Upload
others
View
23
Download
3
Embed Size (px)
Citation preview
Corporate Office: 10th Floor, Melange Tower; No.80-84, Pathrika Nagar; Hitech-City, Madhapur, Hyderabad. Telangana - 500 081.
: 040-45009999(360/341) : [email protected] : http://www.narayanagroup.com
Class: SZ3 JEE-MAIN MODEL Date: 08-08-2020
Time: 3hrs WTM-10 Max. Marks: 300
IMPORTANT INSTRUCTIONS
PHYSICS
Section Question Type +Ve
Marks - Ve
Marks No.of
Qs Total marks
Sec – I(Q.N : 1 – 20) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 21 – 25) Questions with Numerical Answer Type
(+/ - Decimal Numbers) 4 0 5 20
Total 25 100
CHEMISTRY
Section Question Type +Ve
Marks - Ve
Marks No.of
Qs Total marks
Sec – I(Q.N : 26 – 45) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 46 – 50) Questions with Numerical Answer Type
(+/ - Decimal Numbers) 4 0 5 20
Total 25 100
MATHEMATICS Section Question Type
+Ve Marks
- Ve Marks
No.of Qs
Total marks
Sec – I(Q.N : 51 – 70) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 71 – 75) Questions with Numerical Answer Type
(+/ - Decimal Numbers) 4 0 5 20
Total 25 100
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
2
–:SZ3 Jee-Main Exam Syllabus (08-08-20):–
TOPICS
PHYSICS
PRESENT WEEK 50%: PREVIOUS WEEK 50%:
TOPICS
CHEMISTRY
PRESENT WEEK 50%: PREVIOUS WEEK 50%:
TOPICS
MATHS
PRESENT WEEK 50%: PREVIOUS WEEK 50%:
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
3
SECTION-I(1-20)
(Single Answer Type)
This section contains 20 multiple choice questions. Each question has 4 options
(1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.
01. Rain is falling vertically. To a man walking with a speed of 3 km/h,
it appears to fall at 300 with the vertical. He increases his speed.
Now it appears to him to fall at 600 with the vertical. What is his
new speed?
1) 3 km/h 2) 6 km/h
3) 3 3 km/h 3) 9 km/h
02. Relative velocity of A with respect to B is given by AB AG BGV V V= − ,
where AG BGV and V are velocities of A and B with respect to ground. A
person can run uniformly on a horizontal stationary escalator and
move from one of its ends to the other in time tp. If person stands
on the escalator and escalator alone moves at uniform speed, it
takes time te to move from one of its ends to the other. If both are
moving in the same direction, the time taken, t, to move from one
of its ends to the other is
1)t > tp 2) t > te 3) e p
e p
t tt
t t=
+ 4)
e p
e p
t tt
t t=
−
03. A river is flowing from West to East at a speed of 5 m/s. A man on
the south bank of the river capable of swimming at 10 m/s in a still
water wants to swim, across the river in a shortest time. He should
swim in a direction
1) Due North 2) 30 East of West
3) 30 West of North 4) 60 East of North
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
4
04. Relative velocity of A with respect to B is given by AB AG BGV V V= − ,
where AG BGV and V are velocities of A and B with respect to ground.
Two persons A and B are standing on a stationary horizontal
escalator. A runs towards B with a ground speed of 4 ms−1, while
B runs towards A with a ground speed of 5 ms−1. If escalator starts
moving from A to B with a speed of 4 ms−1, relative speed of A with
respect to B?
1) Remains same as was before escalator started moving
2) Increases
3) Decreases
4) Increases if escalator moves from A to B, remains same if it
moves from B to A
05. A boat crosses a river of width 200m in the shortest time and is
found to experience a drift of 100m in reaching the opposite bank.
The time taken now is t. If the same boat is to cross the river by
shortest path, the time taken to cross will be
1) 2t 2) 2t 3) 3t 4) 2
3
t
06. A river flows at the rate of 3 km/hr and a person can row a boat at
a speed of 5 km/hr in still water. If the difference between the times
taken to cross the river by the shortest path and the quickest path
be 4 minutes, the width of the river is (in km)
1) 1
23
2) 1
13
3) 1
34
4) 1
43
07. The path of one projectile as seen from another projectile is a (if
horizontal components of velocities are equal)
1) straight line 2) parabola
3) hyperbola 4) circle
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
5
08. The acceleration of a projectile relative to another projectile is
1) -g 2) g 3) 2g 4)0
09. If a body is thrown with a speed of 19.6m/s making an angle of 030
with the horizontal, then the time of flight is ( )29.8 /g m s=
1) 1 sec 2) 2 sec 3) 2 3 sec 4) 5 sec
10. A ship is moving due East with a velocity of 12 m/sec, a truck is
moving across on the ship with velocity 4 m/sec. A monkey is
climbing the vertical pole mounted on the truck with a velocity of 3
m/sec. The velocity of the monkey as observed by the man on the
shore is (in m/sec)
1) 10 2) 15 3) 13 4) 20
11. To the captain of a ship A travelling with velocity ( )ˆ ˆ3 4 /Av i j km h= − ,
a second ship B appears to have a velocity ( )ˆ ˆ5 12 /Bv i j km h= + . What
is the true velocity of the ship B in (km/h)
1) ˆ ˆ2 16i j+ 2) ˆ ˆ13 8i j+ 3) ˆ ˆ2 16i j− − 4) ( )ˆ ˆ8 i j+
12. Rain is falling vertically with a velocity of 13 kmh− . A man walks in
the rain with a velocity of 14 kmh− . The rain drops will fall on the
man with a velocity of (in 1 kmh− )
1) 5 2) 4 3) 3 4) 1
13. A boat having a speed of 5 km/hr in still water, crosses a river of
width 1 km long the shortest possible path in 15 minutes. The
speed of the river in km/hr.
1) 1 2) 3 3) 4 4) 41
14. The horizontal and vertical displacements of a projectile are given
as x = at & y = bt-ct2. Then velocity of projection is
1) 2 2a b+ 2)
2 2b c+
3) 2 2a c+ 4)
2 2b c−
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
6
15. A ball is thrown with a velocity of u making an angle θ with the
horizontal. Its velocity vector normal to initial vector (u) after a time
interval of
1) sinu
g
2)
cos
u
g 3)
sin
u
g 4)
cosu
g
16. A particle is projected in xy plane with y-axis along vertical, the
point of projection is origin. The equation of the path is
2gy 3x x
2= − . where y and x are in m. Then the speed of projection
in 1ms− is
1) 2 2) 3 3) 4 4) None
17. A body is projected with an initial velocity 20 m/s at 060 to the
horizontal. Its initial velocity vector is ____ ( )210 /g m s=
1) ˆ ˆ10 20i j− 2) ˆ ˆ10 3 10i j+
3) ˆ ˆ10 10 3i j+ 4) None
18. A missile is fired for maximum range with an initial velocity of
120m s− , the range of the missile is ( )210 /g m s=
1) 50 m 2) 60 m 3) 20m 4) 40 m
19. A projectile is given an initial velocity ^ ^
2i j+ .The cartesian equation
of its path is −= 2(g 10ms )
1) 2y 2x 5x= − 2) 29y 12x 5x= −
3) 2y 9x 5x= − 4) 25y x 9x= −
20. A cricket ball is hit for a six leaving the bat at an angle of 060 to
the horizontal with kinetic energy ‘k’. At the top, kinetic energy. of
the ball is
1) Zero 2) k 3) k
4 4) None
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
7
SECTION-II(21-25)
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical
values comprising of positive or negative decimal numbers (place value
ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.
21. A man crosses a river in a boat. If he crosses the river in minimum
time, he takes 10 min with a drift of 120 m. If he crosses the river
taking shortest path, he takes 12.5 min, then width of the river is
_____________m.
22. A man crosses a river in a boat. If he crosses the river in minimum
time, he takes 10 min with a drift of 120 m. If he crosses the river
taking shortest path, he takes 12.5 min, then velocity of the boat
with respect to the river water is __________ m/min.
23. A particle is projected from the ground with an initial speed v at an
angle with horizontal. The average velocity of the particle between
its point of projection and highest point of trajectory is
21 cos .V
PN
+ Then the value of N P+ is
24. A foot ball is kicked with a velocity of 20 m/s at an angle of 045
with the horizontal. The time taken by the ball to strike the ground
is ____________sec. ( )210 /g m s=
25. A ball is thrown at a speed of 40 m/sec at an angle of 060 with the
horizontal. The maximum height reached by the ball is
__________m. ( )210 /g m s=
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
8
SECTION-I(26-45)
(Single Answer Type)
This section contains 20 multiple choice questions. Each question has 4 options
(1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.
26. The rate of diffusion of hydrogen gas is
1) 1.4 times to He gas 2) same as gas
3) 5 times to gas 4) 2 times to gas
27. Which of the following pairs will diffuse at the same rate through a
porous plug
1) 2,CO NO 2) 2 2,NO CO 3) 3 3.NH PH 4) 2 6,NO C H
28. Which of the following is correct
1) Dry gas TotalP Aqueous tension P= −
2) Dry gas TotalP P Aqueous tension= −
3) Total Dry gasP P Aqueous tension= −
4) All
29. A neon-dioxygen mixture contains 70.6g dioxygen and 167.5 g
neon. If pressure of the mixture of gases in the cylinder is 25 bar.
What is the partial pressure of dioxygen in the mixture is
1) 19.75 bar 2) 0.79 bar 3) 5.25 bar 4) 0.21 bar
30. If three unreactive gases having partial pressures ,A B CP P and P and
their moles are 1,2 and 3 respectively then their total pressure will
be
1) A B CP P P P= + + 2) 6
A B CP P PP
+ +=
3) 3
A B CP P PP
+ += 4) 6P =
31. Pressure exerted by saturated water vapour is called
1) Dalton law 2) Aqueous tension
3) Grahams law 4) All
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
9
32. Dalton’s law of partial pressures cannot be applied to the following
pair of gases, which they are mixed
1) 2 2&H O 2)
2 2&H N
3) 3,NH HCl 4) All
33. A gas diffuse 1
5 times as fast as hydrogen, its molecular weight is
1) 50 2) 25 3) 25 2 4) 50 2
34. Hydrogen diffuses six times faster than gas the molar mass of gas
is
1) 72 2) 6 3) 24 4) 31
35. Under similar conditions of temperature and pressure gas having
highest rate as diffusion is
1) Oxygen ( )2O 2) acetylene ( )2 2C H
3) Sulphur dioxide ( )2SO 4) Methane ( )4CH
36. At 025 C and 760 mm of Hg pressure a gas occupies 600mL volume.
What will be its pressure at a height where temperature is 010 C
and volume of the gas is 640 mL.
1) 776.6 mm Hg 2) 676.6 mm Hg
3) 576.6 mm Hg 4) All
37. What is the ‘R’ value in Joules/K/mole is
1) 2 1 18.314 10 bar L k mol− − − 2) 3 1 18.314 Pa m k mol− −
3) 1 18.314 J k mol− − 4) All
38. The number of molecules in one mole of a gas has been determined
to be 236.022 10 and is known as
1) Boyle’s constant 2) Avogadro constant
3) Gas constant 4) All
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
10
39. For one gram molecular weight of a gas (n=1) PV
T=
1) 0.2 cal 2) 2 cal 3) 4 cal 4) 0.4 cal
40. Ion-dipole attractions are present in
1) Water 2) NaCl+Water
3) Benzene ( )6 6C H 4) All
41. The pressure at which one mole of a gas at 00 C occupies a volume
of 1 litre is
1) 1 atm 2) 22.4 atm
3) 760 mm 4) 273 atm
42. A gas of volume 200ml is kept in a vessel at a pressure of 310
pascals at a temperature of 027 .C If the pressure is increased 510
pascals at the same temperature, the volume of the gas becomes
1) 1000 ml 2) 20 ml 3) 2 ml 4) 200 ml
43. London or dispersion forces are due to the presence of
1) Dipole 2) Ions
3) Induced momentary dipoles 4) All
44. Which of the following is a correct representation
1) 1 1 1 2 2 2Pd T Pd T= 2) 1 1 2 2
1 2
d P d P
T T=
3) 1 2
1 1 2 2
P P
d T d T= 4) 2 21 1
1 2
PTPT
d d=
45. Regarding Charles law, which of the following is wrong
1) 2) 3) 4)
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
11
SECTION-II(46-50)
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical
values comprising of positive or negative decimal numbers (place value
ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.
46. How many of the following intermolecular forces are not responsible
for liquid state of bromine at room temperature
I) Dipole-dipole forces
II) London dispersion forces
III) Hydrogen bonds
IV) Ion interaction
47. At 0127 C and 1 atm pressure, a mixture of a gas contains 0.3 moles
of 2 ,N 0.2 moles of 2O , the volume of the mixture is ( in L)
48. The vapour density of a gas is 11.2. The volume occupied by 10g of
the gas at STP is ( in Litres)
49. At atmospheric pressure, a litre vessel contains a mixture of Helium
and Nitrogen. If partial pressure of Nitrogen is 500mm, the partial
pressure of Helium will be (in mm)
50. One litre of methane ( )4CH takes 20 minutes to diffuse out of a
vessel. How long will it take to diffuse one litre of 2SO through the
vessel under the same conditions of temperature and pressure ( in
minutes)
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
12
SECTION-I (51-70)
(Single Answer Type)
This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be
correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.
51. If the equation of the locus of a point equidistant from the points
( )1 1,a b and ( )2 2,a b is ( ) ( )1 2 1 2 0a a x b b y c− + − + = , then the value of c
is
1) 2 2 2 2
1 1 2 2a b a b+ − − 2) ( )2 2 2 2
2 2 1 1
1
2a b a b+ − −
3) 2 2 2 2
1 2 1 2a a b b− + − 4) ( )2 2 2 2
1 2 1 2
1
2a a b b+ + +
52. The line joining ( )5,0 to ( )10cos ,10sin is divided internally in the
ratio 2:3 at P, then the locus of P is
1) 2 22 6 0x xy y x+ + − = 2) 3 0x y+ − =
3) ( )2 23 16x y− + = 4) 2 3x y= −
53. A straight rod of length 3l units slides with its ends ,A B always on
the x and y axes respectively, then the locus of the centriod of
OAB is
1) 2 2 23x y l+ = 2) 2 2 2x y l+ =
3) 2 2 24x y l+ = 4) 2 2 22x y l+ =
54. The perimeter of triangle is 14 units and two of its vertices are
( )3,0− and ( )3,0 , then the locus of the third vertex is
1) 2 2
116 7
x y+ = 2)
2 2
125 16
x y+ =
3) 2 2
17 16
x y+ = 4)
2 2
116 25
x y+ =
55. If ( ) ( ) ( )1,1 , 2,3 , 1,1A B C − are three points. If P is a point such that
the area of the quadrilateral PABC is 3 sq.units, then locus of P is
1) 2 6 0y y+ = 2) 2 6 0y y− =
3) 2 6 0x y+ = 4) 2 6 0x y− =
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
13
56. The locus of the point P moving such that 2 3PA PB= , where
( ) ( )0,0 , 4, 3A B − is
1) 2 25 5 72 54 225 0x y x y+ − + + = 2) 2 25 5 72 54 225 0x y x y+ + − − =
3) ( )2 23 70 52 225 0x y x y+ − + + = 4) ( )2 23 70 52 225 0x y x y+ + − − =
57. The equation of the locus of the point whose distance from X-axis
is twice its distance from the Y-axis is
1) 2 24x y= 2) 2 24y x=
3) 3y x= 4) 4 0x y+ =
58. The locus of a point P, if the join of the points ( )2,3 and ( )1,5−
subtends right angle at P is
1) 2 2 8 13 0x y x y+ − − + =
2) 2 2 8 3 0x y x y− − + + =
3) ( ) ( ) ( )2 2 4 4 0, , 0,4 & 4,0x y x y x y+ − − =
4) ( ) ( ) ( )2 2 8 13 0, , 2,3 & 1,5x y x y x y+ − − + = −
59. If t is parameter, ( )sec , tanA a t b t= and ( ) ( )tan , sec , 0,0 ,B a t b t O= − =
then the locus of the centroid of OAB is
1) 9xy ab= 2) 9xy ab=
3) 2 2 2 29x y a b− = − 4) ( )2 2 2 21
9x y a b− = −
60. The equation of locus of a point P, the difference of whose distances
from ( )5,0− and ( )5,0 is 8, is
1) 2 2
116 9
x y− = 2)
2 2
116 9
x y+ =
3) 2 2
19 8
x y− = 4)
2 2
19 16
x y− =
61. Under rotation of axes through angle , cos sinx y p+ = changes
to cos sinX Y p+ = , then
1) ( )cos cos = − 2) ( )cos cos = −
3) ( )2cos cos = − 4) ( )2cos cos = −
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
14
62. When the axes are translated to the point ( )5, 2− , then the
transformed from of the equation 2 5 11 0xy x y+ − − = is
1) 1X
Y= 2) 1
Y
X= 3) 1XY = 4) 2 1XY =
63. When the axes are rotated through an angle 45 , the transformed
equation of a curve is 2 217 16 17 225X XY Y− + = , then the original
equation of the curve is
1) 2 225 9 225x y+ = 2) 2 225 9 225x y− =
3) 2 2 225x y+ = 4) 2 2 225x y− =
64. The transformed equation of 2 2
2 21
x y
a b− = , when the axes are rotated
through an angle 90 is
1) 2 2
2 21
X Y
a b− = 2)
2 2
2 21
X Y
a b+ = 3)
2 2
2 21
Y X
b a− = 4)
2 2
2 21
Y X
a b− =
65. The angle of rotation of axes in order to eliminate xy-term of the
equation 2xy c= is
1) 12
2)
6
3)
3
4)
4
66. If the axes are rotated through an angle 45 and the point P has
new coordinates ( )2 2, 2 then original coordinates of P are
1) ( )1,3 2) ( )1,3− 3) ( )3,1 4) ( )3,3
67. When the origin is shifted to a suitable point P, the equation
2 22 4 4 0x y x y+ − + = transformed as 2 22 8 8 18 0X Y X Y+ − + + = , then P
is
1) ( )1, 2 2) ( )1, 2− 3) ( )1, 2− 4) ( )1, 2− −
68. If ( )cos ,cos are new coordinates of P when the axes are translated
to the point ( )1,1 , then original coordinates of P are
1) 2 22cos ,2cos2 2
2) 2 22sin ,2sin2 2
3) 2cos ,2cos2 2
4) 2sin ,2sin2 2
SZ3_JEE-MAIN_WTM-10_QP_Dt.08-08-2020
Narayana CO Schools
15
69. If the point ( )3, 2− transformed to the point ( )2,1− when origin is
shifted to P, then P is
1) ( )3, 2 2) ( )5, 3− 3) ( )2, 3− 4) ( )1, 2−
70. To remove the first degree terms of the equation 2 4 2 7 0xy x y+ − + =
, the shifted origin is
1) ( )2, 1− 2) ( )1, 2− 3) ( )1, 2− 4) ( )2,1−
SECTION-II (71 TO 75)
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical
values comprising of positive or negative decimal numbers (place value ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -
123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.
71. By translating the axes, the equation 2 3 4 0xy x y− − − = has changed
to ,XY K= then K is equal to
72. The origin is shifted to ( )1, 2 , if the equation 2 8 4 12 0y x y− − + =
changes as 2 4Y aX= , then a is equal to ______
73. When ( )0,0 is shifted to ( )2, 2− , if the transformed equation of
( ) ( )2 2
2 2 9x y− + + = is 2 2X Y k+ = , then 11k + is equal to _____
74. When ( )0,0 is shifted to ( )3, 3− the coordinates of ( ) ( )5,5 , 2,4P Q −
and ( )7, 7R − in the new system are , , .A B C Then the area of ABC (
in sq.units) is
75. If the locus of the point which is equidistant from ( )2,0 to the Y-
axis is ( )2 1 ,y a x= − then the value of 2 4a + is equal to ______