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Chapter 3. Section 1 Graphing Systems of Equations. Graph each equation. 1. y = 3 x – 2 2. y = – x 3. y = – x + 4 Graph each equation. Use one coordinate plane for all three graphs. 4. 2 x – y = 1 5. 2 x – y = –1 6. x + 2 y = 2. 1 2. Lesson Preview p. 116. - PowerPoint PPT Presentation
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Chapter 3
Section 1
Graphing Systems of Equations
Lesson Preview p. 116Graph each equation.
1. y = 3x – 2 2. y = –x 3. y = – x + 4
Graph each equation. Use one coordinate plane for all three graphs.
4. 2x – y = 1 5. 2x – y = –1 6. x + 2y = 2
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Lesson Preview Answers
1. y = 3x – 2 2. y = –xslope = 3 slope = –1y-intercept = –2 y-intercept = 0
3. y = – x + 4 4. 2x – y = 1
slope = – –y= –2x + 1
y-intercept = 4 y = 2x – 1
5. 2x – y = –1 6. x + 2y = 2–y = –2x – 1 2y = –x + 2y = 2x + 1 y = – x + 1
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Graphing Systems of Equations
Systems of Equations – a set of two or more equations that use the same variable
Linear system – a system where the graph of each equation in a system of two variables is a lineA brace is used to keep the equation system
together
32
3
xy
xy
Solutions to Systems of Linear Equations A solution of a system of equations is a set
of values for the variables that makes all the equations true.
One way to solve linear systems is by graphing -the solution is the point(s) where the graphs intersect
Solve the system by graphing.
x + 3y = 23x + 3y = –6
Check: Show that (–4, 2) makes both equations true.
Graph the equations and find the intersection. The solution appears to be (–4, 2).
x + 3y = 2 3x + 3y = –6(–4) + 3(2) 2 3(–4) + 3(2) –6
(–4) + 6 2 –12 + 6 –6 2 = 2 –6 = –6
3
2
3
1
23
23
xy
xy
yx
2
633
633
xy
xy
yxHere are the equations solved for slope intercept form:
Check Understanding p. 117
Solve by graphing. Check your solution.
2
52
yx
yx
2
52
xy
xygraph
Step1:
Graph the equations (slope-intercept form is nice) Step 2: Locate where the
two graphs intersect
Step 3: Name the coordinate point
(1,3)
Step 4: Check in both equations for accuracy.
55
532
53)1(2
52
yx
22
231
2
yx
Classifying Systems -by the number of solutions (graphing)
Independent – the system has one solution (only one coordinate pair will work for all equations). These lines intersect in one point.
Dependent – the system has no unique solutions (there is more than one coordinate pair that will work). These are graphed as coinciding lines.
Inconsistent – the system has no solution (no coordinate pair will work). These lines are parallel.
Classify the System
Independent
One Solution
Dependent
No Unique Solution
(All points of line are solutions)
Inconsistent
No Solution
Classifying Systems without Graphing-comparing slopes and intercepts
Independent – Different slopes
m ≠
Dependent – Equal slopes Equal y-intercepts
m = b =
Inconsistent – Equal slopes Different y-intercepts
m = b ≠
Step 1: Solve for slope intercept form
Step 2: Write clearly m= and b= for each equation
Step 3: Compare slopes and intercepts
Classify the system without graphing.
Since the slopes are the same, compare the y-intercepts.
y = 3x + 2–6x + 2y = 4
y = 3x + 2 –6x + 2y = 4Rewrite in slope-intercept form. y = 3x + 2
m = 3, b = 2 Find the slope and y-intercept. m = 3, b = 2
Since the y-intercepts are the same, the lines are dependent.
Homework