d) Rs. 84

Solution: -

Simple Interest = (P x R x T) / 100 = (700 x 4 x 3) / 100 = 21 x 4 = 84


Simple Interest

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Mensuration

2A man borrows Rs. 600 from his friend. He agrees to pay it back after 8 months together with simple interest at 8 % per annum. What amount will he pay back?

(a) Rs. 32 (b) Rs. 384 (c) Rs. 984 (d) Rs. 632

Solution: -

P = Rs. 600T = 8/12 yearsR = 8 %

So, Simple Interest = (P x T x R) /100= (600 x 8 x 8) / 100 x 12= 32


Simple Interest

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Mensuration

Average

Average = Sum of Observations / Number of observations

For Example

If x1, x2, x3,…….,xn are Number of observations (N), then the average of these is

X = x1 + x2 + x3….+xn / N

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Mensuration

1 Average

The average of three numbers is 12. If two of these numbers are 13 and 15 what is third number?

(a) 6 (b) 8 (c) 16 (d) 20

Solution: -

Average of three numbers = 12Total average of three numbers = 12 * 3 = 36Sum of two numbers = 13 + 15 = 28The third number = 36 – 28 = 8


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Mensuration

2 Average

The average of 10, 19, 21, 22 and 28 is

(a) 21 (b) 20 (c) 19 (d) 18

Solution: -

Average of 10, 19, 21, 22, 28= (10 + 19 +21 + 22 + 28) / 5= 100 / 5= 20


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Mensuration

Speed, Time, Distance

Formula: -

Distance = Speed x Time

Time = Distance/ Speed

Speed = Distance / Time

To convert the speed in km/hr to m/sec. -> Multiply the numerical value by 5/18To convert the speed in m/sec. to km/hr. -> Multiply the numerical value by 18/5

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Mensuration

1Sampurna Kranti Express departs from Patna at 5:50 pm and arrives New Delhi 8:15 am of next day. What is the total time of the journey?

(a) 12 hrs 25 min. (b) 14 hrs 35 min(c) 14 hrs 25 min (d) 12 hrs 25 min

Solution: - The time taken for the journey = 8:15 am of the next day – 5:50 pm

= 20:15 – 5:50 = 14:25 = 14 hrs 25 min



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Mensuration

2A train 100 meters long is running with the speed of 18 km/hr. In what time it will pass a man on platform.

(a) 20 (b) 40 (c) 22 (d) 2

Solution: -

To pass the man, the train will move the distance equal to its own length.

Distance to be travelled = 100 metersSpeed in m/sec = 18 x 5/18 = 5 m/secTime taken to pass the man = 100 / 5

= 20 sec



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Mensuration

Unitary Method

1. The method in which the answer required to be calculated is always

put to the right hand side.

2. The term to the right side is always put in the numerator.

3. The method in which the value of a unit (one) is first bound to find the

value of many.

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Mensuration

1If 8 books cost Rs. 680. What will be the cost of such 15 books?

(a) 1010 (b) 1275 (c) 2110 (d) 21008

Solution: -

Cost of 8 books = 680Cost of 1 book = 680/8Cost of 15 books = (680/8) x 15

= 1275


Unitary Method


Mensuration

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15 chairs cost Rs. 1530. How many such chairs can be bought with Rs. 4590?

(a) 46 (b) 5 (c) 35 (d) 45

Solution: -

Number of chairs can be bought with Rs. 1530 = 15 chairsNumber of chairs can be bought with Rs. 1 = 15/ 1530 chairsNumber of chairs can be bought with Rs. 4590 = (15/ 1530) x 4590

= 45 chairs


Unitary Method


Mensuration

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Ratio and Proportion

Ratio: - The ratio of a to b is the fraction a/b, written as a:bHere ‘a’ is called as antecedent and ‘b’ is called as consequent.

Proportion: - If a, b, c, d are in proportion then we say a:b = c:d

In a proportion, the product of means (b x c) = product of extremes (a x d)


Mensuration

1The ratio of the numbers of boys and girls in a school is 2:5. If there are 350 students in the school, find the number of girls in the school.

(a) 350 (b) 150 (c) 450 (d) 250

Solution: -

Number of girls = (Ratio Term for girls/ Total sum of Ratio) x Number of Students = 5/(2 +5) x 350 = (5 / 7) x 350 = 250


Ratio and Proportion


Mensuration

2 Ratio and Proportion

If 3:5::60:W The value of W is

(a) 100 (b) 36 (c) 4 (d) non of these

Solution: -

In a proportion

First term x fourth term = second term x third term(Product of extremes) = (Product of Means)So3 x W = 5 x 60W = 5 x 60 / 3W = 100



Mensuration

Calendar

1 Year = 365 days = 52 weeks + 1 day

1 Leap Year = 366 Days = 52 Weeks + 2 Days

1 year = 12 months

Leap year has 29 days in February

1 week = 7 days

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Mensuration

Month Days

January 31

February 28 (Leap year 29)

March 31

April 30

May 31

June 30

July 31

August 31

September 30

October 31

November 30

December 31

1If in a certain year, Sunday falls on 9 January what will be the day on 27 January of the same year

(a) Friday (b) Thursday (c) Saturday (d) Wednesday

Solution: -

As we know the same day repeats after 7 days therefore 9 + 7 = 16, 16 + 7 = 2316 and 23 will also be Sunday so 23 is SundaySo 27 will be Thursday


Calendar

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Mensuration

2 Calendar

If 8 October is Sunday, what will be the day on 8 November

(a) Monday (b) Thursday (c) Saturday (d) Wednesday

Solution: -

A number of days between 8 October to 8 NovemberOctober = 31 – 8 = 23November = 8 Total = 23 + 8 = 31 daysOn dividing 31 by 7 we get the number of odd days = 3So, if Sunday falls on 8 October counting three more days i.e. Wednesday will be the day on 8 November


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Mensuration

Mensuration

SN Square Rectangle Parallelogram Circle

1 Perimeter 4 * Sides 2 (length + breadth) 2 (length + breadth) 2*∏*Radius

2 Area (Side)2 Length * Breadth Base * Height ∏*Radius2

3 Side √Area -------- -------- --------

4 Diagonal √2 * Side √(L) 2+ (B)2 -------- --------

Shapes

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Mensuration

1The perimeter of a square is 144 m. Its area is

(a) 12 sq. meter (b) 72 sq. meter (c) 1296 sq. meter (d) 1728 sq. meter

Solution: -

Perimeter of square = 144 m

4 * side of square = 144Side of square = 144/4

= 36 m

Area of Square = side * side = 36 * 36 = 1296 sq. meters Correct answer is (c)

Mensuration

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Mensuration

2The edge of a cube is 5 cm than the total surface area of the cube is

(a) 150 sq. cm (b) 150 m (c) 300 sq. m (d) 600 sq. m

Solution: -

Edge (Side) of the cube is = 5 cm. Total surface area of the cube = 6 * (side)2

= 6 * (5)2 sq. cm= 6 *25 sq. cm= 150 sq. cm


Mensuration

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Mensuration

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SUB INDEX – Language Ability

GO TO -> Main Index / Language Ability Sub Index

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Adita bilsirangna skang Japanni bi.sarang Jawahar Nehruna chitti seataha aro uamangna mongma mangsako watatchina molmolataha. Ia Indiani bi .sarangni palo uamangna nitobegipa mongma mangsako watataha. Ia mongmara Mysoreoni ong.achim. Uko Japanona sagal gita watataha. Ua Tokyona sokangon, hajalni hajal bi.sarang uko nina re.baha. Uamangoni bangbatan mongmako nikkujachim. Ia mikkim gnanggipa matburing uamangna Indiani chin aro uamangni aro Indiani bi.sarangni gisepo nangrimani chin gita ong.baha. Ia an.chingni boksis Japanni bang.bea bi.sarangna ku.si ong.beaniko on.ahani gimin aro uamangko an.chingni a.songni gimin chanchiatani gimin Nehru ku.si ong.beaha.

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Go to Questions

1.” Ua uamangna nitobegipa mongma mangsako watataha”.Ia sentenceo ‘uamangna’ inon iamangko miksonga.

A) Mysoreni bi.sarang. B) Japanni bi.sarang. C) Tokyoni bi.sarang D) Indiani bi.sarang

2. Hajal hajal Japanni bi.sarang mongmako nina A. Tokyoona re.baaha.B. Uko Indiaoniko watatachim.C. Uan mikmalgimin mongma ong.achim.D. Uamang mongmako mamung saloba nikkujachim.

3.Nehru ku.si ong.beaha maina E. Ua Japanona mongma mangsako watataha.F. Ua boksisara Japanni bi.sarangko an.chingni a.songni gimin chanchiataha.G. Mongma Japano ku.si ong.beaha.H. Indiani manderang ku.si ong.beaha

4. Nehru mongma mangsako Japanona watataha maina,I. Uamang mongmako namnikachim.J. Japanni bi.sarang mangsa bi.ataha.K. Japan sorkari mongma mangsako bi.ataha.L. Uamang mongmko cha.achim.

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Correct Answer is B

Correct Answer is D

Correct Answer is B

Correct Answer is B

Raja saksao dumbur bolni bagan dongachim. Ua dumbur biteko namen namnikbeachim. Uni gimin ua bagano dongtimna gita kana saksa aro ja .kora saksako rakkiaha. Salgipino bangbata biterang gimiaha ine raja nikahaon sawa biterangko chauaha dongtimgiparango sing.aha.” Chinga mamungkoba uija “ine uamang aganchakaha.Uamang sakgni biteko akja ine jechakahaoba raja kanagipa mandeni ja.korako pakkreo gate biterangko akako rim.a namaha. Kanagipa an.tangni ja.ako jakkale aro ja.koragipa an.tangni mikronko jakkale uamang dumbur biteko chauaha. Uamang sakgnina dal.a sastiko on.aha.

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Go to Questions

1 . Raja uni dumbur biteni bagano dongtimgiparangko rakkina sikaha maina. A. Saoba dumbur biterangko chauenga.B. Ua kana aro ja.kora mande sakgnina ka.sachakani gimin uamangna kamko on.na sika.C. Biterang namen gamchatbeachim.D. Saobarang biterangko chaugen ine kenachim.

2. Jensalo raja banga namnamgipa biterang gimaenga ine uiahaon.E. Ua sing.aha sawa uarangko chauaha.F. Ua an.tangan bolrangna dongtimaha.G. Ua sakgni manderangko dongtimna gita rakkiaha.H. Ua sakgni manderangko sasti on.aha.

3. Kanagipa mande aro ja.kora gipa mande tole aganaha maina.I. Uamang namgipa dongtimgiparang ong.jachim.J. Raja uamangni chauako rim.a manjawa ine uamang chanchia.K. Uamang maikai chaua uko raja mamung saloba rimna namjawa ine chanchiachim.L. Uamang rajana kenachim.

4. Dumbur biteko chauaha.M. Uarangni gamchatanina .N. Chaugiparangchi.O. Rajani manderangchi.P. Ua baganko dongtimgiparangchi.

5. Raja an.tangan nikaha.Q. Kanagipa mande an.tangni ja.ako jakkalaha..R. Ja.koragipa an.tangni mikronko jakkalaha.S. Dongtimgipa sakgnian biterangko chauaha.T. Dongtimgiparang kakketko aganaha.

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Correct Answer is D

Correct Answer is A

Correct Answer is C

Correct Answer is D

Correct Answer is C

Pilak jo.ongrang an.chingni bobilrang ine manderang chanchia. Bi.sarang tampirangko, rudatrangko aro ganggurangko so.otna nam.nika. Bang.a rokomni jo.ongrang an.chingni bobilrang ong.a. Mitamrang bolrangko , ba.rarangko , ki.taprangko , nokrangko nosto ka.a aro mitamrang an.chingni cha.anirangko bisi ong .ata. Mitamrang an.chingko chika aro sabisirangko giproroata.

Indiba mitam jo.ongrang an.chingna ripengrang gitaba ong.a. Je joongrangko an.ching gimatana skachim uaindakgipa jo.ongrangko uamang cha.skaa. Bang.a jo.ongrang gnang jemang an.chingni ripeng ba bobilba ong.ja indakgiparang an.chingna mamung dakchakaniko aro saknaniko on.ja.

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Go to Questions

1. ”mitamrang an.chingko chika”. Iano ‘mitam’ katta sako miksonga?A) Manderangko. B) Bi.sarangko. C) bobilrangko D) jo.ongrangko.

2. Mitam jo.ongrang an.chingna nam.ako daka maina :A. Uamang an.chingni noko donga.B. Uamang mitam cha.anirangko nosto ka.a.C. Uamang an.chingko kengnigipa jo.ongoniko naljoke rakkia.D. Uamang kengnigipa jo.ongrangko cha.a.

3. Mitam jo.ongrang namako dakana bate namgijako dakbata.E. Uamang ka.onangata . F. Uamang mitchian gapa. G. Uamang sabisirangko giproroata. H. Uarang gipin jo.ongrangko cha.a .

4. Ia toko segipa an.chingna aganaha.I. Bi.sarangni bewalni gimin.J. Bang.a jo.ongrangni rokomni gimin.K. Jo.ongrangni jakkaltoani gimin.L. Jo.ongrangni bewalni gimin.

5. ka.mao on.sogimin sentencerangoni badia jo.ongni gimin aganani ong.ja.

M. Jo.ongrang kenbegnigipa ong.aN. Jo.ongrang an.chingni bosturangko nosto ka.a.O. Jo.ongrang bang.a sabisirangko ra.bitgiparang ong.a.P. Jo.ongrang rongtale donga.

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Correct Answer is D

Correct Answer is D

Correct Answer is C

Correct Answer is D

Correct Answer is D

Chiniko gritoniko taria. Grit dinggipa biaprango ge.a. Jensalo grit mina unon uarangko den.a. Uni jamano uarangni dal.dalgipa bijakrangko ake gala. Uni jamano uarangni ga.tengrangko kachimote chinini karkanaona watata. Uano uarangni bitchirangko jeta. Jetdaldalgipa bitchirangko mitchigipa chi gita nika. Uni jamano uarangko rongtalate sigrakni songchakanio ding .ata. Unon pilak chirang ranate chini uano sikkongrika. Ua sikkongrikgipa chinisa a .mangni rong daka. Uni jamano uarangko ding.attaie, gipokkujana kingking susranga. Skang salrango chiniko Java aro gipin a.songrangoniko Indiaona ra.baa. Indiba da.ode India a.songtangon chiniko tariengaha. Uttar- Pradesh aro Biharo bang .a chini karkanarang donga.

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Go to Questions

1. Chiniko maidakgipa a.songrango ge.a.?

A. Ding.gipa a.songrango .

B. Rangipa a.songrango.

C. Ka.singipa a.songrango.

D. Gimik rokomni a.songrango.

2.Indiani badia staterango chiniko tarienga?E. Uttar- Pradesh aro Bihar.F. Madhya Pradesh aro Bihar.G. Bihar aro Andhra- Pradesh.H. Madhya – Pradesh aro Uttar- Pradesh.

3. Chinini skanggipa rongara maia?

I. Gipok.J. Gisim.K. A.mangni rongL. Rimit

4. Badia grit bipangni bakko chinini karkanaona watatna skang ratgale gala?M. Bijakrangko.N. Ja.dilrangko.O. Ga.tengrangko. P. Cheksirangko..

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Correct Answer is A

Correct Answer is A

Correct Answer is C

Correct Answer is A

Arabiani bang.bata bakan a.gisi ong.a. Arabrang jemangan songjinmarango ong.ja , uamang bilsi gimikan a.gisiosa donga. Uamang tamburangkosa pinge donga jedakode uarangko altuae rikna aro runa gita man .gen. Uamang uamangni jilgipa mesrangna,, do.bokrangna, gurerangna aro utrangna chi aro samsirangko man.gipa biaprangko amroroe biap damsaoni damsaona katroroesa donga. Ia Arabrang chigipa mingimin dumbur biterangko aro kejulrangkosa cha.achim. Uamang namen gurerangko gakatna namnikachim. Indake uamang gurerangna an.tangni jik dedrangrangna ka.saa gita ka.sachim. Uamang pangnaba an.tangni gurerango bang.dugae bosturangko gatjachim. Utrang uamangna namen jakkaltogipa ong.achim. Uamang utrango an.tangtangba gakata aro bosturangkoba gatachim. Indake bang .a chel.begipa, a.gisiarigipa ramarangko songrena man.ani gimin uamangko uamang “A.gisini jahas “ ine minga.

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Go to Questions

1. Arabrang namnika.A. UtrangkoB. GurerangkoC. Churangko ringnaD. Songjinmao tamburango dongna.

2. Arabrang cha.a.E. Gurerangni be.enkoF. Dumbur aro kejul bitekoG. Draka aro appleko H. mi aro gom miko.

3. Arabrang iarangko jila.I. Do.bokrangko aro mesrangko.J. Mesrangko aro gurerangko.K. Gurerangko aro utrangko L. Kosako janapgimin gimikkon.

4. Arabrang tambuo M. Songjinmarango donga.N. Songadamo donga.O. jillao donga.P. A.gisio donga.

5. Arabrang iako,’’ A.gisini jahas” ine minga.

a) Gureko b) Mesko c) utko d)Tambuko.

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Correct Answer is B

Correct Answer is B

Correct Answer is D

Correct Answer is D

Correct Answer is C

THANK YOUBEST OF LUCK

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FEBRUARY 10 TH 2012