25
Q1(i) Ex 25.1

Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

  • Upload
    others

  • View
    5

  • Download
    0

Embed Size (px)

Citation preview

Page 1: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q1(i)

Ex 25.1

Page 2: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q1(ii)

Page 3: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q1(iii)

Page 4: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q1(iv)

Page 5: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q2

Page 6: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q3(i)

Q3(ii)

Page 7: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q3(iii)

Page 8: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q3(iv)

Page 9: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q3(v)

Q4(i)

Page 10: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q4(ii)

Q4(iii)

Page 11: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q4(iv)

Page 12: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q4(v)

Page 13: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q4(vi)

Page 14: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q4(vii)

Page 15: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q4(viii)

Page 16: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q4(ix)

Page 17: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q5

Page 18: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q6

Page 19: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q7

Page 20: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q8

Q9

Page 21: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q10

Page 22: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q11

Page 23: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q12

Page 24: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q13

Q14

Q15

Page 25: Ex 25 · 2019-09-19 · x2 + a2 — 2ax + + (—2a')2 + a2+2x xA—2a') + 2x 4 2x (x) Hence, required equation of parabola is In a py.abola. vetex is the mid-point of the focus and

Q16

Q17