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Crystal and Amorphous Structure in Materials By MRS AZDUWIN KHASRI

Crystal and Amorphous Structure in Materialsportal.unimap.edu.my/portal/page/portal30/Lecture...Principal Metallic Crystal Structures 90% of the metals have either Body Centered Cubic

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Page 1: Crystal and Amorphous Structure in Materialsportal.unimap.edu.my/portal/page/portal30/Lecture...Principal Metallic Crystal Structures 90% of the metals have either Body Centered Cubic

Crystal and

Amorphous Structure in Materials

By MRS AZDUWIN KHASRI

Page 2: Crystal and Amorphous Structure in Materialsportal.unimap.edu.my/portal/page/portal30/Lecture...Principal Metallic Crystal Structures 90% of the metals have either Body Centered Cubic

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2 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

The Space Lattice

Atoms, arranged in repetitive 3-Dimensional pattern, in long range order (LRO) referred to as crystalline solid /crystalline material.

Example: metals, alloys, and ceramic materials

Some materials whose atoms are not arranged in a long

range, periodic, and repeatable manner and possess only short range order (SRO).

Classified as amorphous/ noncrystalline Example: liquid water

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The Space Lattice and unit cell

Atomic arrangements in crystalline solids can be described by referring the atoms to the points of intersection of a network of lines in 3D which called as space lattice.

• Unit cell is that block of atoms which repeats itself to form space lattice.

Unit Cell

Space Lattice

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4 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Crystal Systems and Bravais

Lattice

Only seven different types of unit cells are necessary to create all point lattices. (fig 3.1 in text books)

According to Bravais (1811-1863) fourteen standard unit cells can describe all possible lattice networks (fig 3.2 in text books)

The four basic types of unit cells are

Simple

Body Centered

Face Centered

Base Centered

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5 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Types of Unit Cells 1. Cubic Unit Cell

a = b = c

α = β = γ = 900

2. Tetragonal

a =b ≠ c

α = β = γ = 900

Simple Body Centered Face centered

Simple Body Centered

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6 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Types of Unit Cells (Cont.) 3. Orthorhombic

a ≠ b ≠ c

α = β = γ = 900

4.Rhombohedral

a =b = c

α = β = γ ≠ 900

Simple Base Centered Face Centered Body Centered

Simple

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7 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Types of Unit Cells (Cont..) 5. Hexagonal

a ≠ b ≠ c

α = β = γ = 900

6. Monoclinic a ≠ b ≠ c

α = β = γ = 900

7.Triclinic a ≠ b ≠ c

α = β = γ = 900

Simple

Simple

Simple

Base Centered

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8 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Principal Metallic Crystal

Structures

90% of the metals have either Body Centered Cubic (BCC), Face Centered Cubic (FCC) or Hexagonal Close Packed (HCP) crystal structure.

FCC Structure HCP Structure BCC Structure

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9 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Simple Cubic Crystal Structure

• Please click on the image below to begin a short tutorial on simple cubic crystal structure

(this file opens in a new window and contains audio commentary)

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10 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Simple Cubic Crystal Structure

Animation

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11 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Body Centered Crystal Structure • Please click on the image below to begin a short tutorial on

body centered crystal structure

(this file opens in a new window and contains audio commentary)

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12 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Body Centered Structure-

Summary Animation

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13 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Body Centered Cubic (BCC)

Crystal Structure

Represented as one atom at each corner of cube and one at the center of cube.

Each atom has 8 nearest neighbors.

Therefore, coordination number is 8.

Atomic site unit cell Hard sphere unit cell Isolated unit cell

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14 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

BCC Crystal Structure (Cont..) Each unit cell has eight 1/8

atom at corners and 1

full atom at the center.

Therefore each unit cell has

Atoms contact each other at cube diagonal

(8x1/8 ) + 1 = 2 atoms

3

4RTherefore, a =

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15 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Atomic Packing Factor of BCC

Structure

Atomic Packing Factor = Volume of atoms in unit cell

Volume of unit cell

Vatoms = = 8.373R3

3

3

4

R= 12.32 R3

Therefore APF = 8.723 R3

12.32 R3 = 0.68

V unit cell = a3 =

32 R

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16 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Face centered crystal Structure

• Please click on the image below to begin a short tutorial on face centered crystal structure

(this file opens in a new window and contains audio commentary)

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17 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Face Centered Crystal Structure

Animation

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18 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Face Centered Cubic (FCC)

Crystal Structure

FCC structure is represented as one atom each at the corner of cube and at the center of each cube face.

Coordination number for FCC structure is 12

Atomic Packing Factor is 0.74

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19 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

FCC Crystal Structure (Cont.)

Each unit cell has eight 1/8

atom at corners and six ½

atoms at the center of six faces.

Therefore each unit cell has

Atoms contact each other

across cubic face diagonal

(8 x 1/8)+ (6 x ½) = 4 atoms

2

4RTherefore, lattice

constant a =

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20 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Cubic Crystal Structures

Summary Animation

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21 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Unit Cells - Example

Animation

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22 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Unit Cells - Example

Animation

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23 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Hexagonal Close-Packed

Structure

• The HCP structure is represented as an atom at each of 12 corners of a hexagonal prism, 2 atoms at top and bottom face and 3 atoms in between top and bottom face.

• Atoms attain higher APF by attaining HCP structure than simple hexagonal structure.

• The coordination number is 12, APF = 0.74.

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24 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

HCP Crystal Structure (Cont..)

Larger cell:

• Each HCP unit cell has

(2 x 6 x 1/6) + (2 x ½) + 3 = 6 atoms

Primitive Cell: • ‘1’ contribute 1/6 • ‘2’ contribute 1/12 • ‘3’ contribute 1 (4(1/6)+ 4(1/12)) + 1 = 2 atoms Ideal c/a ratio is 1.633.

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25 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Atom Positions in Cubic Unit Cells

• Cartesian coordinate system is use to locate atoms.

• In a cubic unit cell

y axis is the direction to the right.

x axis is the direction coming out of the paper.

z axis is the direction towards top.

Negative directions are to the opposite of positive directions.

• Atom positions are

located using unit

distances along the

axes.

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26 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Directions in Cubic Unit Cells

• In cubic crystals, Direction Indices are vector components of directions resolved along each axes, resolved to smallest integers.

• Direction indices are position coordinates of unit cell where the direction vector emerges from cell surface, converted to integers.

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27 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Procedure to Find Direction Indices

Produce the direction vector till it emerges from surface of cubic cell

Determine the coordinates of point of emergence and origin

Subtract coordinates of point of Emergence by that of origin

Are all are integers?

Convert them to smallest possible

integer by multiplying by an integer. Are any of the direction

vectors negative?

Represent the indices in a square bracket without comas with a over negative index (Eg: [121])

Represent the indices in a square bracket without comas (Eg: [212] )

YES

NO

YES NO

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Procedure to Find Direction Indices

(1,1/2,1) - (0,0,0)

= (1,1/2,1)

2 x (1,1/2,1) = (2,1,2)

The direction indices are [212]

(0,0,0)

(1,1/2,1)

z

x

y

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29 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Miller Indices • Miller Indices are are used to refer to specific lattice planes

of atoms.

• Miller indices of a crystal plane are defined as the reciprocals of the fractional intercepts (with fractions cleared) that the plane makes with the crystallographic x, y and z axes of three nonparallel edges of the cubic unit cell.

z

x

y

Miller Indices =(111)

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30 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Miller Indices - Procedure

Choose a plane that does not pass through origin

Determine the x,y and z intercepts

of the plane

Find the reciprocals of the intercepts

Fractions? Clear fractions by multiplying by an integer

to determine smallest set of whole numbers

Enclose in parenthesis (hkl)where h,k,l are miller indicesof cubic crystal plane

forx,y and z axes. Eg: (111)

Place a ‘bar’ over the Negative indices

Yes

Page 31: Crystal and Amorphous Structure in Materialsportal.unimap.edu.my/portal/page/portal30/Lecture...Principal Metallic Crystal Structures 90% of the metals have either Body Centered Cubic

Miller Indices - Examples

• Intercepts of the plane at x,y & z axes are 1, ∞ and ∞

• Taking reciprocals we get (1,0,0).

• Miller indices are (100).

z

x

y

(100)

Intercepts are 1/3, 2/3 & 1. taking reciprocals we get (3, 3/2, 1). Multiplying by 2 to clear fractions, we get (6,3,2). Miller indices are (632).

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Miller Indices - Examples • Plot the plane (101)

• Taking reciprocals of the indices we get (1 ∞ 1).

• The intercepts of the plane are x=1, y= ∞ (parallel to y) and z=1.

• Plot the plane (2 2 1) • Taking reciprocals of the indices

we get (1/2 1/2 1). • The intercepts of the plane are

x=1/2, y= 1/2 and z=1.

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33 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Miller Indices - Example

• Plot the plane

The reciprocals are (1,-1, ∞)

The intercepts are x=1, y=-1 and z= ∞ (parallel to z axis)

To show this plane in a

single unit cell, the

origin is moved along

the positive direction

of y axis by 1 unit. x

y

z (110)

)011(

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34 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Miller Indices – Important

Relationship

• If sets of equivalent lattice planes are related by the symmetry of the crystal system –> planes of family/form

Eg: (100),(010) and (001) are designated collectively as a family or form by the notation {100}

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35 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Cubic crystal Planes, Tutorial

• Please click on the image below to begin a short tutorial on cubic crystal planes.

(this file opens in a new window and contains audio commentary)

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36 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Planes and Directions in

Hexagonal Unit Cells • Four indices are used (hkil) called as Miller-Bravais indices.

• Four axes are used (a1, a2, a3 and c).

• Reciprocal of the intercepts that a crystal plane makes with the a1, a2, a3 and c axes give the h,k,I and l indices respectively.

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37 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Hexagonal Unit Cell - Examples

• Basal Planes:- Intercepts a1 = ∞

a2 = ∞

a3 = ∞

c = 1

(hkli) = (0001)

• Prism Planes :- For plane ABCD,

Intercepts a1 = 1

a2 = ∞

a3 = -1

c = ∞

(hkli) =

)0110(

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38 Foundations of Materials Science and Engineering, 5th Edn. in SI units Smith and Hashemi

Comparison of FCC and HCP

crystals • Both FCC and HCP are close packed and have APF 0.74.

• FCC crystal is close packed in (111) plane while HCP is close packed in (0001) plane.

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ASSIGNMENT 2

DATELINE :THURSDAY (2 OcT 2014)

Before 5 pm

At haz melati

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THE END

THANK YOU