Design of Lead and Lag Compensator

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  • 7/31/2019 Design of Lead and Lag Compensator

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    (GNP/Control Systems-2012)

    Design of Lead and Lag compensator

    Lead Compensator: Phase lead provided by the lead network is used to improve the phasemargin (and hence to improve stability)

    Transfer function of a lead compensator is1

    1)(

    s

    ssG

    C

    with 1 .

    See the example in slide-5 of lecture-17. Design a lead compensator for a unity feedback system

    with)2(

    )(

    ss

    KsG . Design specifications are Kv = 10, Phase margin = 60.

    Kv is higher means system is more accurate. Phase margin is higher means system is more

    stable.

    Letm

    is the phase lead of the compensator,u

    is the phase margin of the uncompensated system

    andd

    is the desired phase margin (the given specification) after compensator.

    Now you can start to do the problem by following the steps given below. Note that lag and lead

    design can be done analytically without drawing Bode plots.

    1. First find the amplifier K to satisfy the accuracy condition.Since Kv = K/2, K=10

    2. With this K, draw Bode plots and find the phase margin of the uncompensated system.(Alternatively you can find the phase margin analytically).

    Phase margin of the uncompensated system( u ) is 25.2

    (See slide-6 of lecture-17).

    3. Find the phase lead (m

    ) of the compensator.

    eudm

    wheree

    is the extra phase to account for the shifting of gain cross over frequency.

    (When we add a lead network, gain cross over frequency shifts to right resulting in lesser

    phase margin). You can guess it as 155e

    In this problem we take 8e

    .m

    =43. (See slide-7 of lecture-17)

    4. Find the parameter using the formulaIn this example 17.0

    5. Find the new gain cross-over frequency where the uncompensated system has a gain ofm

    m

    sin1

    sin1

    )1

    log(20

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    (GNP/Control Systems-2012)

    In this example the uncompensated system has a gain cross over frequency of

    4.25rad/sec. When we are adding a lead compensator the gain cross over will be higherthan 4.25. We place the lead network in such a way that the frequency at which the

    maximum phase lead occurs (m

    )at the new cross over frequency. We know the gain of

    the lead network at this frequency is

    In this example

    Find the frequency at which the uncompensated system has a gain of -7.7dB. In this

    example it is found as 6.8 rad/sec

    6. Equate the frequency found in step 5 tom

    Hence

    The lead compensator transfer function is

    7. Check the phase margin of the compensated system. If the phase margin is less redesignit.

    Lag Compensator: Gain reduction of the lag network is used to improve the phase

    margin (and hence to improve stability)

    Transfer function of a lag compensator is1

    1)(

    s

    ssG

    C

    with 1 .

    See the example in slide-2 of lecture-18. Design a lag compensator for a unity feedback system

    with)4)(1(

    )(

    sss

    KsG . Design specifications are Kv = 5, Phase margin = 43.

    1. First find the amplifier K to satisfy the accuracy condition.Since Kv = K/4, K=20

    2. With this K, draw Bode plots of the uncompensated plant.See slide-3 of lecture-18

    )

    1

    log(20

    dB7.7)1

    log(20

    8.61

    m

    36.0

    106.0136.0

    s

    s

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    (GNP/Control Systems-2012)

    3. Find the new gain cross over frequency (c

    ) where the uncompensated plant has a phase

    margin ofed

    whered

    is the desired phase margin ande

    is the extra phase to

    compensate for the phase lag of the compensator. 155e

    In this problemed

    =43+12=55

    That means the frequency at which the phase of the uncompensated has phase of -125

    is 0.52rad/sec. 52.0

    c

    If you are doing it analytically (without drawing Bode plots) you can skip step-2.Remember there is no need to find the phase margin of the uncompensated system in the

    design of lag networks.

    4. Find the gain of the uncompensated plant at the new cross over frequency and equate it toand find

    In this problem, the gain at 0.52 rad/sec (the new gain cross over frequency) is 20 dB.

    10

    5. Place the upper corner frequency one decade to one octave below the new gain cross overfrequency.

    cc

    5.0

    11.0

    You know the corner frequencies of the lag network are

    1(upper corner frequency) and

    1(lower corner frequency)

    In this problem we select

    Hence the transfer function of the lag compensator is

    6. Check the phase margin of the compensated system. If the phase margin is less redesignit.

    log20

    20log20

    13.01

    177

    17.7

    s

    s