7/22/2019 euler.txt

1/1

PROGRAM ON EULER'S METHOD:

clc;x0=input('Enter the value of x0:');y0=input('Enter the value of y0:');xg=input('Enter the value of xg:');h=input('Enter the value of h:');

n=(xg-x0)/h;

for i=1:nx1=x0+h;y1=y0+h*(x0-y0*y0);x0=x1;y0=y1;

end

fprintf('\n Yg=%f',y1);

OUTPUT:

Enter the value of x0:0Enter the value of y0:1

Enter the value of xg:4Enter the value of h:1

Yg=1.000000