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Chapter 13
InventoryManagement
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Inventory
Stock of items kept by anorganization to meet internal or
external customer demand. Inventory management answers
two questions
How much to orderWhen to order
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Types of Inventory
Raw materials
Purchased parts and supplies
Labor
In-process (partially completed) products
Component parts
Working capital
Tools, machinery, and equipment
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Reasons to Hold
InventoryMeet unexpected demand
Smooth seasonal or cyclical demand
Meet variations in supplier deliveries
Take advantage ofprice discounts
Hedge against priceincreases
Quantity discounts
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Two Forms of Demand
Dependent
Items used internally to produce finalproducts
Independent Items demanded by external customers
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Inventory CostsCarrying Cost/Holding Cost
Cost of holding an item in inventory
Ordering Cost Cost of replenishing inventory
Shortage Cost/Stock Out cost
Temporary or permanent loss ofsales when demand cannot be met
Set Up Cost
Costs for arranging specifice ui ment setu s, etc
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Carrying Cost Cost of holding an item in inventory
Cost depends on Quantity of inventory
Length of time
Cost that increases linearly the number of units
Examples Facility of Storage ( rent, power, heat cooling etc)
Material Handling Equipment
Labor
Record keeping
Production deterioration, spoilage
Two ways to specify carrying cost
Assign total carrying cost(sum all the individual cost on perunit per time bases. (Example Rs 10 per unit per year)
Percentage of value of an item or % of average inventory
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Ordering Cost The cost of replenishing inventory
Expressed as amount/order and areindependent of the order size.
Any cost that increases linearly with
number of orders
Examples Requisition and purchase order
Transportation and shipping Receiving
Inspection
Handling
Accounting and auditing
Increase in order size , decrease in order cost, increase in carrying
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Shortage Cost
Temporary or permanent loss ofsales when demand can not be met
Result into
loss of profit Customer dissatisfaction
Loss of goodwill
Permanent loss of customer and futuresale
Work stopage result into downtimecost and cost of lost production
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10
Single-Period Inventory Model One time purchasing decision (Example:
vendor selling t-shirts at a football game)
Seeks to balance the costs of inventory
overstock and under stock Multi-Period Inventory Models
Fixed-Order Quantity Models
Event triggered (Example: running out of
stock) Fixed-Time Period Models
Time triggered (Example: Monthly sales callby sales representative)
11
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11
uo
u
CC
CP
soldbeunit willy that theProbabilit
estimatedunderdemandofunitperCostCestimatedoverdemandofunitperCostC
:Where
u
o
P
This model states that we
should continue toincrease the size of theinventory so long as theprobability of selling the
last unit added is equal toor greater than the ratioof: Cu/Co+Cu
12
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12
Our college basketball team is playing in atournament game this weekend. Based on ourpast experience we sell on average 2,400 shirtswith a standard deviation of 350. We make Rs100
on every shirt we sell at the game, but lose Rs50on every shirt not sold. How many shirts shouldwe make for the game?Cu=Rs100 and Co= Rs50; P 100 / (100 + 50) = .667
Z.667 = .432 (use NORMSDIST(.667) or Appendix E)therefore we need 2,400 + .432(350) = 2,551 shirts
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Inventory ControlSystems (Multi Period
Inventory Models)Continuous system (fixed-order-
quantity Model/ Perpetual system/EOQor Q Model)
Periodic system (fixed-time-period/Period Review system/P Model)
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Continuous System
Constant amount ordered when inventory declines toreorder point (predetermined level)
The order that is placed is of fixed amount that
minimize the total inventory cost. This amount iscalled EOQ(Economic Order Quantity).
Positive features is continuous monitoring.
Negative aspect :: maintaining a continuous
record is costly Check out system with a laser scanner used by
super malls
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Periodic system
Order placed for variable amount after fixedpassage of time
Decision of order quantity is taken each timewhen order is placed
No need to monitor inventory in betweenthe time intervals
Positive aspects :: no need of recordkeeping, larger inventory level to guardagainst unexpected stockouts
Disadvantage :: less direct control
Exam le :: Colle e bookstore
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ABC Classification
System An inventory classification system wheresmall % of items account for most of theinventory value
Demand volume and value of items vary Classify inventory into 3 categories,
typically on the basis of the dollar valueto the firm
PERCENTAGE PERCENTAGECLASS OF UNITS OF DOLLARS
A 5 - 15 70 - 80B 30 15
C 50 - 60 5 - 10
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Each class requires different level of
inventory monitoring and control
the higher the value of the inventorythe tighter the control
Rationale for ABC Classification ::
Continuous inventory monitoring wasexpensive and not justified for manyitems
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First Step in ABC Analysis is to classify allinventory items as either A,B or C
Assign a dollar value to each item, which is computedby multiplying the dollar cost of one unit by the annualdemand for that item.
Rank all the items according to their annual dollar value( the top 10% as A items, the next 30% as B items andthe last 60% as C items
Second Step is to determine the level of inventorycontrol for each classification
Class A ::
tight inventory control.
Inventory level should be as low as possible,
minimized safety stock
Need accurate demand forecast and detailed recordkeeping
Appropriate inventory ctrl system and inventory modelingprocedure should be used to determine the order quantity
Close attention to be given to purchasing policies andprocedures
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Class B and C need less stringent inventory
control
Carrying cost of Class C is usually lower,therefore it is possible to maintain a largersafety stock
No need to control C items beyond simpleobservation
Apart from cost, the scarcity of parts
or difficulty of supply may also bereasons for giving high priority
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ABC Classification
1 $ 60 902 350 40
3 30 1304 80 605 30 1006 20 1807 10 1708 320 509 510 60
10 20 120
PART UNIT COST ANNUAL USAGE
Example 10.1
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ABC Classification
Example 10.1
1 $ 60 902 350 403 30 1304 80 605 30 1006 20 1807 10 170
8 320 509 510 60
10 20 120
PART UNIT COST ANNUAL USAGETOTAL % OF TOTAL % OF TOTALPART VALUE VALUE QUANTITY % CUMMULATIVE
9 $30,600 35.9 6.0 6.08 16,000 18.7 5.0 11.02 14,000 16.4 4.0 15.0
1 5,400 6.3 9.0 24.04 4,800 5.6 6.0 30.03 3,900 4.6 10.0 40.06 3,600 4.2 18.0 58.05 3,000 3.5 13.0 71.0
10 2,400 2.8 12.0 83.07 1,700 2.0 17.0 100.0
$85,400
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ABC Classification
Example 10.1
1 $ 60 902 350 403 30 1304 80 605 30 1006 20 1807 10 170
8 320 509 510 60
10 20 120
PART UNIT COST ANNUAL USAGETOTAL % OF TOTAL % OF TOTALPART VALUE VALUE QUANTITY % CUMMULATIVE
9 $30,600 35.9 6.0 6.08 16,000 18.7 5.0 11.02 14,000 16.4 4.0 15.0
1 5,400 6.3 9.0 24.04 4,800 5.6 6.0 30.03 3,900 4.6 10.0 40.06 3,600 4.2 18.0 58.05 3,000 3.5 13.0 71.0
10 2,400 2.8 12.0 83.07 1,700 2.0 17.0 100.0
$85,400
A
B
C
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ABC Classification
Example 10.1
1 $ 60 902 350 403 30 1304 80 605 30 1006 20 1807 10 170
8 320 509 510 60
10 20 120
PART UNIT COST ANNUAL USAGETOTAL % OF TOTAL % OF TOTALPART VALUE VALUE QUANTITY % CUMMULATIVE
9 $30,600 35.9 6.0 6.08 16,000 18.7 5.0 11.02 14,000 16.4 4.0 15.0
1 5,400 6.3 9.0 24.04 4,800 5.6 6.0 30.03 3,900 4.6 10.0 40.06 3,600 4.2 18.0 58.05 3,000 3.5 13.0 71.0
10 2,400 2.8 12.0 83.07 1,700 2.0 17.0 100.0
$85,400
A
B
C
% OF TOTAL % OF TOTAL
CLASS ITEMS VALUE QUANTITY
A 9, 8, 2 71.0 15.0B 1, 4, 3 16.5 25.0C 6, 5, 10, 7 12.5 60.0
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ABC Classification
100
80
60
40
20
0| | | | | |
0 20 40 60 80 100
% of Quantity
%o
fValue
A
B
C
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EOQ Model
A formula to determine the optimalorder size that minimizes the sum ofcarrying cost and ordering cost
Assumptions of Basic EOQ Model Demand is known with certainty and
is constant over time
No shortages are allowed
Lead time for the receipt of orders isconstant
The order quantity is received all atonce
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The Inventory Order Cycle
Time
Inventor
yLevel
Reorder point, R
Order quantity, Q
0
Figure 10.1
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The Inventory Order Cycle
Demandrate
TimeLeadtime
Leadtime
Orderplaced
Orderplaced
Orderreceipt
Orderreceipt
Inventor
yLevel
Reorder point, R
Order quantity, Q
0
Figure 10.1
28
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R = Reorder point
Q = Economic order quantity
L = Lead time
L L
Q QQ
R
Time
Number
of unitson hand
1. You receive an order quantity
Q.
2. Your startusing them up
over time.
3. When you reach down
to a level of inventory of
R, you place your next Q
sized order.
4. The cycle thenrepeats.
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EOQ Cost ModelCo
- cost of placing order D- annual demandCc
- annual per-unit carrying cost Q- order quantity
Annual ordering cost =
CoD
Q
Annual carrying cost =CcQ
2
Total cost = +
CoD
Q
CcQ
2
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EOQ Cost ModelCo
- cost of placing order D- annual demandCc
- annual per-unit carrying cost Q- order quantity
Annual ordering cost =
CoD
Q
Annual carrying cost =CcQ
2
Total cost = +
CoD
Q
CcQ
2
TC = +CoD
Q
CcQ
2
= +CoD
Q2
Cc
2
TC
Q
0 = - +C
0D
Q2
Cc
2
Qopt =2C
oD
Cc
Deriving Qopt Proving equality ofcosts at optimal point
=
CoD
Q
CcQ
2
Q2 =2C
oD
Cc
Qopt =2CoD
Cc
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H2
Q+S
Q
D+DC=TC
Total
Annual =
Cost
Annual
Purchase
Cost
Annual
Ordering
Cost
Annual
Holding
Cost+ +
TC=Total annual
cost
D =Demand
C =Cost per unit
Q =Order quantity
S =Cost of placing
an order or setup
costR =Reorder point
L =Lead time
H=Annual holding
and storage cost
per unit of inventory
32
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Using calculus, we take the first derivative of
the total cost function with respect to Q, andset the derivative (slope) equal to zero,solving for the optimized (cost minimized)
value of QoptQ =
2DS
H=
2(Annual D em and)(Order or Setup Cost)
Annual Holding CostO PT
R eorder point, R = d L_
d = average daily demand (constant)
L = Lead time (constant)
_
We also need areorder point totell us when toplace an order
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EOQ Cost Model
Order Quantity, Q
Annualcost ($)
Figure 10.2
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EOQ Cost Model
Figure 10.2
Order Quantity, Q
Annualcost ($)
Ordering Cost =
CoD
Q
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EOQ Cost Model
Order Quantity, Q
Annualcost ($)
Carrying Cost =
CcQ
2
Ordering Cost =
CoD
Q
Figure 10.2
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EOQ Cost Model
Slope = 0
Total Cost
Order Quantity, Q
Annualcost ($)
Minimumtotal cost
Optimal orderQopt
Carrying Cost =
CcQ
2
Ordering Cost =
CoD
Q
Figure 10.2
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EOQ Example
Cc
= $0.75 per yard Co
= $150 D= 10,000 yards
Qopt =2C
oD
Cc
Qopt =2(150)(10,000)
(0.75)
Qopt = 2,000 yards
TCmin = +CoD
Q
CcQ
2
TCmin = +(150)(10,000)
2,000
(0.75)(2,000)
2
TCmin = $750 + $750 = $1,500
Orders per year = D/Qopt
= 10,000/2,000
= 5 orders/year
Order cycle time = 311 days/(D/Qopt)
= 311/5
= 62.2 store days
Example 10.2
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EOQ with
Noninstantaneous Receipt
Q(1-d/p)
Inventorylevel
(1-d/p)Q2
Time0
Maximum
inventorylevel
Averageinventorylevel
Figure 10.3
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EOQ with
Noninstantaneous Receipt
Q(1-d/p)
Inventorylevel
(1-d/p)Q2
Time0
Orderreceipt period
Beginorder
receipt
Endorder
receipt
Maximum
inventorylevel
Averageinventorylevel
Figure 10.3
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EOQ with
Noninstantaneous Receiptp= production rate d= demand rate
Maximum inventory level = Q- d
= Q1 -
Q
p
dp
Average inventory level = 1 -
Q
2
d
p
TC= + 1 -dp
CoD
Q
CcQ
2
Qopt =
2CoD
Cc 1 - d
p
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Production QuantityCc
= $0.75 per yard Co
= $150 D= 10,000 yards
d= 10,000/311 = 32.2 yards per day p= 150 yards per day
Qopt = = = 2,256.8 yards
2CoD
Cc 1 - d
p
2(150)(10,000)
0.75 1 -32.2150
TC= + 1 - = $1,329dp
CoD
Q
CcQ
2
Production run = = = 15.05 days per orderQp
2,256.8
150
Example 10.3
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Production QuantityCc
= $0.75 per yard Co
= $150 D= 10,000 yards
d= 10,000/311 = 32.2 yards per day p= 150 yards per day
Qopt = = = 2,256.8 yards
2CoD
Cc 1 - d
p
2(150)(10,000)
0.75 1 -32.2150
TC= + 1 - = $1,329dp
CoD
Q
CcQ
2
Production run = = = 15.05 days per orderQp
2,256.8
150
Number of production runs = = = 4.43 runs/yearDQ
10,0002,256.8
Maximum inventory level = Q 1 - = 2,256.8 1 -
= 1,772 yards
d
p
32.2
150
Example 10.3
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Quantity Discounts Price per unit decreases as order
quantity increases
TC= + + PDCoDQ
CcQ2
where
P= per unit price of the itemD= annual demand
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Quantity Discounts Price per unit decreases as order
quantity increases
TC= + + PDCoDQ
CcQ2
where
P= per unit price of the itemD= annual demand
ORDER SIZE PRICE
0 - 99 $10100 - 199 8 (d1)
200+ 6 (d2)
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Quantity Discount Model
Figure 10.4
Inventorycost($)
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Quantity Discount Model
Figure 10.4
Qopt
Carrying cost
Ordering cost
Inventorycost($)
Q(d1 ) = 100 Q(d2 ) = 200
TC(d2 = $6 )
TC(d1 = $8 )
TC= ($10 )
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Quantity Discount
QUANTITY PRICE
1 - 49 $1,400
50 - 89 1,100
90+ 900
Co= $2,500
Cc= $190 per computer
D= 200
Qopt = = = 72.5 PCs2C
oD
Cc
2(2500)(200)
190
TC= + + PD= $233,784
CoD
Qopt
CcQopt
2
For Q= 72.5
TC= + + PD= $194,105CoD
Q
CcQ
2
For Q= 90
Example 10.4
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When to Order
Reorder Point is the level of inventoryat which a new order is placed
R= dL
where
d= demand rate per periodL = lead time
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Reorder Point Example
Demand = 10,000 yards/year
Store open 311 days/yearDaily demand = 10,000 / 311 = 32.154 yards/day
Lead time = L = 10 days
R = dL = (32.154)(10) = 321.54 yards
Example 10.5
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Safety Stocks
Safety stock
buffer added to on hand inventory during
lead time Stockout
an inventory shortage
Service level
probability that the inventory availableduring lead time will meet demand
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Variable Demand with
a Reorder Point
Figure 10.5
Reorder
point, R
Q
Time
Inventorylevel
0
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Variable Demand with
a Reorder Point
Figure 10.5
Reorder
point, R
Q
LT
Time
LT
Inventorylevel
0
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Reorder Point with
a Safety Stock
Figure 10.6
Reorderpoint, R
Q
LT
Time
LT
Inventorylevel
0
Safety Stock
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Reorder Point With
Variable DemandR= dL + z d L
where
d= average daily demandL = lead time
d= the standard deviation of daily demand
z= number of standard deviationscorresponding to the service levelprobability
z d L = safety stock
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Reorder Point for
a Service LevelProbability ofmeeting demand duringlead time = service level
Probability ofa stockout
R
Safety stock
dLDemand
z d L
Figure 10.7
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Reorder Point for
Variable DemandThe carpet store wants a reorder point with a95% service level and a 5% stockout probability
d= 30 yards per dayL = 10 days
d = 5 yards per day
For a 95% service level, z= 1.65
R= dL + z d L
= 30(10) + (1.65)(5)( 10)
= 326.1 yards
Safety stock = z d L
= (1.65)(5)( 10)
= 26.1 yards
Example 10.6
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Order Quantity for a
Periodic Inventory SystemQ= d(tb+ L) + z d tb+ L - I
where
d = average demand ratetb = the fixed time between ordersL = lead time
d = standard deviation of demand
z d tb+ L = safety stock
I = inventory level
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Fixed-Period Model with
Variable Demandd= 6 bottles per day
d = 1.2 bottlestb = 60 days
L = 5 daysI= 8 bottlesz= 1.65 (for a 95% service level)
Q= d(tb+ L) + z d tb+ L - I= (6)(60 + 5) + (1.65)(1.2) 60 + 5 - 8
= 397.96 bottles
60
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T+L d
i 1
T+L
d
T+L d
2
=
Since each day is independent and is constant,
= (T + L)
i
2
The standard deviation of a sequenceof random events equals the squareroot of the sum of the variances
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Average daily demand for a product
is 20 units. The review period is 30days, and lead time is 10 days.Management has set a policy ofsatisfying 96 percent of demand
from items in stock. At thebeginning of the review period thereare 200 units in inventory. The daily
Given the information below, how many
units should be ordered?