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Chapter 6

Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

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Page 1: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Chapter 6

Page 2: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Chapter 6.1 Law of SinesIn Chapter 4 you looked at techniques for solving right

triangles.

In this section and the next section you will solve oblique triangles.

Oblique triangles are triangles that have no right angle.

As standard notation, the angles of a triangle are labeled A, B,and C and their opposite angles are labeled a,b,and c.

C

AB

ab

c

Note: Angle A is between b and c, B is between a and c, C is between a and b.

Page 3: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Chapter 6.1 Law of Sines

To solve an oblique triangle, you need to know the measure of at least one side and the measures of any two other parts of the triangle- two sides, two angles, or one angle and one side.

This breaks down into four cases:1. Two angles and any side (AAS or ASA)

2. Two sides and an angle opposite one of them (SSA)

3. Three sides (SSS)

4. Two sides and their included angle (SAS)

Page 4: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Derive Law of Sines

Page 5: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Chapter 6.1 Law of Sines1

NOTE: The Law of Sines can also be written in the

reciprocal form sin sin sinA

a

B

b

C

c

Page 6: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Example #1 GIVEN: Two Angles and One Side-AASC=102.3°, B=28.7°, and b=27.4 feet

Find the remaining angle

and sides

A=180° - B - C

=180° -

By the Law of Sines you

havea

A

b

B

c

Csin sin sin

Page 7: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Try #3 page 398Use Law of Sines to Solve the triangleGIVEN: A=10°, a=4.5, B=60°

Page 8: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Example#2 GIVEN: Two Angles and One Side-ASA

A pole tilts toward the sun at an 8° angle from the vertical, and it casts a 22 foot shadow. The angle of elevation from the tip of the shadow to the top of the pole is 43°. How tall is the pole?

Page 9: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Try #27 page 398Use Law of Sines to Solve the triangle

Page 10: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

The Ambiguous Case (SSA)If two sides and one opposite angle are given, three possible situations can occur: (1) no such triangle exists, (2) one such triangle exists, or (3) two distinct triangles satisfy the conditions

Page 11: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Example #3 Single-Solution Case (SSA)

One solution: a > b

Page 12: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Try #15 page 398Use Law of Sines to Solve the triangle

Page 13: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Example #4 No-Solution Case – SSA Show that there is no triangle for which a = 15, b = 25, and A = 85º

No solution a < h

Page 14: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Try #17 page 398Use Law of Sines to Solve the triangle

Page 15: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Example #5 Two Solution CaseFind two triangles for which a = 12 meters, b = 31 meters, and A = 20.5º

Page 16: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Try #19 page 398Use Law of Sines to Solve the triangle

Page 17: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Area of a Oblique Triangle

A rea base heigh t1

2( )( )

Page 18: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Example #6 Area of an Oblique TriangleFind the area of a triangular lot having two sides of lengths 90 meters and 52 meters and an included angle of 102°

CabArea sin2

1

Page 19: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Try #21 page 398Find the area of the triangle

Page 20: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Example #7 An Application of the Law of SinesThe course for a boat race starts at point A and proceeds in the direction S 52° W to point B, then in the direction S 40° E to point C, and finally back to A. Point C lies 8 kilometers directly south of point A. Approximate the total distance of the race course.

Page 21: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

Try #29 page 398Use Law of Sines to Solve the triangle

Page 22: Chapter 6. Chapter 6.1 Law of Sines In Chapter 4 you looked at techniques for solving right triangles. In this section and the next section you will solve

THEEND