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Capacitors and Current
Dr Jacob Dunningham,School of Physics and Astronomy, University of Leeds
EM-L5-1
Review of Lecture 4
• Electric static energy
U =∫ Q
0V (q) dq
• Capacitance
C = Q/V ; U =1
2
1
CQ2
• Electric field energy density
ue =1
2ε0 E2
Review of Lecture 4 EM-L5-2
Overview of Lecture 5
The plan for today’s lecture
• Combinations of capacitors
• Dielectrics
• Electric current
• Summary
Review of Lecture 4 EM-L5-3
Combination of Capacitors
EM-L5-4
Parallel capacitors
Equal potential difference V across C1 and C2
Q = Q1 + Q2 = C1V + C2V = (C1 + C2) · V
Equivalent capacity
Ceq =Q
V= C1 + C2
Combination of Capacitors EM-L5-5
Parallel capacitors
In general for multiple parallel capacitors Ci:
C =∑i
Ci
Combination of Capacitors EM-L5-6
In series capacitors
Equal charges of ±Q on all plates
V = V1 + V2 =Q
C1+
Q
C2= Q ·
(1
C1+
1
C2
)Equivalent capacitance
1
C=
V
Q=
(1
C1+
1
C2
)
Combination of Capacitors EM-L5-7
In series capacitors
In general for capacitors Ci in series
1
C=∑i
1
Ci
Combination of Capacitors EM-L5-7
Example: equivalent capacity
Find the equivalent capacitance of the network of capacitors
Combination of Capacitors EM-L5-8
Example: equivalent capacity
Find the equivalent capacitance of the network of capacitors
Answer: Ctotal = 2 µF
Combination of Capacitors EM-L5-9
Dielectrics
EM-L5-10
Dielectric
• Definition: Dielectrics are non-conducting materials, such as
air, glass, paper, . . .
• Effect of a dielectric: A dielectric decreases the strength of
the electric field E relative to the electric field E0 in vacuum.
E = E0/κ
κ is called the dielectric constant.
Material dielectric dielectric
constant κ strength kV/mm
Air 1.00059 3
Glass (Pyrex) 5.6 14
Mica 5.4 10 - 100
Paper 3.7 16
Porcelain 7 5.7
Too strong a field can damage the dielectric.
Dielectrics EM-L5-11
Parallel plate capacitor dielectric
Potential difference between plates with separation d
V = E · d =E0 · d
κ=
V0
κ
Effect on capacitance C
C =Q
V=
Q
V0/κ= κ
Q
V0= κ C0
Capacitance becomes
C = κ C0 = κε0 A
d=
ε A
d
where the permittivity of the dielectric ε is
ε = κ · ε0
V0 potential without a dielectric. C0 capacitance without a dielectric.
Dielectrics EM-L5-12
Molecular level view
In an external electric field the dipoles become partially aligned.
Bound charges appear on the surface of the dielectric.
Dielectrics EM-L5-13
Bound charges reduce electric field
The bound charges on the surface of the dielectric generate an
electric field.
This additional field with opposite orientation reduces the exter-
nal electrical field strength.
Dielectrics EM-L5-14
Electric Current
EM-L5-15
Electric current
The electric current I is the amount of charge ∆Q thatflows through a cross sectional area A in time ∆t
Definition of electric current I
I =∆Q
∆t
Unit of current Ampere (A)
1 A =1 C
1 s
Electric Current EM-L5-16
Current and drift velocity
In time ∆t all N charges q in the shaded volume V pass throughthe surface A. With number density of charges, n = N/V :
∆Q = q · n · (A · vd ·∆t)
the current then is
I =∆Q
∆t
I = q · n · A · vd
(n - number density, n = N/V , A - cross sectional area, vd - drift velocity )
Electric Current EM-L5-17
Resistance
Current is driven by the electric field ~E inside the conductorelement of length ∆L exerting a force q · ~E on free charges. Thepotential difference is V = E ·∆L.
Definition of resistance
R(I) = V (I) / I
SI unit 1 Ohm Ω = 1 V/1 A
Ohms law: for many materials R is constant
R = V / I
Electric Current EM-L5-18
Example
(a) carbon or metal film resistor, (b) semiconductor diode
The resistance is not necessarily constant.
Electric Current EM-L5-19
Resistivity
Resistance of a wire depends on length L and cross section A.
R = ρ ·L
A
The resistivity ρ is a characteristic of the conducting material
Electric Current EM-L5-20
Summary
• Parallel capacitor
C =∑
i
Ci
• In series capacitors1
C=∑
i
1
Ci
• Dielectric
E=E0 / κ ; ε=κ · ε0
• Current
I = Q / t ; I = q · n · A · vd
• Resistance
R = V / I
Reading: Tipler, sections 24-4, 24-5, 24-6, 25-1, 25-2
Preparation: Tipler, sections 25-3, 25-4, 25-5
Summary EM-L5-21