1) Date su koordinate tacke A(1000;1000)m ,duzina duzi AB=135.7832 i ugao izmedju tih tacaka <(A,B)=96.85.Izracunati koordinate tacke B? A(1000;1000),Ya=1000,Xa=1000 AB=135.7832 m <(A,B)=96.85 gr Yb =Ya +AB *sin<(A,B) Xb=Xa+AB*cos<(A,B) Pretvaranje gradijana u stepene: て:96.85gr=90`:100gr て*100gr=96.85gr*90` て*100gr =8716.5`gr て=8716.5`gr/100gr て=87.165` Yb=Ya+AB*sin て=1000+135.7832*sin87.165=1000+135.7832*0.998= =1000+135.5116=1135.5116 Xb=Xa+AB*cos て=1000+135.7832*cos87.165=1000+135.7832*0.0494= =1000+6.707=1006.707 Yb=1135.5116 , Xb=1006.707 => B(1135.5116;1006.707) 1
