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Class 9: Class 9: Area, Consumer Surplus, Integration Area, Consumer Surplus, Integration -1.2 -10 q D(q) Demand Function Revenue q D(q)

Class 9: Area, Consumer Surplus, Integration

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Demand Function. D ( q ). Revenue. D ( q ). q. q. Class 9: Area, Consumer Surplus, Integration. Demand Function. Total Possible Revenue. What is Total Possible Revenue?. - PowerPoint PPT Presentation

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Page 1: Class  9:  Area, Consumer Surplus, Integration

Class 9: Class 9: Area, Consumer Surplus, IntegrationArea, Consumer Surplus, Integration

-1.2

-10 q

D(q)

Demand Function

Revenue

q

D(q)

Page 2: Class  9:  Area, Consumer Surplus, Integration

What is Total Possible Revenue?What is Total Possible Revenue?

-1.2

-8

Demand Function

Total PossibleRevenue

The total possible revenue is the money that the producer would receive if everyone who wanted the good, bought it at the maximum price that he or she was willing to pay.

Page 3: Class  9:  Area, Consumer Surplus, Integration

Consumer SurplusConsumer Surplus

-1.2

-8q

D(q)

Revenue

ConsumerSurplus

NotSold

Demand Function

The total extra amount of money that people who bought the good would have been willing to pay is called the consumer surplus.

Page 4: Class  9:  Area, Consumer Surplus, Integration

Finding AreasFinding Areas

What is the area of the region R that is enclosed between the x-axis and the graph of f(x) = 2x x2/2, for x between 1 and 4?

1 4

2

1 R

Page 5: Class  9:  Area, Consumer Surplus, Integration

Finding AreasFinding Areas

What is the area of the region R that is enclosed between the x-axis and the graph of f(x) = 2x x2/2, for x between 1 and 4?

1 4

2

1 R

Page 6: Class  9:  Area, Consumer Surplus, Integration

For n = 6 rectangles

1 4

2

1

1.5 2 2.5 3 3.5

1 4

2

1

x0 x6x2x1 x3 x4 x5

m1 m6m2 m3 m4 m5

f m1( )

{x

Sum of areas called S6

= f(m1)x + f(m2)x + f(m3)x + f(m4)x + f(m5)x + f(m6)x

= 4.531250.

Page 7: Class  9:  Area, Consumer Surplus, Integration

More rectangles: Larger n

1 4

2

1xmfS

n

iin

1

)(

As n increases, the value of Sn increases, getting closer and closer to the true are under the curve.

Page 8: Class  9:  Area, Consumer Surplus, Integration

Integral NotationIntegral Notation

We write the value of the midpoint sum as n gets very large by an integral

bx ax xfdxxfb

a and between )(under Area)(

Page 9: Class  9:  Area, Consumer Surplus, Integration

Find Revenue from Buffalo Dinners Not Sold:Optimum price and quantity are $19.19 and 2300

0 1000 2000 3000 4000 5000

$8

$16

$24

$32

NotSold

ConsumerSurplus

q = 2,300

D(2,300) = $19.99

Revenue$45,977

2,300

$19.99 Demand Function

D(q) = 0.0000018q2 0.0002953q + 30.19

$0

014,4

300,2

643,18$)(SoldNot dqqD

4014

Page 10: Class  9:  Area, Consumer Surplus, Integration

Find Consumer Surplus for Dinners

0 1000 2000 3000 4000 5000

$8

$16

$24

$32

NotSold

ConsumerSurplus

q = 2,300

D(2,300) = $19.99

Revenue$45,977

2,300

$19.99 Demand Function

D(q) = 0.0000018q2 0.0002953q + 30.19

$0

.379,15$977,45$356,61$)()(Surplus

Consumer300,2

0

qRdqqD