Doe Phsc p1 Memo Prep Exam 2008

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PHYSICAL SCIENCES: PHYSICS (P1)FISIESE WETENSKAPPE (V1)

MEMORANDUM

PREPARATORY EXAMINATION 2008VOORBEREIDIENDE EKSAMEN 2008

NATIONALSENIOR CERTIFICATE

GRADE 12


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Physical Science/Fisiese Wetenskappe/P1 DoE/Preparatory Examination 2008NSC - Memorandum

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2

Learning Outcomes and Assessment StandardsLeeruitkomste en Assesseringstandaarde

LO 1/LU 1 LO 2/LU 2 LO 3/LU 3AS 12.1.1:Design, plan and conduct ascientific inquiry to collect datasystematically with regard toaccuracy, reliability and the needto control variables.

Ontwerp, beplan en voerwetenskaplike ondersoek uit omdata te versamel ten opsigte vanakkuraatheid, betroubaarheid endie kontroleer van veranderlikes.

AS 12.1.2:Seek patterns and trends,represent them in different forms,explain the trends, use scientificreasoning to draw and evaluateconclusions, and formulategeneralisations.

Soek patrone en tendense, steldit in verskillende vorms voor,verduidelik tendense, gebruikwetenskaplike beredenering omgevolgtrekkings te maak en teevalueer, en formuleerveralgemenings.

AS 12.1.3:Select and use appropriateproblem-solving strategies to

solve (unseen) problems.

Kies en gebruik geskikteprobleemoplossingsstrategieom (ongesiene) probleme op telos.

AS 12.2.1:Define, discuss and explainprescribed scientific knowledge.

Definieer, bespreek enverduidelik voorgeskrewewetenskaplike kennis.

AS 12.2.2Express and explain prescribedscientific principles, theories,models and laws by indicatingthe relationship between differentfacts and concepts in own words.

Verduidelik en drukvoorgeskrewe wetenskaplikebeginsels, teorie, modelle enwette uit deur die verwantskaptussen verskillende feitekonsepte in eie woorde aan tedui.

AS 12.2.3:Apply scientific knowledge ineveryday life contexts.

Pas wetenskaplike kennis inkontekste van die alledaagselewe toe.

AS 12.3.2:Research case studies andpresent ethical and moralarguments from differentperspectives to indicate theimpact (pros and cons) ofdifferent scientific andtechnological applications.

Vors gevallestudies na en leweretiese en morele argumente uitverskillende perspektiewe om dieimpak (voordele en nadele) vanverskillende wetenskaplike entegnologiese toepassings aan tedui.

.


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SECTION A /AFDELING A

QUESTION 1/VRAAG 1

1.1 Gravitational force/gravitasiekrag9or/of

weight/gewig [12.2.1] (1)

1.2 Impulse/impuls 9 [12.2.1] (1)

1.3 Doppler Effect/Doppler effek9 [12.2.1] (1)

1.4 Alternating current/wisselstroom9 [12.2.1] (1)

1.5 Laser/Laser9 [12.2.1] (1)[5]

QUESTION 2 / VRAAG 2

2.1 D9 [12.2.1] (1)

2.2 G9 [12.2.1] (1)

2.3 B9 [12.2.1] (1)

2.4 H9 [12.2.1] (1)

2.5 C9 [12.2.1] (1)[5]


3.1 True / Waar99 [12.2.3] (2)

3.2 False / Onwaar:

.velocity relative to the train is 1 ms-13....snelheid relatief tot trein is 1 ms-1. 3 [12.2.3] (2)

3.3 False: 3 Onwaar3

transmit green and red light and absorb blue light3

ORA cyan filter laat groen en rooilig deur and absorbeer bloulig OFn Siaanfilter [12.2.3] (2)

3.4 True / Waar99 [12.2.1] (2)

3.5 True / Waar99 [12.2.1] (2)[10]


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4.1 B 999 [12.2.3] (3)

4.2 D 999 [12.1.3] (3)

4.3 C 999 [12.2.3] (3)

4.4 D 999 [12.2.1 ] (3)

4.5 D 999 [12.1.2] (3)[15]

TOTAL SECTION A = 35TOTAAL AFDELING A = 35

SECTION B /AFDELING B

QUESTION 5/VRAAG 5

5.1 Consider downward motion as positive

ya2vv 2i2

f += 3

(0)23 = (-4)2 + 2(9,8)y 3 [Note: vi & a opposite signs]

y = - 0,82 m= 0,82 m upwards3

yabove ground = 6 + 0,82 = 6,82 m 3

OR

Et(top) = Et(bottom)Ep + Ek = Ep + Ek3

mgh + 2i21 mv = mgh + 2f2

1 mv

(m)(9,8)(6)3 + m(-4)23= m(9,8)h + 0 3h = 6,82 m 3 [12.2.3] (5)

5.2 Consider downward motion as positive:

vf= vi + at 3

0 = (-4) + (9,8) t3 [Note: vi & a opposite signs]

t = 0,41 s 3 [12.2.3] (3)


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5

5.3

Checklist/KontrolelysCriteria for graph/ Kriteria vir grafiek

Marks/Punte

Correct shape of graph 0 0,41 s / Korrekte vorm van grafiek 0 0,41 s 9Correct shape of graph 0,41s 1,6 s / Korrekte vorm van grafiek 0,41s- 1,6 s 9Coordinates 0,41 s ; 0,82 m for highest position indicated / Ko-ordinate 0,41 s;0,82 m vir hoogste punt aangedui

9

Coordinates 0,s ; 0,82 m indicated / Ko-ordinate 0 s; 0,82 m aangedui 9Coordinates 1,6s ; 6 m indicated / Ko-ordinate 0,41 s; 0,82 m aangedui 9

[12.1.2]

(5)[13]

0

-0,82

6

0,41 0,82 1,6time (s)

position(m)

down as positiveposition A as reference

0

-0,82

6

0,41 0,82 1,6time (s)

position(m)

down as positiveposition A as reference

-0,82


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QUESTION 6/VRAAG 6

6.1 1,96 x 104 N 9, upward /opwaarts9 [12.2.3] (2)

6.2 pbefore = pafterm1vi1 + m2vi2 = (m1+m2)vf 9

(0) 9 + (2 000)(3) 9 = (1 500 + 2 000)vf9vf= 1,71m.s

-19 westwards9 [12.2.3] (6)

6.3 Fnet t = p

Fnet =t

)uv(m

/

)v

t

v(m iBfB

9

=5,0

)371,1(0002 99

= - 5 160 N

Magnitude of F = 5 160 N 9 [12.2.3] (4)

6.4 The air bubbles will increase the time of impact 9 and thus reduce the

Force. 9 This may minimize damage to the equipment. 9

Die lugborrels verleng die impaktyd9en verminder dus die krag watdie vertraging veroorsaak.9 Hierdie effek kan verhoed dat dievoorraad beskadig word.9 [12.3.2]

(3)[15]


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QUESTION 7/VRAAG 7

7.1 Emech is not conserved. 9 This is not an isolated system / there isfriction9Emeg bly nie behoue.9 Is nie n geisoleerde sisteem / daar iswrywing.9 [12.2.3] (2)

7.2Ek = K =

2

1mv29

=2

1(55)(10)29

= 2 750 J9 [12.2.3] (3)

7.3 Wnc = Ek + Ep

Fcosx = Ekf Eki + Epf- Epi9

(18)cos180o

(8) 9 = ( mvf2

mvi2

) 9+ (mghf - mghi) 9-1449 = Ekf (55)(10)

29 + (55)(9,8)(1,2) 9 0

Ekf= 1 959,2 J 9

OR

Ep = U = mgh (gained)= (55)(9,8)(1,2) 9= 646,8 J9

Work done against friction / Werk gedoen teen wrywing.

W = Fcos x = (18)(cos180o)(8)

= (18)(-1)(8) 9= -144 J 9 (lost)

(Ep + Ek)bottom = (Ep + Ek)top + W9(0 + 2 750 ) 9= 646,89 + Ek + 144

Ek)top = 1 959,2 J 9

ORWnet =Ek9Fnetcosx = Ek

(mgsin + f ) 99cosx = Ekf- Eki

[(55)(9,8)(82,1 ) 9 + 189](cos180o)(8) 9 = Ekf 27509

Eki = 1959,2 J9[12.1.3] (8)

[13]


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QUESTION 8/VRAAG 8

8.1.1

[12.1.2] (2)

8.1.2

[12.1.2] (2)

8.2s

s

LL f)

vv

vv(f

= 9

= 350)40340

0340(

9

= 396,7 Hz 9 [12.2.3] (1)

8.3 When crossing a street , a blind person can determine whether a car is

moving towards9

or away9

from himWanneer n blinde persoon n straat oorsteek kan bepaal word of diemotor kar na9 of weg9 van die person beweeg [12.3.2] (2)

[11]

direction of movement of ambulancerigting van beweging van ambulans

blind manblinde man

99 shorter wavelength/compressed wave

korter golflengte

blinde man direction of movement of ambulanceRigting van beweging van ambulans

blind man

99longer wavelengthlanger golflengte

9

9


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QUESTION 9/VRAAG 9

9.1 Light consisting of a single frequency.99 (or one wavelength)Lig wat net uitn enkele frekwensie bestaan. 99(of een golflengte) [12.2.1] (2)

9.2 Alternate red9 and dark bands9 are observed.

Afwisselende rooi9 en donker stroke9 is waargeneem [12.2.3] (2)

9.3 Red bands as result of constructive and dark bands as result ofdestructive interference.Rooibande as gevolg van konstruktiewe en donkerbande as gevolgvan destruktiewe interferensie [12.2.3]

(2)

9.4 The coloured bands are narrower99/ A greater number of darkbands, closer together are seen.The wavelength of blue light is shorter than red99, resulting in morepoints of interference.Die gekleurede bande is nouer99/ n Groter aantal donker en rooi

stroke nader aan mekaar.Die golflengte van blou lig is korter as rooi,99 en veroorsaak meerinterferensie.

[12.2.2](4)

9.5 More dark and light bands are seen. 99Meer donker en lig stroke word waargeneem.99 [12.2.2] (2)

[12]

QUESTION 10/VRAAG 10

10.1R|| =

21

21

RR

RR

+

9

=)155(

)15)(5(

+

= 3,75 9

RT = 20 + 3,75 = 23,759

IT =TR

V9

=75,23

609

= 2,53 A9 [12.1.3] (6)

10.2 V20 = IR20= (2,53)(20) 9= 50,6 V 9

V|| = (60 50,6)= 9,4 V 9 [12.2.3] (3)

[9]


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10


11.1C=

d

A09

=

002,0

04,01085,8 12 99

= 1,7710-10 F9 [12.2.3] (4)

11.2C =

V

Q9

1,7710-10 =250

Q9

1,7710-10250 = QQ = 4,425 10-8C9 [12.2.3] (3)

11.3 Increase the potential difference99

Verhoog die potensiaalverskil99

[12.2.2]

(2)

11.4 dielectric / dilektriikum9 [12.2.1] (1)

11.5 It stores charge.9 This large amount of charge can cause shock to thebody.Dit berg lading. 9 Die groot hoeveelheid gebergde lading kan skokveroorsaak9 [12.3.2] (2)

[13]


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12.1 Electric energy 9converted to (rotational) mechanical energy. 9Elektriese energie9 word omgesit in meganiese energie [12.2.1]

(2)

12.2.1 A DC motor reverses current direction with the aid of the commutator

whenever the coil is in the vertical 9position to ensure continuousrotation.An AC motor, with alternating current as input, works withoutcommutators since the current alternates. 9

n Gelykstroom motor verander die stroomrigting sodra die spoel in nvertikale posisie is, om die rotasie te volhou.n Wisselstroommotor , wat deur n wisselstroom gevoer word, werksonder kommutators want die stroom wissel.

[12.2.1]

(2)

12.3 Increase the number of turns on each coil/increased number of coils 9Stronger magnets 9 Bigger current 9

Verhoog die aantal windings op elke spoel/meer spoele 9 / Sterkermagnete9/ groter stroom9

[12.2.2]

(3)

12.4.1 Clockwise 9/Kloksgewys [12.2.3] (1)

12.4.2 Its own momentum9/ split ring commutator changes direction9 ofcurrent, every time the coil reaches the vertical position.Eie momentum9 / Die kommutator verander die stroomrigting9sodra diespoel die vertikale posisie bereik [12.2.3]

(2)[10]


13.1 The voltage can change using transformers9. Electrical energy can betransmitted over long distances at low current9, and experience lowenergy loss.Die elektriese spanning kan verander word deur transformators. 9Elekriese energie kan gelei oor langafstande word een laestroomsterkte9, en beperk dus energie verlies [12.3.2] (2)

13.2

2

VV maxrms

= 9

= 2

3259

= 0,707 (325)= 230 V

P = VrmsIrms9= (230)(13) 9= 2 990 W9 [12.1.3]

(5)[7]


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Physical Science/Fisiese Wetenskappe/P1 12 DoE/Preparatory Examination 2008NSC - Memorandum

Copyright reserved/Kopiereg voorbehou


14.1.1 Photo electric effect9Foto elektriese effek9 [12.2.1] (1)

14.1.2 increases /verhoog 9

The higher intensity more photo-electrons emitted per second9/intensity is proportional to the photo-currentHoe hor intensiteit, hoe meer foto-elektrone per sekonde vrygestel9/intensiteit is eweredig aan foto-elektrone [12.2.2] (2)

14.1.3 Increases / toeneem9Blue light has a higher frequency9 than red light therefore a higherenergy9Blou lig het hor frekwensie 9as rooi lig en dus hor energie9 [12.2.2] (3)

14.2.1 High frequency / High energy 9Ho frekwensie / ho energie9 [12.3.2] (1)

14.2.2 High frequency UV light kills microbes and sterilises food. 9Hoe frekwensie UV lig maak mikro organisme dood9 en steriliseervoedsel.9 [12.3.2] (1)

14.2.3 E = Wo + Ek 9(2,95 x 10-19) 9 = (1 x 10-20) 9 + mv2 (9,11 x 10-31) v29 = (2,95 x 10-20) - (1 x 10-20)

v = 2,069 x 105 ms-1 9[12.2.3] (5)

[13]TOTAL = 150

TOTAAL = 150

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Doe Phsc p1 Memo Prep Exam 2008