Sampelasbuton = 300 gr = 0,132 lb

Heater 1500 W, 220 volt, 7 A

Vertical tubes

Counter flow

di = 9 mm = 0,0295 ft

do = 10 mm = 0,0328 ft

Asumsi :

1. Kandungan bitumen = 20 % x 300 gr = 60 gr = 0,132 lb

2. Kondensat = gasoline dengantitikembun 140oC

3. Waktumulaimenetessampaiakhirtetesan = 1 menit

NeracaPanas

Gasoline

Q = m Cpoktan ∆T + m 𝜆oktan

Q = 7,92lb x 0,64 Btu/lb.oF x (932 – 284)oF + 7,92 lb x 200 Btu/lb

Q = 3284,582 + 1584

Q = 4868,582 Btu/lb

Air

Q = m Cp∆T

4868,582 Btu/lb = m x 1 Btu/lb.oF x (122 – 86)oF

m = 135,238 lb/jam = 61,343 kg/jam

LMTD

∆ t=∆ t 1−∆t 2

ln(∆ t 1∆ t 2 )∆ t=810−198

ln( 810198 )

=434,422℉

Condensing Film Coeficients, UD

hio = 480 Btu/jam.ft2.oF (grafik 25, Kern)

Correction Factor (di = 0,354 in) = 1,1

hio = 480 x 1,1 = 528