Data Analysis Concept

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    Module 1: Data analysis keyconcepts

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    Module 1: Learning Objectives

    Understand the definition and purpose of data

    analysis

    Define statistical and M&E key concepts in data

    analysis

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    Data Analysis

    Turning raw datainto useful information

    Purpose is to provide answers to questions beingasked at a program site or research questions

    Even the greatest amount and best quality datamean nothing if not properly analyed!or if not

    analyed at all

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    Answering programmatic questions

    Question: s my program meeting its ob'ectives(

    Analysis# *ompare program targets and actual

    program performance to learn how far you are from

    target+

    nterpretation# ,hy you have or have not achieved

    the target and what this means for your program+

    May require more information+

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    Descriptive analysis

    Describes the sample-target population.demographic & clinic characteristics/

    Does not define causality 0 tells you what1 not

    why E2ample 0 average number of clients seen

    per month

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    !asic terminology and concepts

    3tatistical terms

    4atio

    Proportion

    Percentage

    4ate

    Mean

    Median

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    "atio

    *omparison of two numbers e2pressed as# a to b1 a per b1 a#b

    Used to e2press such comparisons as clinicians to

    patients or beds to clients

    *alculation a-b

    E2ample 0 n district 51 there are 677 nurses and 877

    clinics+ ,hat is the ratio of nurses to clinics( 677

    877

    9 : nurses per clinic1 a ratio of :#;

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    $roportion

    " ratio in which all individuals in the numerator arealso in the denominator+

    Used to compare part of the whole1 such as proportion

    of all clients who are less than ;? years old+ E2ample# f 87 of ;77 clients on treatment are less

    than ;? years of age1 what is the proportion of young

    clients in the clinic(

    87-;77 9 ;-?

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    $ercentage

    " way to e2press a proportion .proportion

    multiplied by ;77/

    E2presses a number in relation to the whole

    E2ample# Males comprise 8-? of the clients1 or

    =7B of the clients are male .7+=7 2 ;77/

    "llows us to e2press a quantity relative to another

    quantity+ *an compare different groups1 facilities1countries that may have different denominators

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    "ate

    Measured with respect to another measuredquantity during the same time period

    Used to e2press the frequency of specific events

    in a certain time period .fertility rate1 mortality

    rate/

    Cumerator and denominator must be from same

    time period

    ften e2pressed as a ratio .per ;1777/

    Source:U+3+ *ensus ureau1 nternational Database+

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    n%ant Mortality "ate

    F *alculation

    F G of deaths H population at risk in same time

    period 2 ;1777

    F E2ample 0 I? infants .less than one year/ diedout of =1777 infants born that year

    F I?-=1777 9 +7;@I 2 ;1777 9 ;@+I

    19 infants died per 1,000 live births

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    #alculating mortality rate

    n 877J1 Mondello clinic had :;1;?? patients on

    "4T+ During that same time period1 ;1?:6 "4T

    clients died+

    ;1?:6

    :;1;??

    949 clients died

    (mortality rate) per

    1,000 clients onA!

    +7=J 2 ;1777 9 =J

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    "ate o% increase

    *alculation

    Total number of increase H time of increase

    Used to calculate monthly1 quarterly1 yearly

    increases in health service delivery+ E2ample#increase in G of new clients1 commodities distributed

    E2ample# *ondom distribution in Kan+ 9 877L as of

    Kune 9 ;1;77+ ,hat is the rate of increase(

    ;1;77 > 877 9 J77-6 9 ;?7 .;?7 condoms per mo/

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    #entral tendency

    Measures of the location of the middle or the center

    of a distribution of data

    Mean

    Median

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    #alculating t&e mean

    "verage number of clients counseled per month

    0 Kanuary# :7

    0 Nebruary# =?0 March# :@

    0"pril# =;

    0 May# :I

    0 Kune# =7

    .:7A=?A:@A=;A:IA=7/ 9 8:;H6 9 :@+?

    Mean or average 9 :@+?

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    Median

    The middle of a distribution .when numbers are inorder# half of the numbers are above the median andhalf are below the median/

    The median is not as sensitive to e2treme values as

    the mean

    dd number of numbers1 median 9 the middle number

    Median of 81 =1 I 9 =

    Even number of numbers1 median 9 mean of the two

    middle numbers

    Median of 81 =1 I1 ;8 9 .=AI/ -8 9 ?+?

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    #alculating t&e median

    *lient ; 0 8

    *lient 8 0 ;:=

    *lient : 0 6I

    *lient = 0 ;7

    *lient ? 0 88;

    9 6I 9 6IA;:= 9 87;-8 9 ;77+?

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