7/24/2019 Example of Filter
2/2
0.5
1.0
2.0
5.0
10
20
20
-20
10
-10
5.0
-5.0
2.0
-2.0
1.0
- 1 . 0
0.5
-0.5
0.2
-0.2
freq (10.00MHz to 4.000GHz)
S(1,1
)
m1
Input Reflection Coefficient
m1freq=
S(1,1)=0.706 / -85.414impedance = Z0 * (0.362 -
2.000GHz
0 . 5
1 . 0
2 . 0
5 . 0
1 0
2 0
20
-20
10
-10
5.0
-5.0
2.0
-2.0
1 . 0
- 1
. 0
0.5
-0.5
0.2
-0.2
freq (10.00MHz to 4.000GHz)
S(2,2
)
Output Reflection Coefficient
0.5 1.0 1.5 2.0 2.5 3.0 3.50.0 4.0
-50
-40
-30
-20
-10
-60
0
freq, GHz
dB(S(2,1
))
m3
m4
Forward Transmission, dBm3freq=dB(S(2,1))=-2.998
2.000GHz
m4freq=dB(S(2,1))=-35.758
3.000GHz
0.5 1.0 1.5 2.0 2.5 3.0 3.50.0 4.0
-50
-40
-30
-20
-10
-60
0
freq, GHz
dB(S(1,2
))
Reverse Transmission, dB
S-Parameters vs. Frequency Del filtro Butterworth de Orden 5
0.5 1.0 1.5 2.0 2.5 3.0 3.50.0 4.0
-20
-10
0
-30
10
freq, GHz
dBm(S(1,1
))
m2
m2freq=dBm(S(1,1))=7.469
2.010GHz
0.5 1.0 1.5 2.0 2.5 3.0 3.50.0 4.0
-150
-100
-50
0
50
100
150
-200
200
freq, GHz
phase(S(2,1
))
