1. (1 points) Disassemble the following 25 memory words: (Hint: There are 13 instructions. Make up your own labels. Use hexadecimal notation for constants and absolute locations.)

0x809c: 83920x809e: 02000x80a0: 20050x80a2: 40B20x80a4: 03E80x80a6: 02000x80a8: E3E20x80aa: 00210x80ac: 93820x80ae: 02020x80b0: 240D0x80b2: D3D20x80b4: 00210x80b6: E0F20x80b8: 00100x80ba: 001D0x80bc: 83920x80be: 02020x80c0: 20050x80c2: C3D20x80c4: 00210x80c6: C0B10x80c8: 00100x80ca: 00000x80cc: 1300

2. (1 points) If the value in R4 is 0x0008, what will the value be in R5 after executing the following 5 lines of binary code? What does the binary program do?

0100 0100 0000 01010101 0101 0000 01010101 0101 0000 01010101 0100 0000 01010101 0101 0000 0101

3.(3 points) A digital output port (8 bits) of an MSP430 processor is assigned to memory location 0x0021. This output port controls 8 LEDs that are connected to Pins 0-7. Three MSP430 assembly instructions can be used to turn ON and OFF and TOGGLE these LEDs. For example, to control the LED connected to Pin 0, we can use

bic.b #0x01, &0x0021 ; turn off the LEDbis.b #0x01, &0x0021 ; turn on the LEDxor.b #0x01, &0x0021 ; toggle the LED

a. What assembly instruction turns on LEDs connected to Pins 3 and 4 at the same time?

b. What assembly instruction turns off all 8 LEDs at the same time?

c. What assembly instruction toggles LEDs connected to Pins 1 and 7?

4. (6 points) For the following assembly code, give contents of R4 after each line is executed.

1.0x8000: MOV.W #FOOEY,R42.0x8004: MOV.W &FOOEY,R43.0x8008: MOV.W FOOEY,R44.0x800c: MOV.W @R4,R45.0x800e: MOV.W @R4,R46.0x8010: MOV.W @R4+,R4

... 0x9000: FOOEY: .word 0xA000

... 0xA000: FOOBAR: .word 0x9000

Answer 1: Answer 2: Answer 3: Answer 4: Answer 5: Answer 6:

5.(6 points) Assemble the following MSP430 assembly instructions. The label TOM is located at address 0x8014. After assembly is completed, what is in memory locations 0x8014, 0x8016, and 0x8018? (Give your answer in hexadecimal with “0x”.)

0x8014: TOM mov.w TOM,BOB BOB

6.(8 points) Identify four problems in the following assembly program. How would you fix the problems? (Identify the problems and change or add instructions to fix them.)

call sqrtFuncmov r0,result ;save…

result: .word 0

sqrtFun:push r4push r5… ; calculate square rootmov r6,r0 ; return results in R0

pop r4pop r5ret

1. (9 points) Compile the following C statements into MSP430 assembly code. (Variables are to be defined on the stack (SP) and referenced from the top of the stack.)

Assuming the stack pointer has 0x027E before the instruction SUB.W #0x0006,SP

What are the stack assignments (shown below) and values for variables x, y, and z just before the final brace?

x = ?y = ?z = ?

{int x;int* y;int** z;

y = &x;z = &y;**z = 10;

}

Answers:

2. (2 points) Given the C program on the right, what is the missing MSP430 assembly instruction generated by the compiler for the line:

getdata.next = &getdata;

Hint: Think about activation records and where each variable is stored in memory.

Answer:

Address Data0x02800x027E Return address SP0x027C 0x027A0x027A 0x02780x0278 0x000A0x0276

SUB.W #0x0006,SP ; { ; int x; ; int* y; ; int** z;

MOV.W SP,0x0002(SP) ; y = &x;MOV.W SP,R15 ; z = &y;INCD.W R15MOV.W R15,0x0004(SP)

MOV.W @R15,R15 ; **z = 10;MOV.W #0x000a,0x0000(R15)

ADD.W #0x0006,SP ; }RET

Main :0x8020: 8221 SUB.W #4,SP0x8020: 4381 0000 CLR.W 0x0000(SP)0x8024: missing instruction0x8028: 5221 ADD.W #4,SP0x802A: 4130 RET

struct node{ int count; struct node *next;};

int main(void){ struct node getdata; getdata.count = 0; getdata.next = &getdata; return 0;}