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WorkConservation of Energy
can never get more work out than you put in
trade-off between force and distance
Win = Wout
Fe × de = Fr × dr
EfficiencyEfficiency
measure of how completely work input is converted to work output
100%WW
Efficiencyin
out
always less than 100% due to friction
Force
Effort Force (Fe)force applied to the machine“what you do”
Resistance Force (Fr)force applied by the machine“what the machine does”
Mechanical AdvantageMechanical Advantage (MA)
number of times a machine increases the effort force
e
r
FF
MA
MA > 1 : force is increasedMA < 1 : distance is increasedMA = 1 : only direction is changed
Mechanical Advantage Find the effort force needed to lift a
2000 N rock using a jack with a mechanical advantage of 10.
GIVEN:
Fe = ?
Fr = 2000 N
MA = 10
WORK:Fe = Fr ÷ MA
Fe = (2000 N) ÷ (10)
Fe = 200 N
MA
Fr
Fe
LeverLever
a bar that is free to pivot about a fixed point, or fulcrum
“Give me a place to stand and I will move the Earth.”– Archimedes
Engraving from Mechanics Magazine, London, 1824
Effort arm
Resistancearm
Fulcrum
Lever Ideal Mechanical Advantage (IMA)
frictionless machine
r
e
LL
IMA Effort arm length
Resistancearm length
Le must be greater than Lr in order to multiply the force.
Problems You use a 160 cm plank to lift a
large rock. If the rock is 20 cm from the fulcrum, what is the plank’s IMA?
GIVEN:
Lr = 20 cm
Le = 140 cm
IMA = ?
WORK:IMA = Le ÷ Lr
IMA = (140 cm) ÷ (20 cm)IMA = 7
IMA
Le
Lr
20cm
160cm
Problems You need to lift a 150 N box using
only 15 N of force. How long does the lever need to be if the resistance arm is 0.3m?
GIVEN:
Fr = 150 N
Fe = 15 N
Lr = 0.3 m
Le = ?
MA = 10
WORK:Le = IMA · Lr
Le = (10)(0.3)
Le = 3 m
Total length = Le + Lr
Total length = 3.3 mIMA
Le
Lr
0.3m
?
150N
15N
Wheel and AxleWheel and Axle
two wheels of different sizes that rotate together
a pair of “rotatinglevers”
Wheel
Axle
Wheel and Axle Ideal Mechanical Advantage
(IMA) effort force is usu. applied to wheel axle moves less
distance but with greater force
a
w
rr
IMA effort radius
resistance radius
Problems A crank on a pasta maker has a
radius of 20 cm. The turning shaft has a radius of 5 cm. What is the IMA of this wheel and axle?
GIVEN:
rw = 20 cm
ra = 5 cm
IMA = ?
WORK:IMA = rw ÷ ra
IMA = (20 cm) ÷ (5 cm)IMA = 4
IMA
rw
ra
5 cm 20 cm
Problems A steering wheel requires a
mechanical advantage of 6. What radius does the wheel need to have if the steering column has a radius of 4 cm?
GIVEN:
IMA = 6rw = ?
ra = 4 cm
WORK:rw = IMA · ra
rw = (6)(4 cm)
rw = 24 cm
IMA
rw
ra
rarw