Database Tuning Slides

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Database TuningPrinciples, Experiments and

Troubleshooting Techniques http://www.mkp.com/dbtune

Dennis Shasha ([email protected])

Philippe Bonnet ([email protected])

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Availability of Materials

1. Power Point presentation is available on my web site (and Philippe Bonnet’s). Just type our names into google

2. Experiments available from Denmark site maintained by Philippe (site in a few slides)

3. Book with same title available from Morgan Kaufmann.

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Database Tuning

Database Tuning is the activity of making a database application run more quickly. “More quickly” usually means higher throughput, though it may mean lower

response time for time-critical applications.

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ApplicationProgrammer

(e.g., business analyst,Data architect)

SophisticatedApplicationProgrammer

(e.g., SAP admin)

DBA,Tuner

Hardware[Processor(s), Disk(s), Memory]

Operating System

Concurrency Control Recovery

Storage SubsystemIndexes

Query Processor

Application

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Outline of Tutorial

1. Basic Principles2. Tuning the guts3. Indexes4. Relational Systems5. Application Interface6. Ecommerce Applications7. Data warehouse Applications8. Distributed Applications9. Troubleshooting

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Goal of the Tutorial

• To show:– Tuning principles that port from one system to

the other and to new technologies– Experimental results to show the effect of these

tuning principles.– Troubleshooting techniques for chasing down

performance problems.

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Tuning Principles Leitmotifs

• Think globally, fix locally (does it matter?)

• Partitioning breaks bottlenecks (temporal and spatial)

• Start-up costs are high; running costs are low (disk transfer, cursors)

• Be prepared for trade-offs (indexes and inserts)

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Experiments -- why and where

• Simple experiments to illustrate the performance impact of tuning principles.

• http://www.diku.dk/dbtune/experiments to get the SQL scripts, the data and a tool to run the experiments.

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Experimental DBMS and Hardware

• Results presented throughout this tutorial obtained with:

– SQL Server 7, SQL Server 2000, Oracle 8i, Oracle 9i, DB2 UDB 7.1

– Three configurations:1. Dual Xeon (550MHz,512Kb), 1Gb RAM, Internal RAID controller

from Adaptec (80Mb) 2 Ultra 160 channels, 4x18Gb drives (10000RPM), Windows 2000.

2. Dual Pentium II (450MHz, 512Kb), 512 Mb RAM, 3x18Gb drives (10000RPM), Windows 2000.

3. Pentium III (1 GHz, 256 Kb), 1Gb RAM, Adapter 39160 with 2 channels, 3x18Gb drives (10000RPM), Linux Debian 2.4.

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Tuning the Guts

• Concurrency Control– How to minimize lock contention?

• Recovery– How to manage the writes to the log (to dumps)?

• OS– How to optimize buffer size, process scheduling, …

• Hardware– How to allocate CPU, RAM and disk subsystem

resources?

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Isolation

• Correctness vs. Performance– Number of locks held by each transaction– Kind of locks– Length of time a transaction holds locks

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Isolation Levels• Read Uncommitted (No lost update)

– Exclusive locks for write operations are held for the duration of the transactions

– No locks for read

• Read Committed (No dirty retrieval)– Shared locks are released as soon as the read operation terminates.

• Repeatable Read (no unrepeatable reads for read/write )– Two phase locking

• Serializable (read/write/insert/delete model)– Table locking or index locking to avoid phantoms

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Snapshot isolation

T1

T2

T3

TIME

R(Y) re

turns 1

R(Z) returns 0

R(X) re

turns 0

W(Y:=1)

W(X:=2, Z

:=3)

X=Y=Z=0

• Each transaction executes against the version of the data items that was committed when the transaction started:– No locks for read– Costs space (old copy of data must

be kept)

• Almost serializable level:– T1: x:=y– T2: y:= x– Initially x=3 and y =17– Serial execution:

x,y=17 or x,y=3– Snapshot isolation:

x=17, y=3 if both transactions start at the same time.

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Value of Serializability -- Data

Settings:accounts( number, branchnum, balance);

create clustered index c on accounts(number);

– 100000 rows

– Cold buffer; same buffer size on all systems.

– Row level locking

– Isolation level (SERIALIZABLE or READ COMMITTED)

– SQL Server 7, DB2 v7.1 and Oracle 8i on Windows 2000

– Dual Xeon (550MHz,512Kb), 1Gb RAM, Internal RAID controller from Adaptec (80Mb), 4x18Gb drives (10000RPM), Windows 2000.

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Value of Serializability -- transactions

Concurrent Transactions:– T1: summation query [1 thread]

select sum(balance) from accounts;

– T2: swap balance between two account numbers (in order of scan to avoid deadlocks) [N threads]

T1: valX:=select balance from accounts where number=X;

valY:=select balance from accounts where number=Y;

T2: update accounts set balance=valX where number=Y;

update accounts set balance=valY where number=X;

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Value of Serializability -- results

• With SQL Server and DB2 the scan returns incorrect answers if the read committed isolation level is used (default setting)

• With Oracle correct answers are returned (snapshot isolation).

Oracle

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Cost of Serializability

Because the update conflicts with the scan, correct answers are obtained at the cost of decreased concurrency and thus decreased throughput.

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Locking Overhead -- data

Settings:accounts( number, branchnum, balance);

create clustered index c on accounts(number);

– 100000 rows– Cold buffer– SQL Server 7, DB2 v7.1 and Oracle 8i on Windows 2000– No lock escalation on Oracle; Parameter set so that there is no

lock escalation on DB2; no control on SQL Server.


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Locking Overhead -- transactions

No Concurrent Transactions:– Update [10 000 updates]update accounts set balance = Val;

– Insert [10 000 transactions], e.g. typical one:insert into accounts values(664366,72255,2296.12);

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Locking Overhead

Row locking is barely more expensive than table locking because recovery overhead is higher than row locking overhead– Exception is updates on

DB2 where table locking is distinctly less expensive than row locking.

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Logical Bottleneck: Sequential Key generation

• Consider an application in which one needs a sequential number to act as a key in a table, e.g. invoice numbers for bills.

• Ad hoc approach: a separate table holding the last invoice number. Fetch and update that number on each insert transaction.

• Counter approach: use facility such as Sequence (Oracle)/Identity(MSSQL).

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Counter Facility -- data

Settings:

– default isolation level: READ COMMITTED; Empty tables


accounts( number, branchnum, balance);create clustered index c on accounts(number);

counter ( nextkey );insert into counter values (1);

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Counter Facility -- transactions

No Concurrent Transactions:– System [100 000 inserts, N threads]

• SQL Server 7 (uses Identity column)insert into accounts values (94496,2789);

• Oracle 8iinsert into accounts values (seq.nextval,94496,2789);

– Ad-hoc [100 000 inserts, N threads]begin transaction NextKey:=select nextkey from counter; update counter set nextkey = NextKey+1; insert into accounts values(NextKey,?,?);commit transaction

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Avoid Bottlenecks: Counters

• System generated counter (system) much better than a counter managed as an attribute value within a table (ad hoc). Counter is separate transaction.

• The Oracle counter can become a bottleneck if every update is logged to disk, but caching many counter numbers is possible.

• Counters may miss ids.

SQLServer

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Insertion Points -- transactions

No Concurrent Transactions:– Sequential [100 000 inserts, N threads]

Insertions into account table with clustered index on ssnumData is sorted on ssnumSingle insertion point

– Non Sequential [100 000 inserts, N threads]Insertions into account table with clustered index on ssnum

Data is not sorted (uniform distribution)100 000 insertion points

– Hashing Key [100 000 inserts, N threads]Insertions into account table with extra attribute att with clustered index on

(ssnum, att)Extra attribute att contains hash key (1021 possible values)1021 insertion points

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Insertion Points

• Page locking: single insertion point is a source of contention (sequential key with clustered index, or heap)

• Row locking: No contention between successive insertions.

• DB2 v7.1 and Oracle 8i do not support page locking.

Row Locking

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Atomicity and Durability

• Every transaction either commits or aborts. It cannot change its mind

• Even in the face of failures:– Effects of committed

transactions should be permanent;

– Effects of aborted transactions should leave no trace.

ACTIVE(running, waiting)

ABORTED

COMMITTEDCOMMIT

ROLLBACK

ØBEGINTRANS

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LOG DATADATADATA

STABLE STORAGE

UNSTABLE STORAGE

WRITE log records before commit

WRITE modified pages after commit

RECOVERY

Pi Pj

DATABASE BUFFERLOG BUFFER

lri lrj

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Log IO -- data

Settings:lineitem ( L_ORDERKEY, L_PARTKEY , L_SUPPKEY,

L_LINENUMBER , L_QUANTITY, L_EXTENDEDPRICE , L_DISCOUNT, L_TAX , L_RETURNFLAG, L_LINESTATUS , L_SHIPDATE, L_COMMITDATE, L_RECEIPTDATE, L_SHIPINSTRUCT , L_SHIPMODE , L_COMMENT );

– READ COMMITTED isolation level

– Empty table


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Log IO -- transactions

No Concurrent Transactions:

Insertions [300 000 inserts, 10 threads], e.g., insert into lineitem values (1,7760,401,1,17,28351.92,0.04,0.02,'N','O','1996-03-13','1996-02-12','1996-03-22','DELIVER IN PERSON','TRUCK','blithely regular ideas caj');

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Group Commits

• DB2 UDB v7.1 on Windows 2000

• Log records of many transactions are written together– Increases throughput by

reducing the number of writes

– at cost of increased minimum response time.

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Put the Log on a Separate Disk


• 5 % performance improvement if log is located on a different disk

• Controller cache hides negative impact– mid-range server, with

Adaptec RAID controller (80Mb RAM) and 2x18Gb disk drives.

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Tuning Database Writes

• Dirty data is written to disk– When the number of dirty pages is greater than

a given parameter (Oracle 8)– When the number of dirty pages crosses a given

threshold (less than 3% of free pages in the database buffer for SQL Server 7)

– When the log is full, a checkpoint is forced. This can have a significant impact on performance.

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Tune Checkpoint Intervals

• Oracle 8i on Windows 2000

• A checkpoint (partial flush of dirty pages to disk) occurs at regular intervals or when the log is full:– Impacts the performance of

on-line processing

+ Reduces the size of log

+ Reduces time to recover from a crash

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Database Buffer Size

• Buffer too small, then hit ratio too small

hit ratio = (logical acc. - physical acc.) / (logical acc.)

• Buffer too large, paging• Recommended strategy:

monitor hit ratio and increase buffer size until hit ratio flattens out. If there is still paging, then buy memory. LOG DATADATA

RAM

Paging Disk

DATABASE PROCESSES

DATABASEBUFFER

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Buffer Size -- data

Settings:employees(ssnum, name, lat, long, hundreds1,

hundreds2);

clustered index c on employees(lat); (unused)– 10 distinct values of lat and long, 100 distinct values of hundreds1

and hundreds2

– 20000000 rows (630 Mb);

– Warm Buffer

– Dual Xeon (550MHz,512Kb), 1Gb RAM, Internal RAID controller from Adaptec (80Mb), 4x18Gb drives (10000 RPM), Windows 2000.

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Buffer Size -- queries

Queries:– Scan Queryselect sum(long) from employees;

– Multipoint queryselect * from employees where lat = ?;

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Database Buffer Size

• SQL Server 7 on Windows 2000

• Scan query:– LRU (least recently used) does

badly when table spills to disk as Stonebraker observed 20 years ago.

• Multipoint query:– Throughput increases with

buffer size until all data is accessed from RAM.

Multipoint Query

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Scan Performance -- data


L_LINENUMBER , L_QUANTITY, L_EXTENDEDPRICE , L_DISCOUNT, L_TAX , L_RETURNFLAG, L_LINESTATUS , L_SHIPDATE, L_COMMITDATE, L_RECEIPTDATE, L_SHIPINSTRUCT , L_SHIPMODE , L_COMMENT );

– 600 000 rows – Lineitem tuples are ~ 160 bytes long– Cold Buffer– Dual Xeon (550MHz,512Kb), 1Gb RAM, Internal RAID controller

from Adaptec (80Mb), 4x18Gb drives (10000RPM), Windows 2000.

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Scan Performance -- queries

Queries:select avg(l_discount) from lineitem;

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Prefetching


• Throughput increases up to a certain point when prefetching size increases.

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Usage Factor


• Usage factor is the percentage of the page used by tuples and auxilliary data structures (the rest is reserved for future)

• Scan throughput increases with usage factor.

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Tuning the Storage Subsystem

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Outline

• Storage Subsystem Components– Moore’s law and consequences– Magnetic disk performances

• From SCSI to SAN, NAS and Beyond– Storage virtualization

• Tuning the Storage Subsystem– RAID levels– RAID controller cache

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Exponential Growth

Moore’s law– Every 18 months:

• New processing = sum of all existing processing• New storage = sum of all existing storage

– 2x / 18 months ~ 100x / 10 years

http://www.intel.com/research/silicon/moorespaper.pdf

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Consequences of “Moore’s law”

• Over the last decade:– 10x better access time

– 10x more bandwidth

– 100x more capacity

– 4000x lower media price– Scan takes 10x longer (3 min vs 45 min)

– Data on disk is accessed 25x less often (on average)

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Data Flood

• Disk Sales double every nine months– Because volume of

stored data increases• Data Warehouses• Internet Logs• Web Archives• Sky Survey

– Because media price drops much faster than areal density.

Graph courtesy of Joe HellersteinSource: J. Porter, Disk/Trend, Inc.http://www.disktrend.com/pdf/portrpkg.pdf

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Memory Hierarchy

Processor cache

RAM

Disks

Tapes / Optical Disks

Access TimePrice $/ Mb

1 ns

x10

x106

x1010

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0.2 (nearline)

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Magnetic Disks1956: IBM (RAMAC) first disk

drive5 Mb – 0.002 Mb/in235000$/year9 Kb/sec

1980: SEAGATEfirst 5.25’’ disk drive5 Mb – 1.96 Mb/in2625 Kb/sec

1999: IBM MICRODRIVEfirst 1’’ disk drive340Mb 6.1 MB/secController

read/write head

disk arm

tracks

platter

spindle

actuator

disk interface

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Magnetic Disks

• Access Time (2001)– Controller overhead (0.2 ms)– Seek Time (4 to 9 ms)– Rotational Delay (2 to 6 ms)– Read/Write Time (10 to 500

KB/ms)

• Disk Interface– IDE (16 bits, Ultra DMA - 25

MHz)– SCSI: width (narrow 8 bits vs.

wide 16 bits) - frequency (Ultra3 - 80 MHz).

http://www.pcguide.com/ref/hdd/

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RAID Levels

• RAID 0: striping (no redundancy)• RAID 1: mirroring (2 disks)• RAID 5: parity checking

– Read: stripes read from multiple disks (in parallel)– Write: 2 reads + 2 writes

• RAID 10: striping and mirroring• Software vs. Hardware RAID:

– Software RAID: run on the server’s CPU– Hardware RAID: run on the RAID controller’s CPU

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Why 4 read/writes when updating a single stripe using RAID 5?

• Read old data stripe; read parity stripe (2 reads)

• XOR old data stripe with replacing one.

• Take result of XOR and XOR with parity stripe.

• Write new data stripe and new parity stripe (2 writes).

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RAID Levels -- data

Settings:accounts( number, branchnum, balance);create clustered index c on accounts(number);

– 100000 rows

– Cold Buffer


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RAID Levels -- transactions

No Concurrent Transactions:– Read Intensive: select avg(balance) from accounts;

– Write Intensive, e.g. typical insert:insert into accounts values (690466,6840,2272.76);

Writes are uniformly distributed.

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RAID Levels• SQL Server7 on Windows

2000 (SoftRAID means striping/parity at host)

• Read-Intensive:– Using multiple disks

(RAID0, RAID 10, RAID5) increases throughput significantly.

• Write-Intensive:– Without cache, RAID 5

suffers. With cache, it is ok.

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RAID Levels

• Log File– RAID 1 is appropriate

• Fault tolerance with high write throughput. Writes are synchronous and sequential. No benefits in striping.

• Temporary Files– RAID 0 is appropriate.

• No fault tolerance. High throughput.

• Data and Index Files– RAID 5 is best suited for read intensive apps or if the

RAID controller cache is effective enough.– RAID 10 is best suited for write intensive apps.

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Controller Prefetching no, Write-back yes.

• Read-ahead:– Prefetching at the disk controller level. – No information on access pattern.– Better to let database management system do it.

• Write-back vs. write through:– Write back: transfer terminated as soon as data is

written to cache. • Batteries to guarantee write back in case of power failure

– Write through: transfer terminated as soon as data is written to disk.

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SCSI Controller Cache -- data

Settings:employees(ssnum, name, lat, long, hundreds1,hundreds2);

create clustered index c on employees(hundreds2);

– Employees table partitioned over two disks; Log on a separate disk; same controller (same channel).

– 200 000 rows per table– Database buffer size limited to 400 Mb.– Dual Xeon (550MHz,512Kb), 1Gb RAM, Internal RAID

controller from Adaptec (80Mb), 4x18Gb drives (10000RPM), Windows 2000.

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SCSI (not disk) Controller Cache -- transactions

No Concurrent Transactions:update employees set lat = long, long = lat where hundreds2 = ?;

– cache friendly: update of 20,000 rows (~90Mb)

– cache unfriendly: update of 200,000 rows (~900Mb)

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SCSI Controller Cache

• SQL Server 7 on Windows 2000.

• Adaptec ServerRaid controller:– 80 Mb RAM– Write-back mode

• Updates• Controller cache increases

throughput whether operation is cache friendly or not.– Efficient replacement policy!

2 Disks - Cache Size 80Mb

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Index Tuning

• Index issues– Indexes may be better or worse than scans – Multi-table joins that run on for hours, because

the wrong indexes are defined– Concurrency control bottlenecks– Indexes that are maintained and never used

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Index

An index is a data structure that supports efficient access to data

Set ofRecords

indexCondition

onattribute

value

Matchingrecords

(search key)

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Index

An index is a data structure that supports efficient access to data

Set ofRecords

indexCondition

onattribute

value

Matchingrecords

(search key)

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Search Keys

• A (search) key is a sequence of attributes.create index i1 on accounts(branchnum, balance);

• Types of keys – Sequential: the value of the key is monotonic

with the insertion order (e.g., counter or timestamp)

– Non sequential: the value of the key is unrelated to the insertion order (e.g., social security number)

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Data Structures

• Most index data structures can be viewed as trees. • In general, the root of this tree will always be in

main memory, while the leaves will be located on disk.– The performance of a data structure depends on the

number of nodes in the average path from the root to the leaf.

– Data structure with high fan-out (maximum number of children of an internal node) are thus preferred.

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B+-Tree

• A B+-Tree is a balanced tree whose leaves contain a sequence of key-pointer pairs.

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75 83 107

96 98 103 107 110 12083 92 9575 80 8133 48 69

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B+-Tree Performance

• Tree levels– Tree Fanout

• Size of key• Page utilization

• Tree maintenance– Online

• On inserts• On deletes

– Offline

• Tree locking• Tree root in main memory

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B+-Tree Performance

• Key length influences fanout– Choose small key when creating an index

– Key compression• Prefix compression (Oracle 8, MySQL): only store that part of

the key that is needed to distinguish it from its neighbors: Smi, Smo, Smy for Smith, Smoot, Smythe.

• Front compression (Oracle 5): adjacent keys have their front portion factored out: Smi, (2)o, (2)y. There are problems with this approach:

– Processor overhead for maintenance

– Locking Smoot requires locking Smith too.

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Hash Index

• A hash index stores key-value pairs based on a pseudo-randomizing function called a hash function.

Hashed key values

01

n

R1 R5

R3 R6 R9 R14 R17 R21 R25Hash

function

key

2341

The length ofthese chains impacts performance

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Clustered / Non clustered index

• Clustered index (primary index)– A clustered index on

attribute X co-locates records whose X values are near to one another.

• Non-clustered index (secondary index)– A non clustered index does

not constrain table organization.

– There might be several non-clustered indexes per table.

Records Records

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Dense / Sparse Index

• Sparse index– Pointers are associated to

pages

• Dense index– Pointers are associated to

records

– Non clustered indexes are dense

P1 PiP2 record

recordrecord

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Index Implementations in some major DBMS

• SQL Server– B+-Tree data structure– Clustered indexes are

sparse– Indexes maintained as

updates/insertions/deletes are performed

• DB2– B+-Tree data structure,

spatial extender for R-tree– Clustered indexes are dense– Explicit command for index

reorganization

• Oracle– B+-tree, hash, bitmap,

spatial extender for R-Tree

– clustered index• Index organized table

(unique/clustered)

• Clusters used when creating tables.

• TimesTen (Main-memory DBMS)– T-tree

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Types of Queries

• Point Query

SELECT balanceFROM accountsWHERE number = 1023;

• Multipoint Query

SELECT balanceFROM accountsWHERE branchnum = 100;

• Range Query

SELECT numberFROM accountsWHERE balance > 10000 and balance <= 20000;

• Prefix Match Query

SELECT *FROM employeesWHERE name = ‘J*’ ;

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More Types of Queries

• Extremal Query

SELECT *FROM accountsWHERE balance = max(select balance from accounts)

• Ordering Query

SELECT *FROM accountsORDER BY balance;

• Grouping Query

SELECT branchnum, avg(balance)FROM accountsGROUP BY branchnum;

• Join Query

SELECT distinct branch.adresseFROM accounts, branchWHERE accounts.branchnum =

branch.numberand accounts.balance > 10000;

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Index Tuning -- data


hundreds2);

clustered index c on employees(hundreds1) with fillfactor = 100;

nonclustered index nc on employees (hundreds2);

index nc3 on employees (ssnum, name, hundreds2);

index nc4 on employees (lat, ssnum, name);– 1000000 rows ; Cold buffer


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Index Tuning -- operations

Operations:– Update:

update employees set name = ‘XXX’ where ssnum = ?;– Insert:

insert into employees values (1003505,'polo94064',97.48,84.03,4700.55,3987.2);

– Multipoint query: select * from employees where hundreds1= ?; select * from employees where hundreds2= ?;

– Covered query: select ssnum, name, lat from employees;

– Range Query: select * from employees where long between ? and ?;

– Point Query: select * from employees where ssnum = ?

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Clustered Index

• Multipoint query that returns 100 records out of 1000000.

• Cold buffer• Clustered index is

twice as fast as non-clustered index and orders of magnitude faster than a scan.

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Index “Face Lifts”

• Index is created with fillfactor = 100.

• Insertions cause page splits and extra I/O for each query

• Maintenance consists in dropping and recreating the index

• With maintenance performance is constant while performance degrades significantly if no maintenance is performed.

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Maintenance

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Index Maintenance

• In Oracle, clustered index are approximated by an index defined on a clustered table

• No automatic physical reorganization

• Index defined with pctfree = 0

• Overflow pages cause performance degradation

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Covering Index - defined

• Select name from employee where department = “marketing”

• Good covering index would be on (department, name)

• Index on (name, department) less useful.

• Index on department alone moderately useful.

81

Covering Index - impact

• Covering index performs better than clustering index when first attributes of index are in the where clause and last attributes in the select.

• When attributes are not in order then performance is much worse.

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Scan Can Sometimes Win

• IBM DB2 v7.1 on Windows 2000

• Range Query• If a query retrieves 10% of

the records or more, scanning is often better than using a non-clustering non-covering index. Crossover > 10% when records are large or table is fragmented on disk – scan cost increases.

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Index on Small Tables

• Small table: 100 records, i.e., a few pages.

• Two concurrent processes perform updates (each process works for 10ms before it commits)

• No index: the table is scanned for each update. No concurrent updates.

• A clustered index allows to take advantage of row locking.

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Bitmap vs. Hash vs. B+-Tree


hundreds2);create cluster c_hundreds (hundreds2 number(8)) PCTFREE 0;create cluster c_ssnum(ssnum integer) PCTFREE 0 size 60;

create cluster c_hundreds(hundreds2 number(8)) PCTFREE 0 HASHKEYS 1000 size 600;

create cluster c_ssnum(ssnum integer) PCTFREE 0 HASHKEYS 1000000 SIZE 60;

create bitmap index b on employees (hundreds2);create bitmap index b2 on employees (ssnum);

– 1000000 rows ; Cold buffer– Dual Xeon (550MHz,512Kb), 1Gb RAM, Internal RAID controller from Adaptec (80Mb),

4x18Gb drives (10000RPM), Windows 2000.

85

Multipoint query: B-Tree, Hash Tree, Bitmap

• There is an overflow chain in a hash index because hundreds2 has few values

• In a clustered B-Tree index records are on contiguous pages.

• Bitmap is proportional to size of table and non-clustered for record access.

Multipoint Queries

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• Hash indexes don’t help when evaluating range queries

• Hash index outperforms B-tree on point queries

Range Queries

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Point Queries

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Tuning Relational Systems

• Schema Tuning– Denormalization, Vertical Partitioning

• Query Tuning– Query rewriting– Materialized views

88

Denormalizing -- data


L_LINENUMBER, L_QUANTITY, L_EXTENDEDPRICE , L_DISCOUNT, L_TAX , L_RETURNFLAG, L_LINESTATUS , L_SHIPDATE, L_COMMITDATE, L_RECEIPTDATE, L_SHIPINSTRUCT , L_SHIPMODE , L_COMMENT );

region( R_REGIONKEY, R_NAME, R_COMMENT );

nation( N_NATIONKEY, N_NAME, N_REGIONKEY, N_COMMENT,);

supplier( S_SUPPKEY, S_NAME, S_ADDRESS, S_NATIONKEY, S_PHONE, S_ACCTBAL, S_COMMENT);

– 600000 rows in lineitem, 25 nations, 5 regions, 500 suppliers

89

Denormalizing -- transactions

lineitemdenormalized ( L_ORDERKEY, L_PARTKEY , L_SUPPKEY, L_LINENUMBER, L_QUANTITY, L_EXTENDEDPRICE , L_DISCOUNT, L_TAX , L_RETURNFLAG, L_LINESTATUS , L_SHIPDATE, L_COMMITDATE, L_RECEIPTDATE, L_SHIPINSTRUCT , L_SHIPMODE , L_COMMENT, L_REGIONNAMEL_REGIONNAME);

– 600000 rows in lineitemdenormalized

– Cold Buffer

– Dual Pentium II (450MHz, 512Kb), 512 Mb RAM, 3x18Gb drives (10000RPM), Windows 2000.

90

Queries on Normalized vs. Denormalized Schemas

Queries:select L_ORDERKEY, L_PARTKEY, L_SUPPKEY, L_LINENUMBER, L_QUANTITY,

L_EXTENDEDPRICE, L_DISCOUNT, L_TAX, L_RETURNFLAG, L_LINESTATUS, L_SHIPDATE, L_COMMITDATE, L_RECEIPTDATE, L_SHIPINSTRUCT, L_SHIPMODE, L_COMMENT, R_NAME

from LINEITEM, REGION, SUPPLIER, NATIONwhereL_SUPPKEY = S_SUPPKEYand S_NATIONKEY = N_NATIONKEYand N_REGIONKEY = R_REGIONKEYand R_NAME = 'EUROPE';

select L_ORDERKEY, L_PARTKEY, L_SUPPKEY, L_LINENUMBER, L_QUANTITY, L_EXTENDEDPRICE, L_DISCOUNT, L_TAX, L_RETURNFLAG, L_LINESTATUS, L_SHIPDATE, L_COMMITDATE, L_RECEIPTDATE, L_SHIPINSTRUCT, L_SHIPMODE, L_COMMENT, L_REGIONNAME

from LINEITEMDENORMALIZEDwhere L_REGIONNAME = 'EUROPE';

91

Denormalization

• TPC-H schema• Query: find all lineitems

whose supplier is in Europe.

• With a normalized schema this query is a 4-way join.

• If we denormalize lineitem and add the name of the region for each lineitem (foreign key denormalization) throughput improves 30%

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Vertical Partitioning

• Consider account(id, balance, homeaddress)

• When might it be a good idea to do a “vertical partitioning” into account1(id,balance) and account2(id,homeaddress)?

• Join vs. size.

93

Vertical Partitioning

• Which design is better depends on the query pattern:– The application that sends a

monthly statement is the principal user of the address of the owner of an account

– The balance is updated or examined several times a day.

• The second schema might be better because the relation (account_ID, balance) can be made smaller:– More account_ID, balance

pairs fit in memory, thus increasing the hit ratio

– A scan performs better because there are fewer pages.

94

Tuning Normalization

• A single normalized relation XYZ is better than two normalized relations XY and XZ if the single relation design allows queries to access X, Y and Z together without requiring a join.

• The two-relation design is better iff:– Users access tend to partition between the two sets Y

and Z most of the time

– Attributes Y or Z have large values

95

Vertical Partitioningand Scan

• R (X,Y,Z)– X is an integer– YZ are large strings

• Scan Query• Vertical partitioning

exhibits poor performance when all attributes are accessed.

• Vertical partitioning provides a sped up if only two of the attributes are accessed.

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Vertical Partitioningand Point Queries

• R (X,Y,Z)– X is an integer– YZ are large strings

• A mix of point queries access either XYZ or XY.

• Vertical partitioning gives a performance advantage if the proportion of queries accessing only XY is greater than 20%.

• The join is not expensive compared to a simple look-up.

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97

Queries

Settings: employee(ssnum, name, dept, salary, numfriends);student(ssnum, name, course, grade);techdept(dept, manager, location);

clustered index i1 on employee (ssnum);nonclustered index i2 on employee (name);nonclustered index i3 on employee (dept);

clustered index i4 on student (ssnum);nonclustered index i5 on student (name);

clustered index i6 on techdept (dept);

– 100000 rows in employee, 100000 students, 10 departments; Cold buffer– Dual Pentium II (450MHz, 512Kb), 512 Mb RAM, 3x18Gb drives

(10000RPM), Windows 2000.

98

Queries – View on Join

View Techlocation:create view techlocation as select ssnum, techdept.dept, location from employee, techdept where employee.dept = techdept.dept;

Queries:– Original:

select dept from techlocation where ssnum = ?;

– Rewritten:select dept from employee where ssnum = ?;

99

Query Rewriting - Views

• All systems expand the selection on a view into a join

• The difference between a plain selection and a join (on a primary key-foreign key) followed by a projection is greater on SQL Server than on Oracle and DB2 v7.1.

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Queries – Correlated SubqueriesQueries:

– Original:select ssnum from employee e1 where salary = (select max(salary) from employee e2 where e2.dept = e1.dept);

– Rewritten:select max(salary) as bigsalary, deptinto TEMP from employee group by dept;

select ssnumfrom employee, TEMPwhere salary = bigsalaryand employee.dept = temp.dept;

101

Query Rewriting – Correlated Subqueries

• SQL Server 2000 does a good job at handling the correlated subqueries (a hash join is used as opposed to a nested loop between query blocks)– The techniques implemented

in SQL Server 2000 are described in “Orthogonal Optimization of Subqueries and Aggregates” by C.Galindo-Legaria and M.Joshi, SIGMOD 2001.

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102

Eliminate unneeded DISTINCTs

• Query: Find employees who work in the information systems department. There should be no duplicates.

SELECT distinct ssnumFROM employeeWHERE dept = ‘information systems’

• DISTINCT is unnecessary, since ssnum is a key of employee so certainly is a key of a subset of employee.

103

Eliminate unneeded DISTINCTs

• Query: Find social security numbers of employees in the technical departments. There should be no duplicates.

SELECT DISTINCT ssnumFROM employee, techWHERE employee.dept = tech.dept

• Is DISTINCT needed?

104

Distinct Unnecessary Here Too

• Since dept is a key of the tech table, each employee record will join with at most one record in tech.

• Because ssnum is a key for employee, distinct is unnecessary.

105

Reaching

• The relationship among DISTINCT, keys and joins can be generalized:– Call a table T privileged if the fields returned by the

select contain a key of T

– Let R be an unprivileged table. Suppose that R is joined on equality by its key field to some other table S, then we say R reaches S.

– Now, define reaches to be transitive. So, if R1 reaches R2 and R2 reaches R3 then say that R1 reaches R3.

106

Reaches: Main Theorem

• There will be no duplicates among the records returned by a selection, even in the absence of DISTINCT if one of the two following conditions hold:– Every table mentioned in the FROM clause is

privileged– Every unprivileged table reaches at least one

privileged table.

107

Reaches: Proof Sketch

• If every relation is privileged then there are no duplicates– The keys of those relations are in the from clause

• Suppose some relation T is not privileged but reaches at least one privileged one, say R. Then the qualifications linking T with R ensure that each distinct combination of privileged records is joined with at most one record of T.

108

Reaches: Example 1

• The same employee record may match several tech records (because manager is not a key of tech), so the ssnum of that employee record may appear several times.

• Tech does not reach the privileged relation employee.

SELECT ssnumFROM employee, techWHERE employee.manager = tech.manager

109

Reaches: Example 2

• Each repetition of a given ssnum vlaue would be accompanied by a new tech.dept since tech.dept is a key of tech

• Both relations are privileged.

SELECT ssnum, tech.deptFROM employee, techWHERE employee.manager = tech.manager

110

Reaches: Example 3

• Student is priviledged• Employee does not reach student (name is not a

key of employee)• DISTINCT is needed to avoid duplicates.

SELECT student.ssnumFROM student, employee, techWHERE student.name = employee.name AND employee.dept = tech.dept;

111

Aggregate Maintenance -- data

Settings:orders( ordernum, itemnum, quantity, storeid, vendorid );create clustered index i_order on orders(itemnum);

store( storeid, name );

item(itemnum, price);create clustered index i_item on item(itemnum);

vendorOutstanding( vendorid, amount);

storeOutstanding( storeid, amount);

– 1000000 orders, 10000 stores, 400000 items; Cold buffer– Dual Pentium II (450MHz, 512Kb), 512 Mb RAM, 3x18Gb drives


112

Aggregate Maintenance -- triggers

Triggers for Aggregate Maintenancecreate trigger updateVendorOutstanding on orders for insert asupdate vendorOutstandingset amount =

(select vendorOutstanding.amount+sum(inserted.quantity*item.price)from inserted,itemwhere inserted.itemnum = item.itemnum)

where vendorid = (select vendorid from inserted) ;

create trigger updateStoreOutstanding on orders for insert asupdate storeOutstandingset amount =

(select storeOutstanding.amount+sum(inserted.quantity*item.price) from inserted,item where inserted.itemnum = item.itemnum)

where storeid = (select storeid from inserted)

113

Aggregate Maintenance -- transactions

Concurrent Transactions:– Insertions

insert into orders values (1000350,7825,562,'xxxxxx6944','vendor4');

– Queries (first without, then with redundant tables)select orders.vendor, sum(orders.quantity*item.price)from orders,itemwhere orders.itemnum = item.itemnumgroup by orders.vendorid;

vs. select * from vendorOutstanding;

select store.storeid, sum(orders.quantity*item.price)from orders,item, storewhere orders.itemnum = item.itemnum

and orders.storename = store.namegroup by store.storeid;

vs. select * from storeOutstanding;

114

Aggregate Maintenance

• SQLServer 2000 on Windows 2000

• Using triggers for view maintenance

• If queries frequent or important, then aggregate maintenance is good.

pect. of gain with aggregate maintenance

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115

Superlinearity -- data

Settings:sales( id, itemid, customerid, storeid, amount, quantity);item (itemid);customer (customerid);store (storeid);

A sale is successful if all foreign keys are present.

successfulsales(id, itemid, customerid, storeid, amount, quantity);

unsuccessfulsales(id, itemid, customerid, storeid, amount, quantity);

tempsales( id, itemid, customerid, storeid, amount,quantity);

116

Superlinearity -- indexes

Settings (non-clustering, dense indexes):index s1 on item(itemid);

index s2 on customer(customerid);

index s3 on store(storeid);

index succ on successfulsales(id);

– 1000000 sales, 400000 customers, 40000 items, 1000 stores

– Cold buffer


117

Superlinearity -- queries

Queries:– Insert/create indexdelete

insert into successfulsalesselect sales.id, sales.itemid, sales.customerid,

sales.storeid, sales.amount, sales.quantityfrom sales, item, customer, storewhere sales.itemid = item.itemidand sales.customerid = customer.customeridand sales.storeid = store.storeid;

insert into unsuccessfulsales select * from sales;godelete from unsuccessfulsaleswhere id in (select id from successfulsales)

118

Superlinearity -- batch queries

Queries:– Small batches

DECLARE @Nlow INT;DECLARE @Nhigh INT;DECLARE @INCR INT;set @INCR = 100000set @NLow = 0set @Nhigh = @INCRWHILE (@NLow <= 500000)BEGIN

insert into tempsales select * from sales where id between @NLow and @Nhighset @Nlow = @Nlow + @INCRset @Nhigh = @Nhigh + @INCRdelete from tempsales

where id in (select id from successfulsales);insert into unsuccessfulsales select * from tempsales;delete from tempsales;

END

119

Superlinearity -- outer join

Queries:– outerjoin

insert into successfulsalesselect sales.id, item.itemid, customer.customerid, store.storeid, sales.amount,

sales.quantityfrom ((sales left outer join item on sales.itemid = item.itemid)left outer join customer on sales.customerid = customer.customerid)left outer join store on sales.storeid = store.storeid;

insert into unsuccessfulsalesselect *from successfulsaleswhere itemid is nullor customerid is nullor storeid is null;godelete from successfulsaleswhere itemid is nullor customerid is nullor storeid is null

120

Circumventing Superlinearity

• SQL Server 2000• Outer join achieves the

best response time.• Small batches do not

help because overhead of crossing the application interface is higher than the benefit of joining with smaller tables.

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121

Tuning the Application Interface

• 4GL– Power++, Visual basic

• Programming language + Call Level Interface– ODBC: Open DataBase Connectivity– JDBC: Java based API– OCI (C++/Oracle), CLI (C++/ DB2), Perl/DBI

• In the following experiments, the client program is located on the database server site. Overhead is due to crossing the application interface.

122

Looping can hurt -- data



– 600 000 rows; warm buffer.


123

Looping can hurt -- queries• Queries:

– No loop:sqlStmt = “select * from lineitem where l_partkey <= 200;”odbc->prepareStmt(sqlStmt);odbc->execPrepared(sqlStmt);

– Loop:sqlStmt = “select * from lineitem where l_partkey = ?;”odbc->prepareStmt(sqlStmt);for (int i=1; i<100; i++){

odbc->bindParameter(1, SQL_INTEGER, i);odbc->execPrepared(sqlStmt);

}

124

Looping can Hurt


• Crossing the application interface has a significant impact on performance.

• Why would a programmer use a loop instead of relying on set-oriented operations: object-orientation?

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Cursors are Death -- data


hundreds2);

– 100000 rows ; Cold buffer


126

Cursors are Death -- queries

Queries:– No cursor

select * from employees;

– Cursor

DECLARE d_cursor CURSOR FOR select * from employees;

OPEN d_cursorwhile (@@FETCH_STATUS = 0)

BEGIN

FETCH NEXT from d_cursorEND

CLOSE d_cursor

go

127

Cursors are Death


• Response time is a few seconds with a SQL query and more than an hour iterating over a cursor.

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Retrieve Needed Columns Only - data



create index i_nc_lineitem on lineitem (l_orderkey, l_partkey, l_suppkey, l_shipdate, l_commitdate);

– 600 000 rows; warm buffer.– Lineitem records are ~ 10 bytes long– Dual Pentium II (450MHz, 512Kb), 512 Mb RAM, 3x18Gb drives


129

Retrieve Needed Columns Only - queries

Queries:– All

Select * from lineitem;

– Covered subsetSelect l_orderkey, l_partkey, l_suppkey, l_shipdate, l_commitdate from lineitem;

130

Retrieve Needed Columns Only

• Avoid transferring unnecessary data

• May enable use of a covering index.

• In the experiment the subset contains ¼ of the attributes.– Reducing the amount of

data that crosses the application interface yields significant performance improvement.

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131

Bulk Loading Data



– Initially the table is empty; 600 000 rows to be inserted (138Mb)

– Table sits one disk. No constraint, index is defined.


132

Bulk Loading Queries

Oracle 8isqlldr directpath=true control=load_lineitem.ctl data=E:\Data\lineitem.tbl

load data infile "lineitem.tbl"into table LINEITEM appendfields terminated by '|' (

L_ORDERKEY, L_PARTKEY, L_SUPPKEY, L_LINENUMBER, L_QUANTITY, L_EXTENDEDPRICE, L_DISCOUNT, L_TAX, L_RETURNFLAG, L_LINESTATUS, L_SHIPDATE DATE "YYYY-MM-DD", L_COMMITDATE DATE "YYYY-MM-DD", L_RECEIPTDATE DATE "YYYY-MM-DD", L_SHIPINSTRUCT, L_SHIPMODE, L_COMMENT

)

133

Direct Path

• Direct path loading bypasses the query engine and the storage manager. It is orders of magnitude faster than for conventional bulk load (commit every 100 records) and inserts (commit for each record).

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134

Batch Size

• Throughput increases steadily when the batch size increases to 100000 records.Throughput remains constant afterwards.

• Trade-off between performance and amount of data that has to be reloaded in case of problem.

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135

Tuning E-Commerce Applications

Database-backed web-sites:– Online shops– Shop comparison portals– MS TerraServer

136

E-commerce Application Architecture

Clients Web servers Application servers Database server

Web

cac

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eb c

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B c

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137

E-commerce Application Workload

• Touristic searching (frequent, cached)– Access the top few pages. Pages may be personalized.

Data may be out-of-date.

• Category searching (frequent, partly cached and need for timeliness guarantees)– Down some hierarchy, e.g., men’s clothing.

• Keyword searching (frequent, uncached, need for timeliness guarantees)

• Shopping cart interactions (rare, but transactional)• Electronic purchasing (rare, but transactional)

138

Design Issues• Need to keep historic information

– Electronic payment acknowledgements get lost.

• Preparation for variable load– Regular patterns of web site accesses during the day, and

within a week.

• Possibility of disconnections– State information transmitted to the client (cookies)

• Special consideration for low bandwidth• Schema evolution

– Representing e-commerce data as attribute-value pairs (IBM Websphere)

139

Caching• Web cache:

– Static web pages– Caching fragments of dynamically created web pages

• Database cache (Oracle9iAS, TimesTen’s FrontTier)– Materialized views to represent cached data. – Queries are executed either using the database cache or

the database server. Updates are propagated to keep the cache(s) consistent.

– Note to vendors: It would be good to have queries distributed between cache and server.

140

Ecommerce -- setting

Settings:shoppingcart( shopperid, itemid, price, qty);

– 500000 rows; warm buffer


141

Ecommerce -- transactions

Concurrent Transactions:– Mix

insert into shoppingcart values (107999,914,870,214);update shoppingcart set Qty = 10 where shopperid = 95047 and itemid = 88636;

delete from shoppingcart where shopperid = 86123 and itemid = 8321;

select shopperid, itemid, qty, price from shoppingcart where shopperid = ?;

– Queries Onlyselect shopperid, itemid, qty, price from shoppingcart where shopperid = ?;

142

Connection Pooling (no refusals)• Each thread establishes a

connection and performs 5 insert statements.

• If a connection cannot be established the thread waits 15 secs before trying again.

• The number of connection is limited to 60 on the database server.

• Using connection pooling, the requests are queued and serviced when possible. There are no refused connections.

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Experiment performed on Oracle8i on Windows 2000

143

Indexing

• Using a clustered index on shopperid in the shopping cart provides:– Query speed-up

– Update/Deletion speed-up

Experiment performed on SQL Server 2000 on Windows 2000

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144

Capacity Planning

• Arrival Rate– A1 is given as an assumption– A2 = (0.4 A1) + (0.5 A2)– A3 = 0.1 A2

• Service Time (S)– S1, S2, S3 are measured

• Utilization– U = A x S

• Response Time– R = U/(A(1-U)) = S/(1-U)(assuming Poisson arrivals)

Entry (S1) 0.4

Search (S2)

Checkout (S3)

0.5

0.1

Getting the demand assumptions rightis what makes capacity planning hard

145

How to Handle Multiple Servers

• Suppose one has n servers for some task that requires S time for a single server to perform.

• The perfect parallelism model is that it is as if one has a single server that is n times as fast.

• However, this overstates the advantage of parallelism, because even if there were no waiting, single tasks require S time.

146

Rough Estimate for Multiple Servers

• There are two components to response time: waiting time + service time.

• In the parallel setting, the service time is still S.

• The waiting time however can be well estimated by a server that is n times as fast.

147

Approximating waiting time for n parallel servers.

• Recall: R = U/(A(1-U)) = S/(1-U)• On an n-times faster server, service time is

divided by n, so the single processor utilization U is also divided by n. So we would get: Rideal = (S/n)/(1 – (U/n)).

• That Rideal = serviceideal + waitideal.• So waitideal = Rideal – S/n• Our assumption: waitideal ~ wait for n

processors.

148

Approximating response time for n parallel servers

• Waiting time for n parallel processors ~ (S/n)/(1 – (U/n)) – S/n = (S/n) ( 1/(1-(U/n)) – 1) =(S/(n(1 – U/n)))(U/n) = (S/(n – U))(U/n)

• So, response time for n parallel processors is above waiting time + S.

149

Example

• A = 8 per second.• S = 0.1 second.• U = 0.8.• Single server response time = S/(1-U) = 0.1/0.2 =

0.5 seconds. • If we have 2 servers, then we estimate waiting time

to be (0.1/(2-0.8))(0.4) = 0.04/1.2 = 0.033. So the response time is 0.133.

• For a 2-times faster server, S = 0.05, U = 0.4, so response time is 0.05/0.6 = 0.0833

150

Example -- continued

• A = 8 per second.• S = 0.1 second.• U = 0.8.• If we have 4 servers, then we estimate waiting

time to be (S/(n – U))(U/n) = 0.1/(3.2) * (0.8/4) = 0.02/3.2 = 0.00625 So response time is 0.10625.

151

Datawarehouse Tuning

• Aggregate (strategic) targeting:– Aggregates flow up from a wide selection of

data, and then – Targeted decisions flow down

• Examples:– Riding the wave of clothing fads– Tracking delays for frequent-flyer customers

152

Data Warehouse Workload

• Broad– Aggregate queries over ranges of values, e.g., find

the total sales by region and quarter.

• Deep – Queries that require precise individualized

information, e.g., which frequent flyers have been delayed several times in the last month?

• Dynamic (vs. Static)– Queries that require up-to-date information, e.g.

which nodes have the highest traffic now?

153

Tuning Knobs

• Indexes

• Materialized views

• Approximation

154

Bitmaps -- data

Settings:lineitem ( L_ORDERKEY, L_PARTKEY , L_SUPPKEY, L_LINENUMBER,

L_QUANTITY, L_EXTENDEDPRICE , L_DISCOUNT, L_TAX , L_RETURNFLAG, L_LINESTATUS , L_SHIPDATE, L_COMMITDATE, L_RECEIPTDATE, L_SHIPINSTRUCT , L_SHIPMODE , L_COMMENT );

create bitmap index b_lin_2 on lineitem(l_returnflag);

create bitmap index b_lin_3 on lineitem(l_linestatus);

create bitmap index b_lin_4 on lineitem(l_linenumber);

– 100000 rows ; cold buffer


155

Bitmaps -- queries

Queries:– 1 attribute

select count(*) from lineitem where l_returnflag = 'N';

– 2 attributesselect count(*) from lineitem where l_returnflag = 'N' and l_linenumber > 3;

– 3 attributesselect count(*) from lineitem where l_returnflag =

'N' and l_linenumber > 3 and l_linestatus = 'F';

156

Bitmaps

• Order of magnitude improvement compared to scan.

• Bitmaps are best suited for multiple conditions on several attributes, each having a low selectivity.A

NR

l_returnflagOF

l_linestatus

0

2

4

6

8

10

12

1 2 3

Th

rou

gh

pu

t (Q

uer

ies/

sec)

linear scan

bitmap

157

Multidimensional Indexes -- data

Settings:create table spatial_facts( a1 int, a2 int, a3 int, a4 int, a5 int, a6 int, a7 int, a8 int, a9 int, a10 int, geom_a3_a7 mdsys.sdo_geometry );create index r_spatialfacts on spatial_facts(geom_a3_a7) indextype is mdsys.spatial_index;create bitmap index b2_spatialfacts on

spatial_facts(a3,a7);

– 500000 rows ; cold buffer– Dual Pentium II (450MHz, 512Kb), 512 Mb RAM, 3x18Gb drives


158

Multidimensional Indexes -- queries

Queries:– Point Queries

select count(*) from fact where a3 = 694014 and a7 = 928878;

select count(*) from spatial_facts where SDO_RELATE(geom_a3_a7, MDSYS.SDO_GEOMETRY(2001, NULL, MDSYS.SDO_POINT_TYPE(694014,928878, NULL), NULL, NULL), 'mask=equal querytype=WINDOW') = 'TRUE';

– Range Queriesselect count(*) from spatial_facts where SDO_RELATE(geom_a3_a7,

mdsys.sdo_geometry(2003,NULL,NULL, mdsys.sdo_elem_info_array(1,1003,3),mdsys.sdo_ordinate_array(10,800000,1000000,1000000)), 'mask=inside querytype=WINDOW') = 'TRUE';

select count(*) from spatial_facts where a3 > 10 and a3 < 1000000 and a7 > 800000 and a7 < 1000000;

159

Multidimensional Indexes

• Oracle 8i on Windows 2000

• Spatial Extension:– 2-dimensional data– Spatial functions used

in the query

• R-tree does not perform well because of the overhead of spatial extension.

0

2

4

6

8

10

12

14

point query range query

Res

po

nse

Tim

e (s

ec) bitmap - two

attributes

r-tree

160

Multidimensional Indexes

R-Tree

SELECT STATEMENT

SORT AGGREGATE

TABLE ACCESS BY INDEX ROWID SPATIAL_FACTS

DOMAIN INDEX R_SPATIALFACTS

Bitmaps

SELECT STATEMENT

SORT AGGREGATE

BITMAP CONVERSION COUNT

BITMAP AND

BITMAP INDEX SINGLE VALUE B_FACT7

BITMAP INDEX SINGLE VALUE B_FACT3

161

Materialized Views -- data

Settings:orders( ordernum, itemnum, quantity, storeid, vendor );

create clustered index i_order on orders(itemnum);

store( storeid, name );

item(itemnum, price);

create clustered index i_item on item(itemnum);

– 1000000 orders, 10000 stores, 400000 items; Cold buffer

– Oracle 9i

– Pentium III (1 GHz, 256 Kb), 1Gb RAM, Adapter 39160 with 2 channels, 3x18Gb drives (10000RPM), Linux Debian 2.4.

162

Materialized Views -- data

Settings:create materialized view vendorOutstanding

build immediate

refresh complete

enable query rewrite

as

select orders.vendor, sum(orders.quantity*item.price)

from orders,item

where orders.itemnum = item.itemnum

group by orders.vendor;

163

Materialized Views -- transactions

Concurrent Transactions:– Insertions

insert into orders values (1000350,7825,562,'xxxxxx6944','vendor4');

– Queriesselect orders.vendor,

sum(orders.quantity*item.price)from orders,itemwhere orders.itemnum = item.itemnumgroup by orders.vendor;

select * from vendorOutstanding;

164

Materialized Views

• Graph:– Oracle9i on Linux

– Total sale by vendor is materialized

• Trade-off between query speed-up and view maintenance:– The impact of incremental

maintenance on performance is significant.

– Rebuild maintenance achieves a good throughput.

– A static data warehouse offers a good trade-off.

0

400

800

1200

1600

MaterializedView (fast on

commit)

MaterializedView (complete

on demand)

NoMaterialized

ViewThro

ughp

ut (s

tate

men

ts/s

ec)

0

2

4

6

8

10

12

14

Materialized View No Materialized View

Res

pons

e Ti

me

(sec

)

165

Materialized View Maintenance

• Problem when large number of views to maintain.

• The order in which views are maintained is important:– A view can be computed

from an existing view instead of being recomputed from the base relations (total per region can be computed from total per nation).

• Let the views and base tables be nodes v_i

• Let there be an edge from v_1 to v_2 if it possible to compute the view v_2 from v_1. Associate the cost of computing v_2 from v_1 to this edge.

• Compute all pairs shortest path where the start nodes are the set of base tables.

• The result is an acyclic graph A. Take a topological sort of A and let that be the order of view construction.

166

Materialized View Example

• Detail(storeid, item, qty, price, date)

• Materialized view1(storeid, category, qty, month)

• Materializedview2(city, category, qty, month)

• Materializedview3(storeid, category, qty, year)

167

Approximations -- data

Settings:– TPC-H schema– Approximations

insert into approxlineitem

select top 6000 *from lineitemwhere l_linenumber = 4;

insert into approxordersselect O_ORDERKEY, O_CUSTKEY, O_ORDERSTATUS, O_TOTALPRICE, O_ORDERDATE, O_ORDERPRIORITY, O_CLERK, O_SHIPPRIORITY, O_COMMENT

from orders, approxlineitemwhere o_orderkey = l_orderkey;

168

Approximations -- queriesinsert into approxsupplierselect distinct S_SUPPKEY,

S_NAME ,S_ADDRESS,S_NATIONKEY,S_PHONE,S_ACCTBAL,S_COMMENT

from approxlineitem, supplierwhere s_suppkey = l_suppkey;

insert into approxpartselect distinct P_PARTKEY,

P_NAME , P_MFGR , P_BRAND , P_TYPE , P_SIZE ,P_CONTAINER , P_RETAILPRICE , P_COMMENT

from approxlineitem, partwhere p_partkey = l_partkey;

insert into approxpartsuppselect distinct PS_PARTKEY,

PS_SUPPKEY,PS_AVAILQTY,PS_SUPPLYCOST,PS_COMMENT

from partsupp, approxpart, approxsupplierwhere ps_partkey = p_partkey and

ps_suppkey = s_suppkey;

insert into approxcustomerselect distinct C_CUSTKEY,

C_NAME ,C_ADDRESS,C_NATIONKEY,C_PHONE ,C_ACCTBAL,C_MKTSEGMENT,C_COMMENT

from customer, approxorderswhere o_custkey = c_custkey;insert into approxregion select * from

region;insert into approxnation select * from

nation;

169

Approximations -- more queries

Queries:– Single table query on lineitemselect l_returnflag, l_linestatus, sum(l_quantity) as sum_qty,

sum(l_extendedprice) as sum_base_price,

sum(l_extendedprice * (1 - l_discount)) as sum_disc_price,

sum(l_extendedprice * (1 - l_discount) * (1 + l_tax)) as sum_charge,

avg(l_quantity) as avg_qty, avg(l_extendedprice) as avg_price, avg(l_discount) as avg_disc, count(*) as count_order

from lineitem

where datediff(day, l_shipdate, '1998-12-01') <= '120'

group by l_returnflag, l_linestatus

order by l_returnflag, l_linestatus;

170

Approximations -- still more

Queries:– 6-way joinselect n_name, avg(l_extendedprice * (1 - l_discount)) as

revenuefrom customer, orders, lineitem, supplier, nation, regionwhere c_custkey = o_custkey

and l_orderkey = o_orderkeyand l_suppkey = s_suppkeyand c_nationkey = s_nationkeyand s_nationkey = n_nationkeyand n_regionkey = r_regionkeyand r_name = 'AFRICA'and o_orderdate >= '1993-01-01'and datediff(year, o_orderdate,'1993-01-01') < 1

group by n_nameorder by revenue desc;

171

Approximation accuracy

• Good approximation for query Q1 on lineitem

• The aggregated values obtained on a query with a 6-way join are significantly different from the actual values -- for some applications may still be good enough.

TPC-H Query Q5: 6 way join

-40

-20

0

20

40

60

1 2 3 4 5

Groups returned in the query

Ap

pro

xim

ated

ag

gre

gat

ed v

alu

es

(% o

f B

ase

Ag

gre

gat

e V

alu

e)

1% sample

10% sample

TPC-H Query Q1: lineitem

-40

-20

0

20

40

60

1 2 3 4 5 6 7 8

Aggregate values

Ap

pro

xim

ated

A

gg

reg

ate

Val

ues

(%

of

Bas

e A

gg

reg

ate

Val

ue)

1% sample

10% sample

172

Approximation Speedup

• Aqua approximation on the TPC-H schema– 1% and 10% lineitem

sample propagated.

• The query speed-up obtained with approximated relations is significant.

00.5

11.5

22.5

33.5

4

Q1 Q5

TPC-H Queries

Res

po

nse

Tim

e (s

ec)

base relations

1 % sample

10% sample

173

Approximating Count Distinct

• Suppose you have one or more columns with duplicates. You want to know how many distinct values there are.

• Imagine that you could hash into (0,1). (Simulate this by a very large integer range).

• Hashing will put duplicates in the same location and, if done right, will distribute values uniformly.

• How can we use this?

174

Approximating Count Distinct

• Suppose you took the minimum 1000 hash values.

• Suppose that highest value of the 1000 is f.

• What is a good approximation of the number of distinct values?

175

Tuning Distributed Applications

• Queries across multiple databases– Federated Datawarehouse– IBM’s DataJoiner now integrated at DB2 v7.2

• The source should perform as much work as possible and return as few data as possible for processing at the federated server

• Processing data across multiple databases

176

A puzzle

• Two databases X and Y– X records inventory data to be used for restocking

– Y contains delivery data about shipments

• Improve the speed of shipping by sharing data– Certain data of X should be postprocessed on Y shortly

after it enters X

– You want to avoid losing data from X and you want to avoid double-processing data on Y, even in the face of failures.

177

Two-Phase Commit

X

Y

commit

commit

Source(coordinator& participant)

Destination(participant)

+ Commits are coordinated between the source and the destination

- If one participant fails then blocking can occur

- Not all db systems support prepare-to-commit interface

178

Replication Server

+ Destination within a few seconds of being up-to-date

+ Decision support queries can be asked on destination db

- Administrator is needed when network connection breaks!

X

Y

Source

Destination

179

Staging Tables

+ No specific mechanism is necessary at source or destination

- Coordination of transactions on X and Y

X

Y

Source

Destination

Staging table

180

Issues in Solution

• A single thread can invoke a transaction on X, Y or both, but the thread may fail in the middle. A new thread will regain state by looking at the database.

• We want to delete data from the staging tables when we are finished.

• The tuples in the staging tables will represent an operation as well as data.

181

States

• A tuple (operation plus data) will start in state unprocessed, then state processed, and then deleted.

• The same transaction that processes the tuple on the destination site also changes its state. This is important so each tuple’s operation is done exactly once.

182

Database X Database Y

Table S Table I

YunprocessedYunprocessed

Yunprocessed

M1

Read from source tableM2

Write to destination

Staging Tables

Table S


Yunprocessed

Database Y

Table I

unprocessedunprocessedunprocessed

Database X

STEP 1 STEP 2

183

Staging Tables

Database X Database Y

Table S Table I


Yunprocessed

Table S


Yunprocessed

Database Y

Table I

processedunprocessedunprocessed

Database X

STEP 3 STEP 4

M3

Update on destination

processedunprocessedunprocessed

M4

Delete source; then dest YXact: Update source siteXact:update destination site

184

What to Look For

• Transactions are atomic but threads, remember, are not. So a replacement thread will look to the database for information.

• In which order should the final step do its transactions? Should it delete the unprocessed tuple from X as the first transaction or as the second?

185

Troubleshooting Techniques(*)

• Extraction and Analysis of Performance Indicators– Consumer-producer chain framework– Tools

• Query plan monitors• Performance monitors• Event monitors

(*) From Alberto Lerner’s chapter

186

A Consumer-Producer Chain of a DBMS’s Resources

High LevelConsumers

IntermediateResources/Consumers

PrimaryResources

PARSEROPTIMIZERPARSER

OPTIMIZER

EXECUTIONSUBSYSTEM

EXECUTIONSUBSYSTEM DISK

SYBSYSTEM DISK

SYBSYSTEM

CACHEMANAGERCACHE

MANAGER

LOGGINGSUBSYSTEMLOGGING

SUBSYSTEM

LOCKINGSUBSYSTEM LOCKING

SUBSYSTEM

NETWORKDISK/

CONTROLLERCPUMEMORY

sql commands

probingspotsfor

indicators

187

Recurrent Patterns of Problems

• An overloading high-level consumer

• A poorly parameterized subsystem

• An overloaded primary resource

Effects are not always felt first where the cause is!

188

A Systematic Approach to Monitoring

• Question 1: Are critical queries being served in the most efficient manner?

• Question 2: Are subsystems making optimal use of resources?

• Question 3: Are there enough primary resources available?

Extract indicators to answer the following questions

189

Investigating High Level Consumers

• Answer question 1: “Are critical queries being served in the most efficient manner?”

1. Identify the critical queries

2. Analyze their access plans

3. Profile their execution

190

Identifying Critical Queries

Critical queries are usually those that:

• Take a long time

• Are frequently executed

Often, a user complaint will tip us off.

191

Event Monitors to Identify Critical Queries

• If no user complains...• Capture usage measurements at specific

events (e.g., end of each query) and then sort by usage

• Less overhead than other type of tools because indicators are usually by-product of events monitored

• Typical measures include CPU used, IO used, locks obtained etc.

192

An example Event Monitor

• CPU indicatorssorted by Oracle’sTrace Data Viewer

• Similar tools: DB2’s Event Monitor and MSSQL’s Server Profiler

193

An example Plan Explainer

• Access plan according to MSSQL’s Query Analyzer

• Similar tools: DB2’s Visual Explain and Oracle’s SQL AnalyzeTool

194

Finding Strangeness in Access Plans

What to pay attention to in a plan

• Access paths for each table

• Sorts or intermediary results (join, group by, distinct, order by)

• Order of operations

• Algorithms used in the operators

195

To Index or not to index?

select c_name, n_name from CUSTOMER join NATIONon c_nationkey=n_nationkey where c_acctbal > 0

Which plan performs best? (nation_pk is an non-clustered index over n_nationkey, and similarly for acctbal_ix over c_acctbal)

196

Non-clustering indexes can be trouble

For a low selectivity predicate, each access to the index generates a random access to the table – possibly duplicate! It ends up that the number of pages read from the table is greater than its size, i.e., a table scan is way better

Table Scan Index Scan

5 sec143,075 pages

6,777 pages136,319 pages

7 pages

76 sec272,618 pages131,425 pages273,173 pages

552 pages

CPU timedata logical reads

data physical readsindex logical reads

index physical reads

197

An example Performance Monitor (query level)

• Buffer and CPU consumption for a query according to DB2’s Benchmark tool

• Similar tools: MSSQL’s SET STATISTICS switch and Oracle’s SQL Analyze Tool

Statement number: 1

select C_NAME, N_NAME

from DBA.CUSTOMER join DBA.NATION on C_NATIONKEY = N_NATIONKEY

where C_ACCTBAL > 0

Number of rows retrieved is: 136308

Number of rows sent to output is: 0

Elapsed Time is: 76.349 seconds

…

Buffer pool data logical reads = 272618

Buffer pool data physical reads = 131425

Buffer pool data writes = 0

Buffer pool index logical reads = 273173

Buffer pool index physical reads = 552

Buffer pool index writes = 0

Total buffer pool read time (ms) = 71352

Total buffer pool write time (ms) = 0

…

Summary of Results

==================

Elapsed Agent CPU Rows Rows

Statement # Time (s) Time (s) Fetched Printed

1 76.349 6.670 136308 0

Statement number: 1

select C_NAME, N_NAME

from DBA.CUSTOMER join DBA.NATION on C_NATIONKEY = N_NATIONKEY

where C_ACCTBAL > 0

Number of rows retrieved is: 136308

Number of rows sent to output is: 0

Elapsed Time is: 76.349 seconds

…

Buffer pool data logical reads = 272618

Buffer pool data physical reads = 131425

Buffer pool data writes = 0

Buffer pool index logical reads = 273173

Buffer pool index physical reads = 552

Buffer pool index writes = 0

Total buffer pool read time (ms) = 71352

Total buffer pool write time (ms) = 0

…

Summary of Results

==================

Elapsed Agent CPU Rows Rows

Statement # Time (s) Time (s) Fetched Printed

1 76.349 6.670 136308 0

198

An example Performance Monitor (system level)

• An IO indicator’s consumption evolution (qualitative and quantitative) according to DB2’s System Monitor

• Similar tools: Window’s Performance Monitor and Oracle’s Performance Manager

199

Investigating High Level Consumers: Summary

Find criticalqueries

Found any?Investigatelower levels

Answer Q1over them

Overcon-sumption?

Tune problematicqueries

yes

yesno

no

200

Investigating Primary Resources

• Answer question 3:“Are there enough primary resources available for a DBMS to consume?”

• Primary resources are: CPU, disk & controllers, memory, and network

• Analyze specific OS-level indicators to discover bottlenecks.

• A system-level Performance Monitor is the right tool here

201

CPU Consumption Indicators at the OS Level

100%

CPU% of

utilization

70%

time

Sustained utilizationover 70% should trigger the alert.

System utilization shouldn’t be more

than 40%.DBMS (on a non-

dedicated machine)should be getting a decent time share.

total usage

system usage

202

Disk Performance Indicators at the OS Level

Wait queue

Average Queue Size

New requestsDisk Transfers

/second

Should beclose to zero

Wait timesshould also be close to

zeroIdle disk with pending requests?Check controller

contention.Also, transfers

should be balanced amongdisks/controllers

203

Memory Consumption Indicators at the OS Level

pagefile

real memory

virtualmemory

Page faults/timeshould be close

to zero. If paginghappens, at least

not DB cache pages.

% of pagefile inuse will tell

you how much memory is “needed.”

204

Investigating Intermediate Resources/Consumers

• Answer question 2:“Are subsystems making optimal use of resources?”

• Main subsystems: Cache Manager, Disk subsystem, Lock subsystem, and Log/Recovery subsystem

• Similarly to Q3, extract and analyze relevant Performance Indicators

205

Cache Manager Performance Indicators

Tablescan

readpage()

Free Page slots

Page reads/writes

Pickvictim

strategy Data Pages

CacheManager

If page is not in the cache, readpage

(logical) generates an actual IO (physical). Fraction of readpages that did not generate

physical IO should be 90% or more (hit ratio)

Pages are regularly saved to disk to make

free space.# of free slots should

always be > 0

206

Disk Manager Performance Indicators

rows

page

extent

file

Storage Hierarchy (simplified)

disk

Displaced rows (moved to other pages) should be kept

under 5% of rows

Free space fragmentation: pages with little space should

not be in the free list

Data fragmentation: ideally files that store DB objects

(table, index) should be in one or few (<5) contiguous extents

File position: should balance workload evenly among all

disks

207

Lock Manager Performance Indicators

Lock request

Object Lock Type TXN ID

LockList

Lockspending list

Deadlocks and timeouts should seldom happen (no

more then 1% of the transactions)

Lock wait time for a transaction should be a

small fraction of the whole transaction time.

Number of lock waitsshould be a small fraction of the number of locks on

the lock list.

208

Investigating Intermediate and Primary Resources: Summary

Answer Q3

Problems at

OS level?Answer Q2

Tune low-levelresources

yesno

Problematic

subsystems?Tune

subsystemsInvestigateupper level

yes no

209

Troubleshooting Techniques

• Monitoring a DBMS’s performance should be based on queries and resources.– The consumption chain helps distinguish

problems’ causes from their symptoms– Existing tools help extracting relevant

performance indicators

210

Recall Tuning Principles

• Think globally, fix locally (troubleshoot to see what matters)

• Partitioning breaks bottlenecks (find parallelism in processors, controllers, caches, and disks)

• Start-up costs are high; running costs are low (batch size, cursors)

• Be prepared for trade-offs (unless you can rethink the queries)

Documents

Database Tuning Slides