Calendr Ques

8/11/2019 Calendr Ques

1/27

Java o Basic Java Programming Tutorials

o Serialization

o JDBC

o Custom Exception

o Threads

Overview of Threads

Create Threads by extending Thread Class

Create Threads by implementing Runnable interface

o Java Interview Questions

o Sample Programs

o J2EE

RDBMS

Quantitative Aptitude

Online Tests

Aptitude Q&A

Speed Mathematics

Scientific Calculator

Miscellaneous

o Difference between Google Analytics and Google Webmaster Tools

o Career Options after 12th

o Common Errors and Suggested Solutions

o Utilities
http://www.careerbless.com/index.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/java/basics/Overview.phphttp://www.careerbless.com/java/serialization/serialization.phphttp://www.careerbless.com/java/jdbc/DB2_Connection.phphttp://www.careerbless.com/java/ExceptionDemo/CustomException.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/java/Threads/Threads_Overview.phphttp://www.careerbless.com/java/Threads/ExtendingThreadClass.phphttp://www.careerbless.com/java/Threads/ImplementingRunnable.phphttp://www.careerbless.com/interview_questions/part1_java.phphttp://www.careerbless.com/samplecodes/java/beginners/home.phphttp://www.careerbless.com/j2ee_tutorials/J2EEhome.phphttp://www.careerbless.com/db/rdbms/Overview.phphttp://www.careerbless.com/aptitude/qa/home.phphttp://www.careerbless.com/tests/testsHome.phphttp://www.careerbless.com/questionsandanswers/index.php?qa=questionshttp://www.careerbless.com/maths/speedmaths/home.phphttp://www.careerbless.com/calculators/ScientificCalculatorhttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/web/website/general/topic1.phphttp://www.careerbless.com/web/website/general/coursesafter12.phphttp://www.careerbless.com/errorsandsolutions/home.phphttp://www.careerbless.com/services/utilities_home.phphttp://www.careerbless.com/index.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/services/utilities_home.phphttp://www.careerbless.com/errorsandsolutions/home.phphttp://www.careerbless.com/web/website/general/coursesafter12.phphttp://www.careerbless.com/web/website/general/topic1.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/calculators/ScientificCalculatorhttp://www.careerbless.com/maths/speedmaths/home.phphttp://www.careerbless.com/questionsandanswers/index.php?qa=questionshttp://www.careerbless.com/tests/testsHome.phphttp://www.careerbless.com/aptitude/qa/home.phphttp://www.careerbless.com/db/rdbms/Overview.phphttp://www.careerbless.com/j2ee_tutorials/J2EEhome.phphttp://www.careerbless.com/samplecodes/java/beginners/home.phphttp://www.careerbless.com/interview_questions/part1_java.phphttp://www.careerbless.com/java/Threads/ImplementingRunnable.phphttp://www.careerbless.com/java/Threads/ExtendingThreadClass.phphttp://www.careerbless.com/java/Threads/Threads_Overview.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/java/ExceptionDemo/CustomException.phphttp://www.careerbless.com/java/jdbc/DB2_Connection.phphttp://www.careerbless.com/java/serialization/serialization.phphttp://www.careerbless.com/java/basics/Overview.phphttp://www.careerbless.com/aptitude/qa/calendar.php


2/27

Home > Quantitative aptitude questions and answers withexplanation > Calendar > Solved Examples

1. Important Formulas2. Solved Examples

1. What day of the week does May 28 2006 fall on

A. Saturday B. MondayC. Sunday D. Thursday

Hide Answer

| Notebook

| Discuss

Here is the answer and explanation

Answer : Option C

Explanation :

28th May 2006 = (2005 years + period from 1-Jan-2006 to 28-May-2006)

We know that number of odd days in 400 years = 0

Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfectmultiple of 400)

Number of odd days in the period 2001-2005

= 4 normal years + 1 leap year

= 4 x 1 + 1 x 2 = 6

Days from 1-Jan-2006 to 28-May-2006 = 31 (Jan) + 28 (Feb) + 31 (Mar) +30 (Apr) + 28(may)

= 148
http://www.careerbless.com/index.phphttp://www.careerbless.com/index.phphttp://www.careerbless.com/aptitude/qa/home.phphttp://www.careerbless.com/aptitude/qa/home.phphttp://www.careerbless.com/aptitude/qa/home.phphttp://www.careerbless.com/aptitude/qa/home.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/aptitude/qa/calendar_imp.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://shownb%281%29/http://shownb%281%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002371.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002371.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002371.phphttp://ads.yahoo.com/clk?3,eJyljdFqg0AQRb8mbyI6E3WL9GE1KClxy8b1Qd-2rtEmphrdsrRfX9OG5AN6GIbD5TLjYuiRgw.-gQCufeU5T6G7JoGnCDqAlhOGIQAiBK4XuBbkUCTF.iLaKCPVKaJXXgKu6B1DaXnTmS6FmA5b3fG.5CsuUJmrxXk00v9Q8.1w0-3v13ZDaJXbpSra6N7alCYD1rGUHXeCHVnKdSaSnsVuV50L3IkaWVpCJU6m.Ob4-rj.bFmd1uMK6QqSZYwxdi2nppne-mae7Xo4L6kc9bv-VM2iF7msWvbNh5KTPXbjDzBbZFs=,http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002371.phphttp://shownb%281%29/http://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/aptitude/qa/calendar_imp.phphttp://www.careerbless.com/aptitude/qa/calendar.phphttp://www.careerbless.com/aptitude/qa/home.phphttp://www.careerbless.com/aptitude/qa/home.phphttp://www.careerbless.com/index.php


3/27

148 days = 21 weeks + 1 day = 1 odd day

Total number of odd days = (0 + 6 + 1) = 7 odd days = 0 odd day

0 odd day = Sunday

Hence May 28 2006 is Sunday.

2. What will be the day of the week 15th August, 2010?A. Thursday B. Sunday

C. Monday D. SaturdayHide Answer |

Notebook | Discuss


Answer : Option B

Explanation :

15th Aug 2010 = (2009 years + period from 1-Jan-2010 to 15-Aug-2010)





= 7 x 1 + 2 x 2 = 11 = (11 - 7x1) odd day = 4 odd day

Days from 1-Jan-2010 to 15-Aug-2010
http://shownb%282%29/http://shownb%282%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002372.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002372.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002372.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002372.phphttp://shownb%282%29/


4/27

= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 30(Jun) +31(Jul) + 15(Aug)

= 227

227 days = 32 weeks + 3 day = 3 odd day

Total number of odd days = (0 + 4 + 3) = 7 odd days = 0 odd day

0 odd day = Sunday

Hence 15th August, 2010 is Sunday.

3. Today is Monday. After 61 days, it will beA. Thursday B. SundayC. Monday D. Saturday

Hide Answer |

Notebook | Discuss


Answer : Option D

Explanation :

61 days = 8 weeks 5 days = 5 odd days

Hence if today is Monday, After 61 days, it will be = (Monday + 5 odd days)

= Saturday

4. On what dates of April, 2001 did Wednesday fall?A. 2 nd, 9 th, 16 th, 23 rd B. 4 th, 11 th, 18 th, 25 th C. 3 rd, 10 th, 17 th, 24 th D. 1 st, 8 th, 15 th, 22 nd, 29 th

Hide Answer | | Discuss
http://shownb%283%29/http://shownb%283%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002373.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002373.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002373.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002374.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002374.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002374.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002374.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002373.phphttp://shownb%283%29/


5/27

Notebook Here is the answer and explanation

Answer : Option B

Explanation :

We need to find out the day of 01-Apr-2001

01-Apr-2001 = (2000 years + period from 1-Jan-2001 to 01-Apr-2001)



Days from 1-Jan-2001 to 01-Apr-2001 = 31 (Jan) + 28 (Feb) + 31 (Mar) +1(Apr) = 91

91 days = 13 weeks = 0 odd day

Total number of odd days = (0 + 0) = 0 odd days

0 odd day = Sunday. Hence 01-Apr-2001 is Sunday.

Hence first Wednesday of Apr 2011 comes in 04 th and successiveWednesdays

come in 11 th , 18 th and 25 th

5. How many days are there in x weeks x daysA. 14x B. 8xC. 7x 2 D. 7



6/27


Answer : Option B

Explanation :

6. The calendar for the year 2007 will be the same for the year

A. 2017 B. 2018C. 2014 D. 2016

Hide Answer |

Notebook | Discuss


Answer : Option B

Explanation :

For a year to have the same calendar with 2007 ,the total odd days from2007 should be 0.

Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017

Odd Days : 1 2 1 1 1 2 1 1 1 2 1

Take the year 2014 given in the choice.

Total odd days in the period 2007-2013 = 5 normal years + 2 leap year

= 5 x 1 + 2 x 2 = 9 odd days

= 2 odd day (As we can reduce multiples of 7 from odd days which will notchange
http://shownb%285%29/http://shownb%285%29/http://shownb%286%29/http://shownb%286%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002376.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002376.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002376.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002376.phphttp://shownb%286%29/http://shownb%285%29/


7/27

anything)


Number of odd days in the period 2007-2015 = 7 normal years + 2 leapyear

= 7 x 1 + 2 x 2 = 11 odd days

= 4 odd days(Even if the odd days were 0, calendar of 2007 will not be same as thecalendar of 2016 because 2007 is not a leap year whereas 2016 is a leapyear. In fact, you can straight away ignore this choice due to this factwithout even bothering to check the odd days)



= 7 x 1 + 3 x 2 = 13 odd days

= 6 odd days



= 8 x 1 + 3 x 2 = 14 odd days

= 0 odd day (As we can reduce multiples of 7 from odd days which will notchange

anything)

Also, both 2007 and 2018 are not leap years.Since total odd days in the period 2007-2017 = 0 and both 2007 and 2018are of same type, 2018 will have the same calendar as that of 2007


8/27

7. Which of the following is not a leap year?A. 1200 B. 800C. 700 D. 2000

Hide Answer

| Notebook | Discuss


Answer : Option C

Explanation :

Remember the leap year rule (Given in the formulas)

1. Every year divisible by 4 is a leap year, if it is not a century.

2. Every 4th century is a leap year, but no other century is a leap year.

800,1200 and 2000 comes in the category of 4th century (such as400,800,1200,1600,2000 etc).

Hence 800,1200 and 2000 are leap years

700 is not a 4th century, but it is a century. Hence it is not a leap year

8. 01-Jan-2007 was Monday. What day of the week lies on 01-Jan-2008?A. Wednesday B. SundayC. Friday D. Tuesday

Hide Answer |

Notebook

| Discuss


Answer : Option D

Explanation :
http://shownb%287%29/http://shownb%287%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002377.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002377.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002377.phphttp://shownb%288%29/http://shownb%288%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002378.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002378.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002378.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002378.phphttp://shownb%288%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion0000002377.phphttp://shownb%287%29/


9/27

Given that January 1, 2007 was Monday.

Odd days in 2007 = 1 (we have taken the complete year 2007 because weneed to find out

the odd days from 01-Jan-2007 to 31-Dec-2007, that is the whole year2007)

Hence January 1, 2008 = (Monday + 1 Odd day) = Tuesday

9. 8th Dec 2007 was Saturday, what day of the week was it on 8th Dec, 2006?

A. Sunday B. TuesdayC. Friday D. Tuesday

Hide Answer |

Notebook | Discuss


Answer : Option C

Explanation :

Given that 8th Dec 2007 was Saturday

Number of days from 8th Dec, 2006 to 7th Dec 2007 = 365 days

365 days = 1 odd day

Hence 8th Dec 2006 was = (Saturday - 1 odd day) = Friday

10. On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?A. Sunday B. FridayC. Saturday D. Monday



10/27


Answer : Option A

Explanation :

Given that 8th Feb, 2005 was Tuesday

Number of days from 8th Feb, 2004 to 7th Feb, 2005 = 366

(Since Feb 2004 has 29 days as it is a leap year)

366 days = 2 odd days

Hence 8th Feb, 2004 = (Tuesday - 2 odd days) = Sunday

11. The last day of a century cannot be

A. Monday B. WednesdayC. Tuesday D. Friday

Hide Answer |

Notebook | Discuss


Answer : Option C

Explanation :


Hence last day of the first century is Friday

Number of odd days in 200 years = 5 x 2 = 10 = 3 ( As we can reducemultiples of 7

from odd days which will not change anything )


11/27

Hence last day of the 2 nd century is Wednesday

Number of odd days in 300 years = 5 x 3 = 15 = 1 ( As we can reduce

multiples of 7

from odd days which will not change anything )

Hence last day of the 3 rd century is Monday

We know that umber of odd days in 400 years = 0. (? 5 x 4 + 1 = 21 = 0)

Hence last day of the 4 th century is Sunday

Now this cycle will be repeated.

Hence last day of a century will not be Tuesday or Thursday or Saturday.

its better to learn this by heart which will be helpful to save time in objectivetype

exams

12. January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?A. Saturday B. WednesdayC. Thursday D. Saturday

Hide Answer |

Notebook | Discuss


Answer : Option C

Explanation :


12/27

Number of odd days in 2008 = 2 (since it is a leap year)

(we have taken the complete year 2008 because we need to find out the odddays from

01-Jan-2008 to 31-Dec-2008, that is the whole year 2008)

Given that January 1, 2008 is Tuesday

Hence January 1, 2009 = (Tuesday + 2 odd days) = Thursday

13. If Jan 1, 2006 was a Sunday, What was the day of the week Jan 1, 2010?

A. Friday B. ThursdayC. Tuesday D. Saturday

Hide Answer |

Notebook | Discuss


Answer : Option A

Explanation :

Given that Jan 1 2006 was a Sunday



= 3 x 1 + 1 x 2 = 5

(note that we have taken the complete year 2006 because the period in2006

is from 01-Jan-2006 to 31-Dec-2006, which is the whole year 2006. Thenthe

complete years 2007, 2008 and 2009 are also involved)


13/27

Hence Jan 1 2010 = (Sunday + 5 odd days) = Friday

14. What was the day of the week on 17th June 1998?A. Monday B. SundayC. Wednesday D. Friday

Hide Answer |

Notebook | Discuss


Answer : Option C

Explanation :

17 Jun 1998 = (1997 years + period from 1-Jan-1998 to 17-Jun-1998)




= Number of odd days in 300 years

= 5 x 3 = 15 = 1

(As we can reduce perfect multiples of 7 from odd days without affectinganything)



= 73 x 1 + 24 x 2 = 73 + 48 = 121 = (121 - 7 x 17) = 2 odd days


14/27

Number of days from 1-Jan-1998 to 17-Jun-1998

= 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 31(may) + 17(Jun)

= 168


Total number of odd days = (0 + 1 + 2 + 0) = 3

3 odd days = Wednesday

Hence 17th June 1998 is Wednesday.

15. 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?A. Friday B. SaturdayC. Wednesday D. Sunday

Hide Answer |

Notebook | Discuss


Answer : Option D

Explanation :

Number of days from 6th March, 2004 to 5th March 2005 = 365 days

(Though Feb 2004 has 29 days as it is a leap year, it will not come in therequired period)


Given that 6th March, 2005 is Monday


15/27

Hence 6th March, 2004 = (Monday - 1 odd day) = Sunday

16. What day of the week was 1 January 1901A. Monday B. TuesdayC. Saturday D. Friday

Hide Answer |

Notebook | Discuss


Answer : Option B

Explanation :

1 Jan 1901 = (1900 years + 1-Jan-1901)





= 5 x 3 = 15 = 1


1-Jan-1901 = 1 odd day

Total number of odd days = (0 + 1 + 1) = 2

2 odd days = Tuesday


16/27

Hence 1 January 1901 is Tuesday.

17. What day of the week will 22 Apr 2222 be?A. Monday B. TuesdayC. Sunday D. Thursday

Hide Answer |

Notebook | Discuss


Answer : Option A

Explanation :

22 Apr 2222 = (2221 years + period from 1-Jan-2222 to 22-Apr-2222)





= 5 x 2 = 10 = 3



= 16 normal years + 5 leap years

= 16 x 1 + 5 x 2 = 16 + 10 = 26 = 5 odd days


17/27

Number of days from 1-Jan-2222 to 22 Apr 2222

= 31 (Jan) + 28 (Feb) + 31 (Mar) + 22(Apr) = 112


Total number of odd days = (0 + 3 + 5 + 0) = 8 = 1 odd day

1 odd days = Monday

Hence 22 Apr 2222 is Monday.

18. Today is Thursday. The day after 59 days will be?A. Monday B. TuesdayC. Saturday D. Sunday

Hide Answer |

Notebook | Discuss


Answer : Option D

Explanation :

59 days = 8 weeks 3 days = 3 odd days

Hence if today is Thursday, After 59 days, it will be = (Thursday + 3 odddays)

= Sunday

19. What is the year next to 1990 which will have the same calendar as that of the year 1990?A. 1992 B. 2001C. 1995 D. 1996



18/27


Answer : Option B

Explanation :

For a year to have the same calendar with 1990 ,total odd days from 1990should be 0.

Take the year 1992 from the given choices. Total odd days in the period 1990-1991= 2 normal years 2 x 1 = 2 odd days

Take the year 1995 from the given choices.

Number of odd days in the period 1990-1994 = 4 normal years + 1 leapyear 4 x 1 + 1 x 2 = 6 odd days

Take the year 1996 from the given choices. Number of odd days in the period 1990-1995= 5 normal years + 1 leap year 5 x 1 + 1 x 2 = 7 odd days 0 odd days(As we can reduce multiples of 7 from odd days which will not changeanything)

Though number of odd days in the period 1990-1995 is 0, there is a catchhere.1990 is not a leap year whereas 1996 is a leap year.Hence calendar for 1990 and 1996 will never be the same.

Take the year 2001 from the given choices. Number of odd days in the period 1990-2000= 8 normal years + 3 leapyears 8 x 1 + 3 x 2 = 14 odd days 0 odd days Also, both 1990 and 2001 are normal years.Hence 1990 will have the same calendar as that of 2001

20. January 1, 2004 was a Thursday, what day of the week lies on January 1 2005.A. Saturday B. MondayC. Saturday D. Tuesday

Hide Answer | Discuss


19/27

| Notebook


Answer : Option C

Explanation :

Given that January 1, 2004 was Thursday.

Odd days in 2004 = 2 (because 2004 is a leap year)

(Also note that we have taken the complete year 2004 because we need tofind out

the odd days from 01-Jan-2004 to 31-Dec-2004, that is the whole year2004)

Hence January 1, 2005 = (Thursday + 2 Odd days) = Saturday

21. If the first day of a year (other than leap year) was Friday, then which was the last day ofthat year?A. Saturday B. Friday

C. Tuesday D. Monday

Hide Answer |

Notebook | Discuss


Answer : Option B

Explanation :

Given that first day of a normal year was Friday

Odd days of the mentioned year = 1 (Since it is an ordinary year)


20/27

Hence First day of the next year = (Friday + 1 Odd day) = Saturday

? Last day of the mentioned year = Friday

22. If 1 st October is Sunday, then 1 st November will beA. Saturday B. ThursdayC. Wednesday D. Tuesday

Hide Answer |

Notebook | Discuss


Answer : Option C

Explanation :

Given that 1 st October is Sunday

Number of days in October = 31

31 days = 3 odd days

(As we can reduce multiples of 7 from odd days which will not changeanything)

Hence 1 st November = (Sunday + 3 odd days) = Wednesday

23. Arun went for a movie nine days ago. He goes to watch movies only on Thursdays. Whatday of the week is today?A. Wednesday B. SaturdayC. Friday D. Sunday

Hide Answer |

Notebook | Discuss


Answer : Option B


21/27

Explanation :

Clearly it can be understood from the question that 9 days ago was aThursday

Number of odd days in 9 days = 2 (As 9-7 = 2, reduced perfect multiple of 7from total days)

Hence today = (Thursday + 2 odd days) = Saturday

24. 1.12.91 is the first Sunday. Which is the fourth Tuesday of December 91?

A. 20.12.91 B. 22.12.91C. 24.12.91 D. 25.12.91

Hide Answer |

Notebook | Discuss


Answer : Option C

Explanation :

Given that 1.12.91 is the first Sunday

Hence we can assume that 3.12.91 is the first Tuesday

If we add 7 days to 3.12.91, we will get second Tuesday

If we add 14 days to 3.12.91, we will get third Tuesday

If we add 21 days to 3.12.91, we will get fourth Tuesday

=> fourth Tuesday = (3.12.91 + 21 days) = 24.12.91

25. If the day before yesterday was Thursday, when will Sunday be?


22/27

A. Day after tomorrow B. TomorowC. Two days after today D. Today

Hide Answer |

Notebook | Discuss


Answer : Option B

Explanation :

Day before yesterday was Thursday

=>Yesterday was a Friday

=> Today is a Saturday

=> Tomorrow is a Sunday

26. The second day of a month is Friday, What will be the last day of the next month which has31 days?A. Friday B. SaturdayC. Wednesday D. Data inadequate

Hide Answer |

Notebook | Discuss


Answer : Option D

Explanation :

We cannot find out the answer because the number of days of the current

month is not given.

27. How many days will there be from 26 th January,1996 to 15 th May,1996(both days included)?A. 102 B. 103C. 111 D. 120


23/27

Hide Answer |

Notebook | Discuss


Answer : Option C

Explanation :

Number of days from 26-Jan-1996 to 15-May-1996 (both days included)

= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May) = 111

28. If 25 th of August in a year is Thursday, the number of Mondays in that month is

A. 4 B. 5C. 2 D. 3

Hide Answer |

Notebook | Discuss


Answer : Option B

Explanation :

Given that 25 th August = Thursday

Hence 29 th August = Monday

So 22 nd ,15 th and 8 th and 1 st of August will be Mondays

Number of Mondays in August = 5

29. If the seventh day of a month is three days earlier than Friday, What day will it be on thenineteenth day of the month?

A. Saturday B. MondayC. Sunday D. Wednesday

Hide Answer | Discuss
http://shownb%2827%29/http://shownb%2827%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023727.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023727.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023727.phphttp://shownb%2828%29/http://shownb%2828%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023728.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023728.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023728.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023729.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023729.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023729.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023729.phphttp://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023728.phphttp://shownb%2828%29/http://www.careerbless.com/aptitude/qa/discuss/calendar/discussion00000023727.phphttp://shownb%2827%29/


24/27

| Notebook


Answer : Option C

Explanation :

Given that seventh day of a month is three days earlier than Friday

=> Seventh day is Tuesday

=> 14 th is Tuesday

=> 19 th is Sunday

30. Every second Saturday and all Sundays are holidays. How many working days will be therein a month of 30 days beginning on a Saturday?A. 24 B. 23C. 18 D. 21

Hide Answer |

Notebook | Discuss


Answer : Option B

Explanation :

Mentioned month has begins on a Saturday and has 30 days

Sundays = 2 nd , 9 th , 16 th , 23 rd , 30 th

=> Total Sundays = 5

Second Saturdays = 8 th and 22 nd

Total Second Saturdays = 2


25/27

Total Holidays = Total Sundays + Total Second Saturdays = 5 + 2 = 7

Total days in the month = 30

Total working days = 30 - 7 = 23

Comments(36)New est

gugan 17 Jul 2014 2:34 PM nice

Like | Dislike | Reply | Flag

Raghu 14 Jul 2014 6:17 PM Good Explanation. I learned some basic stuff today. Thanks for the post.


Sachin Kasab 30 May 2014 2:02 PM Very nice


SANJEEV KUMAR 12 Apr 2014 1:59 PM I like it


lakshmi 16 Feb 2014 8:52 AM How many odd days are der in 302 days?Like | Dislike | Reply | Flag

rahul 09 Aug 2014 12:54 PM 302/7=43 and remainder is 1 so odd day is 1

http://like%28%274861%27%2C%271%27%29/http://like%28%274861%27%2C%271%27%29/http://dislike%28%274861%27%2C1%29/http://dislike%28%274861%27%2C1%29/http://dislike%28%274861%27%2C1%29/http://flag%28%274861%27%2C1%29/http://flag%28%274861%27%2C1%29/http://flag%28%274861%27%2C1%29/http://like%28%274805%27%2C%272%27%29/http://like%28%274805%27%2C%272%27%29/http://dislike%28%274805%27%2C2%29/http://dislike%28%274805%27%2C2%29/http://dislike%28%274805%27%2C2%29/http://flag%28%274805%27%2C2%29/http://flag%28%274805%27%2C2%29/http://flag%28%274805%27%2C2%29/http://like%28%274331%27%2C%273%27%29/http://like%28%274331%27%2C%273%27%29/http://dislike%28%274331%27%2C3%29/http://dislike%28%274331%27%2C3%29/http://dislike%28%274331%27%2C3%29/http://flag%28%274331%27%2C3%29/http://flag%28%274331%27%2C3%29/http://flag%28%274331%27%2C3%29/http://like%28%273763%27%2C%274%27%29/http://like%28%273763%27%2C%274%27%29/http://dislike%28%273763%27%2C4%29/http://dislike%28%273763%27%2C4%29/http://dislike%28%273763%27%2C4%29/http://flag%28%273763%27%2C4%29/http://flag%28%273763%27%2C4%29/http://flag%28%273763%27%2C4%29/http://like%28%273238%27%2C%275%27%29/http://like%28%273238%27%2C%275%27%29/http://dislike%28%273238%27%2C5%29/http://dislike%28%273238%27%2C5%29/http://dislike%28%273238%27%2C5%29/http://flag%28%273238%27%2C5%29/http://flag%28%273238%27%2C5%29/http://flag%28%273238%27%2C5%29/http://like%28%275026%27%2C%276%27%29/http://like%28%275026%27%2C%276%27%29/http://dislike%28%275026%27%2C6%29/http://dislike%28%275026%27%2C6%29/http://dislike%28%275026%27%2C6%29/http://flag%28%275026%27%2C6%29/http://flag%28%275026%27%2C6%29/http://flag%28%275026%27%2C6%29/http://ads.yahoo.com/clk?3,eJyljN1qgzAYhq-mZyKaxBmRHSSKpaOms1XEnkWT-lNXM5si3v3sWroL2MPHy8PLx2tD.60sT46DOJCQOxgi30bYdYTn8RIZlu.7yPUsBDEABjiALMrULa0pw8czJXc-3ESQJzWxCCke.onvGZBho5vkUc1BBsX0Wx-oIv-hSvbDUzeELJt1iMmsLkeR1fT1FZ7hLmxaBli3TVnH1omO06hngd2yjvbbfN.GIe2LPGrivJh3f.vvhtForVaQrEC03DRNZsVHKceyl9erWQ1fS8uVbvVNyEW.-RIV7-VF8NFUjfoBSyllng==,http://flag%28%275026%27%2C6%29/http://dislike%28%275026%27%2C6%29/http://like%28%275026%27%2C%276%27%29/http://flag%28%273238%27%2C5%29/http://dislike%28%273238%27%2C5%29/http://like%28%273238%27%2C%275%27%29/http://flag%28%273763%27%2C4%29/http://dislike%28%273763%27%2C4%29/http://like%28%273763%27%2C%274%27%29/http://flag%28%274331%27%2C3%29/http://dislike%28%274331%27%2C3%29/http://like%28%274331%27%2C%273%27%29/http://flag%28%274805%27%2C2%29/http://dislike%28%274805%27%2C2%29/http://like%28%274805%27%2C%272%27%29/http://flag%28%274861%27%2C1%29/http://dislike%28%274861%27%2C1%29/http://like%28%274861%27%2C%271%27%29/


26/27

deepthireddy 04 Mar 2014 5:47 PM 1


deepthireddy 04 Mar 2014 5:46 PM 3


Sreeju 16 Feb 2014 10:33 PM 302 = 43*7 + 1Hence, 1 odd day


imman 08 Nov 2013 9:37 PM

very easy to learn thanq.. Like | Dislike | Reply | Flag

next last

Add a new comment ...

Sign in (optional)

Name Email

Please answer the simple math question given below

4 + 1 =
http://like%28%273382%27%2C%277%27%29/http://like%28%273382%27%2C%277%27%29/http://dislike%28%273382%27%2C7%29/http://dislike%28%273382%27%2C7%29/http://dislike%28%273382%27%2C7%29/http://flag%28%273382%27%2C7%29/http://flag%28%273382%27%2C7%29/http://flag%28%273382%27%2C7%29/http://like%28%273381%27%2C%278%27%29/http://like%28%273381%27%2C%278%27%29/http://dislike%28%273381%27%2C8%29/http://dislike%28%273381%27%2C8%29/http://dislike%28%273381%27%2C8%29/http://flag%28%273381%27%2C8%29/http://flag%28%273381%27%2C8%29/http://flag%28%273381%27%2C8%29/http://like%28%273244%27%2C%279%27%29/http://like%28%273244%27%2C%279%27%29/http://dislike%28%273244%27%2C9%29/http://dislike%28%273244%27%2C9%29/http://dislike%28%273244%27%2C9%29/http://flag%28%273244%27%2C9%29/http://flag%28%273244%27%2C9%29/http://flag%28%273244%27%2C9%29/http://like%28%272531%27%2C%2710%27%29/http://like%28%272531%27%2C%2710%27%29/http://dislike%28%272531%27%2C10%29/http://dislike%28%272531%27%2C10%29/http://dislike%28%272531%27%2C10%29/http://flag%28%272531%27%2C10%29/http://flag%28%272531%27%2C10%29/http://flag%28%272531%27%2C10%29/http://www.careerbless.com/aptitude/qa/calendar.php?pageNum_getComments=1&sortOption=N#commentshttp://www.careerbless.com/aptitude/qa/calendar.php?pageNum_getComments=1&sortOption=N#commentshttp://www.careerbless.com/aptitude/qa/calendar.php?pageNum_getComments=3&sortOption=N#commentshttp://www.careerbless.com/aptitude/qa/calendar.php?pageNum_getComments=3&sortOption=N#commentshttp://www.careerbless.com/aptitude/qa/calendar.php?pageNum_getComments=3&sortOption=N#commentshttp://www.careerbless.com/aptitude/qa/calendar.php?pageNum_getComments=1&sortOption=N#commentshttp://flag%28%272531%27%2C10%29/http://dislike%28%272531%27%2C10%29/http://like%28%272531%27%2C%2710%27%29/http://flag%28%273244%27%2C9%29/http://dislike%28%273244%27%2C9%29/http://like%28%273244%27%2C%279%27%29/http://flag%28%273381%27%2C8%29/http://dislike%28%273381%27%2C8%29/http://like%28%273381%27%2C%278%27%29/http://flag%28%273382%27%2C7%29/http://dislike%28%273382%27%2C7%29/http://like%28%273382%27%2C%277%27%29/


27/27

Home | [email protected] | Copyright | Terms and Conditions | PrivacyPolicy

Copyright 2012-2014 www.careerbless.com. All rights reserved.
http://www.careerbless.com/index.phphttp://www.careerbless.com/index.phphttp://www.careerbless.com/policies/copyright.phphttp://www.careerbless.com/policies/copyright.phphttp://www.careerbless.com/policies/copyright.phphttp://www.careerbless.com/policies/termsconditions.phphttp://www.careerbless.com/policies/termsconditions.phphttp://www.careerbless.com/policies/termsconditions.phphttp://www.careerbless.com/policies/privacypolicy.phphttp://www.careerbless.com/policies/privacypolicy.phphttp://www.careerbless.com/policies/privacypolicy.phphttp://www.careerbless.com/policies/privacypolicy.phphttp://www.careerbless.com/policies/privacypolicy.phphttp://www.careerbless.com/policies/privacypolicy.phphttp://www.careerbless.com/policies/termsconditions.phphttp://www.careerbless.com/policies/copyright.phphttp://www.careerbless.com/index.php

Documents

Calendr Ques