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[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx 1 Bruce Mayer, PE Chabot College Mathematics Bruce Mayer, PE Licensed Electrical & Mechanical Engineer [email protected] Chabot Mathematics §1.1 Intro to Functions

Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Chabot Mathematics. §1.1 Intro to Functions. Bruce Mayer, PE Licensed Electrical & Mechanical Engineer [email protected]. §1.1 Learning Goals. Identify the domain of a function, and evaluate a function from an equation Gain familiarity with piecewise- defined functions - PowerPoint PPT Presentation

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Page 1: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx1

Bruce Mayer, PE Chabot College Mathematics

Bruce Mayer, PELicensed Electrical & Mechanical Engineer

[email protected]

Chabot Mathematics

§1.1 Intro to

Functions

Page 2: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx2

Bruce Mayer, PE Chabot College Mathematics

§1.1 Learning Goals

Identify the domain of a function, and evaluate a function from an equation

Gain familiarity with piecewise-defined functions

Introduce and illustrate functions used in economics

Form and use composite functions in applied problems

Page 3: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx3

Bruce Mayer, PE Chabot College Mathematics

ReCall the Ordered-Pair

An ordered pair (a, b) is said to satisfy an equation with variables a and b if, when a is substituted for x and b is substituted for y in the equation, the resulting statement is true; e.g.,

An ordered pair that satisfies an equation is called a solution of the eqn

16791673 16as

3,16by Satisfied7 Eqn2

?

2

xy

Page 4: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx4

Bruce Mayer, PE Chabot College Mathematics

Ordered Pair Dependency

Frequently, the numerical values of the variable y can be determined by assigning appropriate values to the variable x. For this reason, y is sometimes referred to as the dependent variable and x as the independent variable.• i.e., if we KNOW x,

we can CALCULATE y

Page 5: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx5

Bruce Mayer, PE Chabot College Mathematics

Mathematical RELATION

Any SET of ordered pairs is called a relation.

The set of all first components is called the domain of the relation,

The set of all SECOND components is called the RANGE of the relation

Page 6: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx6

Bruce Mayer, PE Chabot College Mathematics

Example Domain & Range

Find the Domain and Range of the relation:• { (Titanic, $600.8), (Star Wars IV, $461.0),

(Shrek 2, $441.2), (E.T., $435.1), (Star Wars I, $431.1), (Spider-Man, $403.7)}

SOLUTION• The DOMAIN is the set of all first

components, or {Titanic, Star Wars IV, Shrek 2, E.T., Star Wars I, Spider-Man}

Page 7: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx7

Bruce Mayer, PE Chabot College Mathematics

Example Domain & Range

Find the Domain and Range for the relation:• { (Titanic, $600.8), (Star Wars IV, $461.0),

(Shrek 2, $441.2), (E.T., $435.1), (Star Wars I, $431.1), (Spider-Man, $403.7)}

SOLUTION• The RANGE is the set of all

second components, or {$600.8, $461.0, $441.2, $435.1, $431.1, $403.7)}.

Page 8: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx8

Bruce Mayer, PE Chabot College Mathematics

FUNCTION Defined

A function is a “Rule” which “takes” a set X to a set Y, and is a relation in which each element of X corresponds to ONE, and ONLY ONE, element of Y.

Page 9: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Functional Correspondence A relation may be defined by a

correspondence diagram, in which an arrow points from each domain element to the element or elements in the range that correspond to it.

Page 10: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Is Relation a Fcn?

Determine whether the relations that follow are functions. The domain of each relation is the family consisting of Malcolm (father), Maria (mother), Ellen (daughter), and Duane (son).

1. For the relation defined by the following diagram, the range consists of the ages of the four family members, and each family member corresponds to that family member’s age.

Page 11: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Is Relation a Fcn?

Page 12: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Is Relation a Fcn?

1. SOLUTION: The relation IS a FUNCTION, because each element in the domain corresponds to exactly ONE element in the range.

• For a function, it IS permissible for the same range element to correspond to different domain elements. The set of ordered pairs that define this relation is {(Malcolm, 36), (Maria, 32), (Ellen, 11), (Duane, 11)}.

Page 13: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Is Relation a Fcn?

2. For the relation defined by the diagram on the next slide, the range consists of the family’s home phone number, the office phone numbers for both Malcolm and Maria, and the cell phone number for Maria. Each family member corresponds to all phone numbers at which that family member can be reached.

Page 14: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Is Relation a Fcn?

Page 15: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Is Relation a Fcn?

2. SOLUTION: The relation is NOT a function, because more than one range element corresponds to the same domain element. For example, both an office ph. number and a home ph. number correspond to Malcolm.

• The set of ordered pairs that define this relation is {(Malcolm, 220-307-4112), (Malcolm, 220-527-6277 ), (MARIA, 220-527-6277), (MARIA, 220-416-5204), (MARIA, 220-433-8195), (Ellen, 220-527-6277), (Duane, 220-527-6277)}.

Page 16: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Function Notation Typically use single letters such as f, F, g, G,

h, H, and so on as the name of a function. For each x in the domain of f, there

corresponds a unique y in its range. The number y is denoted by f(x) read as “f of x” or “f at x”.

We call f(x) the value of f at the number x and say that f assigns the f(x) value to y. • Since the value of y depends on the given value

of x, y is called the dependent variable and x is called the independent variable.

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Bruce Mayer, PE Chabot College Mathematics

Function Forms Functions can be described by:

• A Table

• A Graph

yx

Page 18: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Function Forms

Math Functions are MOST OFTEN described by:• An EQUATION

– The Eqn can be used to MAKE aTable or Graph

y x2

f x x2

y x2 6x 8

g x x2 6x 8

NOTE: f(x) ≠ “f times x”• f(x) indicates

EVALUATION of the function AT the INDEPENDENT variable-value of x

Page 19: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Evaluating a Function

Let g be the function defined by the equation y = g(x) = x2 – 6x + 8

Evaluate each function value:

a. g 3 b. g 2 c. g1

2

d. g a 2 e. g x h SOLUTION

a. g 3 32 6 3 8 1

Page 20: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Evaluating a Function

Evaluate fcn y = g(x) = x2 – 6x + 8

b. g 2 c. g1

2

d. g a 2 e. g x h SOLUTION

b. g 2 2 2 6 2 8 24

c. g1

2

1

2

2

61

2

8

21

4

Page 21: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Evaluating a Function

Evaluate fcn y = g(x) = x2 – 6x + 8

d. g a 2 e. g x h SOLUTIONd. g a 2 a 2 2 6 a 2 8

a2 4a 4 6a 12 8

a2 2a

e. g x h x h 2 6 x h 8

x2 2xh h2 6x 6h 8

Page 22: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example is an EQN a FCN??

Determine whether each equation determines y as a function of x.

a. 6x2 – 3y = 12 b. y2 – x2 = 4 SOLUTION a.

6x2 3y 12

6x2 3y 3y 12 12 3y 12

6x2 12 3y

2x2 4 y

any value of x corresponds to ONE value of y so it DOES define y as a function of x

Page 23: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example is an EQN a FCN??

Determine whether each equation determines y as a function of x.

a. 6x2 – 3y = 12 b. y2 – x2 = 4 SOLUTION b. TWO values of y

correspond to the same value of x so the expression does NOT define y as a function of x.

y2 x2 4

y2 x2 x2 4 x2

y2 x2 4

y x2 4

Page 24: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Implicit Domain

If the domain of a function that is defined by an equation is not explicitly specified, then we take the domain of the function to be the LARGEST SET OF REAL NUMBERS that result in REAL NUMBERS AS OUTPUTS.• i.e., DEFAULT Domain is all x’s that

produce VALID Functional RESULTS

Page 25: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Find the Domain

Find the DOMAIN of each function.

a. f x 1

1 x2 b. g x x

c. h x 1

x 1d. P t 2t 1

SOLUTIONa. f is not defined when the denominator is 0.

1−x2 ≠ 0 → Domain: {x|x ≠ −1 and x ≠ 1}

Page 26: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Find the Domain

SOLUTION

• The square root of a negative number is not a real number and is thus excluded from the domain

b. g x x

x NONnegative → Domain: {x|x ≥ 0}, [0, ∞)

Page 27: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Find the Domain

SOLUTION

• The square root of a negative number is not a real number and is excluded from the domain, so x − 1 ≥ 0. Thus have x ≥ 1

• However, the denominator must ≠ 0, and it does = 0 when x = 1. So x = 1 must be excluded from the domain as well

DeNom NONnegative-&-NONzero → Domain: {x|x > 1}, (1, ∞)

c. h x 1

x 1

Page 28: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Find the Domain

SOLUTION

• Any real number substituted for t yields a unique real number.

NO UNDefinition → Domain: {t|t is a real number}, or (−∞, ∞)

d. P t 2t 1

Page 29: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Composite Functions

In the real world, functions frequently occur in which some quantity depends on a variable that, in turn, depends on yet another variable.

Functions such as these are called COMPOSITE FUNCTIONS

Page 30: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Composing a Function

Composition with sets A & B by fcns g & f

1

3

7

A

( ) 3 1g x x

4

10

22

B

1( ) 3

2f x x

−1

2

8

C

fg

h h(x) = ?

Page 31: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Composing a Function

From The Diagram notice that since f takes the output from g we can combine f and g to get a function h:

1

3

7

A

( ) 3 1g x x

4

10

22

B

1( ) 3

2f x x

- 1

2

8

C

h h(x) = ?

f (g (x)) = f (3x + 1)

1(3 1) 3

2x

3 5

2 2x

This Yields an eqn for h:3 5

( ) .2 2

h x x

Page 32: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Composing a Function

The function h is the composition of f and g and is denoted f○g (read “the composition of f and g”, or “f composed with g”, or “f circle g”).

1

3

7

A

( ) 3 1g x x

4

10

22

B

1( ) 3

2f x x

- 1

2

8

C

h h(x) = ?

3 5( ) .

2 2h x x

Page 33: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

COMPOSITION OF FUNCTIONS

If f and g are two functions, the composition of function f with function g is written as f○g and is defined by the equation

f og x f g x , The function where the domain of f○g

consists of those values x in the domain of g for which g(x) is in the domain of f

Page 34: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

COMPOSITION OF FUNCTIONS

Graphically the f○g Domain Chain

Page 35: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

COMPOSITION OF FUNCTIONS

Conceptually the f○g Operation Chain

Page 36: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Evaluate Composites

Given: f x x3 and g x x 1.

Find Each of the Following

a. f og 1 b. go f 1 c. f o f 1 d. gog 1

Solution a.

a. f og 1 f g 1 f 2 23

8

Page 37: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Evaluate Composites

Solution b.

b. go f 1 g f 1 g 1 11 2

Solution c.

c. f o f 1 f f 1 f 1 1 3 1

Solution d.

d. gog 1 g g 1 g 0 0 1 1

f x x3 and g x x 1.

Page 38: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Fcn Composition

Given f(x) = 4x and g(x) = x2 + 2, find

( ) and ( ).f g x g f x

SOLUTION

( ) ( ( ))f g x f g x = f (x2 + 2)

= 4(x2 + 2) = 4x2 + 8

Page 39: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

[email protected] • MTH15_Lec-01_sec_1-1_Fcn_Intro.pptx39

Bruce Mayer, PE Chabot College Mathematics

Example Fcn Composition

Given f(x) = 4x and g(x) = x2 + 2, find

( ) and ( ).f g x g f x SOLUTION

( ) ( ( ))g f x g f x = g(4x)

= (4x)2 + 2

= 16x2 + 2 This example shows

that in general ( ) ( ).f g x g f x

Page 40: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Fcn Composition

Given: f x 2x 1 and g x x2 3. Find Each Composite Function

a. f og x b. go f x c. f o f x

a. f og x f g x f x2 3 2 x2 3 1

2x2 6 1

2x2 5

Solution a.

Page 41: Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege

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Bruce Mayer, PE Chabot College Mathematics

Example Fcn Composition

Given: f x 2x 1 and g x x2 3.

Solution b. a. f og x b. go f x c. f o f x

b. go f x g f x g 2x 1 2x 1 2 3 4x2 4x 2

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Bruce Mayer, PE Chabot College Mathematics

Example Fcn Composition

Given: f x 2x 1 and g x x2 3.

Solution c. a. f og x b. go f x c. f o f x

c. f o f x f f x f 2x 1 2 2x 1 1 4x 3

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Bruce Mayer, PE Chabot College Mathematics

Example Composite Domain

Given: Let f x x 1 and g x 1

x.

c. Find f og x and its domain.

d. Find go f x and its domain.

b. Find go f 1 .a. Find f og 1 .

Solution a.

a. f og 1 f g 1 f 1 11 0

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Bruce Mayer, PE Chabot College Mathematics

Example Composite Domain

Given: Let f x x 1 and g x 1

x.

Solution b.

b. go f 1 g f 1 g 0 not defined

Soln c.

c. f og x f g x f1

x

1

x1

• Domain: (−∞, 0)U(0, ∞) or {x|x ≠ 0}

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Bruce Mayer, PE Chabot College Mathematics

Example Composite Domain

Given: Let f x x 1 and g x 1

x.

Soln d.• Domain: (−∞, −1)U(−1, ∞) or {x|x ≠ −1}

d. go f x g f x g x 1 1

x 1

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Bruce Mayer, PE Chabot College Mathematics

DEcomposing a Function

Given: Let H x 1

2x2 1.

Show that each of the following provides a DEcomposition of H(x)a. Express H x as f g x ,

where f x 1

x and g x 2x2 1.

b. Express H x as f g x , where f x 1

x and g x 2x2 1.

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Bruce Mayer, PE Chabot College Mathematics

Decomposing a Function

Solution: a. Express H x as f g x , where f x 1

x and g x 2x2 1.

a. f g x f 2x2 1

1

2x2 1

H x

Let H x 1

2x2 1.

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Bruce Mayer, PE Chabot College Mathematics

Decomposing a Function

Solution:Let H x 1

2x2 1.

b. Express H x as f g x , where f x 1

x and g x 2x2 1.

b. f g x f 2x2 1

1

2x2 1

H x

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Bruce Mayer, PE Chabot College Mathematics

All Done for Today

SomeStatinDrugs

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Bruce Mayer, PE Chabot College Mathematics

Bruce Mayer, PELicensed Electrical & Mechanical Engineer

[email protected]

Chabot Mathematics

Appendix

srsrsr 22

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Bruce Mayer, PE Chabot College Mathematics

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Bruce Mayer, PE Chabot College Mathematics

P1-37

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Bruce Mayer, PE Chabot College Mathematics

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Bruce Mayer, PE Chabot College Mathematics

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Bruce Mayer, PE Chabot College Mathematics

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Bruce Mayer, PE Chabot College Mathematics

Function Equality

Two functions f and g are equal if and only if:

1. f and g have the same domain • and

2. f(x) = g(x) for all x in the domain.