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1/31 3.9 (#33) 2015-11-09 11:18:43 3.9 Related rates

esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

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Page 1: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

1/31 3.9 (#33)2015-11-09 11:18:43

3.9

Related rates

Page 2: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

2/31 3.9 (2/31)2015-11-09 11:18:43

Relate rates problems(find the derivative of a certain

function)• Identify functions.• Write relation(s) between functions.• Differentiate using implicit differentiation.• Plug in values• Solve for derivative

Page 3: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

3/31 3.9 (3/31)2015-11-09 11:18:43

Useful to remember

• Pythagorean theorem• Similar triangles• Trigonometry (triangle def of sin, cos, tan)• Law of cosines• Uniform circular motion (a=wt, w=v/r)• Volume of a cone• Surface area of a sphere (4* pi * r^2)

Page 4: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

4/31 3.9 (4/31)2015-11-09 11:18:43

Page 5: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

5/31 3.9 (5/31)2015-11-09 11:18:43

Page 6: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

6/31 3.9 (6/31)2015-11-09 11:18:43

Page 7: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

7/31 3.9 (7/31)2015-11-09 11:18:43

Page 8: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

8/31 3.9 (8/31)2015-11-09 11:18:43

Page 9: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

9/31 3.9 (9/31)2015-11-09 11:18:43

Page 10: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

10/31 3.9 (10/31)2015-11-09 11:18:43

Page 11: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

11/31 3.9 (11/31)2015-11-09 11:18:43

Page 12: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

12/31 3.9 (12/31)2015-11-09 11:18:44

Page 13: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

13/31 3.9 (13/31)2015-11-09 11:18:44

Page 14: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

14/31 3.9 (14/31)2015-11-09 11:18:44

Page 15: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

15/31 3.9 (15/31)2015-11-09 11:18:44

Page 16: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

16/31 3.9 (16/31)2015-11-09 11:18:44

Page 17: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

17/31 3.9 (17/31)2015-11-09 11:18:44

Page 18: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

18/31 3.9 (18/31)2015-11-09 11:18:44

Page 19: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

19/31 3.9 (19/31)2015-11-09 11:18:44

Similar to homework problem

Page 20: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

20/31 3.9 (20/31)2015-11-09 11:18:44

Page 21: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

21/31 3.9 (21/31)2015-11-09 11:18:44

Page 22: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

22/31 3.9 (22/31)2015-11-09 11:18:44

Page 23: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

23/31 3.9 (23/31)2015-11-09 11:18:44

Page 24: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

24/31 3.9 (24/31)2015-11-09 11:18:44

Page 25: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

25/31 3.9 (25/31)2015-11-09 11:18:44

Page 26: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

26/31 3.9 (26/31)2015-11-09 11:18:44

• A search light in a prison rotates counterclockwise at a rate of 3 revolutions per second. The light shines on a long straight wall that is 40 feet from the search light. How fast is the light beam moving across the wall when the beam is hitting the wall at a spot which is 80 feet from the light ?

Page 27: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

27/31 3.9 (27/31)2015-11-09 11:18:44

Page 28: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

28/31 3.9 (28/31)2015-11-09 11:18:44

Page 29: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

29/31 3.9 (29/31)2015-11-09 11:18:44

Page 30: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

30/31 3.9 (30/31)2015-11-09 11:18:44

2. (13 points) In this problem you should use the law of cosines:

a2 + b2 − 2ab cos θ = c2,

where θ is an angle in the triangle, c is the opposite side, and a and b are the adjacentsides.

Two straight roads intersect at point P at a 60◦ angle. Car A is traveling away from Pon one road, and car B on the other road. You’re in car A, which has a device that canmeasure distance from car B and also the rate at which that distance is increasing.At a certain moment you have traveled 3 km away from P and are moving at 80km/hr. At that time the device shows that your distance from car B is 7 km, andthis distance is increasing at 100 km/hr.

θP a

cb

car A

car B

At that instant find

(a) (5 pts) the distance car B has traveled from P;

(b) (8 pts) the speed at which car B is moving.

3

Page 31: esep2/classes/124/3.9.pdf2. (13 points)In this problem you should use the law of cosines: a2 +b2 −2abcosθ = c2, whereθisanangleinthetriangle,cistheopposite side, andaandbaretheadjacent

31/31 3.9 (31/31)2015-11-09 11:18:45

5. (14 points) Two carts, A and B, areconnected by a rope 28 ft long that passesover a pulley P (see the figure).

The point Q is on the floor 12 feet directlybeneath P and between the carts. Cart Ais being pulled away from Q at a speed of7 ft/s. How fast is cart B moving toward Qat the instant when cart A is 5 ft from Q?

B A

12

P

Q

7