Cast a Horoscope

7/23/2019 Cast a Horoscope

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Way to cast a horoscope

To caste a horoscope, following accurate details are required:

Date of birthTime of birth

Place of birth.

Time of Birth: It is recorded for India as IST - Indian Standard Time (and for other countriesas GMT - Greenwich Mean Time). GMT is 5 hours ahead of IST. But for casting a horoscope!oca" Mean Time is used which depends on the p"ace of #irth.

Place of Birth: !ogitude and "atitude of the p"ace of #irth are used to find the time correctionto #e app"ied to the IST to find out the !oca" Mean Time.

Longitude: It is the arc drawn from $orth %o"e to South %o"e to mar& the "ocation in degreesof a particu"ar p"ace from a centra" p"ace (Greenwich). '"" p"aces are "ocated either to theest or to the ast of Greenwich. *or e+amp"e the "ongitude of Bom#a, is / 501 .

Latitude: It is the arc drawn to mar& the "ocation in degrees of a particu"ar p"ace $orth or

South of 2uator. *or e+amp"e the "atitude of Bom#a, is 34/ 541 $.

iderealTime: It is the time ta&en #, the earth to ma&e one fu"" rotation. It is not e+act", hours #ut goes on changing according to increase or decrease in the duration of da,s andnights. It is ca""ed 6erna" 2uino+ time and it is a measure of earth1s rotation with respect tothe e2uino+ which has a 7er, sma"" retrograde motion. Siderea" time is used for ca"cu"ation ofthe 'scendant.

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*or ma&ing the horoscope first of all we ha)e to calculate the "scendant. 'scendant isthe rising sign at the time of #irth. !et us see how the 'scendant is ca"cu"ated. This wi"" #edone with the he"p of two #oo&s 7i8. Ta#"e of 'scendants and 'nnua" phemeries 399 (forthe ,ear of #irth) #, !ahiri. These two #oo&s can #e procured from the mar&et.

Details of sample birth are once again gi)en below. We would calculate "scendantfor this.

Date of birth : *+.*.*--,Time of birth : ./+ "0 $TPlace of birth : Bombay.

e ha7e indicated the !ongitude and !atitude of Bom#a, as a#o7e. These were ta&en frompage 303 of the #oo& ;Ta#"e of 'scendants;. This #oo& contains the necessar, informationa#out man, ma


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*ormu"a for getting the correction time to IST to find out !MT is 35/ = 3 hour or 3/ = minutes(%"ease note !ongitude is gi7en in degrees (/) minutes (1) and seconds (11) > 3/ = ?01 31 =?011) whereas the time is gi7en in hrs minutes and seconds >3 hr = ?0 minutes 3 minute =?0 seconds@. Ao not confuse the minutes of !ongitude with the minutes of time.'s per a#o7e formu"a di7ide !ongitude / 501 #, 35 to &now the !MT. It comes to: hr 53

mt 0 secs. owC This is shown #e"ow to faci"itate ,our understanding of the ca"cu"ations.D/E35 = 3E35 (i.e. hrs F 3E35 hrs)3E35 + ?0 (to ma&e minutes) = 4 minutesence hr 4 minutes$ow 501 E35 = 5E35 (i.e. minutes F 5E35 or 3E minutes).3E + ?0 (to ma&e seconds) = 0 seconds.ence hrs 4F minutes 0 seconds = h 53 m 0 s.$ow deduct 5 h 0 m 0 s (as GMT is F5h 0 m 0 s of IST) from h 53m 0s: h 53 m 0 s

- 5 h 0 m 0 s - 0 h 4 m 0s

This means 4 m 0 s shou"d #e deducted from IST to find !MT.

tep $$

The ne+t step is to find out the sidereal time for the gi)en date, time and place ofbirth.

Siderea" time for 30th Aecem#er(*rom page Ta#"e of 'sc) 3 h 3 m 0 sorrection to Indian siderea" time for Bom#a, (*rom page 303 "ast co"umn Ta#"e of'sc) F 0? sorrection for 399 (*rom page Ta#"e II Ta#"e of 'sc) F 3 m 5 sSiderea" time for 3 $oon on 30.3.399 for Bom#a,3 h 3? m 05s ..B$ow "et us ca"cu"ate siderea" time for the time of #irth on 30.3.399 for Bom#a,: 's the

#irth is #efore 3 $oon deduct from 3 h 00 m 00 s!MT h 33 m 0 s

4 h 4 m 0 s ... (*or afternoon #irth there is no need of this deduction. orrection to increase the timeinter7a" is ap""ied straight to the !MT).

$ow app", correction to increase the time inter7a" (*rom page 5 Ta#"e I6 Ta#"e of 'sc):for 4 hr F 3 m 39 sfor 4 m F 4 s

for 4 hr 4 m: 3 m s ..... A$ow add and A. This comes to 4 h 50 m 0 s.Siderea" time at 3 $oon 3 h 3? m 05 s!ess corrected time inter7a" - 4 h 50 m 0 s(*or #irth in the afternoon this shou"d #e added.)Siderea" Time for the gi7en 4 h 5 m 54 s ...


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#irth time:tep $$$$ow to find out the "scendant, refer to Tables gi)en in the boo1 Table of "scendantsfor )arious latitudes. Search for the "atitude of Bom#a, (or its nearest p"ace if the same isnot a7ai"a#"e). Hn page 9 Ta#"e for !atitude 39/ $ is gi7en. 's gi7en ear"ier the "atitude for

Bom#a, the re2uired p"ace of #irth is 34/ 541 $ (sa, 39/ $).In this page we ha7e to search for the 'scendant for the Siderea" Time gi7en a#o7e as 4 hr5 m 54 s as at .'scendant for*or 4 h m ? s 300 ?1

*or 4 h 4 m ?s 330 31ence for m 551(1s1 is the 8odiac sign Aegree (/) and minute (1) a"read, e+p"ained a#o7e).

If we deduct the former from the "atter we get minutes = 55 m #ut we need minutes (4h m F 3 m 541 (3 m 541 is appro+imate", e2ua" to 1) = 4 h ? m. So for minutes we get4 m (55E: .5 sa, 4).Therefore 'scendant for 4 h 5 m 54 s (Hr sa, 4 h ? m)

= ? s 30/ ?1

F 41? s 33 31

tep $2$ow apply correction for "yanamasha for *--,as per page ? of Ta#"es of 'scedants

which is -?1.Therefore 'scendant for the re2uired #irth: ? s 33/ 31

- ?1'scendant(I): ?s 30/ 41This means 'scending sign is !i#ra () and it has tra7e""ed 30/ 41in !i#ra.

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$ow to p"ace the p"anets in the horoscopes longitudes of planets ha)e to be calculated.

*or this we proceed as under:3.4efer to "nnual (phemeris, *--. Longitudes of different p"anets for the entire ,ear

month-wise da,-wise ha7e #een gi7en as at 5.0 'M IST. Hn page 0 search the re2uireddate i.e. 30th Aecem#er. 'gainst this the "ongitudes for p"anets on 30.3.399 at 5.0 'Mare gi7en. But our re2uired #irth time is .50 'M i.e. h 0 m after 9.3.399 at 5.0 'M..*ind out the "ongitudes of p"anets as on 9.3.399 at 5.0 'M from page 0 and add thedistance co7ered #, p"anets in h 0 m. This can #e done in the fo""owing wa, :


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*ind out the "ongitudes of p"anets as gi7en #e"ow :-------------------------------------------------------------------------------------- 9.3.399 30.3.399 Aifference-------------------------------------------------------------------------------------- s / 1 s / 1--------------------------------------------------------------------------------------

Sun - - 04 - - 09 3/ 31Moon 5 - - 0 ? - 4 - ? 3/ 91Mars - - 54 - 4 - 51Mercur, - 9 - 30 - 30 - 3 3/ 31upiter ? - 3 - 03 ? - 3 - 3 3316enus - 3 - ? - 35 - 0 3/ 3?1Saturn 30- 3 - 0 30- 3 - 1Jahu - 9 - 3 - 9 - 3 1Ketu 3 - 9 - 3 3 - 9 - 3 1

--------------------------------------------------------------------------------------!alculation of Longitude of un

$ow we wou"d use the proportiona" "ogarithms ta#"es pro7ided in the 'nnua" phemeris 399in the end. ori8onta"", degrees or hours are gi7en and 7ertica"", minutes are gi7en.'s ca"cu"ated a#o7e speed of Sun comes to 3/ 31.!og for 3/ 31 (*rom the a#o7e Ta#"e) 3.0'dd "og for the difference of h 0 m 0.03(Ta&e hori8onta"", h and 7ertica"", 01and see them meet at 03) 3.0$ow search this figure (3.0) in the a#o7e Ta#"e. The nearest figure is 3.05. This iswritten at the cross-section of 0/ 51. This means Sun has tra7e"ed 51 in h 01.Longitude of un on -.*.*-- 5 s 6 +78 at /.+ "0

'dd the distance co7ered in 0 s 00/ 51 hr 0 mLongitude of un at the gi)en birth time 5s 96 +/8

Simi"ar", we can ca"cu"ate for other p"anets

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