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Deflection of Indeterminate Structure Session 03-04
Matakuliah : S0725 – Analisa StrukturTahun : 2009
Bina Nusantara University 3
Contents
•Elastic Beam Theory•Moment area•Conjugate Beam Method
Bina Nusantara University 4
Introduction
What is deflection?Deflection can occur from various
causes, such as loads, settlement,
temperature or fabrication error of material.
Deflection must be limited in order to prevent cracking and damaging of structure.
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Introduction
What is caused of structure
deflection?
In general It caused by its internal loading such as
Normal force, shear force or bending moment
Bina Nusantara University 6
Introduction
What is caused of Beam &
Frames deflection?
It caused by internal bendingWhat is caused of truss
deflection?
It caused by internal axial forces
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Introduction
Deflection Diagram represent
the Elastic Curve for the points at the centroids of cross-sectional area along the members
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Introduction
Deflection on supports :
(1) Roller = 0
A
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Introduction
Deflection on supports :
(2) Pin = 0
A
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Introduction
Deflection on supports :
(3) Fixed Support = 0 ; = 0
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Introduction
Deflection on supports :(4) Fixed Connected Joint causes the joint to rotate the members by the same amount of
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Introduction
Deflection on supports :(5) Pin Connected Joint the members will have a different slope or rotation at pin, since the pin can’t support moment
1
2
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Introduction
Sign Convention Bending Moment
M+Longitudinal axis
M+
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Introduction
Sign Convention Bending Moment
M-Longitudinal axis
M-
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Introduction
Deflection curve :BA
P2
P1
Moment
-
+
BA Deflection curve
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xP P
y
Elastic curve
The deflection is measured from the original neutral axis to the neutral axis of the deformed beam.
The displacement y is defined as the deflection of the beam.
It may be necessary to determine the deflection y for every value of x along the beam. This relation may be written in the form of an equation which is frequently called the equation of the deflection curve (or elastic curve) of the beam
Importance of Beam Deflections
A designer should be able to determine deflections, i.e.
In building codes ymax <=Lbeam/300
Analyzing statically indeterminate beams involve the use of various deformation relationships.
Bina Nusantara University 17
Elastic Beam Theory
xP P
y
Elastic curve
The deflection is measured from the original neutral axis to the neutral axis of the deformed beam.
The displacement y is defined as the deflection of the beam.
It may be necessary to determine the deflection y for every value of x along the beam. This relation may be written in the form of an equation which is frequently called the equation of the deflection curve (or elastic curve) of the beam
Bina Nusantara University 18
Elastic Beam TheoryImportance of Beam
Deflections
A designer should be able to determine deflections, i.e.
ymax <=Lbeam/300
Analyzing statically indeterminate beams involve the use of various deformation relationships.
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Double-Integration Method
The deflection curve of the bent beam is
Mdx
ydEI
2
2
In order to obtain y, above equation needs to be integrated twice.
y
Radius of curvature
y
x
)(Curvature1
EI
MEIM
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Double-Integration Method
An expression for the curvature at any point along the curve representing the deformed beam is readily available from differential calculus. The exact formula for the curvature is
2
32
2
2
1
dxdy
dxyd
small is dx
dy2
2
dx
yd M
dx
ydEI
2
2
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The Integration Procedure
Integrating once yields to slope dy/dx at any point in the beam.
Integrating twice yields to deflection y for any value of x.
The bending moment M must be expressed as a function of the coordinate x before the integration
Differential equation is 2nd order, the solution must contain two constants of integration. They must be evaluated at known deflection and slope points (i.e. at a simple support deflection is zero, at a built in support both slope and deflection are zero)
Double-Integration Method
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Sign Convention
Positive Bending Negative Bending
Assumptions and Limitations
Deflections caused by shearing action negligibly small compared to bending
Deflections are small compared to the cross-sectional dimensions of the beam
All portions of the beam are acting in the elastic range
Beam is straight prior to the application of loads
Double-Integration Method
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First Moment –Area Theorem
The first moment are theorem states that: The angle between the tangents at A and B is equal to the area of the bending moment diagram between these two points, divided by the product EI.
Moment Area
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B
A
dxEI
MTangent at A
A B
Tangent at B
d
d
xdx
ds
M
Moment Area
dxEI
MxB
A
d
dsdds
EIM
dx with ds replace sdeflection lateral small isit dsEI
Md
dxEI
Mddx
EI
Md
B
A give willgintegratin
B
A
dxEI
Mxdx
EI
Mxxd
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The second moment area theorem states that: The vertical distance of point B on a deflection curve from the tangent drawn to the curve at A is equal to the moment with respect to the vertical through B of the area of the bending diagram between A and B, divided by the product EI.
dxEI
MxB
A
d
dsdds
EIM dx with ds replace sdeflection lateral small isit ds
EI
Md
dxEI
Mddx
EI
Md
B
A give willgintegratin
B
A
dxEI
Mxdx
EI
Mxxd
Moment AreaSecond Moment –Area Theorem
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Procedure1. The reactions of the beam are determined
2. An approximate deflection curve is drawn. This curve must be consistent with the known conditions at the supports, such as zero slope or zero deflection
3. The bending moment diagram is drawn for the beam. Construct M/EI diagram
4. Convenient points A and B are selected and a tangent is drawn to the assumed deflection curve at one of these points, say A
5. The deflection of point B from the tangent at A is then calculated by the second moment area theorem
Moment Area
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P
PL L
P
A
B
Tangent at A
Tangent at B
Moment Area
Problem
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P
PL L
P
A
B
Tangent at A
Tangent at B
PL
M
33
2
2
3PLLPL
LEI
EI
PL
3
3
PLL
EI 2 EI
PL
2
2
Moment Area
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WL2
2WL
Tangent A
L
A W N per unit length
B
= ?
2
2WL
xL
WLA
23
1 2
Lx4
3
84
3
23
42 WL
LLWL
EI
EI
WL
8
4
Moment Area
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Example
L
aP
aP
P P
aaL
2
Pa
Tangent A
A = ?
Moment Area
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aPaa
aaL
aL
PaEI3
2
2242
3
22
32448a
PaLaLaLPa
3
3332 43
2468 L
a
L
aPLPaPaL
3
33 43
24 L
a
L
a
EI
PL
Moment Area
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Conjugate Beam
The method requires the same amount of computation as the moment-area theorems to determine a beam’s slope or deflection. However, the method relies only on the principles of
statics, its application will be more familiar
Dr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes
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Using the similarity of equations for
Beam Statics Beam deflection
Or integrating
wdxV
dxEI
M)(
dxdx
EI
Mv )(
dxwdxM
Unit = kN·m2/EI Unit = kN·m3/EIDr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes
Bina Nusantara University 34
Theorem 1: The slope at a point in the real beam is numerically equal to the shear at the corresponding point in the conjugate beam.
Theorem 2: The displacement of a point in the real beam is numerically equal to the moment at the corresponding point in the conjugate beam.
Conjugate Beam
Dr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes
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Conjugate Beam•Draw the conjugate beam for the real beam with a proper boundary conditions
•Load the conjugate beam with the real beam’s M/EI diagram. This loading is directed downward when
M/EI is positive and upward when M/EI is negative•Determine the statics of the conjugate beam: reactions, Shear force and moments•Shear force V corresponds to the slope of the real beam, moment M corresponds to the displacement v of the real beam.
Dr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes
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Conjugate BeamREAL BEAM CONJUGATE BEAM
Dr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes
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Conjugate BeamREAL BEAM CONJUGATE BEAM
Dr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes
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Conjugate BeamREAL BEAM CONJUGATE BEAM
Dr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes
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Conjugate BeamREAL BEAM CONJUGATE BEAM
++++ ++++
++++
++++
Dr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes
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Determine the maximum deflection of the steel beam shown in the figure. E = 200 GPa, I = 60(106) mm4.
A
9 m
8 kN
B
x
3 m
2 kN 6 kN
Conjugate Beam
Dr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes
Bina Nusantara University 41
8 kN
A B
x
18kNm
A’ B’
x
18/EI
Conjugate Beam
Real Beam
45/EI 63/EI
Maximum deflection occurs at the point
where the slope is zero
This corresponds to the same point in the
conjugate beam where the shear is zero
2 kN
6 kN
9 m 3 m
81/EI 27/EI
Conjugate Beam
Dr Yan Zhuge lecturer notesDr Yan Zhuge lecturer notes