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Chapter 15 – Series & Parallel ac Circuits
Chapter 16 – Series–Parallel ac Networks
Lecture 22
by Moeen Ghiyas
19/04/23 1
Chapter 15 – Series & Parallel ac Circuits
Chapter 15 - Series & Parallel ac Circuits
Equivalent Circuits
Chapter 16 - Series-Parallel ac Networks
Reduction Methods
Ladder Networks
Assignment # 4 - Submission by 10:30 am 23 Apr
19/04/23 3
The term equivalent refers only to the fact that for the same
applied potential, the same impedance and input current will
result (in the equivalent circuit).
Whether a series or parallel ac circuit, the total impedance of
two or more elements in series is often equivalent to an
impedance that can be achieved with fewer elements of
different values
However, the equivalent elements and their values are
determined by the frequency applied.
For example, for circuit of fig
The total impedance at the frequency
applied is equivalent to a capacitor
with a reactance of 10Ω , as shown
Always keep in mind that this equivalence is true only at
the applied frequency. If the frequency changes, the
reactance of each element changes, and the equivalent
circuit will change — perhaps from capacitive to inductive
in the above example
Another interesting example,
which is the impedance of a
series circuit with a resistor of
1.92Ω and an inductive
reactance of 1.44Ω , as shown
Current I will be same in equivalent circuit for same input voltage E
For a parallel circuit of one resistive element and one reactive
element, the series circuit with the same input impedance will
always be composed of one resistive and one reactive element.
The impedance of each element of the series circuit will be different
from that of the parallel circuit, but the reactive elements will always
be of the same type; i.e., an R-L circuit and an R-C parallel circuit
will have an equivalent R-L and R-C series circuit respectively
The same is true when converting from a series to a parallel circuit.
The equivalent series circuit for a resistor and reactance in parallel
can be found by determining total impedance in rectangular form;
The equivalent parallel circuit for a resistor and reactance in series
can be found by determining total admittance in rectangular form;
See proof in book
Determine YT.
Determine YT. - Network is redrawn with phasor notation
Determine YT. - The admittance Y is
Sketch the admittance
diagram.
Find E and IL.
Compute the power factor of the network and the power delivered.
Determine the equivalent series circuit as far as the terminal
characteristics of the network are concerned.
Determine the equivalent series circuit as far as the terminal
characteristics of the network are concerned.
Determine the equivalent parallel network from the equivalent
series circuit, and calculate the total admittance YT
Determine YT for the equivalent parallel circuit.
Chapter 16 – Series–Parallel ac Networks
Reduce the network to the fundamental structure preferably
towards source to determine the total impedance of the network
and redraw network by combining series and parallel elements.
The source current and voltages can then be determined.
Later work back (Expand) from the source through the network to
find specific quantities.
When you have arrived at a solution, check to see that it is
reasonable by considering the magnitudes. If not, either solve the
network using another approach, or check over your work very
carefully
EXAMPLE - For Fig :
a. Calculate the current Is
b. Find the voltage Vab
Solution
Simplify the circuit and redraw
In this case the voltage Vab is lost in
the redrawn network, which will be
worked backwards later
Now we know Z1 = 5Ω /53.130
and Z2 = 10Ω / -36.870
Determine ZT
Calculate I or IS
Now we know Z1 = 5Ω /53.130
and Z2 = 10Ω / -36.870
and IS = 22.36 A /-26.560
Determine branch currents using ohms law
Now I1 and I2 known
Working backwards to original cct
To find Vab apply KVL,
EXAMPLE - For the network of Fig
a. Compute I.
b. Find I1, I2, and I3.
c. Verify KCL by showing that I = I1 + I2 + I3
d. Find the total impedance of the circuit.
EXAMPLE - For the network of Fig
Redrawing the circuit reveals a parallel circuit
Calculate Impedances to determine currents
The total admittance is
The current I becomes
Since the voltage is same across parallel branches
c. Verify by KCL
d. Find the total impedance of the circuit
A general sinusoidal ac ladder network is as shown. The current I6 is
desired.
ac ladder network with ZT, ZT’, ZT” and currents I, I3 defined.
Determining impedances and then working backwards calculating
currents to finally know the current I6 as desired.
Ch 15 - Q. 17, 23, 31
Ch 16 - Q. 11, 13
Submission by 09:00 am 23 Apr 2012
19/04/23 35
Chapter 15 - Series & Parallel ac Circuits
Equivalent Circuits
Chapter 16 - Series-Parallel ac Networks
Reduction Methods
Ladder Networks
Assignment # 4 - Submission by 10:30 am 23 Apr
19/04/23 37