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VOLUME 87, NUMBER 24 PHYSICAL REVIEW LETTERS 10 DECEMBER 2001 Editor’s Note: Issues similar to those made in the following two Comments were also raised in a paper by N. Garcia and M. Nieto-Vesperinas, Madrid, Spain. Comment on “Negative Refraction Makes a Perfect Lens” The very high spatial frequencies of an optical image are carried by waves with a wave vector larger than vc, i.e., highly damped, evanescent waves. These waves do not contribute to the far field; therefore, one is restricted to near-field optics for image formation below the diffraction limit. To remedy the damping of evanescent waves Pendry [1] has recently proposed to employ negative refractive in- dex materials to create a perfect lens giving rise to sub- wavelength resolution in the far field. As shown by the author a slab of such a material with simultaneously neg- ative dielectric constant e and negative magnetic perme- ability m [2] has a transmission coefficient for evanescent waves that is exponentially large; i.e., it counterbalances the damping in the surrounding normal medium. The pur- pose of this Comment is to show that Pendry uses incorrect arguments to arrive at his, otherwise, correct conclusions. The flow of the argumentation in Ref. [1] is as follows: Consider a wave carrying high lateral (in the x , y direc- tion) spatial information. In free space such a wave de- cays exponentially in the positive z direction; its wave vector k z i a is imaginary, with a. 0. On the basis of causality Pendry argues that the wave vector k 0 z i a 0 of the evanescent wave inside the negative-index material has the same sign. Consequently, the electric field is ex- ponentially decaying in the positive z direction both inside and outside the slab. This line of argument leads to the following inconsis- tencies: First, the causality argument is completely at odds with the result of Veselago [2] that the component of the wave vector perpendicular to the interface changes sign, when going from left-handed to right-handed material or vice versa. Second, the author shows that the ampli- tude transmission coefficient of the slab is exponentially increased [Eq. (21) of Ref. [1] ], completely inconsistent with the exponential decay of the electric field component across the slab. Third, the summation over the various terms in the geometrical series does not converge, since for m 21 and k 0 z k z the transmission Fresnel coef- ficient as well as the reflection Fresnel coefficient is infi- nitely large. To avoid the aforementioned issues it suffices to realize that the problem in essence is two dimensional, so that the Maxwell equations split up into two separate sets (see, e.g., Ref. [3]): a set for E polarization and a set for H polariza- tion. Consider the set of E polarization (s-polarized light) with the electric field vector pointing along the y axis. Since there is no spatial dependence on y, the continuity of H x is the same as continuity of E y m≠z . Since m is changing sign at every interface and downstream from the slab we must have an exponentially decaying amplitude, it follows that inside the slab the amplitude of the wave must exponentially increase and upstream of the slab it must exponentially decrease, implying that k 0 z 2k z for both propagating and evanescent waves. Applying the conti- nuity of E y as well as of E y m≠z , the amplitude of the electric field at the exit face of the slab can be expressed in the amplitude at the entrance face of the slab. One obtains an amplitude increase of a factor exp2ik z d. Not only the overall transmission coefficient has increased but also the amplitude of the electric field vector, as it should. Note that there is no backreflected wave at the faces of the slab since the amplitude Fresnel coefficients for reflection are equal to zero and those for transmission equal to unity. The consequence of this is that for a macroscopic thick- ness of the slab and atomic size point sources the ampli- tude of the electric field can easily reach values beyond the breakdown of any material as the exponent 2ik z d can easily reach a value of the order of 10 8 . This surprising result is not at all evident from Ref. [1]. With the kind of evanescent waves described above, which are at each point in space either exponentially de- creasing or increasing, there is no energy transport. These solutions are clearly not applicable when a source is turned on, i.e., when the fields are building up, or in the presence of absorbers, e.g., a detector in the focal plane. To find the proper solutions for those practical situations, includ- ing the buildup of the field to unphysically large values at the exit face of the slab, is a far from trivial task. For instance, the total electrical field at each point in space in- tegrated over all possible wave vectors must be calculated in order to find the energy density. For the solutions as given in Ref. [1] this integral diverges at locations in the slab downstream from the image point for sources with sharp boundaries. G. W. ’t Hooft Philips Research Laboratories 5656 AA Eindhoven, The Netherlands Huygens Laboratory, University Leiden 2300 RA Leiden, The Netherlands Received 24 November 2000; published 20 November 2001 DOI: 10.1103/PhysRevLett.87.249701 PACS numbers: 78.20.Ci, 42.30.Wb, 73.20.Mf, 78.66.Bz [1] J.B. Pendry, Phys. Rev. Lett. 85, 3966 (2000). [2] V.G. Veselago, Sov. Phys. Usp. 10, 509 (1968). [3] Max Born and Emil Wolf, Principles of Optics (Pergamon Press, Oxford, 1999), Sec. 11.4.1. 249701-1 0031-9007 01 87(24) 249701(1)$15.00 © 2001 The American Physical Society 249701-1

Comment on “Negative Refraction Makes a Perfect Lens”

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Page 1: Comment on “Negative Refraction Makes a Perfect Lens”

VOLUME 87, NUMBER 24 P H Y S I C A L R E V I E W L E T T E R S 10 DECEMBER 2001

Editor’s Note: Issues similar to those made in the following two Comments were also raised in a paper by N. Garcia andM. Nieto-Vesperinas, Madrid, Spain.

Comment on “Negative Refraction Makesa Perfect Lens”

The very high spatial frequencies of an optical imageare carried by waves with a wave vector larger than v�c,i.e., highly damped, evanescent waves. These waves donot contribute to the far field; therefore, one is restricted tonear-field optics for image formation below the diffractionlimit. To remedy the damping of evanescent waves Pendry[1] has recently proposed to employ negative refractive in-dex materials to create a perfect lens giving rise to sub-wavelength resolution in the far field. As shown by theauthor a slab of such a material with simultaneously neg-ative dielectric constant e and negative magnetic perme-ability m [2] has a transmission coefficient for evanescentwaves that is exponentially large; i.e., it counterbalancesthe damping in the surrounding normal medium. The pur-pose of this Comment is to show that Pendry uses incorrectarguments to arrive at his, otherwise, correct conclusions.

The flow of the argumentation in Ref. [1] is as follows:Consider a wave carrying high lateral (in the x, y direc-tion) spatial information. In free space such a wave de-cays exponentially in the positive z direction; its wavevector kz � ia is imaginary, with a . 0. On the basisof causality Pendry argues that the wave vector k0

z � ia0

of the evanescent wave inside the negative-index materialhas the same sign. Consequently, the electric field is ex-ponentially decaying in the positive z direction both insideand outside the slab.

This line of argument leads to the following inconsis-tencies: First, the causality argument is completely at oddswith the result of Veselago [2] that the component of thewave vector perpendicular to the interface changes sign,when going from left-handed to right-handed material orvice versa. Second, the author shows that the ampli-tude transmission coefficient of the slab is exponentiallyincreased [Eq. (21) of Ref. [1] ], completely inconsistentwith the exponential decay of the electric field componentacross the slab. Third, the summation over the variousterms in the geometrical series does not converge, sincefor m � 21 and k0

z � kz the transmission Fresnel coef-ficient as well as the reflection Fresnel coefficient is infi-nitely large.

To avoid the aforementioned issues it suffices to realizethat the problem in essence is two dimensional, so that theMaxwell equations split up into two separate sets (see, e.g.,Ref. [3]): a set for E polarization and a set for H polariza-tion. Consider the set of E polarization (s-polarized light)with the electric field vector pointing along the y axis.Since there is no spatial dependence on y, the continuityof Hx is the same as continuity of ≠Ey�m≠z. Since m is

249701-1 0031-9007�01�87(24)�249701(1)$15.00

changing sign at every interface and downstream from theslab we must have an exponentially decaying amplitude, itfollows that inside the slab the amplitude of the wave mustexponentially increase and upstream of the slab it mustexponentially decrease, implying that k0

z � 2kz for bothpropagating and evanescent waves. Applying the conti-nuity of Ey as well as of ≠Ey�m≠z, the amplitude of theelectric field at the exit face of the slab can be expressed inthe amplitude at the entrance face of the slab. One obtainsan amplitude increase of a factor exp�2ikzd�. Not onlythe overall transmission coefficient has increased but alsothe amplitude of the electric field vector, as it should. Notethat there is no backreflected wave at the faces of the slabsince the amplitude Fresnel coefficients for reflection areequal to zero and those for transmission equal to unity.

The consequence of this is that for a macroscopic thick-ness of the slab and atomic size point sources the ampli-tude of the electric field can easily reach values beyondthe breakdown of any material as the exponent 2ikzd caneasily reach a value of the order of 108. This surprisingresult is not at all evident from Ref. [1].

With the kind of evanescent waves described above,which are at each point in space either exponentially de-creasing or increasing, there is no energy transport. Thesesolutions are clearly not applicable when a source is turnedon, i.e., when the fields are building up, or in the presenceof absorbers, e.g., a detector in the focal plane. To findthe proper solutions for those practical situations, includ-ing the buildup of the field to unphysically large valuesat the exit face of the slab, is a far from trivial task. Forinstance, the total electrical field at each point in space in-tegrated over all possible wave vectors must be calculatedin order to find the energy density. For the solutions asgiven in Ref. [1] this integral diverges at locations in theslab downstream from the image point for sources withsharp boundaries.

G. W. ’t HooftPhilips Research Laboratories5656 AA Eindhoven, The NetherlandsHuygens Laboratory, University Leiden2300 RA Leiden, The Netherlands

Received 24 November 2000; published 20 November 2001DOI: 10.1103/PhysRevLett.87.249701PACS numbers: 78.20.Ci, 42.30.Wb, 73.20.Mf, 78.66.Bz

[1] J. B. Pendry, Phys. Rev. Lett. 85, 3966 (2000).[2] V. G. Veselago, Sov. Phys. Usp. 10, 509 (1968).[3] Max Born and Emil Wolf, Principles of Optics (Pergamon

Press, Oxford, 1999), Sec. 11.4.1.

© 2001 The American Physical Society 249701-1