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CHAPTER 1 SIGLE-PHASE TRASFORMER 1.0 DEFIITIO OF TRASFORMER 1.1 COSTRUCTIO 1.2 PRICIPLE OF OPERATIO 1.3 FARADAY’S LAW AD LEZ’S LAW 1.3.1 FARADAY’S LAW 1.3.2 LENZ’S LAW 1.4 EMF EQUATIO 1.5 TRASFORMER EQUIVALET CIRCUIT MODEL 1.5.1 IDEAL TRANSFORMER 1.5.2 PRACTICAL TRANSFORMER 1.5.3 IMPEDANCE TRANSFER 1.5.4 EXACT EQUIVALENT CIRCUIT 1.5.5 APPROXIMATE EQUIVALENT CIRCUIT 1.6 PHASOR DIAGRAMS 1.7 TRASFORMER TESTS 1.7.1 OPEN CIRCUIT TEST 1.7.2 SHORT CIRCUIT TEST 1.8 TYPES OF LOSSES 1.9 VOLTAGE REGULATIO 1.10 EFFICIECY AD MAXIMUM EFFICIECY

Chapter 1 Single Phase Transformer

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  • CHAPTER 1

    SIGLE-PHASE TRASFORMER

    1.0 DEFIITIO OF TRASFORMER

    1.1 COSTRUCTIO

    1.2 PRICIPLE OF OPERATIO

    1.3 FARADAYS LAW AD LEZS LAW

    1.3.1 FARADAYS LAW

    1.3.2 LENZS LAW

    1.4 EMF EQUATIO

    1.5 TRASFORMER EQUIVALET CIRCUIT MODEL

    1.5.1 IDEAL TRANSFORMER

    1.5.2 PRACTICAL TRANSFORMER

    1.5.3 IMPEDANCE TRANSFER

    1.5.4 EXACT EQUIVALENT CIRCUIT

    1.5.5 APPROXIMATE EQUIVALENT CIRCUIT

    1.6 PHASOR DIAGRAMS

    1.7 TRASFORMER TESTS

    1.7.1 OPEN CIRCUIT TEST

    1.7.2 SHORT CIRCUIT TEST

    1.8 TYPES OF LOSSES

    1.9 VOLTAGE REGULATIO

    1.10 EFFICIECY AD MAXIMUM EFFICIECY

  • 1.0 DEFIITIO OF TRASFORMER

    A transformer is a device that transfers electrical energy from one circuit to

    another through a shared magnetic field. A changing current in the first circuit

    (the primary) creates a changing magnetic field; in turn, this magnetic field

    induces a voltage in the second circuit (the secondary).

    It can raise (step-up) or lower (step-down) the voltage in a circuit but with a

    corresponding decrease or increase in current

    1.1 COSTRUCTIO

    A transformer is a static machine. Although it is not an energy conversion device, it is

    indispensable in many energy conversion systems. It is a simple device, having two or

    more electric circuits coupled by a common magnetic circuit.

    A transformer essentially consists of two or more windings coupled by a mutual magnetic

    field. Ferromagnetic cores are used to provide tight magnetic coupling and high flux

    densities. Such transformers are known as iron core transformers. They are invariably

    used in high-power applications. Air core transformers have poor magnetic coupling and

    are sometimes used in low-power electronic circuits.

    Two types of core constructions are normally used, as shown in Fig. 1.0. In the core type

    (Fig. 1.0a), the windings are wound around two legs of a magnetic core of rectangular

    shape. In the shell type (Fig. 1.0b), the windings are wound around the center leg of a

    three-legged magnetic core. To reduce core losses, the magnetic core is formed of a stack

    of thin laminations.

    L-shaped laminations are used for core-type construction and E-shaped laminations are

    used for shell-type construction. To avoid a continuous air gap (which would require a

    large exciting current), laminations are stacked alternately as shown in Fig. l.0c and

    Fig. 1.0d.

  • Fig. 1.0: Transformer core construction. (a) Core-type (b) Shell-type (c) L-shaped lamination

    (d) E-shaped lamination

    A schematic representation of a two-winding transformer is shown in Fig. 1.1. The two

    vertical bars are used to signify tight magnetic coupling between the windings. One

    winding is connected to an ac supply and is referred to as the primary winding. The other

    winding is connected to an electrical load and is referred to as the secondary winding.

    The winding with the higher number of turns will have a high voltage and is called the

    high-voltage (HV) or high-tension (HT) winding. The winding with the lower number of

    turns is called the low-voltage (LV) or low-tension (LT) winding. To achieve tighter

    magnetic coupling between the windings, they may be formed of coils placed one on top

    of another (Fig. l.0a) or side by side (Fig. l.0b) in a pancake coil formation where

    primary and secondary coils are interleaved. Where the coils are placed one on top of

    another, the low-voltage winding is placed nearer the core and the high-voltage winding

    on top.

  • Fig. 1.1: Schematic representation of a two-winding transformer

    Transformers have widespread use. Their primary function is to change voltage level. A

    transformer is a device for converting electric energy at one voltage level to electric

    energy at another voltage level through the action of a magnetic field. It plays an

    extremely important role in modern life by making possible the economical long distance

    transmission of electric power.

    1.2 PRICIPLE OF OPERATIO

    When a voltage is applied to the primary of a transformer, a flux is produced in the core

    as given by Faradays law. The changing flux in the core then induced a voltage in the

    secondary winding of the transformer. Because transformer cores have very high

    permeability, the net magnetomotive force required in the core to produce its flux is very

    small. Since the net magnetomotive force is very small, the primary circuits

    magnetomotive force must be approximately equal and opposite to the secondary

    circuits magnetomotive force. This fact yields the transformer current ratio.

    The transformer is based on two principles:

    First, that an electric current can produce a magnetic field (electromagnetism)

    and,

    Second, that a changing magnetic field within a coil of wire induces a voltage

    across the ends of the coil (electromagnetic induction).

    Transformer is only converting from AC signal into AC signal.

    The primary is connected to source of alternating (AC) voltage

  • By changing the current in the primary coil, one changes the strength of its

    magnetic field; since the secondary coil is wrapped around the same magnetic field,

    which it produces mutually-induced e.m.f (electromotive force)

    If the secondary coil is closed, a current flows in it and so a voltage is induced across

    the secondary terminal. Therefore, electrical energy is transferred from primary to

    the secondary terminal.

    Example

    Refer to Fig. 1.2

    Fig. 1.2: Example of transformer structure

    When the switch is closed:

    Current in primary coil increases

    Creates increasing magnetic field in primary coil

    Induces current in secondary coil

    Lamp lights up

    When current in primary coil becomes steady:

    No more changes in the magnetic field in primary coil

    No more current induced in secondary coil

    Lamp goes off

  • When switch is opened:

    Current in primary coil decreases to zero

    Creates decreasing magnetic field in primary coil

    Induces current in opposite direction in secondary coil

    Lamp lights up again

    1.3 FARADAYS LAW AD LEZS LAW

    1.3.1 FARADAYS LAW

    Faradays law states that if a flux passes through a turn of a coil of wire, a voltage will be

    induced in the turn of wire that is directly proportional to the rate of change in the flux

    with respect to time. In equation form,

    dt

    de

    ind

    = (1.0)

    where ind

    e is the voltage induced in the turn of the coil and is the flux passing through

    the turn. If a coil has turns and if the same flux passes through all of them, then the

    voltage induced across the whole coil is given by

    dt

    de

    ind

    = (1.1)

    where:

    inde = voltage induced in the coil

    = number of turns of wire in coil

    = flux passing through coil

    1.3.2 LEZS LAW

    The minus sign in the Faradays Law equations (Eqn. 1.1) above is an expression of

    Lenzs law. Lenzs law states that the direction of the voltage build up in the coil is such

    that if the coil ends were short circuited, it would produce current that would cause a flux

  • opposing the original flux change. Since the induced voltage opposes the change that

    causes it, a minus sign is included in Eqn. 1.1. To understand this concept clearly,

    examine Fig. 1.3. If the flux shown in the figure is increasing in strength, then the voltage

    built up in the coil will tend to establish a flux that will oppose the increase.

    Fig.1.3: The meaning of Lenzs law: (a) A coil enclosing an increasing magnetic flux;

    (b) Determining the resulting voltage polarity.

    A current flowing as shown in Fig. 1.3(b) would produce a flux opposing the increase, so

    the voltage on the coil must be built up with the polarity required to drive that current

    through the external circuit. Therefore, the voltage must be built up with the polarity

    shown in the figure. Since the polarity of the resulting voltage can be determined from

    physical considerations, the minus sign in Eqn. 1.0 and Eqn. 1.1 is often left out.

    There is one major difficulty involved in using Eqn. 1.1 in practical problems. That

    equation assumes that exactly the same flux is present in each turn of the coil.

    Unfortunately, the flux leaking out of the core into the surrounding air prevents this from

    being true. If the windings are tightly coupled, so that the vast majority of the flux

    passing through one turn of the coil does indeed pass through all of them, then Eqn. 1.1

    will give valid answers. But if leakage is quite high or if extreme accuracy is required, a

    different expression that does not make that assumption will be needed. The magnitude of

    the voltage in the i th turn of the coil is always given by

    ( )dt

    de i

    ind

    = . (1.2)

  • If there are turns in the coil of wire, the total voltage on the coil is

    =

    =

    1i

    1indee

    ( )

    =

    =

    1i

    i

    dt

    d

    = =

    1i

    idt

    d .. (1.3)

    The term in parentheses in Eqn. 1.3 is called the flux linkage of the coil, and

    Faradays law can be rewritten in terms of flux linkage as

    dt

    de

    ind

    = (1.4)

    where

    =

    =

    1i

    i . (1.5)

    The units of flux linkage are weber-turns.

    Faradays law is the fundamental property of magnetic fields involved in transformer

    operation. The effect of Lenzs law in transformers is to predict the polarity of the

    voltages induced in transformer windings.

    Faradays law also explains the eddy current losses. A time-changing flux induces

    voltage within a ferromagnetic core in just the same manner as it would in a wire

    wrapped around that core. These voltages cause swirls of current to flow within the core.

    It is the shape of these currents that gives rise to the name eddy currents. These eddy

    currents are flowing in a resistive material (the iron of the core), so energy is dissipated

    by them. The lost energy goes into heating the iron core.

    The amount of energy lost to eddy currents is proportional to the size of the paths they

    follow within the core. For this reason, it is customary to break up any ferromagnetic core

    that may be subject to alternating fluxes into many small strips, or laminations, and to

    build the core up out of these strips. An insulating oxide or resin is used between the

  • strips, so that the current paths for eddy currents are limited to very small areas. Because

    the insulating layers are extremely thin, this action reduces eddy current losses with very

    little effect on the cores magnetic properties. Actual eddy current losses are proportional

    to the square of the lamination thickness, so there is a strong incentive to make the

    laminations as thin as economically possible.

    Example

    Figure below shows a coil of wire wrapped around an iron core. If the flux in the core is

    given by the equation

    t377sin05.0= Wb

    If there are 100 turns on the core, what voltage is produced at the terminals of the coil?

    Of what polarity is the voltage during the time when flux is increasing in the reference

    direction shown in the figure? Assume that all the magnetic flux stays within the core

    (i.e., assume that the flux leakage is zero).

    Solution

    The direction of the voltage while the flux is increasing in the reference direction must be

    positive to negative, as shown in figure. The magnitude of the voltage is given by

    dt

    de

    ind

    =

    ( ) ( )t377sin05.0dt

    dturns100=

    t377cos1885= @ ( )V90t377sin1885 +

  • 1.4 EMF EQUATIO

    Let 1

    = No. of turns in primary

    2

    = No. of turns in secondary

    m = Maximum flux in core in Webers

    = A*Bm

    f = Frequency of AC input in Hz

    The flux increases from its zero value to maximum value from in one quarter of the cycle

    i.e. in 1/4 f second

    Rate of change of flux = f4/1

    m

    Unit: wb/s or volt

    Average e.m.f/ turns = m

    f4

    If flux ( )m

    varies sinusoidally, then:

    R.M.S value/turn = *11.1 average value

    = m

    f4*11.1

    = m

    f44.4 volts

  • E.M.F induced in primary = (r.m.s / turn) * (No. of primary turns)

    = 1m

    f44.4

    = 1m

    AfB44.4 (a)

    E.M.F induced in secondary = (r.m.s / turn) * (No. of secondary turns)

    = 2m

    f44.4

    = 2m

    AfB44.4 (b)

    From (a) and (b):

    m

    1

    1 f44.4

    E=

    m

    2

    2 f44.4

    E=

    E.M.F per turns is same in both windings

    From equation (a) and (b), we get:

    a

    E

    E

    2

    1

    2

    1 == Where a = voltage transformation ratio

    If a 1, then the transformer is called step- down transformer

  • 1.5 TRASFORMER EQUIVALET CIRCUIT MODEL

    1.5.1 IDEAL TRASFORMER

    Fig. 1.4: Basic Transformer Fig. 1.5: Ideal Transformer Equivalent Circuit

    Consider a transformer with two windings, a primary winding of 1

    turns and a

    secondary winding of 2

    turns, as shown schematically in Fig.1.6. In a schematic

    diagram it is a common practice to show the two windings in the two legs of the core,

    although in an actual transformer the windings are interleaved. Let us consider an ideal

    transformer that has the following properties:

    Fig. 1.6(a): Ideal transformer

    1. The winding resistances are negligible.

    2. All fluxes are confined to the core and link both windings; that is, no leakage

    fluxes are present. Core losses are assumed to be negligible.

    3. Permeability of the core is infinite (i.e. ). Therefore, the exciting current

    required to establish flux in the core is negligible; that is, the net mmf required to

    establish a flux in the core is zero.

    ss

    pp

    EV

    EV

    =

    =

  • When the primary winding is connected to a time-varying voltage1

    v , a time-varying flux

    is established in the core. A voltage 1

    e will be induced in the winding and will equal

    the applied voltage if resistance of the winding is neglected:

    dt

    dev

    111

    == ..... (1.6)

    The core flux also links the secondary winding and induces a voltage2

    e , which is the

    same as the terminal voltage2

    v :

    dt

    dev

    222

    == .... (1.7)

    From Eqn. 1.6 and Eqn. 1.7,

    a

    v

    v

    2

    1

    2

    1 == .. (1.8)

    where a is the turns ratio.

    Eqn. 1.8 indicates that the voltages in the windings of an ideal transformer are directly

    proportional to the turns of the windings.

    Let us now connect a load (by closing the switch in Fig. 1.6(a)) to the secondary winding.

    A current 2

    i will flow in the secondary winding, and the secondary winding will provide

    an mmf 22

    i for the core. This will immediately make a primary winding current 1

    i flow

    so that a counter mmf 11

    i can oppose22

    i . Otherwise 22

    i would make the core flux

    change drastically and the balance between 1

    v and 1

    e would be disturbed. Note that in

    Fig. 1.6 that the current directions are shown such that their mmfs oppose each other.

    Because the net mmf required to establish a flux in the ideal core is zero,

    =2211

    ii net mmf 0=

    2211ii = ... (1.9)

    a

    1

    i

    i

    1

    2

    2

    1 == .... (1.10)

  • The currents in the windings are inversely proportional to the turns of the windings. Also

    note that if more current is drawn by the load, more current will flow from the supply. It

    is this mmf-balancing requirement (Eqn. 1.9) that makes the primary know of the

    presence of current in the secondary.

    From Eqn. 1.8 and Eqn. 1.10

    2211

    iviv = (1.11)

    That is, the instantaneous power input to the transformer equals the instantaneous power

    output from the transformer. This is expected, because all power losses are neglected in

    an ideal transformer. Note that although there is no physical connection between load and

    supply, as soon as power is consumed by the load, the same power is drawn from the

    supply. The transformer, therefore, provides a physical isolation between load and supply

    while maintaining electrical continuity.

    If the supply voltage 1

    v is sinusoidal, then Eqn. 1.8, 1.10, and 1.11 can be written in

    terms of rms values:

    a

    V

    V

    2

    1

    2

    1 ==

    a

    1

    I

    I

    1

    2

    2

    1 ==

    2211

    IVIV = . (1.12)

  • 1.5.2 PRACTICAL TRASFORMER

    Fig. 1.6(b): Equivalent circuit of practical transformer

    pV = Primary terminal voltage (input)

    sV = Secondary terminal voltage (output)

    spR,R = Leakage resistance on the primary and secondary respectively

    spX,X = Leakage reactance on the primary and secondary respectively

    cR = Core resistance

    mX = Magnetizing reactance

    pI = Primary current

    sI = Secondary current

    p = Primary winding turns

    s = Secondary winding turns

  • 1.5.3 IMPEDACE TRASFER

    Consider the case of a sinusoidal applied voltage and secondary impedance2

    Z , as shown

    in Fig. 1.7a.

    Fig. 1.7: Impedance transfer across an ideal transformer.

    2

    2

    2I

    VZ =

    The input impedance is

    2

    22

    2

    2

    1

    1

    1I

    Va

    a/I

    aV

    I

    VZ ===

    2

    2 Za=

    So

    22

    2

    1'ZZaZ ==

    Impedance 2

    Z connected in the secondary will appear as impedance 2

    'Z looking from

    the primary. The circuit in Fig. 8a is therefore equivalent to the circuit in Fig. 1.7b.

    Impedance can be transferred from secondary to primary if its value is multiplied by the

    square of the turns ratio. Impedance from the primary side can also be transferred to the

    secondary side, and in that case its value has to be divided by the square of the turns

    ratio:

    121Z

    a

    1'Z =

    This impedance transfer is very useful because it eliminates a coupled circuit in an

    electrical circuit and thereby simplifies the circuit.

  • 1.5.4 EXACT EQUIVALET CIRCUIT

    Fig. 1.8: The model of the real transformer

    The figure above shows the accurate model of the transformer but it is quite

    difficult to analyze practical circuits containing transformers

    Thus the equivalent circuit normally has converted to the equivalent circuit at a

    single voltage level.

    Therefore, the equivalent circuit must be referred either to its primary side or to

    its secondary side in problem solutions.

    Fig. 1.9: Exact equivalent circuit (referred to the primary side)

  • Fig. 1.10: Exact equivalent circuit (referred to the secondary side)

    1.5.5 APPROXIMATE EQUIVALET CIRCUIT

    Fig. 1.11: The model of the real transformer

    The excitation branch has a very small current compared to the load current of the

    transformers.

    Moreover, it is so small that under normal circumstances it causes a completely

    negligible voltage drop in p

    R andp

    X . Thus, it can be simplified into approximate

    equivalent circuits.

  • Fig. 1.12: Approximate equivalent circuit (referred to the primary side)

    Fig. 1.13: Approximate equivalent circuit (referred to the secondary side)

  • 1.6 PHASOR DIAGRAMS

    It is easy to determine the effect of the impedances and the current phase on the

    transformer voltage regulation by drawing the phasor diagram.

    s

    V is assumed to he at an angle of 0 and all other voltages and currents are

    compared to that references.

    A transformer phasor diagram is presented by applying Kirchhoffs \/voltage the

    transformer equivalent circuit and an equation will be as follows.

    Lagging Power Factor

    Fig. 1.14: Lagging power factor

    Unity Power Factor

    Fig. 1.15: Unity power factor

    ++=seqseqs

    pIjXIR0V

    a

    V

    ++= seqseqs

    pIjXIR0V

    a

    V

    ++= 0IjX0IR0Va

    Vseqseqs

    p

  • Leading Power Factor

    Fig. 1.16: Leading power factor

    1.7 TRASFORMER TEST

    1.7.1 OPE CIRCUIT TEST

    Must be conducted at the rated terminal voltage

    The values of c

    R (core resistance) and m

    X (magnetizing reactance) can be

    determined by opening the output line at the secondary side of transformer as in

    figure below

    Fig. 1.17: Open-circuit test

    ococ

    oc1

    OCIV

    Pcos=

    C

    OC

    cI

    VR =

    M

    OC

    MI

    VX =

    cosIIOCC

    = sinIIOCM

    =

    ++++= seqseqs

    pIjXIR0V

    a

    V

  • CHECK

    If ocp

    VV = Therefore c

    R and m

    X (Primary side)

    Else

    ocsVV = Therefore

    cR and

    mX (Secondary side)

    1.7.2 SHORT CIRCUIT TEST

    Always conducted at the rated winding current

    Current flowing in excitation branch is neglect since the input voltage is so low

    during the short-circuit test.

    Thus the entire voltage drop in the transformer can be attributed to the series

    elements in the circuit:

    The determined values of eq

    R (winding resistance) and eq

    X (winding reactance)

    Fig. 1.18: Short-circuit test

    (Note: minus sign inductance only)

    scsc

    SCSC

    IV

    P1cos=

    scsc

    sc

    eqI

    0VZ

    =

    eqeqeqjXRZ +=

  • CHECK

    If scp

    II =

    Therefore pppeq

    jXRZZ +==

    Else

    If scs

    II =

    Therefore ssseq

    jXRZZ +==

    p

    rated

    pV

    SI =

    s

    rated

    sV

    SI =

    1.8 TYPES OF LOSSES

    Copper ( )RI 2 Losses : resistive heating losses in the secondary and primary windings

    Eddy current losses : resistive heating losses in the core of the

    transformer

    Hysteresis losses : a heat loss caused by the magnetic properties of

    the armature

    Leakage flux : in turn causes losses due to frictional heating in

    susceptible cores. Magnetic flux lines produced by

    the primary winding that do not link the turns of the

    secondary winding

  • 1.9 VOLTAGE REGULATIO

    Defined as the difference between the voltage magnitude at the load terminals of the

    transformer at full load and at no load in percent of full load voltage.

    a) Equivalent circuit referred to primary side

    Fig. 1.19(a): Approximate equivalent circuit (referred to primary)

    Voltage regulation %100V

    VV

    FLs

    FLsLs

    =

    Since at no load, the voltage regulation can also be expressed as

    Voltage regulation( )

    ( )

    %100V

    VV

    FLs

    FLsp

    =

    ( ) pLs VV =

  • b) Equivalent circuit referred to secondary side

    Fig. 1.19(b): Approximate equivalent circuit (referred to secondary)

    Voltage regulation %100V

    VV

    FLs

    FLsLs

    =

    Since at no load, the voltage regulation can also be expressed as

    Voltage regulation( )

    ( )

    %100V

    Va/V

    FLs

    FLsp

    =

    ( ) a/VV pLs =

  • 1.10 EFFICIECY AD MAXIMUM EFFICIECY

    To measure the efficient of the transformer

    a) Equivalent circuit referred to primary side

    Fig. 1.20(a): Approximate equivalent circuit (referred to primary side)

    %100xPP

    P

    lossout

    out

    +=

    %100xPPcosIV

    cosIV

    coreCuss

    ss

    ++=

    %100xPPncosInV

    cosInV

    coreCu

    2

    ss

    ss

    ++=

    c

    2

    p

    coreR

    VP =

    1eq

    2

    pcuRIP =

  • b) Equivalent circuit referred to secondary side

    Fig. 1.20(b): Approximate equivalent circuit (referred to secondary side)

    When maximum efficiency occurs:

    cu

    c

    P

    Pn = and 1cos =

    %100xPP

    P

    lossout

    out

    +=

    %100xPPncosInV

    cosInV

    coreCu

    2

    ss

    ss

    ++=

    ( )c

    2

    p

    coreR

    a/VP =

    2eq

    2

    scuRIP =