23
Bluman, Chapter 5 1

Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

  • Upload
    others

  • View
    12

  • Download
    0

Embed Size (px)

Citation preview

Page 1: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Bluman, Chapter 5 1

Page 2: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

guessing

Suppose there is multiple choice quiz on

a subject you don’t know anything

about…. 15th Century Russian Literature;

Nuclear physics etc.

You have to guess on every question.

There are 5 questions and each question

has 4 choices.

Bluman, Chapter 5 2

Page 3: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Let x be the score on the test.

Find p(x=0)

In another words the probability you will get

a score of zero, i.e. you will get all the

questions wrong

Find p(x=1)

In another words the probability you will get

a score of 1, i.e. you will get only one

question correct.

Bluman, Chapter 5 3

Page 4: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Bluman, Chapter 5 4

Question

number

Correct or wrong

1

2

3

4

5

Page 5: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Repeat the process:

P(2)=

P(3)=

p(4)=

P(5)=

Bluman, Chapter 5 5

Page 6: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

What if the number of questions

changed

Let’s say now the test has 10 questions

and each question has 4 choices.

What does the probability distribution chart

looks like?

Bluman, Chapter 5 6

Page 7: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Bluman, Chapter 5 7

x P(x)

0

1

2

3

4

5

6

7

8

9

10

Page 8: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

What if the number of choices

changes

Let’s say now the test has 10 questions

and each question has 5 choices.

What does the probability distribution chart

looks like?

Bluman, Chapter 5 8

Page 9: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Bluman, Chapter 5 9

1

2

3

4

5

6

7

8

9

10

Page 10: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

5-3 The Binomial Distribution

10

Many types of probability problems have

only two possible outcomes or they can be

reduced to two outcomes.

Examples include:

when a coin is tossed it can land on heads or

tails,

when a baby is born it is either a boy or girl.

It will rain or it won’t

A person will pass the bar exam or not.

Page 11: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

The Binomial Distribution

Bluman, Chapter 5 11

The binomial experiment is a probability

experiment that satisfies these requirements:

1. Each trial can have only two possible

outcomes—success or failure.

2. There must be a fixed number of trials.

3. The outcomes of each trial must be

independent of each other.

4. The probability of success must remain the

same for each trial.

Page 12: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Notation for the Binomial Distribution

Bluman, Chapter 5 12

The symbol for the probability of success

The symbol for the probability of failure

The numerical probability of success

The numerical probability of failure

and P(F) = 1 – p = q

The number of trials

The number of successes

P(S)

P(F)

p

q

P(S) = p

n

X

Note that X = 0, 1, 2, 3,...,n

Page 13: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

The Binomial Distribution

!

- ! !

X n XnP X p q

n X X

Bluman, Chapter 5 13

In a binomial experiment, the probability of

exactly X successes in n trials is

number of possible probability of adesired outcomes desired outcome

or

X n X

n xP X C p q

Page 14: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Chapter 5

Discrete Probability Distributions

Section 5-3

Example 5-16

Page #272

Bluman, Chapter 5 14

Page 15: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Example 5-16: Survey on Doctor Visits

A survey found that one out of five Americans say

he or she has visited a doctor in any given month.

If 10 people are selected at random, find the

probability that exactly 3 will have visited a doctor

last month.

Bluman, Chapter 5 15

!

- ! !

X n XnP X p q

n X X

3 7

10! 1 43

7!3! 5 5

P

15

10,"one out of five" , 3 n p X

0.201

Page 16: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Chapter 5

Discrete Probability Distributions

Section 5-3

Example 5-17

Page #273

Bluman, Chapter 5 16

Page 17: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Example 5-17: Survey on Employment A survey from Teenage Research Unlimited

(Northbrook, Illinois) found that 30% of teenage

consumers receive their spending money from

part-time jobs. If 5 teenagers are selected at

random, find the probability that at least 3 of them

will have part-time jobs.

Bluman, Chapter 5 17

3 25!

3 0.30 0.702!3!

P

5, 0.30,"at least 3" 3,4,5 n p X

0.132

4 15!

4 0.30 0.701!4!

P 0.028

5 05!

5 0.30 0.700!5!

P 0.002

3 0.132

0.028

0.002

0.162

P X

Page 18: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Chapter 5

Discrete Probability Distributions

Section 5-3

Example 5-18

Page #273

Bluman, Chapter 5 18

Page 19: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Example 5-18: Tossing Coins

A coin is tossed 3 times. Find the probability of

getting exactly two heads, using Table B.

Bluman, Chapter 5 19

12

3, 0.5, 2 n p X 2 0.375 P

Page 20: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

The Binomial Distribution

Mean: np

2Variance: npq

Bluman, Chapter 5 20

The mean, variance, and standard deviation

of a variable that has the binomial distribution

can be found by using the following formulas.

Standard Deviation: npq

Page 21: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Chapter 5

Discrete Probability Distributions

Section 5-3

Example 5-23

Page #276

Bluman, Chapter 5 21

Page 22: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Example 5-23: Likelihood of Twins The Statistical Bulletin published by Metropolitan

Life Insurance Co. reported that 2% of all American

births result in twins. If a random sample of 8000

births is taken, find the mean, variance, and

standard deviation of the number of births that

would result in twins.

Bluman, Chapter 5 22

8000 0.02 160 np

2 8000 0.02 0.98 156.8 157 npq

8000 0.02 0.98 12.5 13 npq

Page 23: Bluman, Chapter 5 1 - navimath...Bluman, Chapter 5 17 3 0.30 0.70 5! 32 2!3! P n p X o 5, 0.30,"at least 3" 3,4,5 0.132 0.0284 0.30 0.70 5! 41 1!4! P 5 0.30 0.7050 5! 0.002 0!5! P

Tech notes

Read technology

notes on page

281.

Read example 5-

19 on page 274

Exercises 5.3

Page 276 #1,

5, 11, 15 and

17

Bluman, Chapter 5 23