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Division of a two digit-number by a one digit number
Make four equal groups from 32:
32 = 30 + 2 Decompose
10 10 10 Can not group it into 4 parts.
32 4
Make four equal groups from 32:
32 4
32 = 30 + 2 Decompose
10 10 10 Can not group it into 4 parts.
5 5 5 5 5 5 Further decompose
Make four equal groups from 32:
32 4
32 = 5 5 5 5 5 5 2
Make four equal groups from 32:
32 4
32 = 5 5 5 5 5 5 2
Make four equal groups from 32:
32 4
32 =
5
5 5 5 5 5 2
Make four equal groups from 32:
32 4
32 =
5 5
5 5 5 5 2
Make four equal groups from 32:
32 4
32 =
5 5 5
5 5 5 2
Make four equal groups from 32:
32 4
32 =
5 5 5 5
5 5 2
Make four equal groups from 32:
32 4
32 =
5 5 5 5
5 5 2
Make four equal groups from 32:
32 4
32 =
5 5 5 5
5 5 2
2 2 1 2 2 1
Decompose
Make four equal groups from 32:
32 4
32 =
5 5 5 5
22 2 1 2 2 1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2
2
2 1 2 2 1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2
2 2
1 2 2 1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2
2 2
1
2
2 1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2
2 2
1
2 2
1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2
2 2
1
2 2
1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2
2 2
1
2 2
1
1 1
Decompose
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2 2
1
2 2
1 1 1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2 2
1
2 2
1 1 1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2 2
1
2 2
1
1 1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2 2
1
2 2
1 1
1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2 2
1
2 2
1 1 1
Make four equal groups from 32:
32 4
32 =
5 5 5 5
2 2
1
2 2
1 1 1
8 8 8 8
Make four equal groups from 32:
32 4
32 :(30 + 2) 4
30 4 = 7, R 2 = 7 + (2 4)
Make four equal groups from 32:
32 4
32 :(30 + 2) 4
30 4 = 7, R 2 = 7 + (2 4)
2 4 = R 2 = (2 4)
Make four equal groups from 32:
32 4
32 :(30 + 2) 4
30 4 = 7 + (2 4)
2 4 = (2 4)
32 4 = 7 + (2 4) + (2 4)
= 7 + [(2+2) 4]
Make four equal groups from 32:
32 4
32 :(30 + 2) 4
32 4 = 7 + [(2+2) 4]
= 7 + [4 4]
= 7 + 1
= 8
Long Division Procedure: 623 7
7 6 2 3 7 6 0 0 7 2 0 7 3+ +=
Divide a number from the left (100’s).
Any remainder will be added to the nextright position (10’s). Divide the number.
Any remainder will be added to thenext right position (1’s). Divide theNumber.
• Computation of the answer is quick.
• Grouping a large number, and adding the remainder to the smaller number is systematic and easy.
• Making estimate starts with working with the digit on the left (biggest place value).
Advantage:
• Takes a long time to reach the answer.
• The method will fail in Algebra to determine series!
• Frustrating to solve complex word problems in a reasonable amount of time.
Disadvantage with the alternative method, such as Everyday Math
