1

MC LC

MC LC .......................................................................................................... 1

CHNG I: TNH NG C ........................................................................... 2

I.1 CHN NG C ...................................................................................... 2

I.2 PHN PHI T S TRUYN .................................................................. 4

I.3 TNH TON THNG S TRN CC TRC ........................................... 4

I.4 TNG HP KT QU .............................................................................. 7

CHNG 2: THIT K CC B TRUYN ..................................................... 8

II.1 THIT K B TRUYN BNH RNG .................................................. 8

II.2 THIT K B TRUYN XCH ............................................................. 20

CHNG III: CHN KHP NI, TNH TRC, THEN V LN.............. 28

III.1 CHN KHP NI ................................................................................. 28

III.2 THIT K TRC .................................................................................. 30

CHNG IV: THIT K KT CU ............................................................... 51

IV.1 KCH THC C BN CA B HP GIM TC ........................... 51

IV.2 KT CU NP , BNH RNG ......................................................... 52

CHNG V: BI TRN, LP GHP V IU CHNH N KHP ............ 55

V.1 BI TRN .............................................................................................. 55

V.2 BNG K KIU LP, SAI LCH GII HN V DUNG SAI LP

GHP ............................................................................................................. 56

V.3 IU CHNH LC N KHP .............................................................. 57

TI LIU THAM KHO ................................................................................. 58

2

CHNG I: TNH NG C

I.1 CHN NG C

Thng s u vo:

1. Lc ko xch ti: F = 3720 [N]

2. Vn tc bng ti: v = 1,29 [m/s]

3. S rng a xch ti: z = 8 [rng]

4. Bc xch ti: p = 90 [mm]

5. Thi hn phc v: lh = 16000 [h]

6. S ca lm vic: soca = 2 [ca]

7. Gc nghing ng ni tm vi b truyn ngoi: 120 []

8. c tnh lm vic: Va p nh

I.1.1 Cng sut cn tnh trn trc ng c

a) Cng sut lm vic

b) Hiu sut h dn ng

Tra bng 2.3 P19 [1]

3

- Hiu sut b truyn bnh rng nghing:

- Hiu sut b truyn xch:

- Hiu sut ln:

- Hiu sut khp ni:

c) Cng sut cn thit trn trc ng c

I.1.2 S vng quay s b ca trc cng tc

a) S vng quay ca trc cng tc

b) T s truyn s b

Theo bng 2.4 P21[1]:

- T s truyn b truyn bnh rng tr:

- T s truyn b truyn xch:

Vy

Ta chn

4

Cn c vo v ta tra ph lc [1] ta chn c ng c 4A112M4Y3

Cng sut danh

ngha (kW)

S vng quay thc

H s m my

H s qu ti

Khi lng (kg)

ng knh trc ng c

(mm)

5,5

1425

2

2,2

56

32

I.2 PHN PHI T S TRUYN

T s truyn thc:

Chn t s truyn ca hp gim tc:

I.3 TNH TON THNG S TRN CC TRC

I.3.1 S vng quay

Gi trc I l trc vo ca hp gim tc v trc II l trc ra ca hp gim tc.

- S vng quay trn trc I:

Vi, t s truyn gia trc ng c v trc I:

5

- S vng quay trn trc II:

Vi, t s truyn ca hp (trc I so vi trc II):

- S vng quay trn trc cng tc:

Vi, t s truyn t trc II n trc cng tc:

I.3.2 Cng sut trn cc trc

- Cng sut trn trc cng tc:

- Cng sut trn trc II:

Vi, hiu sut t trc 2 n trc cng tc

- Cng sut trn trc I:

Vi, hiu sut t trc I n trc II:

6

- Cng sut trn trc ng c:

Vi, hiu sut t trc ng c n trc I:

I.3.3 Momen xon trn cc trc

p dng CT

- Momen xon trn trc ng c:

- Momen xon trn trc I:

- Momen xon trn trc II:

- Momen xon trn trc cng tc:

7

I.4 TNG HP KT QU

Trc / Thng s

ng c Trc I Trc II Trc cng tc

Cng sut [kW]

5,42 5,37 5,21 4,8

S vng quay [v/ph]

1425 1425 285 107,5

Momen xon [N.mm]

36323,51 35988,42 174580,70 426418,60

8

CHNG 2: THIT K CC B TRUYN

II.1 THIT K B TRUYN BNH RNG

II.1.1 Chn vt liu v ng sut cho php

1. Chn vt liu bnh rng

Tra bng 6.1 P92 [1] ta c:

- Vt liu bnh ln:

+ Nhn hiu thp: Thp 45.

+ Ch nhit luyn: Ti ci thin.

+ rn HB2 = 192 240. Ta chn HB2 = 235.

+ Gii hn bn: .

+ Gii hn chy: .

- Vt liu bnh nh:

+ Nhn hiu thp: Thp 45.

+ Ch nhit luyn: Ti ci thin.

+ rn HB1 = 241 285. Ta chn HB1 = 250 ( tng kh nng

chy mn ca bnh rng nn ta nhit luyn bnh rng nh t rn cao hn

bnh rng ln t 10 15 n v, tc l HB1 HB2 + (10 15).

+ Gii hn bn: .

+ Gii hn chy: .

2. ng sut cho php

9

a) ng sut tip xc v un cho php

{

Trong :

- Chn s b: v .

- : h s an ton khi tnh v tip xc v un, tra bng 6.2 T94 [1] ta

c:

+ Vi bnh rng ch ng: .

+ Vi bnh rng b ng: .

-

: ng sut tip xc cho php v ng sut ung cho php ng

vi chu k c s, tra bng 6.2 T94 [1] ta c:

+ Vi bnh ch ng

+ Vi bnh b ng

- : H s tui th, xt n nh hng ca thi gian phc v v ch

ti trng ca b truyn:

Trong :

10

+ : Bc ca ng cong mi khi th v ng sut tip xc v ng

sut un. Do bnh rng c .

+ : S chu k thay i ng sut khi th v ng sut tip xc v

ng sut un, ta c:

{

+ : S chu k thay i ng sut tng ng, do b truyn chu

ti tnh nn , vi:

: s ln n khp trong mt vng quay;

: vn tc vng ca bnh rng.

: tng s gi lm vic ca bnh rng.

{

Ta thy:

{

, vi i = 1; 2.

T , ta xc nh c cc gii hn bn tip xc v bn un.

{

11

Do y l bnh tr rng nghing nn:

b) ng sut cho php khi qu ti

{

II.1.2 Xc nh thng s ca b truyn

1. Xc nh cc thng s n khp

a) Modun php (m):

Vi, l khong cch trc. chn ta phi tnh s b khong cch trc.

Ta c:

Trong :

- : H s ph thuc vt liu lm bnh rng ca cp bnh rng. Tra bng

6.5 T96 [1] ta c

.

- : Momen xon trn trc ch ng,

- : ng sut tip xc chp php,

- : T s truyn,

12

- : H s chiu rng vnh rng, tra bng 6.6 T97 [1] ta chn

- : H s k n s phn b khng u ca ti trng trn chiu

rng vnh rng khi tnh v ng sut tip xc v un, tra bng 6.7 T97 [1] ng vi

s b tr 6 ta c: .

Ta chn

Tra bng 6.8 T99 [1], ta chn

b) Xc nh s rng

Chn

- S rng bnh nh:

- S rng bnh ln:

Chn

- T s truyn thc t:

- Sai s t s truyn:

|

| |

|

nn chp nhn c.

c) Xc nh gc nghing ca rng

13

( nm trong khong 80 200 )

d) Xc nh gc n khp

(

) (

)

Vi l gc profin gc, .

Gc nghing ca rng trn hnh tr c s:

2. Xc nh cc h s v mt s thng s v ng hc

Ta c, t s truyn thc t l nn:

- ng knh vng ln ca cp bnh rng:

{

- Vn tc vng ca bnh rng:

- Tra bng 6.13 T106 [1] vi bnh tr rng nghing v , ta

c cp chnh xc ca b truyn l 9.

- Tra ph lc 2.3 T250 [1] vi , cp chnh xc 9, rng nghing,

ta c: .

- Vi cp chnh xc ng hc l 9, khi gia cng t cp nhm

.

14

- Vi v .

- Do .

- Chn

.

- Do .

- H s tp trung ti trng ng: . (Tra bng 6.7

T97 [1])

- Tra bng 6.14 T107 [1] ta c h s phn b khng u ti trong trn

cc i rng khi tnh v ng sut tip xc v ng sut un vi

v cp chnh xc 9: .

3. Mt s thng s hnh hc ca cp bnh rng

a) ng knh vng chia

{

b) Khong cch trc chia

c) ng knh nh rng

{

d) ng knh y rng

{

15

e) ng knh vng c s

{

II.1.3 Tnh kim nghim rng

1. Kim nghim v ng sut tip xc

Trong :

- ng sut tip xc cho php:

- H s nh hng n c tnh vt liu ca cc bnh rng n khp, tra bng

6.5 T96 [1] ta c:

- H s k n hnh dng ca b mt tip xc:

- H s xt s trng khp ca rng, ph thuc vo h s trng khp ngang

v h s trng khp hc .

( (

))

Ta thy nn .

16

- H s ti trng khi tnh v tip xc:

Thay vo ta c

Ta thy: v

Vy rng m bo bn tip xc.

2. Kim nghim v bn un

{

Trong :

- : ng sut un cho php ca bnh ch ng v b ng.

{

- : H s ti trng khi tnh v un

- : H s xt n s trng khp ca rng:

17

- : H s k n nghing ca rng:

- : H s dng rng, ph thuc vo s rng tng ng

{

Vy chn .

Tra bng 6.18 T109 [1], vi ta c: .

Thay cc thng s vo ta c:

{

=> m bo bn un.

3. Kim nghim v qu ti

{

Vi, l h s qu ti,

. Thay cc thng s vo ta c

{

Vy m bo iu kin qu ti.

18

II.1.4 Phn tch v tnh lc n khp

Vy ta c ln nh sau:

- Lc dc trc ca bnh dn v bnh b dn:

- Lc hng tm ca bnh dn v bnh b dn:

- Lc tip tuyn ca bnh dn v bnh b dn:

II.1.5 Tng hp kt qu tnh ton

19

Thng s

K hiu n v Kt qu tnh ton

Vt liu C45 - Ti ci thin

Khong cch trc

Modun php

S rng -

T s truyn thc t -

Sai lch t s truyn %

Gc nghin ca rng

H s dch chnh -

ng knh ln

ng knh chia

ng knh nh rng

ng knh y rng

ng knh vng c s

Chiu rng vnh rng

Lc vng

Lc hng tm

Lc dc trc

20

II.2 THIT K B TRUYN XCH

Thng s yu cu:

{

II.2.1 Chn loi xch

Chn xch con ln v n thch hp vi vn tc thp.

II.2.2 Xc nh cc kch thc v thng s b truyn

1. Chn s rng a xch

Chn

Chn

- Tnh li t s truyn thc t:

- Sai s t s truyn:

Vy sai lch c th chp nhn.

2. Xc nh bc xch

Bc xch c tra theo bng 5.5 T81 [1] vi iu kin:

21

Trong :

- Cng sut tnh ton:

Ta chn b truyn th nghim l b truyn xch tiu chun, c s rng v vn tc

vng a xch nh: . Do vy ta tnh c:

- H s rng:

- H s vng quay:

- , vi cc h s tra trong bng 5.6 T82 [1]

+ : H s nh hng ca v tr b truyn vi ,

.

+ : H s nh hng ca khong cch trc v chiu di xch, chn

, .

+ : H s nh hng ca bi trn, .

+ : H s xt n nh hng ca vic bi trn, .

+ : H s ti trng ng, va p nh nn .

+ : H s k n ch lm vic ca b truyn, soca = 2 nn

.

Thay cc s liu vo ta c:

22

Tra bng 5.5 T82 [1] vi iu kin v , ta

c:

- Bc xch: .

- ng knh cht: .

- Chiu di ng: .

- Cng sut cho php: .

3. Xc nh khong cch trc v s mt xch

Chn .

Ta c s mt xch:

Chn s mt xch l s chn: .

Tnh li khong cch trc:

(

(

)

(

)

)

(

(

)

(

)

)

xch khng qu trng th cn gim mt lng:

23

Do :

Chn .

- Tra bng 5.9 T85 [1] vi loi xch ng con ln, bc xch ta

c s ln va p cho php ca xch l: .

Vy s ln va p tha mn.

4. Kim nghim bn xch

Trong :

- : Ti trng ph hng. Tra bng 5.2 T71 [1] vi ta c

, khi lng a xch .

- : H s ti trng ng, chn tng ng vi ch lm vic

trung bnh v ti trng m my so vi ti trng danh ngha.

- Lc vng:

- Lc cng do lc ly tm sinh ra:

- Lc cng do trng lng nhnh xch gy ra:

24

( : h s ph thuc vng ca xch, nn chn )

- : H s an ton cho php, tra bng 5.10 T86 [1] vi v

ta c: .

Thay cc s liu vo ta c:

Vy xch m bo an ton.

5. Kim nghim rng a xch v bn tip xc

Trong :

- : Din tch chiu ca bn l, tra bng 5.12T87 [1] vi

.

- : H s xt n nh hng ca s rng a xch, tra bng T87 [1] theo

s rng , ta c .

- : H s phn b ti trng khng u gia cc dy, v ch c mt dy

xch nn .

- : Lc va p trn m dy xch

- : modun n hi

Thay s liu vo ta c:

25

Do vy tra bng 5.11 T86 ta chn vt liu lm a xch l thp 45 (ti ci thin),

vi cng b mt , c

Vy rng a xch m bo bn tip xc.

6. Xc nh thng s a xch

a) ng knh vng chia

(

)

( )

(

)

( )

b) ng knh nh rng

( (

)) ( (

))

( (

)) ( (

))

c) Bn knh y

( : tra bng 5.2 T78 [1])

d) ng knh chn rng

26

II.2.3 Tnh lc tc dng ln trc

( : h s k n trng lng ca xch, vi ta c =1,05)

II.2.4 Bng tng hp kt qu tnh ton b truyn xch

Thng s K hiu n v Kt qu tnh ton

Loi xch - Xch ng con ln

Vt liu C45 Ti ci thin

Bc xch

S dy xch -

S mt xch -

S rng a xch -

T s truyn thc t -

Sai lch t s truyn

ng knh a xch

ng knh nh rng

Bn knh y

27

ng knh chn rng

Khong cch trc

Lc tc dng ln trc

28

CHNG III: CHN KHP NI, TNH TRC,

THEN V LN

III.1 CHN KHP NI

- Chn kt cu ni trc: Ni trc vng n hi.

- Momen xon cn truyn gia hai trc:

Trong :

+ : h s ch lm vic, tra bng 16.1 T58 [2], chn .

+ : momen xon danh ngha ti trc ng c,

dmdD0

D

l1 l2

D3

d 1

l2

l

l1l3

h

Bl

L B1

dc

Hnh v minh ha ni trc vng n hi

29

- Theo bng 16.10a T68 [2], ta c th chn ni trc vng n hi c kch thc

c bn sau:

T,Nm

125 32 125 65 165 80 56 90 4 4600 5 42 30 28 32

- Kch thc c bn ca vng n hi: bng 16.10b T69 [2].

T,Nm

125 14 M10 20 62 34 15 28 1,5

- Chn vng n hi bng cao su.

+ Kim nghim bn ca vng n hi v cht: Theo iu kin sc bn

dp ca vng n hi (T69 [2] ):

Trong :

+ : H s ch lm vic, .

+ ng sut dp cho php ca vng n hi cao su:

Tha mn iu kin bn dp ca vng n hi cao su.

- Kim nghim v sc bn ca cht theo cng thc:

trong :

30

+

.

+ ng sut un cho php ca vt liu lm cht:

Tha mn iu kin bn un ca cht.

Nh vy, khp ni vng n hi c cc thng s nu trn l hp l.

III.2 THIT K TRC

III.2.1 Chn vt liu

Chn thp 45 thng ha, tra bng 6.1 T92 [1] c , ng

sut xon cho php , chn

III.2.2 Xc nh s b ng knh trc

1. S t lc chung cho c h thng

2. Tnh s b ng knh trc

X Y

ZF

F

FF

F

F

t

t

a

a

r

r1

1

1

2

2

2

(II)

(I) C

F

F

sin

cos

Fk

31

- ng knh trc c xc nh :

- ng knh trc I :

chn .

- ng knh trc II :

chn .

3. Xc nh khong cch gia cc gi v cc im t lc

Da vo ng knh trc II, tra bng 10.1 T189 [1] ta xc nh c b

rng ca ln, vi th .

- Chiu di may a xch l :

Chn .

- Chiu di may bnh rng tr :

+ Bnh rng tr I :

Chn .

+ Bnh rng tr II :

32

Chn .

- Chiu di may khp ni :

Chn .

33

- Khong cch t mt mt ca chi tit quay n thnh trong ca hp hoc khong

cch gia cc chi tit quay : .

- Khong cch t mt mt n thnh trong ca hp:

- Khong cch t mt mt ca chi tit quay n np :

- Chiu cao np v u bu lng:

Tra bng 10.4 T191[1] vi hp gim tc bnh rng tr 1 cp hnh 10.6, ta c:

III.2.3 Tnh ton thit k cm trc I

1. Tnh thit k trc I

Theo cng thc 10.1 ta c:

34

- Lc t khp ni tc dng ln trc:

- Tnh lc ti cc gi:

+ {

+ {

- Bng tng kt:

Thng s n v Gi tr

35

Chn ng knh cc on trc ca trc I:

2. Tnh then

36

Chn then c kch thc theo bng 9.1a T173 [1] :

ng knh

Kch thc tit din then

Chiu su rnh then Bn knh ln ca rnh

Trn trc Trn l

Nh nht Ln nht

Ta c chiu di may , chn chiu di then l: .

3. Tnh ln

- Tng lc dc trc : .

- Lc hng tm tc dng ln "0" v "1":

- Xt t s

, vi l h s xt n vng no quay, chn vng trong quay th

:

37

Vy, ta nn chn a cn theo bng P2.11 T261 [1], ta c cc thng

s sau :

K

hiu

III.2.4 Tnh ton thit k cm trc II

1. Tnh thit k trc

a. Tnh lc: (Tnh b truyn xch)

+ {

+ {

Bng tng hp kt qu

38

Thng s n v Gi tr

b. Tnh momen

+

{

+

{

+

{

c) Tnh ng knh cc on trc theo momen

39

- ng knh cc on trc :

Vi, : Momen un trong mt phng xOy v yOz ti cc tit din A, O, B.

: ng sut cho php ca thp ch trc,

- Ti tit din A:

- Ti tit din 0:

- Ti tit din B:

40

41

- Da vo kt cu ta chn

2. Tnh then

a. Chn kch thc then

Chn then c kch thc theo bng 9.1a T173 [1] :

Tit din

ng knh

Kch thc tit din then

Chiu su rnh then

Bn knh ln ca rnh

Trn trc

Trn l

Nh nht

Ln nht

A

B

Ta c :

- chiu di may bnh rng tr , chn chiu di then l:

.

- Chiu di may a xch , chn chiu di then l:

.

b. Kim nghim then chn theo bn dp v ct

- Theo bn dp:

Vi, : momen xon trn trc 2,

42

: ng sut dp cho php i vi mi then, trong trng hp lm bng

then chu va p nh theo bng 9.5 T178 [1] c .

Vy m bo bn dp.

- Theo bn ct:

Vi, : ng sut ct cho php vi thp 45 chu ti trng va p nh, ta chn

.

Vy m bo bn ct.

c. Kim nghim trc theo bn mi v tnh

- Kim nghim trc theo bn mi

Vi, : H s an ton cho php, .

v : H s an ton ch xt ring ng sut php v h s an ton ch

tnh ring ng sut tip ti tit din , ).

43

Trong :

- v : l gii hn mi v xon ng vi chu k i xng,

;

- : l bin v tr s trung bnh ca ng sut php v ng sut

tip ti tit din .

+ Vi tit din trn:

+ Vi tit din trc c 1 rnh then:

44

- V trc II quay 1 chiu, ng sut thay i theo chu k mch ng:

+ Vi tit din trn:

+ Vi tit din trc c 1 rnh then :

- v : H s k n nh hng ca tr s ng sut trung bnh n bn

mi, tra bng 10.7 T197 [1] .

- v : H s xc nh theo cng thc

45

(

)

(

)

Trong :

+ : h s tp trung ng sut theo trng thi b mt, ph thuc vo

phng php gia cng v nhn b mt, theo bng 10.8 T197 [1]. Chn tin

. Vi .

+ : H s tng bn b mt trc, ph thuc vo phng php tng bn b

mt v c tnh vt liu. Ta khng tng bn nn .

+ v : H s kch thc k n nh hng ca kch thc tit din

trc n gii hn mi, tr s cho trong bng 10.10 T198 [1].

Dng chu ti

+ v : H s tp trung ng sut thc t khi un v khi xon, tr s

ca chng ph thuc vo loi yu t gy tp trung ng sut:

* Ti tit din 0: . Tra bng 10.11

T198 [1] ta c

* Ti tit din A, B: Tra bng 10.12 T199 [1] ta c v

.

+ Vy ti tit din 0:

46

+ Vy ti tit din A:

+ Vy ti tit din B:

Do v nn m bo bn mi.

Vy c 3 tit din u m bo bn mi.

- Kim tra trc v bn tnh:

+ Ti tit din A:

47

+ Ti tit din B:

+ Ti tit din 0:

Vy ti 3 tit din u m bo.

3. Tnh ln

a. Chn loi v kch thc ln

- Tng lc dc trc : .

48

- Lc hng tm tc dng ln 0 v 1 l:

- Xt t s

vi V l h s xt n vng quay, ta chn vng trong quay.

Vy .

Ta chn a cn theo bng P2.11 T261 [1]

K

hiu

b. Kim nghim kh nng ti ng ca

- Theo bng 11.4 T216 [1] vi a cn:

- Lc dc trc do lc hng tm sinh ra trn cc l:

49

- Theo s b tr a cn nh hnh v trn ta c:

.

.

- Xt t s

vi V l h s xt n vng no quay, ta chn vng trong

quay. Vy .

- Theo bng 11.4 vi a cn ta c:

- Ti trng quy c:

Trong : l h s k n c tnh ca ti trng, (va p nh).

l h s k n nh hng ca nhit , .

50

Thay s liu vo ta c:

V nn ch ch cn tnh 1

- Kh nng ti trng ng:

Vi, l bc ca ng cong mi,

(i vi a cn).

l tui th tnh bng triu vng quay

Vy a cn m bo kh nng ti ng.

c. Tnh kim nghim kh nng ti tnh

Xt biu thc

Vy a cn m bo kh nng ti tnh.

51

CHNG IV: THIT K KT CU

IV.1 KCH THC C BN CA V HP GIM TC

V hp ca hp gim tc c nhim v m bo v tr tng i gia cc

chi tit v b phn my, tip nhn ti trng do cc chi tt lp trn v truyn ti,

ng du bi trn, bo v cc chi tit trnh bi bm.

Ch tiu c bn ca hp gim tc l cng cao v khi lng nh, v vy

vt liu nn dng l .

Cc kch thc ca hp gim tc

Tn gi Biu thc tnh ton Kt qu

Chiu dy: Thn hp ,

Np hp

Chn

Chn

Gn tng cng: Chiu dy Chiu cao dc

. Chn .

=40. Khong

Dc ng knh: Bulng nn Bulng cnh Bulng ghp bch np v

than Vt ghp lp Vt ghp lp ca thm du

Chn . . Chn . Chn

. Chn . Chn

Mt bch ghp np thn:

B dy bch thn hp B dy bch np hp B rng bch np hp

. Chn . Chn

Kch thc gi trc ng knh ngoi v tm

nh kch thc np

52

l vt B rng mt ghp bulng

cnh : Tm l bulng cnh :

. ( l khong cch t tm bulng n mp l) Chiu cao

. Chn . Chn . Chn Xc nh theo kt cu

Mt hp:

Chiu dy B rng mt hp

. Chn

Khe h gia cc chi tit: Gia bnh rng vi thnh trong hp Gia nh bnh rng ln vi y hp Gia mt bn cc bnh rng

. Chn

. Chn

S lng bulng nn

: Chiu di v rng ca hp

IV.2 KT CU NP , BNH RNG

IV.2.1 Np

Gm hai loi np kn v np thng c s dng vi mc ch l che

kn ng thi thng qua cch lp ghp gia np v c th iu chnh c

s n khp ca b truyn nh iu chnh mng, dy ca cc cn m. Kch

thc ca cc np c xc nh thng qua kch thc ca mt bch np trn

b hp gim tc v ng knh ngoi ca .

i vi trc I: ;

i vi trc II: ;

53

IV.2.2 Bnh rng

i vi bnh rng I: Lm lin trc

i vi bnh rng II:

54

Chn .

Chn .

Chn .

55

CHNG V: BI TRN, LP GHP V IU

CHNH N KHP

V.1 BI TRN

V.1.1 Bi trn hp gim tc

bi trn b truyn trong hp gim tc ta s dng du bi trn. Vic

chn loi du bi trn c tin hnh trn c s kt cu b truyn v c tnh

lm vic ca n. i vi b truyn c vn tc vng ca bnh rng l

v vt liu bnh rng l thp c th ta da

va bng 18.11 T100 [2], ta c nht ca du l . Da vo

nht chn, ta chn loi du bng 18.13 T101 [2] l loi du my bay

.

V.1.2 Bi trn ln

Vi vn tc vng ca bnh rng ngm trong du (Bnh rng 1) c

nn ta dng m bi trn.

i vi trc I: ; .

i vi trc II: ; .

56

V.2 BNG K KIU LP, SAI LCH GII HN V DUNG SAI LP

GHP

Trc V tr lp Kiu lp Sai lch gii hn Khe

h/ di

Bao B bao

I

Bnh rng

Trc

+21

0

+15

+2

+19

-15

Bc- Trc

+53

+20

+15

+2

+52

+5

Trc - ln +15

+2

V hp - ln +30

0

V hp Np

+30

0

-100

-146

+176

+100

Bc Trc

+53

+20

+15

+2

+51

+5

Ni trc Trc

+21

0

+15

+2

+19

-15

Bnh rng

Trc

+25

0

+18

+2

+23

-18

57

II

Trc - ln +18

+2

a xch Trc

+21

0

+18

+2

+19

-18

Bc Trc

+64

+25

+18

+2

+62

+7

V hp - ln +30

0

V hp Np

+30

0

-100

-146

+176

+100

V.3 IU CHNH LC N KHP

iu chnh lc n khp ca hp gim tc bnh rng tr ta chn chiu

rng bnh rng nh tang so vi chiu rng ca bnh rng ln.

58

TI LIU THAM KHO

[1]. Trnh Cht, L Vn Uyn Tnh ton thit k h dn ng c kh, Tp 1.

Nh xut bn Gio dc.

[2]. Trnh Cht, L Vn Uyn Tnh ton thit k h dn ng c kh, Tp 2.

Nh xut bn Gio dc.

[3]. Nguyn Trng Hip Chi tit my, Tp 1 2. Nh xut bn Gio dc. H

Ni 1994.

[4]. Ninh c Tn Dung sai v Lp ghp. Nh xut bn Gio dc. H Ni

2004.

Ch thch ti liu:

Vi, : l bng s liu hoc cng thc.

: Trang s.

[B]: Ti liu s.