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    By Steve Chyo

    Senior Design EngineerVithi Singh

    Product Manager

    Tyco Electronics Magnetics

    The low cost, simplicity o design

    and intrinsic eciency o yback

    transormers have made them a

    popular solution or power sup-

    ply designs o below 100W to

    150W. Other advantages o the

    yback transormer over circuits

    with similar topology include iso-lation between primary and sec-

    ondary and the ability to provide

    multiple outputs and a choice o

    positive or negative voltage orthe output.

    This article discusses design

    parameters or the yback or

    swinging choke type o trans-

    ormer used in yback convert-

    ers. The latter has been used or

    many years and its topology is

    unique within the transormer-

    isolated amily o regulators.

    Flyback transormer unction

    When the switch is turned on,energy is stored in the primary

    (within the core material). As

    shown in Figure 1, the polarity

    dots on the transormer and the

    diode are arranged such that

    there is no energy transerred to

    the load when the switch is on.

    When the switch is turned o,

    the polarity o the transormerwinding reverses due to the

    collapsing magnetic feld, the

    output rectifer conducts and theenergy stored in the core mate-

    rial is transerred to the load. This

    activity continues until the core is

    depleted o energy or the power

    switch is once again turned on.

    The yback regulator can

    operate in either discontinu-

    ous or continuous mode. In the

    discontinuous mode (see Figure

    2), the energy stored in the core

    when the FET is on/o is com-

    pletely emptied rom the coreduring the yback period. In the

    continuous mode, (see Figure 3)the FET is turned on beore the

    core empties o yback energy.

    A typical yback transormer

    may operate in both modes de-

    pending on the load and input

    voltage.

    Designers should considerthe maximum load at low volt-

    age, including all conditions

    within the operating range o

    the yback, as it will simply shut

    down (discontinuous mode)

    between cycles and wait or the

    load demand to catch up withthe power-delivery capability.

    This is one o the most dynamic

    characteristics o the yback,

    regulated over a wide range o

    input voltage and load.

    Figure 1. Typical yback transormer circuit

    Flyback transformer tutorial:function and design

    Flyback transFormer

    Figure 2. Flyback transormer in discontinuous mode

    EE Times-India | April 2006 | eetindia.com

    http://www.eetindia.co.in/http://www.eetindia.co.in/
  • 7/30/2019 Eeiol 2006apr24 Pow Ta 01

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    Design parameters or a

    fyback transormer

    The ollowing equations are re-

    quently used to speciy a yback

    transormer. They are ollowed by

    a typical design example.

    Let V= L dj/dt, and Vin,min =

    ( L p I p p ) / ( m a x )Where Vin = input voltage, V

    Lp = primary inductance, mH

    Ipp = peak current, A

    max = maximum duty cycle, s = operating switching requen-

    cy, kHz

    For discontinuous mode,

    Power out = *Lp*Ipp*

    Ipp = (2Pout)/(Vin,min* max)

    In the yback transormer,as mentioned above, regula-

    tion is accomplished by PWM.

    I the transormer Vin varies

    rom Vin,min to Vin,max, thenmin = (max) /

    ((1- max)C + max)

    where C = Vin,max / Vin,min

    Since Ipp is known,

    Lp = (Vin,min* max) / (Ipp*)

    Although designers may rely

    on experience or core selec-tion, that can only result in an

    approximation. The ollowing

    ormula is recommended or abetter estimate.

    Ac*Ae = (((6.33*4)*L

    p*Ipp*D)*108) / Bmax.

    Where Ac = winding area, cm

    Ae = core eective area, cm

    Bmax = Bsat/2, Gauss. Consult

    core manuacturers or ma-

    terial and loss vs. requencyD = diameter o wire, inch

    Air gap must be calculatedor the yback transormer, since

    it is operating single-ended and

    uses only hal the ux capac-

    ity. This may create potential or

    driving the core into saturation.

    Gap (cm) = lg =

    ((0.4**Lp*Ipp)*108) /

    (Ae*Bmax)

    Ater the air gap length is

    determined, the primary andsecondary number o turns can

    be ound.

    Npri = (Bmax*lg) / (.4**Ipp)

    Nsec = (Np(Vp + Vd) (1-max)) /

    (Vin,min* max)

    The ollowing example dem-

    onstrates the design o a yback

    transormer in the discontinuous

    mode. Modern designs utilizePFC (power actor correction),

    positioned immediately ater

    rectifcation. Boost topology is

    requently used or its dynamic

    characteristic and wide range

    o input voltage. PFC will not be

    covered in this example.

    Design parameters

    Vinput = 85 to 132 VAC

    Voutput = 5VDC @ 10A = 50Watts

    Frequency = 100kHzAssume max = .45

    Discontinuous Mode

    1) Calculate the peak Ipp

    Since Vin,min = 85VAC,

    then Vin,min = 85*1.4-

    20V or ripple and diode

    drop gives about 100VDC.

    Thus, Ipp = 2Pout / (Vin,min*max) = 100 / (100*.45) =

    2.22 A

    2) Calculate the min Vin,max

    = 132VAC*1.4 = 185VDC

    Allowing a 10% margin,

    Vin,max = 203VDC, say 200VDC

    Allowing a 10% mar-

    gin or Vin,min = 90VDC

    This gives us an input volt-

    age ratio C = 200/90 = 2.22

    Thereore min = .45 /((1-.45)*2.22+ .45) = .27

    As is evident rom these

    results, the transormer willoperate over the duty ratio o

    0.27 to 0.45 or the Vin range

    o 200VDC to 90VDC.

    3) Calculate primary inductance

    Lp = 90*.45 / (2.22*100kHz) =

    .18mH

    4) Select core

    In this example we will use

    a current density o about

    300 cm/A. Since Ipp =

    2.22A, a total centimetres

    will be 300*2.22 = 666 cm.From wire chart, 22 AWG

    has diameter o 0.028 inch.

    We chose Magnetics, Inc

    material type P and rom

    their catalogue selected

    Bmax = 500 Gauss. This will

    give us about 100mW/cm.

    T h e r e o r e ,

    AcAe = (6.33*4)*( .00018Hy)*2 .22*( .028)*

    (108) / (500) = 1.59 cm4.

    From the catalogue PQ43230(PQ3230) size has AcAe =

    1.60 cm4.

    5) Calculate the air gap length

    Lg = (.4**.00018*(2.22)*108)

    / (1.37*(500)) = .30 cm (ap-

    prox) at centre leg o the

    core.

    6) Calculate primary and sec-

    ondary number o turns

    Npri = 500*.30 /(.4*3.14*2.22) = 54 turns

    Nsec = 54*(5 + 1) (1 - .45)

    / (90*.45) = 4.4 turns.

    We will use 5 turns because

    there will be losses rom

    winding, PCB and other para-

    sitic losses which we did not

    include. Next select wire or

    the output. For 10A, a wire o

    10*300 = 3000cm, we choose

    16AWG or the secondary. To

    minimize copper losses due

    to skin eect, we propose

    using multiple strands othinner wires (4 strands o 22

    AWG is equivalent o single

    16 AWG).

    Design engineers must also

    check or bobbin fll actor and

    temperature raise calculations,

    as implementation o saety re-

    quirements will increase the sizeo the yback transormer.

    Custom fyback transormers

    CoEv Magnetics oers a wide

    range o SMPS transormers

    to meet customer needs and

    requirements. Designed to opti-

    mize size, cost and perormance

    or specifc applications, custom

    transormer packages are de-

    veloped using a wide range o

    parameters, including:

    - Turns ratio

    - Current Handling Capability- Drive Levels

    - Inductance

    - Leakage inductance

    - Sel Resonant Frequency

    - DC Resistance

    - Mounting Confguration

    - Isolation Voltage

    Figure 3. Flyback transormer in continuous mode

    eetindia.com | April 2006 | EE Times-India

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