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8/14/2019 Chapter 11 Homework Answers
http://slidepdf.com/reader/full/chapter-11-homework-answers 1/2
Chapter 11 Homework answers
3) C has only 2s and 2p orbitals, which formulates a maximum of 4hybrid orbitals. Si has the 3d orbital in addition to the 3s and 3p, so itcan forum up to 6 orbitals.
7) a) sp2b)sp2c)sp2
13) sp3d s + 3p + d
sp2 s + 3p
15) I’ll upload this later, I have to figure out what I wrote
20) a) false, double bond = sigma bond + pi bondb) false, triple bond = sigma bond + 2 pi bondc) trued)truee) false, pi bond comes after sigma bondf) false, end to end electron sharing results in a bond with theelectron density along the boundaries
23) (I can’t draw on Word, so try and use the description. If youreally need it, I can go on WiZiQ and write it out on a whiteboard)
a) At the center is nitrogen. On one side of fluorine with a singlebond to nitrogen, and it has 6 electrons. On the left side isoxygen with a double bond, and it has 4 electrons. Nitrogen hasa sp2 hybridzation with 2 sigma bonds and a pi bind.b) At the center is two carbons, which are double bonded toeach other. Each carbon is also attached to two fluorine atoms. The fluorine atoms each have 6 electrons. The carbons have sp2hybrization, with 3 sigma bonds and 1 pi bond.c) There are two carbons in the center, which are single bondedto each other. Each carbon is also triple bonded to a nitrogen. The nitrogen also has 2 electrons. The carbons have sp
hybridzation, with 2 sigma bonds and 2 pi bonds.
25)
H3C HC = C Single C – H bond and C – C bond are
sigma bonds
H CH3 Double C – C bond is a sigma bond and a
8/14/2019 Chapter 11 Homework Answers
http://slidepdf.com/reader/full/chapter-11-homework-answers 2/2
pi bond Trans
(there is a double bond between the Cs and single bonds from thedouble bonds to the four on the sides)
H3C CH3C = C Single C – H bond and C – C bond are
sigma bonds
H C Double C – C bond is a sigma bond and api bond
cis(same thing here)