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หลักการเบื้องตนของระบบ
อัดอากาศ
Proportional relationship between pressure, temperature and volume: still valid:
Compressed air is ...... compressed atmospheric air... a mixture of gases... compressible... an energy carrier
userair main
air treatmentAir centre
Power stationgrid system
transformeruserWhat is compressed
air?
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
...is generated by the weightof the atmosphere. It is dependent on the DENSITYof the air and the height:
The normal atmospheric pressure at sea level is 1.013 bar (760 mmHg (Torr))
Atmospheric pressure...
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
atmospheric pressure
vacuum100%
0%
pamb
Absolute pressure ...
... is the pressure measuredfrom absolute zero.It is used for all theoreticalapproaches and is required invacuum and blower techniques.
Gauge pressure ...
... is the practical reference pressureand is based on atmospheric pressure.
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
absolute pressure
gauge pressurevacuum
(g) (g) (g) (g)
Pg
Physical lawsCOMPRESSED AIR is atmospheric air under pressure. That means energy is stored in the air. When the compressed air expands againthis energy is released as WORK.
pressure (energy)
EXPANSION
WORK
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
Generally:Equivalents
105 Pa = 1 bar
1 MPa = 10 bar
Gauge pressure1 bar = 14,5 psi(g)
1 hPa = 0,001 bar
1 bar = 10197 mmWC
1 bar = 750,062 Torr
Dimensions:
A = 1 m2
1 Pascal (Pa) =1 Newton (N)
1 m² (A)
1 N
Pressure (p) = Force (F)Area (A)
Definition of pressures
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
Basic units m = Meter
s = Second
K = Kelvin
kg = Kilogram
A = Ampere
mol = Molar mass
Derived units N = Newton
bar = Bar
J = Joule
C = Celsius
Pa = Pascal
Ω = Ohm
W = Watt
Hz = Hertz
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
If the volume is reduced under constant temperature,the pressure increases.
Heat dissipation
Natural lawsIsotherms (constant temperature)
p0 x V0 = p1 x V1 = constant
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
Heat dissipation
V
p
p1
p0
V1 V0dV
T0 = T1
1
0
Isotherms (constant temperature)
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
Gas law relating to a closed system:
p0 x V0 p1 x V1
T0 T1= = R = constant
p = pressure (bar (absolute))V = volume (m3)T = temperature (K)R = special gas constants
e.g. R = 28.96 = 289.6
for dry air
bar·m³K
Jkg·K
Gas equation
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
nitrogen78%
oxygen21%
other gasses1%
Components of air
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
7 m³atmospheric
air volume
ambient air pressure1 bar (a)
working pressure7 bar (a) = 6 bar (g)
1 working m³
Volume
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
The volume of atmospheric air decreases at an inverse ratio to the respective absolute pressures (at constant temperature,without taking humidity into account)
Ambient air pressure p0, V0
Working pressure7 bar (a)= 6 bar (g)
Expansion:
Workingpressurep1, V1
Volume
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
pp
Flow velocity in air lines
V = flow volumev = velocityA = pipe sectional area
V = A1 x v1 = A2 x v2 • A1
A2
v2
v1=
•
A1v1
A2v2
valid is:
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
Flow profilepipe wall
border layer
flow velocity
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
Flow typesWe differentiate between:laminar (even) and turbulent (swirling) flow
1. Training Course in Compressed Air Technology1. Training Course in Compressed Air Technology
อุปกรณหลักในระบบอัดอากาศ หลักการใชงาน
และการบํารุงรักษา 1.Air Compressors
Compressed Air Generation
ejector centrifugal-turbo
axial-turbo
vane liquidring
screw rotaryblower
labyrinth diaphragm
rotary reciprocating
trunk crosshead free-piston
single-rotor double-rotor
helical
displacementcompressor
dynamic compressor
Compressor types
Compressed Air Generation
Screw compressors
fluid with heat of compression
thermostaticvalve
fluid filter
hot fluid
compressedair
fluid-air mixture
cooled fluid
Construction:
Compressed Air Generation
1st stage,centrifugal
2nd stage, separatorelementa) coarse filter
layerb) fine filter
layer
Fluid separation:
อุปกรณหลักในระบบอัดอากาศ หลักการใชงาน
และการบํารุงรักษา
2. Air Dryer
1. Air inlet2. Air to air heat exchanger3. Refrigerant to air heat exchanger4. Refrigerant compressor5. Condensate separation,
automatic condensate drain6. Compressed air outlet
Refrigeration drying
Air Treatment
อุปกรณหลักในระบบอัดอากาศ หลักการใชงาน
และการบํารุงรักษา
3. Filter
Streamed from the inside to the outside.Used as a liquid filter
Principle the same as all deep-bed filters
Prefilter
used as a coarse filter for 100% saturated compressed air (or for water vapour components in the liquid phase)
Air Treatment
Streamed from the inside to the outside. Used as a deep-bed filter
Microfilter
0.01 to 0.001 micronfor liquids(aerosols) and particles
Air Treatment
contaminated air filter medium (deep-bed filter) technically oil-free clean air
Direct interception
Impact
Diffusion /Coalescence
How does the microfilter work?Air Treatment
อุปกรณหลักในระบบอัดอากาศ หลักการใชงาน
และการบํารุงรักษา
4. Drain
condensate collection
cyclonicair movement
deflector
air outletair inletCondensate separation
To ensure sufficient separation,liquids and heavy particles are
subjected to centrifugal forces athigh rates of flow.
The degree of separation is around 95% at 6 bar, 20 °C and the nominalvolumetric flow rate. The pressure
drop is approximately 0.05 bar .
Air Treatment
compressedair outlet
pipework falling atapprox. 2 ‰condensate
collector
condensatedrain
Condensate separation
The compressed air discharged from the aftercooler of a compressor is normally
saturated with water vapour to 100%. If the temperature of the compressed air
falls, the water vapour condenses.
A coarse separation of the condensate can be achieved if the pipework and the compressed air outlets are installed as
shown in the illustration.
Air Treatment
• used directly at the takeoff point• mechanical filter
• rotating movement• deflection plate
• condensate drain (important!)
Condensate separationFine filter
Air Treatment
Drainage occurs only when sufficient condensate has collected
No compressed air blowoff
Regular maintenance required
condensate inlet
air back flow line connection
manual valvecondensate
outlet
Condensate drains: float type
Air Treatment
• automatic and regular drainage• 230 V / 50 Hz
• interval 1.5 to 30 min• opening period 0.4 to 10 sec
• condensate can be directed into a disposal canister
1
3
2
1 ball valve2 dirt trap
3 solenoid valve withintegrated or external
timer
Condensate drains: solenoid valve, timer controlled
Air Treatment
Capacitive level sensingAutomatic pressure matching
Self-monitoringVolt-free alarm contact
Condensate drains: Electronic level-sensingtype (Eco-Drain)
2 collection chamber9 discharge pipe6 level sensor8 valve seat
1 condensate inlet 4 solenoid valve2 collection chamber5 valve
diaphragm3 pressure balance line
Air Treatment
การประหยัดพลงังานในระบบอัด
อากาศ
1. การออกแบบระบบ และ เลือกใชงาน
Parallel Line Diagram
Series Lind Diagram
Optimal design and installation
การประหยัดพลังงานในระบบอัดอากาศ
2. การหาปริมาณลมที่ตองการ ตามชนิดของโหลด
Ø
Air consumption chart for pneumatic cylinders
Working pressure in bar
Air consumption per cylinder stroke in litres/cm
Table air consumption for pneumatic cylindersTable air consumption for pneumatic cylinders
Air consumption of pneumatic equipmentexamples:
Paint spray gunswater colours andthin cellulos paintø 0.5 mmNitro and thinsynthetic resinsø 1.5 mmø 1.8 mm
Thick nitro andnormal syntheticresins ø 2.0 mm
ø
Lime-water colour,compound filling guns ø 3.0 mmBlow gunø 1 / 1.5 / 2 mmSpray gun
Equipment, type Working pressure
bar (g)Air consumptionl/min m³/h
Nozzle
flat round flat round
451.0
2.53.5
4.5
5.0
6.03.0
150215
270
320
60/135/240 4/8/14
35
110160
180
230
3
913
16
19
2
710
11
14
65 4
Example: spray gun
Working periods of the toolper hour
Standstill periods of the toolper hour
Overall working period per hour: 25 min
overall working period 25 minUtilisation factor = =
reference period 60 min
Utilisation factor of the spray gun is approx. 40%
Determining the utilisation factor
3. Sizing a compressor3. Sizing a compressor
10 20 30 40 50 60 70 80 90 100 150 20000
00
500 1000 1500 2000 2500 3000 3500 4000
1
2
3
4
5
6
7
2 3 4 5 6
8
10
Nozzle diameter (mm)
Air volume
l/min
m³/h
Gau
ge p
ress
ure
(bar
)
3. Sizing a compressor3. Sizing a compressor
Air consumption of free-jet nozzles
Nozzlediameter
( mm)
0.51.01.52.03.04.05.06.08.0
10.0
2
83055100225
410 330640 510900 7201250 10001950 1570
4
124590
170375
700 5501050 8501520 12202700 21504230 3400
6
1565125240520
980 7801500 12002120 17003770 30005900 4700
8
2085160310675
12501870275048007500
10
2510520038082515002300335058509200
Gauge working pressure ( bar )
Air consumption of nozzles (l / min)
The lower values are valid for sandblasting!
3. Sizing a compressor3. Sizing a compressor
The optimum duty-cycleof a reciprocating compressor-is 70 %.The required air delivery is:
334+33+50+66 l/min0.7
The required reciprocating compressor must have a freeair delivery of at least 690 l/minat a gauge pressure of 8 bar.
The model selected is:K 1200-500, max. gauge working pressure 10 bar, 865 l/min free air delivery at 8 bar gauge pressure and7.5 kW rated motor power.
Total demand = 150 + 80 + 24 + 80 = 334 l/minThe following must be addedfor leakagesfor errorsas a reserve
+ 10 % = 33 l/min+ 15 % = 50 l/min+ 20 % = 66 l/min
Sizing a reciprocal compressor
7. Sizing a compressor
= 690 l/min
Air demandWorkingpressure (g)
NumberUtilisationfactor
Effectiveair demand
Paint spray-gunØ 1.5 mmflat jet
Paint spray-gunØ 3 mmflat jet
Blow-gunØ 2 mm
Screw-driver
150 l/min 320 l/min 240 l/min 400 l/min
2.5 bar 5 bar 6 bar 6 bar
2 1 1 1
50 % 25 % 10 % 20 %2 x 150 x 0.5
150 l/min320 x 0.2580 l/min
240 x 0.124 l/min
400 x 0.280 l/min
Workingspecification
Total demand = 150 + 80 + 24 + 80 = 334 l/minThe following must be added:for leakagesfor errorsas a reserve
+ 10 % = 33 l/min+ 15 % = 50 l/min+ 20 % = 66 l/min
The optimum duty cycle of ascrew compressor is 100 %.The required air delivery is:
The required screw compressor must have a free air delivery of at least 483 l/min at a gaugepressure of 7.5 bar.
The model selected is:Aircenter 6 (SX6-TA5-280), working pressure max. 7.5 bar,583 l/min free air deliveryat 7.5 bar gauge pressure and4 kW rated motor power.
Sizing a screw compressor
( 334+33+50+66 l/min )
7. Sizing a compressor
= 483 l/min
Air demandWorkingpressure (g)
NumberUtilisationfactor
Effectiveair demand
Paint spray-gunØ 1.5 mmflat jet
Paint spray-gunØ 3 mmflat jet
Blow-gunØ 2 mm
Screw-driver
150 l/min 320 l/min 240 l/min 400 l/min
2.5 bar 5 bar 6 bar 6 bar
2 1 1 1
50 % 25 % 10 % 20 %2 x 150 x 0.5
150 l/min320 x 0.2580 l/min
240 x 0.124 l/min
400 x 0.280 l/min
Workingspecification
ขอสรุปสําหรับการปรับปรุงระบบลมอดัเพื่อการลดพลังงาน
ปรับปรุงโดยไมมีการลงทุน
1. การลดแรงดันลมจากตนทาง(หองปมลม)
2. การจัดใหปมลมทาํงานใหเหมาะสมกับปรมิาณความตองการของเครื่องจักร3. การลดแรงดันลมเทาที่เครื่องจักรตองการดวย regulator4. การเปลี่ยนอะไหลสิ้นเปลอืงในระยะกําหนดเวลาใชงาน 5. การเลือก main line filter สําหรับคุณภาพลมอัดตามที่เครื่องจักร
ตองการ 6. การควบคุมการใชลมใหเหมาะสม เชน ใชลมเปาตัวทําความสะอาด,ใชลมเปา
ตัวแทนพัดลม และใชลมเปาชิ้นงานแทนระบบสปรงิหรือตัวเกี่ยวออก7. การตรวจเช็คประสิทธิภาพของปมลมอยางสม่ําเสมอทุกป8. เลือก mode การควบคุมปมลมใหเหมาะสมกับลักษณะของ load
(Dual control,Quandro control,Modulation control)
ปรับปรุงโดยมกีารลงทุน
1. เปลี่ยนปมลมทีม่ีประสิทธภิาพต่ําดวยปมลมทีม่ีประสิทธภิาพสูงกวา
2. ใชระบบควบคุมกลางในกรณีที่มีปมลมหลายตัว
3. ใชปมลมทีส่ามารถควบคุมความเร็วรอบไดในกรณ ีload demand มีการ
เปลี่ยนแปลงมากๆ หรือแบงปมลมสําหรับ peak load เปนหลายตัวแทนตัวใหญ ตัวเดียว
4. เปลี่ยนชุด auto-drain เปนแบบที่ไมมีการสูญสียลมขณะ drain น้ํา
5. ซื้อลมในราคา fix unit จากผูผลิตลมเพื่อจําหนาย
6. การตรวจหาและลดปรมิาณลมรัว่
7. การตรวจสอบขนาดทอทางเดินลมไมใหมี pressure drop สูงเกินมาตรฐาน
8. การปรบัปรงุระบบระบายความรอนในหองปมลม
9. การเลือกชนิดของair dryer ใหเหมาะสมกับ process
10. การนําลมระบายความรอนจากปมลมไปใชใหเกิดประโยชน
11. ใชขนาดถงัลมใหเหมาะสมกับขนาดของปมลม และปรมิาณการใชลมของโรงงาน
Minimum diameters of pipes
FADm3/min
working pressure 7.5 bar (g)
length of pipelineup to 50 m up to 100 m up to 200 m over 200 m
see straight-line graph
up to 0.5up to 1,0up to 1.5up to 2.0up to 3.0up to 5.0
3/4"1"1"
1 1/4"1 1/4"1 1/2"
1"1"
1 1/4"1 1/2"1 1/2"
2"
1 1/4"1 1/4"1 1/2”
2"2"
up to 7.5 1 1/2" 2 1/2" 2 1/2"
The Air MainThe Air Main
2"
Minimum diameters of pipes
FADm3/min
working pressure 7.5 bar (g)
length of pipelineup to 50 m up to 100 m up to 200 m over 200 m
see straight-line graph
up to 12.5up to 15,0up to 17.5up to 20.0up to 25.0up to 30.0
2 1/2"2 1/2"2 1/2"
3"3"3"
2 1/2"2 1/2"
3"3"
DN100DN100
3"3"
DN100DN100DN100DN100
up to 40.0 DN100 DN100 DN 125
The Air MainThe Air Main
Straight-line graphfor determining insidepipe diameter (steps 1 to 8)
1
2
3
4
5
67 8
Pipe length in m
Free air deliverym³/h - m³/min
Insidepipe dia. (mm)
System-pressurebar (g)
Pressure lossesbar
The Air MainThe Air Main
Trace leaksTrace leaks• soap connections
• locate source of noise• leakage spray
• ultra-sound device
Example:hole diameter: 3 mm
air loss: 0.5 m3/min (6 bar gauge)0.5 m3/min x 60 min/h = 30 m3/h
30 m3/h x 8000 h/year = 240,000 m3/year
240,000 m3/year x 0.33 Baht/m3 = 79,200 Baht/year
The Air MainThe Air Main
Max. pressure= required working pressure of the users+ sum of all losses (air main, air treatment devices)+ switching differential for compressor control
switching differential:ON = 7 bar (g)OFF = 7.5 bar (g)
screw compressordryer
Determining the highest pressure of an air centre
Pressure Setting.
p (bar)
Switching points offour equally sized units.All units can beinterchanged via the MAC 41
p too low alarm
Unit 1
2
3
4
Switching Points (first example)Cascade control
pmax
pmin
idlestop
full load
20406080
100
mot
or p
ower
in %
time
pres
sure
A B C D E
t1
t2
Dual ControlFull load - idle - stop operating mode
Types of compressor controlTypes of compressor control
Quadro ControlFull load - idle - stop with automaticselection of optimum operating mode
t5 t6
A B C D E F GH I K L M N OP Q R S T U V W
t3
t3
t8
t1
t2
t1
t4
t3
t1
t7
pmax
pmin
idlestop
full load
20406080
100
mot
or p
ower
in %
time
pres
sure
Types of compressor controlTypes of compressor control
Dual Control (CP)Constant pressure, continuous delivery modeusing a proportional controller
A B C D E F G H I K L
t1
t3t2 t1
pR
pmax
pmin
idlestop
full load
20406080
100
mot
or p
ower
in %
time
pres
sure
Types of compressor controlTypes of compressor control
inlet temperatureT1
inlet pressure p1
inlet humidity Frel1
dischargetemperature T2
dischargepressure p2
discharge volume V2
Power consumption in kW
Measurement of free air delivery
Package
Economic Appraisal
internal motor losses,accounted for in themotor efficiency
Motor shaft output power:mechanical forcein kW that the motor transmits into the shaft
Drive losses of thecooling fan Transmission losses of
belts/gearing
Compressor shaft power:required mechanicalforce in kW at thedrive shaft Rated motor power:
mechanical shaft powerin kW that the motor cansupply at 100% load.Quoted on the nameplate
Overallelectricalpowerconsumption
Electrical power consumption offan motor, if separate fan is fitted
0 0 0
Flow of force and power
kWh
Economic Appraisal
5000
5,5
6,0
6,5
airend 1
7,0
1000 1500 2000 2500 3000
kW/min m³
spec. power
point of optimal utilisation
speedmin-1
FAD in m³/min9 14 19 24
Specific power of a screw compressor airendat 7 bar related to speed and free air delivery (FAD)
Economic Appraisal
AS 36 / 7.5 bar ( g ) ( 22 KW ) = 3.68 CU.m / min ( 3680l / min )
Full load Input power = 25.8 KWUnload = 6.9 KW
Load Hour----------------- = Duty Cycle in %Service Hour
Example: Example:
การทํางานของโรงงาน 12 ชม. / วัน = 60 % Load
Power Full Load = 60 X 12 X 25.8 X 3.5 = 650 บาท
100
Power Unload = (100-60) X 12 X 6.9 X 3.5 = 115 บาท
100
Total = 765 บาท ตอวัน
ปริมาณลมที่ใชตอวัน = 60 X 12 X 60 X 3.68 = 1589 CU . m.
100
สรุปคากระแสไฟตอ CU . m . = 765 = 0.48 บาท
1589
ตัวอยาง การคํานวณหาคาพลังงานไฟฟาของปมลม
ปริมาณลมรั่ว = 500 l / min
ปริมาณลมรั่วตอวัน = 12 X 500 X 60 = 360 CU. m.
1000
เงินที่ตองจายคาไฟสําหรับลมรั่วตอวัน = 360 X 0.48 = 172 บาท
ถาคิดตอป = 172 X 26 X 12
= 53900 บาท / ป