Disproved By:Sierra Baney

2012

Curving A Bullet

• Wanted (6/11) Movie CLIP - Wesley's First Curved Bullet (2008) HD - YouTube

Mr. X

Video Breakdown

• Mr. X runs out a hallway window from a skyscraper and shoots at a man on a building across the street.

• While in the air he shoots 3 shots. • He lands about 12 feet below his original

height.

Involved Physics

• Linear Motion: Velocity• Relative Motion• Conservation of Momentum:– Inelastic Collisions

• Projectile Motion

• Wanted (1/11) Movie CLIP - Cross Kills Mr. X (2008) HD - YouTube

Citadel Building

• 131 Dearborn St, Chicago• Total Height:– 580 ft = 177 m– 37 stories

Carbon and Carbide Building

• 230 Michigan Avenue, Chicago• Total Height:– 503 ft = 153m– 37 stories

Estimations

• Secondary Roof– 400 ft = 121.92m

• Height Mr. X drops– 12 ft = 3.66 m

Calculating Velocity

• OSHA Minimum Requirement (Office)– 61ft = 18.59m

• 3 doorways 18.59 X 3 = 55.78m• OSHA Minimum Requirement (Elevator)

1.74m• 55.78 + 1.74• Total distance 131.89m in 28 sec

Calculating Velocity (Cont)

• Velocity = Distance / Time• 57.53 / 6.3 = 9.13 m/s– 20.42 mph

• Fastest recorded speed was 10.35 m/s – top physical condition

David O’Hara

• Mr. X• Height: 5’11’’ = 1.80m• Estimated Weight: 165lbs = 74.83kg• Stride: .748m per stride

Momentum: Beretta 92S

• 2 shots • Muzzle velocity: 1250 ft/s = 381m/s• Mass: 970g = .97kg• Momentum = Mass X Velocity• M= .97 X 381 = 369.57

Momentum: Flintlock Pistol

• 1 shot• Muzzle Velocity: 1000ft/s = 304.8m/s • Mass: 2.98lbs = 1.35kg• Momentum = Mass X Velocity• M= 1.35 X 304.8 = 411.99

Conservation of Momentum:Inelastic Collisions

• (m1 + m2)V = (m1v1f) + (m2V2f)• (mass man/gun/bullet)man’s velocity mass/velocity of bullet mass/velocity man/gun

Conservation of Momentum: Inelastic Collisions

• Finding the final velocity to use for projectile motion• Information for equation:– Mass of man/gun/bullet: 74.84kg– Mass of Bullets: .2kg each (3 bullets)– Mass of first gun (2 shots): .97kg– Mass of second gun (1 shot): 1.35kg– Velocity of Man running: 9.13m/s– Muzzle Velocity first gun: 381m/s– Muzzle Velocity of second gun: 304.8m/s

Conservation of Momentum: Inelastic Collisions: Equation (m1 + m2)V = (m1v1f) + (m2V2f)

(mass man/gun/bullet)man’s velocity mass/velocity of bullet mass/velocity man/gun

• First Shot• (74.84 + .2 + .2 + .2 + 2.32)9.13 = .2(381) + (74.84 + 2.32)vf• 709.95 = 76.2 + 77.16vf • Vf = 8.21m/s

• Second Shot• (74.84 + .2 + .2 + 2.32)8.21 = .2(381) = (74.84 + 2.32)vf• 636.77 = 76.2 + 77.16vf• 560.57 = 77.16vf• Vf = 7.27 m/s

• Third Shot• (74.84 + .2 + 2.32)7.27 = .2(304.8) + (74.84 + 2.32)vf• 562.41 = 60.96 + 77.16vf• 501.45 = 77.16vf• Vf = 6.50m/s

Projectiles: Time it should take to jump the distance

• d = vxt because horizontal velocity is constant

• City of Chicago street measurements: – D = 100 ft = 30.48m

• 30.48m = 9.13m/s x time• t = 3.34s

Projectiles: How much height he would lose in that time

• H = ½ g t2

• H = ½ 9.81 m/s2 (3.34 sec)2

• H = 55.78m

• 15 times that shown in the video