16
Corporate Office: 10th Floor, Melange Tower; No.80-84, Pathrika Nagar; Hitech-City, Madhapur, Hyderabad. Telangana - 500 081. : 040-45009999(360/341) : [email protected] : http://www.narayanagroup.com Class: SZ3 JEE-MAIN MODEL Date: 08-08-2020 Time: 3hrs WTM-10 Max. Marks: 300 IMPORTANT INSTRUCTIONS PHYSICS Section Question Type +Ve Marks - Ve Marks No.of Qs Total marks Sec – I(Q.N : 1 – 20) Questions with Single Answer Type 4 -1 20 80 Sec – II(Q.N : 21 – 25) Questions with Numerical Answer Type (+/ - Decimal Numbers) 4 0 5 20 Total 25 100 CHEMISTRY Section Question Type +Ve Marks - Ve Marks No.of Qs Total marks Sec – I(Q.N : 26 – 45) Questions with Single Answer Type 4 -1 20 80 Sec – II(Q.N : 46 – 50) Questions with Numerical Answer Type (+/ - Decimal Numbers) 4 0 5 20 Total 25 100 MATHEMATICS Section Question Type +Ve Marks - Ve Marks No.of Qs Total marks Sec – I(Q.N : 51 – 70) Questions with Single Answer Type 4 -1 20 80 Sec – II(Q.N : 71 – 75) Questions with Numerical Answer Type (+/ - Decimal Numbers) 4 0 5 20 Total 25 100

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Page 1: Class: SZ3 JEE-MAIN MODEL Date: 08-08-2020 Time: 3hrs WTM ... · 8/8/2020  · Marks: 300 IMPORTANT INSTRUCTIONS PHYSICS Section Question Type +Ve Marks - Ve Marks No.of Qs Total

Corporate Office: 10th Floor, Melange Tower; No.80-84, Pathrika Nagar; Hitech-City, Madhapur, Hyderabad. Telangana - 500 081.

: 040-45009999(360/341) : [email protected] : http://www.narayanagroup.com

Class: SZ3 JEE-MAIN MODEL Date: 08-08-2020

Time: 3hrs WTM-10 Max. Marks: 300

IMPORTANT INSTRUCTIONS

PHYSICS

Section Question Type +Ve

Marks - Ve

Marks No.of

Qs Total marks

Sec – I(Q.N : 1 – 20) Questions with Single Answer Type 4 -1 20 80

Sec – II(Q.N : 21 – 25) Questions with Numerical Answer Type

(+/ - Decimal Numbers) 4 0 5 20

Total 25 100

CHEMISTRY

Section Question Type +Ve

Marks - Ve

Marks No.of

Qs Total marks

Sec – I(Q.N : 26 – 45) Questions with Single Answer Type 4 -1 20 80

Sec – II(Q.N : 46 – 50) Questions with Numerical Answer Type

(+/ - Decimal Numbers) 4 0 5 20

Total 25 100

MATHEMATICS Section Question Type

+Ve Marks

- Ve Marks

No.of Qs

Total marks

Sec – I(Q.N : 51 – 70) Questions with Single Answer Type 4 -1 20 80

Sec – II(Q.N : 71 – 75) Questions with Numerical Answer Type

(+/ - Decimal Numbers) 4 0 5 20

Total 25 100

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2

–:SZ3 Jee-Main Exam Syllabus (08-08-20):–

TOPICS

PHYSICS

PRESENT WEEK 50%: PREVIOUS WEEK 50%:

TOPICS

CHEMISTRY

PRESENT WEEK 50%: PREVIOUS WEEK 50%:

TOPICS

MATHS

PRESENT WEEK 50%: PREVIOUS WEEK 50%:

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3

SECTION-I(1-20)

(Single Answer Type)

This section contains 20 multiple choice questions. Each question has 4 options

(1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.

01. Rain is falling vertically. To a man walking with a speed of 3 km/h,

it appears to fall at 300 with the vertical. He increases his speed.

Now it appears to him to fall at 600 with the vertical. What is his

new speed?

1) 3 km/h 2) 6 km/h

3) 3 3 km/h 3) 9 km/h

02. Relative velocity of A with respect to B is given by AB AG BGV V V= − ,

where AG BGV and V are velocities of A and B with respect to ground. A

person can run uniformly on a horizontal stationary escalator and

move from one of its ends to the other in time tp. If person stands

on the escalator and escalator alone moves at uniform speed, it

takes time te to move from one of its ends to the other. If both are

moving in the same direction, the time taken, t, to move from one

of its ends to the other is

1)t > tp 2) t > te 3) e p

e p

t tt

t t=

+ 4)

e p

e p

t tt

t t=

03. A river is flowing from West to East at a speed of 5 m/s. A man on

the south bank of the river capable of swimming at 10 m/s in a still

water wants to swim, across the river in a shortest time. He should

swim in a direction

1) Due North 2) 30 East of West

3) 30 West of North 4) 60 East of North

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04. Relative velocity of A with respect to B is given by AB AG BGV V V= − ,

where AG BGV and V are velocities of A and B with respect to ground.

Two persons A and B are standing on a stationary horizontal

escalator. A runs towards B with a ground speed of 4 ms−1, while

B runs towards A with a ground speed of 5 ms−1. If escalator starts

moving from A to B with a speed of 4 ms−1, relative speed of A with

respect to B?

1) Remains same as was before escalator started moving

2) Increases

3) Decreases

4) Increases if escalator moves from A to B, remains same if it

moves from B to A

05. A boat crosses a river of width 200m in the shortest time and is

found to experience a drift of 100m in reaching the opposite bank.

The time taken now is t. If the same boat is to cross the river by

shortest path, the time taken to cross will be

1) 2t 2) 2t 3) 3t 4) 2

3

t

06. A river flows at the rate of 3 km/hr and a person can row a boat at

a speed of 5 km/hr in still water. If the difference between the times

taken to cross the river by the shortest path and the quickest path

be 4 minutes, the width of the river is (in km)

1) 1

23

2) 1

13

3) 1

34

4) 1

43

07. The path of one projectile as seen from another projectile is a (if

horizontal components of velocities are equal)

1) straight line 2) parabola

3) hyperbola 4) circle

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08. The acceleration of a projectile relative to another projectile is

1) -g 2) g 3) 2g 4)0

09. If a body is thrown with a speed of 19.6m/s making an angle of 030

with the horizontal, then the time of flight is ( )29.8 /g m s=

1) 1 sec 2) 2 sec 3) 2 3 sec 4) 5 sec

10. A ship is moving due East with a velocity of 12 m/sec, a truck is

moving across on the ship with velocity 4 m/sec. A monkey is

climbing the vertical pole mounted on the truck with a velocity of 3

m/sec. The velocity of the monkey as observed by the man on the

shore is (in m/sec)

1) 10 2) 15 3) 13 4) 20

11. To the captain of a ship A travelling with velocity ( )ˆ ˆ3 4 /Av i j km h= − ,

a second ship B appears to have a velocity ( )ˆ ˆ5 12 /Bv i j km h= + . What

is the true velocity of the ship B in (km/h)

1) ˆ ˆ2 16i j+ 2) ˆ ˆ13 8i j+ 3) ˆ ˆ2 16i j− − 4) ( )ˆ ˆ8 i j+

12. Rain is falling vertically with a velocity of 13 kmh− . A man walks in

the rain with a velocity of 14 kmh− . The rain drops will fall on the

man with a velocity of (in 1 kmh− )

1) 5 2) 4 3) 3 4) 1

13. A boat having a speed of 5 km/hr in still water, crosses a river of

width 1 km long the shortest possible path in 15 minutes. The

speed of the river in km/hr.

1) 1 2) 3 3) 4 4) 41

14. The horizontal and vertical displacements of a projectile are given

as x = at & y = bt-ct2. Then velocity of projection is

1) 2 2a b+ 2)

2 2b c+

3) 2 2a c+ 4)

2 2b c−

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15. A ball is thrown with a velocity of u making an angle θ with the

horizontal. Its velocity vector normal to initial vector (u) after a time

interval of

1) sinu

g

2)

cos

u

g 3)

sin

u

g 4)

cosu

g

16. A particle is projected in xy plane with y-axis along vertical, the

point of projection is origin. The equation of the path is

2gy 3x x

2= − . where y and x are in m. Then the speed of projection

in 1ms− is

1) 2 2) 3 3) 4 4) None

17. A body is projected with an initial velocity 20 m/s at 060 to the

horizontal. Its initial velocity vector is ____ ( )210 /g m s=

1) ˆ ˆ10 20i j− 2) ˆ ˆ10 3 10i j+

3) ˆ ˆ10 10 3i j+ 4) None

18. A missile is fired for maximum range with an initial velocity of

120m s− , the range of the missile is ( )210 /g m s=

1) 50 m 2) 60 m 3) 20m 4) 40 m

19. A projectile is given an initial velocity ^ ^

2i j+ .The cartesian equation

of its path is −= 2(g 10ms )

1) 2y 2x 5x= − 2) 29y 12x 5x= −

3) 2y 9x 5x= − 4) 25y x 9x= −

20. A cricket ball is hit for a six leaving the bat at an angle of 060 to

the horizontal with kinetic energy ‘k’. At the top, kinetic energy. of

the ball is

1) Zero 2) k 3) k

4 4) None

Page 7: Class: SZ3 JEE-MAIN MODEL Date: 08-08-2020 Time: 3hrs WTM ... · 8/8/2020  · Marks: 300 IMPORTANT INSTRUCTIONS PHYSICS Section Question Type +Ve Marks - Ve Marks No.of Qs Total

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7

SECTION-II(21-25)

(Numerical Value Answer Type)

This section contains 5 questions. The answer to each question is a Numerical

values comprising of positive or negative decimal numbers (place value

ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.

21. A man crosses a river in a boat. If he crosses the river in minimum

time, he takes 10 min with a drift of 120 m. If he crosses the river

taking shortest path, he takes 12.5 min, then width of the river is

_____________m.

22. A man crosses a river in a boat. If he crosses the river in minimum

time, he takes 10 min with a drift of 120 m. If he crosses the river

taking shortest path, he takes 12.5 min, then velocity of the boat

with respect to the river water is __________ m/min.

23. A particle is projected from the ground with an initial speed v at an

angle with horizontal. The average velocity of the particle between

its point of projection and highest point of trajectory is

21 cos .V

PN

+ Then the value of N P+ is

24. A foot ball is kicked with a velocity of 20 m/s at an angle of 045

with the horizontal. The time taken by the ball to strike the ground

is ____________sec. ( )210 /g m s=

25. A ball is thrown at a speed of 40 m/sec at an angle of 060 with the

horizontal. The maximum height reached by the ball is

__________m. ( )210 /g m s=

Page 8: Class: SZ3 JEE-MAIN MODEL Date: 08-08-2020 Time: 3hrs WTM ... · 8/8/2020  · Marks: 300 IMPORTANT INSTRUCTIONS PHYSICS Section Question Type +Ve Marks - Ve Marks No.of Qs Total

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8

SECTION-I(26-45)

(Single Answer Type)

This section contains 20 multiple choice questions. Each question has 4 options

(1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.

26. The rate of diffusion of hydrogen gas is

1) 1.4 times to He gas 2) same as gas

3) 5 times to gas 4) 2 times to gas

27. Which of the following pairs will diffuse at the same rate through a

porous plug

1) 2,CO NO 2) 2 2,NO CO 3) 3 3.NH PH 4) 2 6,NO C H

28. Which of the following is correct

1) Dry gas TotalP Aqueous tension P= −

2) Dry gas TotalP P Aqueous tension= −

3) Total Dry gasP P Aqueous tension= −

4) All

29. A neon-dioxygen mixture contains 70.6g dioxygen and 167.5 g

neon. If pressure of the mixture of gases in the cylinder is 25 bar.

What is the partial pressure of dioxygen in the mixture is

1) 19.75 bar 2) 0.79 bar 3) 5.25 bar 4) 0.21 bar

30. If three unreactive gases having partial pressures ,A B CP P and P and

their moles are 1,2 and 3 respectively then their total pressure will

be

1) A B CP P P P= + + 2) 6

A B CP P PP

+ +=

3) 3

A B CP P PP

+ += 4) 6P =

31. Pressure exerted by saturated water vapour is called

1) Dalton law 2) Aqueous tension

3) Grahams law 4) All

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32. Dalton’s law of partial pressures cannot be applied to the following

pair of gases, which they are mixed

1) 2 2&H O 2)

2 2&H N

3) 3,NH HCl 4) All

33. A gas diffuse 1

5 times as fast as hydrogen, its molecular weight is

1) 50 2) 25 3) 25 2 4) 50 2

34. Hydrogen diffuses six times faster than gas the molar mass of gas

is

1) 72 2) 6 3) 24 4) 31

35. Under similar conditions of temperature and pressure gas having

highest rate as diffusion is

1) Oxygen ( )2O 2) acetylene ( )2 2C H

3) Sulphur dioxide ( )2SO 4) Methane ( )4CH

36. At 025 C and 760 mm of Hg pressure a gas occupies 600mL volume.

What will be its pressure at a height where temperature is 010 C

and volume of the gas is 640 mL.

1) 776.6 mm Hg 2) 676.6 mm Hg

3) 576.6 mm Hg 4) All

37. What is the ‘R’ value in Joules/K/mole is

1) 2 1 18.314 10 bar L k mol− − − 2) 3 1 18.314 Pa m k mol− −

3) 1 18.314 J k mol− − 4) All

38. The number of molecules in one mole of a gas has been determined

to be 236.022 10 and is known as

1) Boyle’s constant 2) Avogadro constant

3) Gas constant 4) All

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39. For one gram molecular weight of a gas (n=1) PV

T=

1) 0.2 cal 2) 2 cal 3) 4 cal 4) 0.4 cal

40. Ion-dipole attractions are present in

1) Water 2) NaCl+Water

3) Benzene ( )6 6C H 4) All

41. The pressure at which one mole of a gas at 00 C occupies a volume

of 1 litre is

1) 1 atm 2) 22.4 atm

3) 760 mm 4) 273 atm

42. A gas of volume 200ml is kept in a vessel at a pressure of 310

pascals at a temperature of 027 .C If the pressure is increased 510

pascals at the same temperature, the volume of the gas becomes

1) 1000 ml 2) 20 ml 3) 2 ml 4) 200 ml

43. London or dispersion forces are due to the presence of

1) Dipole 2) Ions

3) Induced momentary dipoles 4) All

44. Which of the following is a correct representation

1) 1 1 1 2 2 2Pd T Pd T= 2) 1 1 2 2

1 2

d P d P

T T=

3) 1 2

1 1 2 2

P P

d T d T= 4) 2 21 1

1 2

PTPT

d d=

45. Regarding Charles law, which of the following is wrong

1) 2) 3) 4)

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11

SECTION-II(46-50)

(Numerical Value Answer Type)

This section contains 5 questions. The answer to each question is a Numerical

values comprising of positive or negative decimal numbers (place value

ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.

46. How many of the following intermolecular forces are not responsible

for liquid state of bromine at room temperature

I) Dipole-dipole forces

II) London dispersion forces

III) Hydrogen bonds

IV) Ion interaction

47. At 0127 C and 1 atm pressure, a mixture of a gas contains 0.3 moles

of 2 ,N 0.2 moles of 2O , the volume of the mixture is ( in L)

48. The vapour density of a gas is 11.2. The volume occupied by 10g of

the gas at STP is ( in Litres)

49. At atmospheric pressure, a litre vessel contains a mixture of Helium

and Nitrogen. If partial pressure of Nitrogen is 500mm, the partial

pressure of Helium will be (in mm)

50. One litre of methane ( )4CH takes 20 minutes to diffuse out of a

vessel. How long will it take to diffuse one litre of 2SO through the

vessel under the same conditions of temperature and pressure ( in

minutes)

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SECTION-I (51-70)

(Single Answer Type)

This section contains 20 multiple choice questions. Each question has 4 options (1), (2), (3) and (4) for its answer, out of which ONLY ONE option can be

correct. Marking scheme: +4 for correct answer, 0 if not attempted and -1 in all other cases.

51. If the equation of the locus of a point equidistant from the points

( )1 1,a b and ( )2 2,a b is ( ) ( )1 2 1 2 0a a x b b y c− + − + = , then the value of c

is

1) 2 2 2 2

1 1 2 2a b a b+ − − 2) ( )2 2 2 2

2 2 1 1

1

2a b a b+ − −

3) 2 2 2 2

1 2 1 2a a b b− + − 4) ( )2 2 2 2

1 2 1 2

1

2a a b b+ + +

52. The line joining ( )5,0 to ( )10cos ,10sin is divided internally in the

ratio 2:3 at P, then the locus of P is

1) 2 22 6 0x xy y x+ + − = 2) 3 0x y+ − =

3) ( )2 23 16x y− + = 4) 2 3x y= −

53. A straight rod of length 3l units slides with its ends ,A B always on

the x and y axes respectively, then the locus of the centriod of

OAB is

1) 2 2 23x y l+ = 2) 2 2 2x y l+ =

3) 2 2 24x y l+ = 4) 2 2 22x y l+ =

54. The perimeter of triangle is 14 units and two of its vertices are

( )3,0− and ( )3,0 , then the locus of the third vertex is

1) 2 2

116 7

x y+ = 2)

2 2

125 16

x y+ =

3) 2 2

17 16

x y+ = 4)

2 2

116 25

x y+ =

55. If ( ) ( ) ( )1,1 , 2,3 , 1,1A B C − are three points. If P is a point such that

the area of the quadrilateral PABC is 3 sq.units, then locus of P is

1) 2 6 0y y+ = 2) 2 6 0y y− =

3) 2 6 0x y+ = 4) 2 6 0x y− =

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56. The locus of the point P moving such that 2 3PA PB= , where

( ) ( )0,0 , 4, 3A B − is

1) 2 25 5 72 54 225 0x y x y+ − + + = 2) 2 25 5 72 54 225 0x y x y+ + − − =

3) ( )2 23 70 52 225 0x y x y+ − + + = 4) ( )2 23 70 52 225 0x y x y+ + − − =

57. The equation of the locus of the point whose distance from X-axis

is twice its distance from the Y-axis is

1) 2 24x y= 2) 2 24y x=

3) 3y x= 4) 4 0x y+ =

58. The locus of a point P, if the join of the points ( )2,3 and ( )1,5−

subtends right angle at P is

1) 2 2 8 13 0x y x y+ − − + =

2) 2 2 8 3 0x y x y− − + + =

3) ( ) ( ) ( )2 2 4 4 0, , 0,4 & 4,0x y x y x y+ − − =

4) ( ) ( ) ( )2 2 8 13 0, , 2,3 & 1,5x y x y x y+ − − + = −

59. If t is parameter, ( )sec , tanA a t b t= and ( ) ( )tan , sec , 0,0 ,B a t b t O= − =

then the locus of the centroid of OAB is

1) 9xy ab= 2) 9xy ab=

3) 2 2 2 29x y a b− = − 4) ( )2 2 2 21

9x y a b− = −

60. The equation of locus of a point P, the difference of whose distances

from ( )5,0− and ( )5,0 is 8, is

1) 2 2

116 9

x y− = 2)

2 2

116 9

x y+ =

3) 2 2

19 8

x y− = 4)

2 2

19 16

x y− =

61. Under rotation of axes through angle , cos sinx y p+ = changes

to cos sinX Y p+ = , then

1) ( )cos cos = − 2) ( )cos cos = −

3) ( )2cos cos = − 4) ( )2cos cos = −

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62. When the axes are translated to the point ( )5, 2− , then the

transformed from of the equation 2 5 11 0xy x y+ − − = is

1) 1X

Y= 2) 1

Y

X= 3) 1XY = 4) 2 1XY =

63. When the axes are rotated through an angle 45 , the transformed

equation of a curve is 2 217 16 17 225X XY Y− + = , then the original

equation of the curve is

1) 2 225 9 225x y+ = 2) 2 225 9 225x y− =

3) 2 2 225x y+ = 4) 2 2 225x y− =

64. The transformed equation of 2 2

2 21

x y

a b− = , when the axes are rotated

through an angle 90 is

1) 2 2

2 21

X Y

a b− = 2)

2 2

2 21

X Y

a b+ = 3)

2 2

2 21

Y X

b a− = 4)

2 2

2 21

Y X

a b− =

65. The angle of rotation of axes in order to eliminate xy-term of the

equation 2xy c= is

1) 12

2)

6

3)

3

4)

4

66. If the axes are rotated through an angle 45 and the point P has

new coordinates ( )2 2, 2 then original coordinates of P are

1) ( )1,3 2) ( )1,3− 3) ( )3,1 4) ( )3,3

67. When the origin is shifted to a suitable point P, the equation

2 22 4 4 0x y x y+ − + = transformed as 2 22 8 8 18 0X Y X Y+ − + + = , then P

is

1) ( )1, 2 2) ( )1, 2− 3) ( )1, 2− 4) ( )1, 2− −

68. If ( )cos ,cos are new coordinates of P when the axes are translated

to the point ( )1,1 , then original coordinates of P are

1) 2 22cos ,2cos2 2

2) 2 22sin ,2sin2 2

3) 2cos ,2cos2 2

4) 2sin ,2sin2 2

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69. If the point ( )3, 2− transformed to the point ( )2,1− when origin is

shifted to P, then P is

1) ( )3, 2 2) ( )5, 3− 3) ( )2, 3− 4) ( )1, 2−

70. To remove the first degree terms of the equation 2 4 2 7 0xy x y+ − + =

, the shifted origin is

1) ( )2, 1− 2) ( )1, 2− 3) ( )1, 2− 4) ( )2,1−

SECTION-II (71 TO 75)

(Numerical Value Answer Type)

This section contains 5 questions. The answer to each question is a Numerical

values comprising of positive or negative decimal numbers (place value ranging from Thousands Place to Hundredths Place). Eg: 1234.56, 123.45, -

123.45, -1234.56, -0.12, 0.12 etc. Marking scheme: +4 for correct answer, 0 in all other cases.

71. By translating the axes, the equation 2 3 4 0xy x y− − − = has changed

to ,XY K= then K is equal to

72. The origin is shifted to ( )1, 2 , if the equation 2 8 4 12 0y x y− − + =

changes as 2 4Y aX= , then a is equal to ______

73. When ( )0,0 is shifted to ( )2, 2− , if the transformed equation of

( ) ( )2 2

2 2 9x y− + + = is 2 2X Y k+ = , then 11k + is equal to _____

74. When ( )0,0 is shifted to ( )3, 3− the coordinates of ( ) ( )5,5 , 2,4P Q −

and ( )7, 7R − in the new system are , , .A B C Then the area of ABC (

in sq.units) is

75. If the locus of the point which is equidistant from ( )2,0 to the Y-

axis is ( )2 1 ,y a x= − then the value of 2 4a + is equal to ______

Page 16: Class: SZ3 JEE-MAIN MODEL Date: 08-08-2020 Time: 3hrs WTM ... · 8/8/2020  · Marks: 300 IMPORTANT INSTRUCTIONS PHYSICS Section Question Type +Ve Marks - Ve Marks No.of Qs Total