Big Bottle RAD H2O

AnalysisSimplistically, all the radon in the water is transferred to the

closed air loop;

Cw * Vw = Ca * VaCw = Ca * Va / Vw

but some radon is left in the water. At equilibrium, the water to air concentration ratios will be 𝛂, given by

𝛂 = 0.105 + 0.405 * exp(-0.0502*T)where T is the temperature in ℃ (Weigel, 1978).

We can therefore add an air equivalent volume Vw to Va.𝛂

Cw * Vw = Ca * (Va + 𝛂Vw)

A head space must be left in the bottle to prevent it exploding if the water heats up, so

we correct for that:

Cw * (Vw - Vh/𝛂) = Ca * (Va + 𝛂Vw)

or

Cw = Ca * (Va + 𝛂Vw) / (Vw - Vh/𝛂)

Thanks