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BB101 Engineering Science Chapter 6 Temperature and Heat

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  • TEMPERATURE AND HEAT BB101- ENGINEERING SCIENCE

    UNIT SAINS JMSK PUO/DIS 2012 Page 56

    6.0 TEMPERATURE AND HEAT

    At the end of this chapter, students should be able to

    define temperature and heat

    describe the process of heat transfer

    define heat capacity, specific heat capacity and state its unit.

    apply the concept and formula in solving problems on heat capacity and specific heat capacity

    calculate heat energy transferred between two objects at different temperature

    determine temperature at thermal equilibrium

    6.1 Definition of temperature and heat

    Temperature, T Temperature is measure of the degree of hotness of a body. A hot body has a high temperature whereas a cold body has a low temperature. Heat, Q Heat is a form of energy being transferred from a hot body to a cold body. The total amount of heat in the body depends on the mass, material and temperature of the body.

    Differences between temperature and heat

    Temperature Heat

    1. The degree of hotness of a body 2. Base Quantity. 3. Unit: Kelvin (K) @ degree celcius (C) 4. Can measured by using thermometer.

    1. A form of energy. 2. Derived quantity. 3. Unit: Joule (J) 4. No specific measuring equipment

    6.2 Describe the Process Of Heat Transfer

    Heat transferred from one place or body to another in three different ways. The three methods are Conduction, Convection and Radiation.

    Conduction Convection Radiation

    The vibration of molecules or

    atoms from warmer to cooler

    areas.

    Heat is transferred from one place to

    another place by the actual motion of a

    hot fluid

    Heat energy is transferred by electromagnetic radiation

    Conduction occurs in a solid

    material.

    Convection dominant form of heat

    transfer in liquids and gasses.

    No transmission medium required.

    Examples: putting your hand on a

    stove burner. The amount of

    energy transferred depends on

    how conductive the material is.

    Metals are good conductors, so

    Examples: The cooling system of a

    car, in which water is circulated

    between the hot engine block and the

    radiator. In the radiator, the convected

    heat is conducted through thin-walled

    Examples: heat transferred by x-rays, radio waves, gamma rays and ultraviolet.

  • TEMPERATURE AND HEAT BB101- ENGINEERING SCIENCE

    UNIT SAINS JMSK PUO/DIS 2012 Page 57

    they are used to transfer energy

    from the stove to the food in pots

    and pans.

    metal tubes to the atmosphere.

    6.3 Definition of Heat Capacity (Q) and Specific Heat Capacity

    Heat Capacity, Q The amount of heat energy (Q) gained or lost by a substance is equal to the mass of the substance (m) multiplied by its specific heat capacity (c) multiplied by the change in temperature (final temperature - initial temperature)

    Q = m x c x (Tf - Ti) = mc

    Specific Heat capacity, c

    Specific Heat Capacity (c) of a substance is the amount of heat required to raise the temperature of 1kg of the substance by 1oC (or by 1 K).

    The units of specific heat capacity are J oC-1 kg-1 or J K-1 kg-1

    Q = mc m = mass (kg) c = specific heat capacity (J/kgoC)

    = temperature change (oC)

  • TEMPERATURE AND HEAT BB101- ENGINEERING SCIENCE

    UNIT SAINS JMSK PUO/DIS 2012 Page 58

    6.4 Calculate Heat Capacity, Specific Heat Capacity and Energy transfer

    Example 1 How much heat does 25 g of aluminium give off as it cools from 100 oC to 20 oC?. Given, c aluminium = 880 J/kg

    oC. Solution:

    Q = mc = 0.025 kg x 880 J/kgoC x (100 oC - 20 oC) = 1.8 kJ Example 2 The amount of heat needed to increase the temperature of a piece of marble from 27C to 37C is 2.64kJ. The mass of the marble is 0.25kg. Calculate the specific heat capacity of the marble.

    Q = mc

    c = mc

    Q

    = )2737)(25.0(

    )1064.2( 3

    = 1101056 CJkg

    Example 3 42 kJ heat is used to raise water temperature from 20oC to 30oC. Determine the mass of the water. For water, c water = 4.2 kJ/kgoC. Solution:

    Q = mc 42000 J = m x 4.2 kJ/kgoC x (30-20) oC m = 42000 /42000 m = 1 kg Example 4 An iron spoon of mass 500 g is heated from 200C to 1000C. Calculate the heat absorbed by

    the iron spoon. Given, c iron = 452 110 CJkg

    Q = mc = (500x10-3) x 452 x (100-20) = 18080Joule

  • TEMPERATURE AND HEAT BB101- ENGINEERING SCIENCE

    UNIT SAINS JMSK PUO/DIS 2012 Page 59

    6.5 Determine temperature at thermal equilibrium Thermal Condition: A condition where two objects in thermal contact has no net

    transfer of heat energy between each other. Two bodies are said to be in thermal equilibrium when:

    a) they are at same temperature b) the net rate of heat flow between them is zero or there is no net heat flow

    between them When two substances having different temperatures are introduced or kept together,

    heat energy flows from a substance at higher temperature to a substance at lower temperature. Also, heat continues to be transferred till their temperatures are equalized.

    Example 1 In preparing tea, 600 g of water at 90 oC is poured into a 200 g pot at 20 oC. What is the final temperature of the water? Given, c pot = 0.84 kJ / kg.

    oC. Solution: Heat lost by water = Heat gained by pot

    (mc) water = (mc) pot (0.6 kg)(4.2 kJ / kg.oC)(90 oC - T) = (0.2 kg)(0.84 kJ / kg.oC)(T - 20 oC) (226.8 - 2.52 T) kJ = (0.168 T - 3.36) kJ 230.16 = 2.688 T T = 230.16 2.688 T = 85.6 oC

    Q lost = Q gained Heat Lost = Heat Gained

    mhot chot (thot - tmixed) = mcold ccold (tmixed - tcold)

  • TEMPERATURE AND HEAT BB101- ENGINEERING SCIENCE

    UNIT SAINS JMSK PUO/DIS 2012 Page 60

    Example 2 A silver spoon of mass 50.0 g is at a temperature of 23 0C. This spoon is used to stir coffee which is at temperature of 91 0C. The mass of the coffee is 220 g. The final temperature reached by the spoon and coffee after stirring is 88 0C. Calculate

    a) Heat absorbed by the spoon b) The specific heat capacity of the coffee.

    [Given, c spoon =0.23k110 CJkg ]

    Solution:

    a) Heat absorbed by the spoon, Q =mc

    = (50 10-3)( 0.23 103)(88 23) = 747.5 Joule

    b) Heat released by the coffee = Heat absorbed by the spoon

    mcoffeeccoffeecoffee = 747.5

    ccoffee = )3)(10 220(

    5.7473-

    ccoffee 6.1132110 CJkg

    Example 3 A block of iron of mass 3 kg at temperature 310C is heated with an electric heater rated 100 W for 1.5 minutes. Find the rise in temperature and the final temperature of the block of iron.

    [c iron = 452 110 CJkg ]

    Solution: Heat supplied by heater, Q = Power x time = (100 x 1.5 x 60) =9000 Joule Heat received by iron black = 9000 J

    9000 = 3 x 452 x

    = 452) x 3(

    9000

    C064.6

    Final temperature = (310C+ C064.6 ) = 37.640C

  • TEMPERATURE AND HEAT BB101- ENGINEERING SCIENCE

    UNIT SAINS JMSK PUO/DIS 2012 Page 61

    Tutorial Heat and Temperature 1. A tank holding 8 kg of water at 28C is heated by 1.5 kW electric immersion heater for a

    period of 5 minutes. If the heat lost to the surroundings can be neglected, find the final temperature of the water. (Specific heat capacity of water is 4200 Jkg-1C-1)

    2. A piece of metal of mass 0.5 kg is heated to 100C in boiling water. It is then transferred into a well-insulated beaker containing 1.5 kg of water at 27C. If the final steady temperature of the water in the beaker is 32C, what is the specific heat capacity of the metal? Assume that there is no loss of heat to the surroundings and ignore the heat transferred to the beaker. (Specific heat capacity of water is 4200 J kg-1C-1)

    3. A piece of lead of mass 2 kg is dropped from the top floor of a building 32.5 m high. If its initial gravitational potential energy is converted totally into thermal energy, find the temperature rise of the lead on hitting the ground. (Specific heat capacity pf lead = 130 J kg-1C-1 and g = 9.81 ms-2).

    4. If 2.5 kg of hot water at 100C is added to 10 kg of cold water at 28C and stirred well. What is the final temperature of mixture? (Neglect the heat absorbed by container and the heat lost by the surroundings.)

    5. A kettle with 20C of water in in it needs 200kJ energy to heat the water until 80C. Calculate the mass of the water. (Specific heat capacity of water is 4200 J kg-1C-1)

    6. A 1.5 kW water heater is used to boil 2.5 kg of 20C water. Calculate the time required to boil the water temperature reaches 100C. (Specific heat capacity of water is 4200Jkg-1C-1)

    7. A block of iron of mass 2 kg at temperature 30C is heated with an electric heater rated 100 W for 1 minute. Find the rise in temperature of the bock of iron.(Specific heat capacity of iron is 452 J Kg-1C-1)

    8. 600 g of copper at temperature of 1150C IS PUT IN 300 g of water with initial temperaure 200C. If there is no heat exchange with the outside, find the final temperature. [Given ccopper = 390J kg

    -1C-1 and cwater=4200 J kg-1C-1]

    Answer: 1) 41.4C 2) 926.47 J/kgC 3) 2.46C 4) 42.4C 5) 0.79 kg 6) 560 s 7) 36.6C 8) 34.88 0C Minimum requirement assessment task for this topic: 1 Theory Test & 1 Lab work & End of Chapter 2 Specification of Theory Test: CLO1 - C1, Specification of lab work: CLO2 (C2, P1), Specification of End of Chapter: CLO3 (C2, A1) COURSE LEARNING OUTCOME (CLO) Upon completion of this topic, students should be able to:

    1. Identify the basic concept of temperature and heat, (C1)

    2. Apply concept of temperature and heat to prove related physics principles. (C2,P1)

    3. Apply the concept of temperature and heat in real basic engineering problems. (C2,

    A1)

    Compliance to PLO : PLO1 , LD1 (Knowledge) Theory Test 2 PLO2, LD2 (Practical Skill) Experiment 4 PLO4, LD4 (Critical Thinking & Problem Solving Skills)

  • TEMPERATURE AND HEAT BB101- ENGINEERING SCIENCE

    UNIT SAINS JMSK PUO/DIS 2012 Page 62

    In this strategy, students individually consider an issue or problem and then discuss their ideas with a

    partner.

    Purpose: Encourage students to think about a question, issue, or reading, and then refine their

    understanding through discussion with a partner.

    What teachers do What students do

    During

    Give students several questions (such as

    Temperature and Heat Tutorial) and let them to

    spend several minutes to think about and writing

    down the answers.

    Set clear expectations regarding the focus

    of the thinking and sharing to be done.

    Put students in pairs to share and clarify

    their ideas and understanding.

    Monitor students dialogue by circulating

    and listening.

    Formulate thoughts and ideas, writing them

    down as necessary to prepare for sharing with a

    partner.

    Practise good active listening skills when

    working in pairs, using techniques such as

    paraphrasing what the other has said, asking for

    clarification, and orally clarifying their own

    ideas and answers.

    After

    Call upon some pairs to share their learning

    and ideas with the whole class.

    Possibly extend the Think/Pair/Share with a

    further partner trade, where students swap

    partners and exchange ideas/ answers again.

    Pinpoint any information that is still unclear after

    the pair discussion, and ask the class and

    teacher for clarification.