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Aula Teórica 11. Integral Budgets: Momentum. General Principle & Mass. The rate of accumulation inside a Control Volume balances the fluxes plus production minus consumption:. - PowerPoint PPT Presentation
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Aula Teórica 11
Integral Budgets: Momentum
General Principle & Mass• The rate of accumulation inside a Control Volume
balances the fluxes plus production minus consumption:
)(.. SiSodAncnudVt surfacevc
• Fluid Mass has no source/sink and no diffusion and consequently the accumulation balances the advective flux. If the fluid is incompressible there is no accumulation and thus mass flowing in balances the mass flowing out and so does the volume in incompressible flows:
SE
SE
SE
surface
AUAU
AUAU
dAnu
.0
Momentum
• In case of momentum
)(.. SiSodAncnudVt surfacevc
iu
dVolgx
pdAnunuudVu
t iisurface
ii
vc
i
..
• In lecture 4 we have seen that the Sources/Sinks of momentum are the pressure and gravity forces.
• Momentum diffusive flux is in fact the Shear stress that we can compute explicitly from the velocity derivative only if we know the velocity profile. For that reason we will call it shear stress in the integral budget approach.
Integral momentum budget
• Let us consider: incompressible and stationary flow.
dVolgx
pdAnunuudVu
t iisurface
ii
vc
i
..
dVolgx
pdAnuu i
isurface
ii
.0
• If we assume that the velocity is uniform at the inlet and the outlet of the volume:
• If p is uniform along inlet and outlet:
Intlets
iOutlets
i
surface
i QUQUdAnuu .
WeightdVolgi
dApndVolx
p
surface
ii
ioutletinlet
ji
surface
i FPApndApn
• And finally we get: VolgFVFPApnQUQU
iiiSurface
jiIntlets
iOutlets
i
Integral Momentum Budget
• This is an algebraic equation applicable if:– Stationary and incompressible flow,– Velocity is uniform at each inlet and outlet,– Pressure is uniform along surfaces (e.g. inlets and outlets).
• Can inlets be located in zones where streamlines have curvature?• Being a budget, this equation permits the calculation of a term
knowing all the others.
• Where is the summation of pressure forces other than those acting at inlet and outlet and is the summation of the friction forces.
VolgFVFPApnQUQUiii
Surfaceji
Intletsi
Outletsi
iFP
iFV
Example 1• Calculate the force exerted by the fluid over the
deflector neglecting friction V=2 m/s and jet radius is 2 cm and theta is 45º.
• We have a flow with an inlet and an outlet. • Velocity has a component at the inlet and
two at the outlet• Pressure is atmospheric at inlet and outlets
and thus the velocity modulus remains constant.
• We have to compute budgets along both directions x and y.
D= 2cm A= 0.000315m2
V= 2m/s Q= 0.000629m3/s
Theta 45 1.26N
0.88971N
0.88971N
Fx= -0.37N
Fy= 0.88971N
F= 0.963015N
VolgFVFPApnQUQUiii
Surfaceji
Intletsi
Outletsi
Example 2• The Jet is hitting the surface
perpendicularly (Vj=3m/s), but the surface is moving (Vc=1m/s). D=10 cm. Calculate the force and power supplied.
VolgFVFPApnQUQUiii
Surfaceji
Intletsi
Outletsi
Intlets
iOutlets
i
surface
i QUQUdAnuu .
• If the control volume is moving, fluxes depend on the flow velocity relative to the control volume:
Intletsjciij
Outletscii
Intletsi
Outletsi
surface
i
AUUUAUUU
QUQUdAnuu
.
Relative or absolute reference
• Discharge must be computed using relative velocity.• Transported velocity can be the relative or the absolute velocity. Usually the
relative velocity is more intuitive.
IntletsRiC
OutletsRiC
IntletsRiR
OutletsRiR
IntletsRi
OutletsRi
surface
i
RIntlets
jCjOutlets
C
Intletsi
Outletsi
surface
i
QUQUQUQU
QUQUdAnuu
So
QAUUAUU
but
QUQUdAnuu
.
.
Example 2 Vc= 1m/s
D= 10cm
Vj= 3m/s A= 0.007864m2
VRj= 2 Q= 0.015728m3/s
Theta 90 31.46N
0N
0Symmetrical
Fx= -31.46N
Fy= 0N
F= 31.456N
Symmetrical VolgFVFPApnQUQU
iiiSurface
jiIntlets
iOutlets
i
Summary
• The integral momentum equation states describes the momentum conservation principle (Newton law) assuming simplified solutions for momentum flux calculations.
• It is useful when flow is stationary and incompressible.
• Becomes more useful when associated to the Bernoulli Energy Conservation Equation.