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Chapter 16 Notes 1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can be neutral, basic, or acidic 2. common ion effect; buffers: common ion reduces % ionization of weak acid; buffers: neutralization plus weak acid/base equilibrium 3. titrations: acid (base) is systematically and quantitatively added to base (acid) in order to determine the concentration

Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

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Page 1: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 1

Chapter 16 Aqueous Equilibria: Applications1. neutralization reactions: K large, ~100% completion due to formation of water; salts can be neutral, basic, or acidic

2. common ion effect; buffers: common ion reduces % ionization of weak acid; buffers: neutralization plus weak acid/base equilibrium

3. titrations: acid (base) is systematically and quantitatively added to base (acid) in order to determine the concentration of the base (acid)

Page 2: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 2

strong acid - strong base:1. examples: HCl with NaOH; HClO4 with KOH; NaOH with HNO3

2. salts: all neutral therefore NO acid-base equilibria; the chemistry is all neutralization

3. the pH titration curve: plot pH (y-axis) vs. volume added base (x-axis)

Page 3: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 3

Titration Curve: Strong Acid with Strong Base

02468

101214

0 10 20 30 40 50 60

volume added base (ml)

pH

a.

b.c.

a. before adding baseb. halfway to equivalence pointc. 1 ml before equivalence point

d.

e.

f.

d. equivalence pointe. 1 ml after equivalence point(f. beyond equivalence point)

Page 4: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 4

example: 40.0 ml of 0.10 M HCl is titrated with 0.10 M NaOH; calculate pH at points a-f.Hints:•Don’t forget dilution!•Calculate pH as though adding base from the beginning.•What volume NaOH is required to reach equivalence point?a. before adding base

pH=-log[H1+]=-log(0.10)=1.00

b. halfway to equivalence point: 20.0 ml added base (total)chemistry : H1+ + OH1- H2O

c. 1 ml before equivalence point: 39.0 ml added base (total)chemistry :

Page 5: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 5

d. equivalence point: 40.0 ml added base (total)chemistry :

e. 1 ml after equivalence point (total)chemistry :

f. beyond equivalence point (total)chemistry :

Page 6: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 6

0

2

4

6

8

10

12

14

0 10 20 30 40 50 60

volume added base (ml)

pH

note rapid change in pH near the equivalence point

Page 7: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

7

Titration Curve: Weak Acid with Strong Base

02468

101214

0 10 20 30 40 50 60

volume added base (ml)

pH a.c.

b.

buffer

a. before adding baseb. halfway to equivalence pointc. 1 ml before equivalence point

e.

d.

f.

d. equivalence pointe. 1 ml after equivalence point(f. beyond equivalence point)

Page 8: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 8

a. before adding base: pH of a weak acid (equilibrium)chemistry:

b. halfway to equivalence point:chemistry:

c. 1 ml before equivalence point:chemistry:

Page 9: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 9

d. equivalence point: chemistry:

[pH of a conjugate base of a weak acid; look up Kb or calculate using Kb=Kw/Ka]

e. 1 ml after equivalence point: chemistry:

[pH of a strong base (OH1- contribution from conjugate base is insignificant)]

(f. beyond equivalence point: see e.)

Page 10: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 10

0

2

4

6

8

10

12

14

0 10 20 30 40 50 60

volume added base (ml)

pH pH, strong acid

pH, weak acid

Note change in pH near equivalence point.

Contrast strong-strong and strong-weak: what are the 2 most important differences?

Page 11: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 11

Figure 16.7

Page 12: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 12

Figure 16.8

Page 13: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 13

Figure 16.9: Titration of weak base with strong acid

buffer: use base form of H-H equation

Page 14: Chapter 16 Notes1 Chapter 16 Aqueous Equilibria: Applications 1. neutralization reactions: K large, ~100% completion due to formation of water; salts can

Chapter 16 Notes 14

Figure 16.9: Titration of polyprotic weak acid with strong base

pH=(pKa1+pKa2)/2