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Wednesday, May 27, 2015
Electric Machines: Principles, Applications, and Control Schematics, International Edition
Dino Zorbas
ISBN: 9781133628521
Errata
Page
Number Description of Correction Print
Run
Affected
12 Towards bottom of the page, change “Appendices” to “Appendixes” 1
43 Equation 1.75:
Revise as
2
45 Equations 1.83 & 1.84: the S should be bolted
Equation 1.86: , the S should be bolted
2
52
Replace Fig. 1-35 with:
2
57 Exercise 1-14 f, the description should be “Apparent” only 2
90 & 91 The effective length of the conductor is 2αm, α should be revised as a, Then the
following equation also need to be revised as:
2
123 Section 1.2.15 Force, Energy, and Torque should be moved under Section 1.3 2
Wednesday, May 27, 2015
124 Equation 1.200 should be revised as
2
124 Equation 1.201 should be revised as
2
125 Add missing parenthesis at the end of paragraph 2: “(see Fig. 1-92(b)).” 1
138 Equation of no. 3 should be revised as:
0BdA
2
145 Problem 1-7, FIG.P1-7, the figure should be revised as From ∞:to-∞ To ∞:to∞ 2
146 Problem 1-11
(iα should be revised as ia)
2
154 In first line of caption for Fig. 2-2, change “Stalney” to “Stanley” 1
159 1 line after paragraph 1, center equation
1
168
(α should be revised as a)
2
169 FIG.2-13, the line should be removed as below.
2
200
(-41.9 should be 41.9)
2
257 FIG.3-8 (b) should be revised as below
2
Wednesday, May 27, 2015
268 formula 3.37, X2 should be revised as X2 2
276 g, (ηa should be revised as na) 2
317 FIG. 3-43 should be revised as below.
2
327 Problem 3-9, the correct answers should be the answer from 3-11. 2
328 Problem 3-11, the correct answers should be the answer from 3-13. 2
328 Problem 3-13, the correct answers should be the answer from 3-9 2
334 Equation 4..4 should read as:
)cos()cos(2
1coscos BABABA
2
335 FIG. 4-2(a) should be revised as below.
2
335 Equation 4.6, the translator suggested the formula could be revised as below:
f bm m mI I I
2
Wednesday, May 27, 2015
335 Equation 4.7 & 4.8 should be revised as:
2
337 Exercise 4-1, the answers should be revised as below
2
338 Change FIG.4-4(b) to this:
(b) Add part (c)
(c)
F should be revised as
2
360 Equation 5.2, ηs should be revised as ns 2
367 Equation 5.12 should be revised as below
2
382 From Eqs. (5.48) and (5.49), the reactive power versus the motors field current can
be drawn as shown in Fig. 5-17. The leading power factor corresponds to negative
VAR and the lagging power factor to positive VAR. At 100% field excitation, the
power factor is equal to unity and the reactive power is equal to zero.
2
Wednesday, May 27, 2015
382 FIG. 5-17 should be revised as below:
2
401 Example 5-5, solution (a) should be revised as below:
Vb = 3.3 kV, Sb = 1.2 MVA
2
406 Equation 5.72 should be revised as below: Xd = Xq = Xs
2
414 Example 5-7, solution (b) should be revised as below:
2
438 FIG. 6-7 should be redrawed as below
2
Wednesday, May 27, 2015
440 FIG. 6-8 should be redraw as below
2
449 The equation should be revised as below
2
471 FIG. 6-26(b) should be redraw as below
2
475 the equation should be revised as below
2
Wednesday, May 27, 2015
480 Example 6-7, 40 should be revised as 40°
2
485 FIG. 6-34(a) should be redraw as below
2
486 FIG. 6-34(d) &(e) should be redraw as below
2
Wednesday, May 27, 2015
505 Table 7-2 should be revised as below
2
513 FIG. 7-11(b) should be revised as below
2
Wednesday, May 27, 2015
523 FIG. 7-19 should be revised as below
2
525 FIG. 7-20 should be revised as below
2
538 Remove periods after “A” and “B” 1
582
example A-4, the equation should be deleted
2
588 the equation should be revised as below
2
Wednesday, May 27, 2015
596 In Fig. P-B2, add missing e in “X = 0.28 Ω/phase” 1
611 Moment of inertia: 1 kg · m2 = 23.7 lb · ft2 = 0.737 slug· ft2
615-616 Renumber the list; it should start “1 Boylstad, R.” and end on 616 with “14 Baldor Motors” 1
617 1-11 b. Delete “, $ 1113” 1
617 2-7 b. Change “98.7 A” to “95.2 A” 1
618 2-11 b. change “–0. 76 %” to “–0.7%” 1
618 2-16 d. Bold “pu” 1
618 3-6 c. change 1674 r/min to 1665 r/min 1
618 4-1 a. 2006.07 /–94.1 A, 1663.38 /– 23.4 A ; b. 119.2 µF 1 620 Add answer F-2 after B-2: “F-2 a. 3.75 kΩ, 54 µW; b. 44.63 µW” 1