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11/29/2011
1
Chem 526Chem 526
NMR for Analytical Chemists
Lecture 21Lecture 21
(Ch 4, Ch 6)
Class Schedule
HW9 due on Thursday• 11/17 Follow up of 2D Exps 3D Experiments Intro• 11/17 Follow up of 2D Exps, 3D Experiments Intro• 11/22 YOUR Presentation• 11/24 (No Class)• 11/29 Final Exam Prep Final Exam Dec 1 (Thr)
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Final Presentation• How it works?
– Density Operators– Explanation of Components
• How the spectrum looks like?How the spectrum looks like?– What are the two (three) axes?– What do the cross peaks represent?
• What kind of information can you extract from the spectrum?
• What is the advantage of this method?HMQC vs HSQC– HMQC vs HSQC
– NOESY vs TOCSY– Heteronuclear vs Homonuclear– 2D vs 3D
• Example of an application (Show at least two spectra &Explain) 20 mins +5 min Question time
Final Presentation on multidimensional NMR (ch 6-7) (Nov 22)
1H/1H homonuclear correlation (20 min presentation) COSY TOCSY (6.5) + DQF COSY Group 1
1H/(15N/13C) heteronuclear correlation HMQC (7.1.1.1) & HSQC (7.1.1) Group 2 HNCO, HNCOCA, HCANH (7.4) Group 3
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A 2D NMR experiment: Basic Scheme
Preparation MixingEvolution (t1) Acquisition (t2)
t
t2
FT t2
t2FT t1
ω1
ω2
diagonal peaks (ω1 = ω2)cross peaks (ω1 ≠ ω2)
Thanks to Hongyan & Jie
6.5 TOCSY
A train of composite pulse(DIPSI-2, WALTZ-16 etc)
● Eliminates chemical shifts ● Create strong coupling
Hmix = 2J’(IXSX + IYSY + IZSZ)
● Create strong coupling
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TOCSY Transfer
• Heff = 2J(IXSX + IYSY+IZSZ )
(0) = IX
[IXSX, IYSY] = [IYSY, IZSZ] =
[IZSZ, IXSX] = 0 & [(0), IXSX] = 0
IX – 2 JIZSZ IXcosJ + 2IYSZsinJ2IYSZ – 2 JIYSY 2IYSZ cosJ+ SXsinJ
[Q1]
[Q1] [Q2]
TOCSY vs. NOESY
• Magnetization transfer mechanism:
TOCSY: J-coupling (Through bond)
NOESY: NOE effect (Through space)
• 3D NOESY-TOCSY
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Cross Relaxation in NOESY
preparation evolution(t1) mixing acquisition(t2)
d I t
dtI t I tkz
k kz kj jzj k
( )( ) ( )
k kj
k j
I I a S az z II m z IS mm ( ) ( )
Solomon Equation
IS
NOE c
IS cr
202 4
2 602 240
16
1 4
Pulse sequence & Product Operator Analysis
CtItII zyt
y @)sin()cos( 11111111
BIAI y
x
z @@ 12
1
t1 t2 1 2
1 2 3 4
DtItItI z
Ix
zy @)cos()sin()cos( 1112
111111
tI zm)cos( 111
EtaItIK
kmkkzz
m @)cos()()cos( 111
1111
t1 t2m 1 2
P+1
0
-1
EDA B C F
EtaIK
kmkkz @)cos()( 11
11
FtaItaIK
kmkkymy @)cos()()cos()( 11
2111111
Fig. 1 pulse sequence and coherence level diagram for the NOESY experiment.
Cross peaks
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NOESY Spectrum
Axes:1H chemical shift
Cross peaks d(1HA-1HB) <5 Ao
Fig. 2 A expansion of a NOESY spectrum
Diagonal peaks (1HA, 1HB) when 1HA = 1HB
7.1 Sensitivity in Heteronuclear Correlation 2D NMR
• S/N ex det3/2[1 –exp(-R1exTc)]
H ~4C ~10N
Relative S/N
• Ex 1H Det 1H 32• Ex 1H Det 13C 4• Ex 13C Det 13C 1
Relative S/N
• Ex 1H Det 1H 330• Ex 1H Det 15N 10• Ex 15N Det 15N 1
[Q1]
[Q2]
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HMQC/2Y
I
Y
/2Y /2Y
σ(0) = IZ
H = SSZ + 2JIZSZ
S
Y Y
t1
↑ ↑ ↑
IX 2IYSZ
1 3 4↑2 ↑5 6↑
IX 2IYSZ
2IYSX
2IY(cSX +sSY) 2IY(-cSZ +sSY) IXcosSt1
X6: cosSt1{IXcosIt2+ IYsinIt2}Q6
t1 tmix
IX 2IYSZ
2IYSX
How do you select signals only from the DQ coherence
2IYSZ IX
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Basic HSQC
/2Y Y
I
S
Y
/2Y /2Y
t1
Cf. HMQC
HSQC/2X
Y
I
/2Y/2Y X
H = SSZ + 2JIZSZ
S
Y /2Y
t1
/2Y X
IZ – /2IX (Q1)(Q1) – 2JIZSZ2 (Q2)(Q2) – 3/2IY (Q3)(Q3) – 3/2SY 2IZSX
2IZSX – SSZt1 (Q4)
J2 = /2
Single Quantum Coherence
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HSQC/2X Y
I
/2Y /2Y X
H = SSZ + 2JIZSZ
S
J2 = /2
Y /2Y
t1
/2Y X
2IZSX – SSZt1 c2IZSX+ s(Q6)c2IZSX+ s(Q6) – /2IY -c2IXSX+ s(Q6) – /2SYc2IXSZ+ s(Q7) –2JIZSZ2 (Q8)
6.2 COSY with couplingI: 90Y – t1 – 90X – t2 –
I1Z – /2IY I1X
I1X –1I1Zt1 I1Xcos1t1 +I1Ysin1t1I1X 1I1Zt1 I1Xcos1t1 I1Ysin1t1
–2JI1ZI2Zt1 {I1Xcos(Jt1)+ 2I1YI2Z[Q1] }cost1+ {I1Ycos(Jt1) + [Q2] }sint1
– /2IX {I1Xcos(Jt1) -2I1ZI2Y[Q1]}cost1+ {I1Zcos(Jt1) + [Q3] }sint1
p+1
-10
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6.2 COSY with couplingI: 90Y – t1 – 90X – t2 –I1Z – /2IY I1X
I1X –1I1Zt1 I1Xcos1t1 +I1Ysin1t1–2JI1ZI2Zt1 {I1Xcos(Jt1)+ 2I1YI2Z[Q1] }cost1
+ {I1Ycos(Jt1) + [Q2] }sint1– /2IX {I1Xcos(Jt1) - 2I1ZI2Ysin(Jt1)}cost1
+ {I1Zcos(Jt1) + [Q3] }sint1
cos(Jt1)cost1 = {cos(Jt1+t1)+ cos(Jt1-t1)}/2
sin(Jt1)cost1 = {sin(Jt1+t1) - sin(t1 - Jt1)}/2
Absorbance
Dispersion
Problem of COSY?
Diagonal Peak DispersionCross Peak Absorbance
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6.3.1 DQF-COSY (p437-449)
Remove Dispersive Diagonal Peaks by Only Selecting Double Quantum Coherence
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t1 tmix
How do you select signals only from the DQ coherence
DQF-COSY with couplingI: 90X – t1 – 90X –90X+- t2 –
I1Z – /2IX -I1Y
-I1X –IZt1 -I1Ycost1 +I1Xsint1
1X Z 1 1Y 1 1X 1
–2JI1ZI2Zt1 {-I1Ycos(Jt1)+ 2I1XI2Z[Q1] }cost1+{I1Xcos(Jt1) - 2I1YI2Z[Q2] }sint1
– /2IX {-I1Zcos(Jt1) -2I1XI2Y sin(Jt1)}cost1+{I1Xcos(Jt1) + [Q4] }sint1
– /2IX {-I1Ycos(Jt1) -2I1XI2Zsin(Jt1)}cost1+{-I1Xcos(Jt1) + [Q4] }sint1
2I1XI2 = 1/2{(2I1XI2Y + 2I1YI2X) +(2I1XI2Y - 2I1YI2X)}
DQ ZQDQ – /2IX (2I1XI2Z + 2I1ZI2X)
–2JI1ZI2Zt2 sin(Jt2) (I1Y + I2Y)
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IY
-IX-IX
-IYcos +IXsin
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-IYcos +IXsin
Pulse Phase & Receiver Phase
<I+> =< IX> + i<IY> <I+> ={< IX> + i<IY>}e-i
Receiver Phase:
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Effects of Phase Shift in General Case
p IX qp q
I
p IX+ exp{-i(q-p)} q
p IX q
p IX+ exp{-i(q-p)} q
Q – P
0
Effects of Phase Shift =0 =/2 = =3/2
0
1
2
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Phase Shift of RF Pulse• U RF() = exp(-iI) ; = /2
= RZ()exp(-iIX) RZ-1()
U RF-1() = RZ()exp(iIX)RZ
-1()
URF()IZURF-1() =
RZ() exp(-iIX)RZ-1()IZRZ() exp(iIX) RZ
-1()
R ( ) ( iI )I (iI ) R 1( )= RZ() exp(-iIX)IZ exp(iIX) RZ-1()
= RZ()IYRZ-1()
= IY+
The Effects of Phase ShiftRZ
-1()pRZ () = RZ-1()|m+p><m|RZ ()
= exp(iIZ)|m+p><m|exp(-i IZ)= exp{i(m+p))|m+p><m|exp(-im)
p IX q
I e p{i (p q)}
exp{i(m p))|m p><m|exp( im)= exp{i(m+p-m)}|a><b| = exp(ip)|a><b|= exp(ip)p
p IX+ exp{i(p-q)} q
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Phase shift of RF Pulse
• U RF() = exp(-iI) ; = /2
= RZ()exp(-iIX) RZ-1()
URF() p URF-1()
=RZ() exp(-iIX)RZ-1() p RZ() exp(iIX)RZ
-1()
= RZ() exp(-iIX) p exp(iIX)RZ-1()exp(ip)
= RZ() (q ) RZ-1() exp(ip)
= q exp[i(p-q)]
Coherence Selection by Phase Cycle
UXRF()pUXRF-1() = q
URF()pURF-1() = qexp{-i(q-p)}
= qexp{-ip} (4.32)
UXRF()pUXRF-1() = p+1 + p+2
U RF() U RF-1() = [Q1]URF()pURF () = [Q1]
UXRF()pUXRF-1() = p + p+2
URF()pURF-1() = [Q2]
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3D NOESY-HSQC
Ii Ij Sj Ij(t1) (t2) (t3)
NOE JIS JIS
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3D Triple Resonance Experiments
3D Triple Resonance
• Bax Coworkers ~ 1990
• Target ~ 30 kDa
• With deuteration 60-1 MDa
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Naming of 3D Triple-Resonance Experiments
The spins frequency labeled in the t1-t3i d l b l dperiods are labeled as
HN, N, HA, CA, CO, HB, CB
The spins not frequency labeled are placed in parenthesesin parentheses
(HN)-N-(CO)-C-(CO)-(N)-HN
HNCAHN(CO)CA
Two Type of Experiments
“Out & Back”
(HN) N CA (N) HNOut transfer & Back transfer
“Straight-Through”
HNCA
Straight Through
HA (CA) N HN
H(CA)NH
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3D HNCA
4-9 Hz7 11 Hz
(1HN) 15N 13CA (15N) 1HN
7-11 Hz
A 1HN/13CA slice in HNCA for ubiquitin(15N = 121.6 ppm)
13CA
1HN
Q. How can you read the spectrum?
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Transfer Efficiency from 1HN to 13CA
A 1HN/13CA slice in HNCA for ubiquitin(15N = 121.6 ppm)
13CACA for G47
CA for K48
1HN for K48
1HN
Q. How can you read the spectrum?
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a
b
c
e
a)
b)
JNCJHN JNC JHN
b)
c)
e)
Application: HNCO2D 1H/13CO projection 3D 1H/13CO Slice at 15N shift of 119.7 ppm
Kay L.E. et al; J. Mag. Res. 89, 496-514 (1990)