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Demonstration of 2D Piping using (FDL/Fitting Definition Language) Ductil Iron Various Fittings in 8” Pipe Size
;=======================
Name = DI 90 Elbow
;=======================
;Created by: J.A. Cross 10/2004
;=======================
;Horizontal Pipe Centerline
;=======================
;NewO
Data = ADI_Bends,DI_Flange
Layer = PipeCL
LINE X1 Y2 X2 Y2
X1 = A
Y1 = 0
CP1
X2 = 0
Y2 = 0
;=======================
;Vertical Pipe Centerline
;=======================
LINE X1 Y2 X2 Y2
X1 = LastX
Y1 = 0
X2 = LastX
Y2 = -1 A *
CP2
;=======================
;Right Flange
;=======================
Layer = PipeWall
RECTANGLE X1 Y1 X2 Y2
X1 = A
Y1 = FL_DI 2 / -1 *
X2 = A
Y2 = FL_DI 2 /
X3 = A FL_TH -
Y3 = LastY
X4 = LastX
Y4 = FL_DI 2 / -
;=======================
;Left Flange
;=======================
RECTANGLE X1 Y1 X2 Y2
;first point ('lower left' of
flange)
;
X1 = Fl_Di 2 / -
;first Y
Y1 = A -1 *
;Second Point ('Upper Left')
X2 = LastX FL_DI +
Y2 = LastY
X3 = LastX
Y3 = LastY Fl_Th +
X4 = LastX Fl_Di -
Y4 = LastY
;=======================
;Pipe Edges inner/outer
;=======================
ARC Xc Yc R A1 A2
;center Y for Arc
Xc = A Fl_Th -
Yc = -1 A * Fl_Th +
R = A Fl_Th - Pi_Di 2 / -
A1 = 90
A2 = 180
;=======================
;Pipe Inner Edge
;=======================
ARC Xc Yc R A1 A2
Xc = LastX
Yc = LastY
R = A Fl_Th - Pi_Di 2 / +
A2 = 180
;[EOF] end of fitting ==
Demonstration of 2D Piping using (FDL/Fitting Definition Language) Ductil Iron 90º Elbow Pipe Sizes 8,10,12,14,16,18,20,24,30,36,42 and 48 Inches
Demonstration of 2D Piping using (FDL/Fitting Definition Language) Ductil Iron Various Fittings in 8” Pipe Size
Demonstration of 2D Piping using (FDL/Fitting Definition Language) Ductil Iron 90º Elbow Pipe Sizes 8,10,12,14,16,18,20,24,30,36,42 and 48 Inches