26 27

CALCULATING WHEEL-OVER POINT

Vladimir N. Drachev

The article consists of two parts. The first one presents a ship turning method in restricted waters that based on calculating the wheel-over point. The second part presents the method of ship’s turning in shallow waters that taking into account the increasing radius of turning due to increase of resistance of water and large water masses.

Keywords: ship, turning, radius of circulation, wheel-over point, turning radius, shallow waters, restricted water maneuvers.

For safety sailing it is necessary for any vessel to take into account her ability to turn in restricted areas. A vessel cannot make a turning immediately and at one point. The simplest method is the method when the arc between a new course and an old one is drawn by a turning radius.

Entering point A0 and pull out point B0 of a turning circle are the points of an arc contact with previous and new courses (see Figure 1.1). But actually if a vessel begins starting a wheel-over at point A0 she reaches a new course in point B1 only.

For big-sized vessels distance B0B1 can reach a considerable value. This mistake can be worse if a vessel has a “dead interval” when ratio B0B1/RTR (TR – turning radius) becomes more than a unit. Besides, within the opening period a vessel has a shift from her initial course to the side opposite to the turning. But usually, this value is not more than some tens of meters. However, due to drifting the extreme aft point of a vessel with an extended hull deviates to a distance A0A0' which becomes commensurable with a fairway breadth. Therefore, safe maneuvering

Asia-Pacific Journal of Marine Science&Education, Vol. 2, No. 1, 2012, pp. 27-46

28 29

of big tonnage vessels in restricted areas can be obtained provided a seafarer has got full information about ship‘s ability to make a turn. A new method has been offered to find a wheel-over point while performing a turning circle through deep water. This method is based on using tangent to a turning circle trajectory.

Every vessel has the table of maneuvering characteristics for performing turning circles in deep water with 35, 20 and 10 degrees rudder position.

Turning circles are drawn so, that point A0 is the point of starting wheel-over. Figure 1.3 shows plotted TR1 (track 1) and TR2 (track 2) both of which cross at point C. Then a turning angle must be defined as the difference between TR1 and TR2 and marked as ΔTR.

Figure 1.2 shows the tangent drawn to the trajectory with a 20 degrees rudder position. Point C is the intercept of the tangent with the line of the ship’s initial track which is measured in cables. Thus value A0C is the advance whilst turning at angle ΔTR with a 20 degrees rudder angle.

To find a starting wheel-over point on the TR1 (Figure 1.3) it is necessary to measure A0C

Fig. 1.1. Calculated and real circle

Fig. 1.2. Deep water turning circle with 35°, 20°, 10° wheel position

Vladimir N. Drachev

28 29

(Figure 1.2) and to put the same value relevant to the chart scale on the TR1 (Figure 1.3) from the point C in opposite direction. The end of this segment is marked as point A0 which is the starting wheel-over point. Thus wheel-over point A0 is found through the turning circle which belongs to this vessel only.

To change position of a rudder angle to perform a turning it is necessary to draw the tangent to any of the three trajectories. The value A0C will change the chosen trajectory. Accordingly, point A0 will change its position on the TR1.

Suitable visual bearing or radar distance should be drawn toward point A0 to determine a moment when a vessel is in the wheel-over position.

Any trajectory of a turning is a moving vessel’s center of gravity. Figure 4 shows the vessel heading to the upper point of the trajectory which has value of 90 degrees plus β (angle drift). This trajectory is performed with the rudder in unchanged position all the time.

In realty at point A0 rudder is put over at an indicated angle. Аt first a vessel begins moving according to the trajectory. Then at an appointed moment the rudder angle is reduced to an indicated value. The turning speed slowly begins to reduce and turning radius slowly to increase. The trajectory starts to change growing up.

Fig. 1.3. Course alteration and wheel-over

Fig.1.4. Vessel heading during turning

Calculating Wheel-over Point

30 31

At the next appointed by a seafarer moment value of the rudder angle is changed in position straight or the turning has to be met the helm which in this case has position with the rudder angle to the side opposite to the turning. At this time turning speed quickly reduces and turning radius sharply increases. And at a moment when she begins proceeding her course turning radius grows up to for ever and ever.

To value the accuracy of a turning circle on a new course by a tangent method the mathematical model of the bulk carrier with next data is taken:

Displacement 33089 tLOA in full load 182.9 mLBP in full load 173.9 mBreadth 22.6 mDraft (bow) 10.1 mDraft (stern) 10.7 mDraft middle in full loaded 10.4 m

As an example the turns with the rudder in position starboard 20 degrees are examined. At first the turning circle is fulfilled. Turning data are written with the interval of five degrees. After that the turning circle is drawn.

A turning angle is decomposed and each of components answers its angle rudder position only. In general case ΔTR will be presented in form of

ΔTR = ΔTR1 + ΔTR2 + ΔTR3 + ΔTR4where ΔTR – turning angle ΔTR1 – turning angle with the rudder in position 20 degrees ΔTR2 – turning angle with the rudder in position 10 degrees ΔTR3 – turning angle with the rudder in position straight ΔTR4 – turning angle with the rudder in position 5 degrees to the side opposite to the turning.

Any turning angle ΔTR is calculated for turning trajectory with the rudder in position 20 degrees. Therefore all tangents are drawn to this trajectory. The turnings are fulfilled from 20 to 90 degrees at intervals of ten degrees. To fulfilled turning at the appointed angle the rudder changes must

Vladimir N. Drachev

30 31

be the following (see Table 1.1 at the end of the first part of the article):1. a) If value of ΔTR is from 20 to 60 degrees the rudder has to be in

position 20 degrees for ½ΔTR or this angle value answers value ΔTR1 and which is written in the first column.

b) If value of ΔTR is from 60 to 90 degrees the rudder has to be in position 20 degrees for ⅔ΔTR or this angle value answers value ΔTR1 and which is written in the first column.

2. On achievement of a turning with value of ΔTR1 the moment to start to change position of a rudder angle from 20 to 10 degrees the same board. The mathematical model continues turning until value which is 100 less than turning angle. At this time angle value is equal ΔTR1+ΔTR2 and is written in the third column.

3. a) When the turning reaches value ΔTR1+ΔTR2 and value of turning angle is 10 degrees less than set angle the rudder is changed in position straight. The mathematical model goes on turning before angle reaches appointed value. At this moment turning angle value is equal ΔTR1+ΔTR2+ΔTR3=ΔTR and is written in the fourth column. b) When the turning reaches value ΔTR1+ΔTR2 and value of turning angle is 10 degrees less than set angle the rudder is changed in position straight. The mathematical model goes on turning before angle reaches value which is 5 degrees less appointed angle. At this moment turning angle value is equal ΔTR1+ΔTR2+ΔTR3 and is written in the fourth column.

4. a) When the turning angle reaches value ΔTR1+ΔTR2+ΔTR3 and value of turning angle is 5 degrees less than set angle the rudder is changed in position 5 degrees to the side opposite to the turning. The mathematical model goes on turning before angle reaches appointed angle value or turning speed is around zero. At this moment turning angle value is equal ΔTR1+ΔTR2+ΔTR3+ΔTR4=ΔTR and it is written in the fifth column. b) When the turning angle reaches value ΔTR1+ΔTR2 and value of turning angle is 10 degrees less than set angle the rudder is changed in position 5 degrees to the side opposite to the turning. The mathematical model goes on turning before angle reaches appointed

Calculating Wheel-over Point

32 33

angle value or turning speed is around zero. At this moment turning angle value is equal ΔTR1+ΔTR2+ΔTR4=ΔTR and it is written in the fifth column. The movement parameters are written at each moment changing of the rudder position.

The turning angles are examined from 20 to 90 degrees at intervals in 10 degrees. The tangents are drawn for each turning angle.

A final turning angle is realized in three variants with different position of the rudder, therefore three turnings are made for each angle, three trajectories are drawn and three values are written in the Table 1.1 as a distance of each track between final turning point and the tan-gent.

Then to value the accuracy of turning on a new course by a tangent method the ma-thematical model of the tanker with next data is taken:

Displacement 77100 tLOA in full load 242.8 mLBP in full load 228.0 mBreadth 32.2 mDraft (bow) 12.5 mDraft (stern) 12.5 m

At first the operations are fulfilled the same as for previous model. A turning angle is discomposed and each of components answers its angle rudder position only. In general case ∆TR will be presented in form of

ΔTR = ΔTR1 + ΔTR2 + ΔTR3 + ΔTR4 ,

where ΔTR, ΔTR1, ΔTR2 − same as for previous model; ΔTR3 – turning angle with the rudder in position 10 degrees to

the side opposite to the turning; ΔTR4 – turning angle with the rudder in position 15 degrees to

the side opposite to the turning. Then operations are fulfilled the same as for previous model with the

exception that a final turning angle is realized in two variants and all data are written in the Table 1.2 (see at the end of the first part of the article).

Then to value the accuracy of turning on a new course by a tangent

Vladimir N. Drachev

32 33

method the ma-thematical model of the RO-RO with next data is taken: Displacement 25400 tLOA in full load 184,2 mLBP in full load 174,0 mBreadth 30,6 mDraft (bow) 8,2 mDraft (stern) 8,2 m

Then all operations are fulfilled the same as for previous model of the tanker with the exception that all data are written in the Table 1.3 (see at the end of the first part of the article).

These way three mathematical models are taken to value the accuracy of a turning on a new course by tangent method. It is necessary to take notice that the final turning part differs from each other by the angle of rudder position. It is a necessity for this to stop turning speed.

All vessels are fulfilled turnings with different position of the rudder at final part. Part-ly turning speed reduced to zero when a vessel did not reach appointed course and data was written in a table. In others cases a vessel reached appointed course although she had some turning speed but data was written. But if this turning was continued angle value did not reach more than 3,5 degrees above appointed when the turning speed was zero. In this case a vessel had to return to her course and distance did not increase between a vessel and tangent. The values of whole distance are written in the Table 1.4 (see at the end of the first part of the article).

Calculating Wheel-over Point

34 35

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Vladimir N. Drachev

34 35

∆K

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Calculating Wheel-over Point

36 37

∆K

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Vladimir N. Drachev

36 37

Turningangle

Distance from point when the vessel is on appointed course to the tangent

Bulk carrier Tanker RO - RO

20°-3.02.0 10.0 -2.04.0 10.0 -2.0

30°-4.02.0 8.0 2.03.8 18.0 4.0

40°3.02.0 8.0 5.05.0 22.0 8.0

50°5.08.0 14.0 8.016.0 28.0 10.0

60°8.08.0 16.0 7.012.0 28.0 12.0

70°10.013.0 16.0 14.020.0 16.0 16.0

80°11.016.0 16.0 4.024.0 24.0 9.0

90°14.020.0 20.0 6.026.0 32.0 6.0

Table 1.4.

Calculating Wheel-over Point

38 39

2. CALCULATING WHEEL-OVER POINT FOR SHALLOW WATER

The shallow water has considerable influence upon increase of a turning circle radius for account:

- Increasing resistance of water.- Increase of large water masses.In the circular letter IMO MSC/circ. 1053 adopted on the 5th

December 2002 the deep, unrestricted water is determined as next: “The water depth should exceed four times the mean draught of the ship”. Therefore the deep water is water with the depth, which is equal to five and more draughts of the ship.

A new method to calculate a wheel-over point for any shallow water with using turning cir-cle for deep water is suggested.

At first the turning circle for the depth of 52 m (depth equal to 5 draughts of the ship) will be compared with the turning circle for the depth of 120 m (depth equal to 11, 5 draughts of the ship).

The turning circles for each of the above-mentioned depths are fulfilled with the position of the helm from 35 degrees to 10 degrees at intervals of 5 degrees. Then each movement trajectory is drawn.

After that the values of advances are calculated for turning from 20 degrees to 90 degrees at intervals of 10 degrees for both depths of 120 m and 52 m.

The values of the advances are written in the table below as follows:- For each rudder position two turning circles (for depth 120 m and

for depth 52 m) are made. - For each turning angle two values of the advances (for depth 120 m

and for depth 52 m) are written.- Difference is found between two advances which are made for

various depths but with the same rudder angle position and the angle of turning.

48 comparisons are received and only five of them exceed 0.05 cbl (9.1 m). The largest dif-ference reaches 0.09 cbl (16.38 m).

Received comparisons show that turning circles made at the depth of five draughts are the same as one made and it is possible to consider these depths as deep water. Therefore the depths will be accepted as

Vladimir N. Drachev

38 39

Angle of turning R

udde

r 35°

Rud

der 3

0°R

udde

r 25°

Rud

der 2

0°R

udde

r 15°

Rud

der 1

0°Advances at depth 120 m, cbl

Advances at depth52 m, cbl

Difference advances, cbl

Advances at depth120 m, cbl

Advances at depth52 m, cbl

Difference advances, cbl

Advances at depth120 m, cbl

Advances at depth52 m, cbl

Difference advances, cbl

Advances at depth120 m, cbl

Advances at depth52 m, cbl

Difference advances, cbl

Advances at depth120 m, cbl

Advances at depth52 m, cbl

Difference advances, cbl

Advances at depth120 m, cbl

Advances at depth52 m, cbl

Difference advances, cbl

201,

401,

340,

061,

351,

360,

011,

461,

520,

061,

541,

580,

041,

751,

760,

012,

122,

150,

03

301,

601,

510,

091,

631,

620,

011,

761,

810,

051,

861,

900,

042,

112,

130,

022,

602,

560,

04

401,

781,

730,

051,

861,

860

2,03

2,07

0,04

2,15

2,20

0,05

2,46

2,46

03,

033,

020,

01

502,

021,

970,

052,

102,

100

2,28

2,32

0,04

2,47

2,51

0,04

2,81

2,81

03,

473,

430,

04

602,

242,

220,

022,

332,

350,

022,

572,

620,

052,

822,

830,

013,

163,

190,

033,

933,

900,

03

702,

492,

470,

022,

612,

610

2,87

2,94

0,07

3,16

3,19

0,03

3,56

3,61

0,05

4,41

4,41

0

802,

782,

780

2,92

2,93

0,01

3,23

3,26

0,03

3,55

3,56

0,01

4,02

4,03

0,01

4,92

4,92

0

903,

083,

070,

013,

273,

290,

023,

573,

650,

083,

983,

980

4,51

4,51

05,

525,

540,

02

Tabl

e 2.

1. D

iffer

ence

of a

dvan

ces i

n ca

bles

at d

epth

s of 1

20 m

and

52

m fo

r var

ious

pos

ition

s of r

udde

r and

ang

le tu

rnin

g

Calculating Wheel-over Point

40 41

deep water if it is more than five draughts. But in reality a turning circle will be fulfilled at more deep water.

To calculate a wheel-over point at any depth which is less than five draughts for a definite turning angle and a rudder position it is necessary to find the advance with the help of a turning circle for deep water using the same rudder position. Then the advance for required shallow water must be calculated as follows:

1. To find the coefficient for the depth equal to five draughts (deep water) which is equivalent to the advance

,

where T – middle draught H – depth equal to five draughts;

2. To find the coefficient for he depth accepted for calculation

,

where k1 – coefficient for the calculation depth, HSH – the depth less than five draughts (depth for calculation);

3. To find the coefficient of shallow water which defines the advance increasing of a deep water turning circle

k2 = k1 - 0.2 , where k2 – a coefficient of shallow water increasing the advance of

a deep water turning circle;

4. To find the advance for shallow water (the coefficient of deep water advance is accepted as 1, then the coefficient of shallow water is added and the sum is multiplied by the advance of deep water)

SSHW = SDW (1+k2) = SDW[1+(k1- 0.2)],

where SSHW – advance of shallow water, SDW – advance of deep water.

TH T5

150 2= = ,

k THSH

1 =

Vladimir N. Drachev

40 41

The final formula looks like this

To value accuracy of the coefficient the mathematical model of the bulk carrier is used with the following data:

Displacement 33089 tLength full 182.7 mBreadth full 22.1 mDraught fore 10.1 m aft 10.7 m mean 10.4 m

The following depths are taken for the turning circle:120.0 m - deep water32.1 m - the depth equal to three draughts21.4 m - the depth equal to two draughts18.0 m, 16.0 m, 14.5 m, 13.0 m - different depths

Six turning circles are made at each depth at the position of the helm from 35 degrees to 10 degrees at intervals of 5 degrees. 42 turning circles are made to starboard side and the same number is made to port side. All 84 turning circles are made according to this mathematical model.

At each turning circle the advance values are calculated for turning angles from 20 degrees to 90 degrees at the intervals of 10 degrees. Each calculated advance is compared with the advance received from the drawing (see Table 2.2 at the end of the article).

The Table 2.2 shows the comparison advances between those received from the turning circle calculated value on condition that the rudder is in position of 35 degrees starboard side.

The first column contains depths, which are accepted for turning circles. The depth of 120 meters is deep water and this line belongs to all turning angles. Other deeps are considered as shallow water with their data for each turning angle.

In the second column for the depth of 120 meters the upper value is the coefficient for deep water. The lower value is the coefficient for deep-water advance, which is accepted as 1. Other values belong to

S S THSHW DWSHW

= + −

1 0 2,

Calculating Wheel-over Point

42 43

shallow water depths. For each shallow water depth upper value is a ratio of the draught to the depth which is at this line and it is the coefficient of this depth. The lower value is the coefficient for shallow water advance at this line.

Next columns keep data for turning angles, which were accepted for turning circles, and each of them has left and right parts. Upper left data indicate value of the advance in millimeters received from drawing but lower port data indicate the same value in cables. Lower starboard data are received as a result of multiplication of the deep water advance for this turning angle by the shallow water coefficient which is at this line. Two values are compared and if the difference is more than 0,3 cables this both cells are made gray. Other advances are calculated in the same way including a tactical diameter.

The Table 2.2 is made up for the rudder in position of 35 degrees only. The same tables are made up for each rudder position from 35 degrees to 10 degrees at the intervals of 5 degrees.

After all the tables are filled and comparisons values are made for following data are received:

- 483 values don not exceed the difference of 0.3 cable (55.5 m) between the calculated and the ones received from the drawing (88.6%).

- 66 values exceed difference 0.3 cables (55.5 m) between the calculated and the received ones from the drawing (11.4%).

- 27 values exceed the difference 0.4 cables (74.1 m) between the calculated and the re-ceived from ones drawing (4.7%).

For the depths equal to two and three draughts of the mathematical model the tactical diameters are more than 0.3 cables (55.5 m) in 3 out of 24. If a depth is less than two draughts a tactical diameters sharp increase and the calculated and measured values reach up to 3 cables.

To determine the value accuracy of the coefficient the mathematical model of the tanker is used with following data:

Displacement 77100 tLength full 242.8 mBreadth full 32.2 mDraught fore 12.5 m aft 12.5 m

mean 12.5 m

Vladimir N. Drachev

42 43

The following depths are taken for a turning circle: 120.0 m - deep water, 38.0 m - the depth equal to three draughts, 25.2 m - the depth equal to two draughts, 21.0 m, 18.0 m, 15.0 m - different depths.

It is fulfilled operations the same as with the mathematical model of the bulk carrier and as a result of this the following data are received:

- 170 values don not exceed difference of 0.3 cables (55.5 m) between the calculated and received values from the drawing (70.8%);

- 70 values exceed the difference of 0.3 cables (55.5 m) between the calculated and received values from drawing (29.1%);

- 38 values exceed the difference of 0.4 cables (74.1 m) between the calculated and received values from the drawing (15.8%).

For the depths equal to two and three draughts of the mathematical model the tactical diameters are more than 0.3 cables (55.5 m) in 2 out of 12 values. If a depth is less two draughts a tactical diameters increase sharply and the difference between the calculated and measured values reach up to 4 cables.

After estimating the coefficient of the above-mentioned two mathematical models the particulars of the m/v “Norilsk” are used:

Displacement 30758 t Length full 173,5 m Breadth full 24,55 m Draught fore 10,00 m aft 10,70 m mean 10,35 m

The deep water turning circle is drawn on basis of the real tests. However, there are no data are for drawing the turning circle in another scale. Therefore the turning circle is drawn in natural size (see Figure 2.1).

The turning circle for shallow water is drawn on the basis of calculation and for ratio of the depth to the draught equal to 1.25 (see Figure 2.2). Therefore the calculation could be made with some mistakes which would arise because of increase of the turn circle. And as a result it is received 8 caparisons between of calculated advances and advances received from drawings (see Table 2.3). The comparison results are as follows:

5 values exceed the difference of 0.3 cables;

Calculating Wheel-over Point

44 45

4 values exceed the difference of 0.4 cables;The maximum difference of 0.65 cable.

The advance calculation method is offered on the basis comparisons which are received as shown above. Thus is possible to find wheel-over point with the help deep water turning circle easily. But for using this method a vessel must have turning circles which are received at dif-ferent rudder angles and fulfilled more exactly then m/v “Norilsk”.

M/V “NORILSK”Turning circle was made up in loaded condition and in deep water (result of real tests). The turning circle was fulfilled of rudder position of 35° starboard side and with the following particulars:Draught fore - 10.0 m, Draught aft - 10.7 m, Initial speed - 11.4 kt, Rudder position - 35° S/side, Advance - 2.2 cb, Maximum diameter - 3.3 cb

M/V “NORILSK”Turning circle was made up in loaded condition and in shallow water (result of calculating). The turning circle was fulfilled at rudder position 35° starboard side and with the following particulars: Draught fore - 10.0 m,Draft aft - 10.7 m,Initial speed - 11.4 kt,Rudder position - 35° S/side,Draught/depth ratio - 1.25,Advance - 3.0 cb, Maximum diameter - 4.7 cb

Figure 2.1. Deep water turning circle

Figure 2.2. Shallow water turning circle

Vladimir N. Drachev

44 45

HT/

H k

Turn

ing

angl

e

20°

30°

40°

50°

60°

70°

80°

90°

Tact

. Dia

m.

a/dr

a/ca

la/

dra/

cal

a/dr

a/ca

la/

dra/

cal

a/dr

a/ca

la/

dra/

cal

a/dr

a/ca

la/

dra/

cal

a/dr

a/ca

l

mm

/cb

mm

/cb

mm

/cb

mm

/cb

mm

/cb

mm

/cb

mm

/cb

mm

/cb

mm

/cb

120.

0 0

,200

65,0

74

,0

82,5

93

,5

103,

5

115,

5

128,

5

142,

5

160,

0

1,0

001,

40

1,60

1,

78

2,02

2,

24

2,49

2,

78

3,08

3,

46

32,1

0,32

470

,0

77,7

89

,0

101,

0

113,

0

125,

5

140,

5

160,

0

190,

0

1,12

41,

511,

581,

681,

801,

922,

002,

182,

272,

442,

512,

712,

803,

033,

123,

463,

464,

103,

88

21,4

0,48

669

,0

88,0

99

,5

112,

0

127,

0

142,

0

158,

0

178,

0

223,

5

1,28

61,

491,

811,

902,

062,

152,

292,

422,

602,

742,

873,

073,

213,

413,

573,

843,

964,

834,

44

18,0

0,57

874

,0

89,0

10

4,5

12

0,0

13

8,0

15

6,5

17

9,0

20

5,0

28

1,5

1,37

81,

601,

931,

922,

202,

262,

462,

592,

782,

983,

083,

383,

443,

873,

824,

434,

246,

084,

76

16,0

0,65

077

,0

94,5

11

3,0

13

0,0

15

0,5

17

1,5

19

4,5

21

9,5

31

9,0

1,45

01,

662,

042,

042,

322,

442,

582,

812,

933,

253,

243,

703,

624,

204,

024,

744,

466,

895,

01

14,5

0,71

785

,0

103

12

2,5

14

1,5

16

1,0

18

4,0

20

7,5

23

5,5

34

0,0

1,51

71,

842,

132,

222,

422,

652,

703,

063,

063,

483,

393,

973,

784,

484,

215,

094,

677,

345,

24

13,0

0,80

087

,0

106,

0

129,

5

150,

5

175,

0

201,

0

228,

5

262,

0

395

1,60

01,

882,

252,

292,

562,

802,

853,

253,

233,

783,

584,

343,

994,

944,

445,

664,

928,

535,

53

-0,3

2+0

,35

+0,5

0+0

,42

-0,3

3+0

,74

-0,3

8

-0,3

7

Tabl

e 2.

2

T

he d

ista

nce

from

cro

ssin

g tr

acks

to w

heel

-ove

r poi

nt d

epen

ding

on

turn

ing

angl

e an

d m

anoe

uvri

ng d

epth

d

epen

ding

on

turn

ing

angl

e an

d m

anoe

uvri

ng d

epth

with

rudd

er p

ositi

on o

f 35

degr

ees,

star

boar

d si

de

Bulk

car

rier

, D =

330

89 t,

L =

182

,7 m

, Lw

= 1

73,9

m, В

= 2

2,6

m; 1

cb

=46

,3 m

m ;T

F =10

,1; T

A =

10,7

; ТM =

10,4

Calculating Wheel-over Point

46 47

HT/

H k

Turn

ing

angl

e

20°

30°

40°

50°

60°

70°

80°

90°

a/dr

a/ca

la/

dra/

cal

a/dr

a/ca

la/

dra/

cal

a/dr

a/ca

la/

dra/

cal

a/dr

a/ca

la/

dra/

cal

mm

/cb

mm

/cb

mm

/cb

mm

/cb

mm

/cb

mm

/cb

mm

/cb

mm

/cb

Dee

p w

ater

0,2

00

1,0

000,

45

0,70

0,

98

1,23

1,

46

1,72

1,

98

2,28

12,9

40,

800

1,60

00,

660,

721,

021,

121,

361,

571,

521,

971,

982,

342,

302,

742,

613,

163,

003,

65

0,06

0,10

0,21

0,45

0,36

0,44

0,55

0,65

Tabl

e 2.

3

T

he d

ista

nce

from

cro

ssin

g tr

acks

to w

heel

-ove

r poi

nt d

epen

ding

on

turn

ing

angl

e an

d m

aneu

veri

ng d

epth

a

t rud

der p

ositi

on o

f 35

degr

ees,

star

boar

d si

de

m/v

“N

ORI

LSK

”, ∆

= 3

0758

т, L

= 1

73.5

m,

Lw =

164

.9 m

, В =

24.

55 m

,1

cb=

40 m

m, Т

F=10

.0, Т

A =10

.7, Т

M =

10.3

51.

Tur

ning

circ

le in

load

ed c

ondi

tion

(res

ult o

f rea

l tes

ts).

2. T

urni

ng c

ircle

in lo

aded

con

ditio

n in

shal

low

wat

er (o

n th

e ba

sis c

alcu

latio

n).

3. D

epth

to d

raug

ht ra

tio o

f the

ship

is 1

,25

Н /

Т =

1,2

5;

Н /

10,3

5 =

1,2

5;

Н =

1,2

5 *

10,3

5 =

12,

94

Vladimir N. Drachev