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Atoms:
Atomic number:
Each element is characterized by an atomic number.
Atomic number (Z) is defined as the number of protons in the nucleus of
an atom.
Ex. Helium atom has 2 protons
Atomic number of helium (Z) = number of protons = 2
Mass number:
Mass number (A) is the sum of the number of protons and the number of
neutrons or it is equal to the number of nucleons
Mass number (A) = Z + N
A = mass number
Z: atomic number
N: number of neutrons
Example: nitrogen atom has 7 protons and 7 neutrons
Mass number of Nitrogen = Z+N = 7 +7 = 14
Atomic mass:
The atomic mass of a single atom is simply its total mass and is typically
expressed in atomic mass units or amu
Atomic Mass = A amu
Example helium: Mass number = 4
Then atomic mass = A amu= 4 amu
Atomic representation:
Application 1:
Lithium (Li) contains 3 positively charged particles and 4 neutral
particles.
1. Give the symbol of lithium
2. Indicate the number of protons
3. Determine the atomic number
4. Calculate the mass number
5. Write the atomic symbol
Solution:
1) Li
6. 2) number of protons = number of positively charged particles = 3
7. 3) atomic number (z) = number of protons = 3
8. 4) Mass number (A) = Z+N = 3+ 4 = 7
9. 5) Atomic representation:
Application 2:
Potassium (K) contains 20 uncharged particles. Its mass number is 39.
1. Give the symbol of potassium.
K
2. Determine the number of protons.
A = Z + N
Z= A – N = 39 – 20 = 19
3. Write the atomic representation
Application 3:
Consider the following atoms:
126C - 19
9F
1. Identify the number of protons in each atom.
In an atom, the number of proton = atomic number (Z)
For carbon: nb of protons = 6
For Fluorine: nb. of protons = 9
2. Indicate the mass number in each atom.
For carbon A=12
For Fluorine A= 19
3. Calculate the number of neutrons in each atom.
A= Z + N
Then N = A – Z
For C: N = 12 -6 = 6
For F: N = 19 – 9= 10
Charge of an atom:
Q atom = Q nucleus + Q electron cloud
- Q nucleus = Q protons + Q neutrons
= number of protons X relative charge of 1 proton
- Q Electron cloud = Q electrons
= number of electrons X relative charge of 1 electron
In general, Q atom = 0 (atom is neutral)
So, Q nucleus = - Q electron cloud
Note: In a neutral atom, number of protons = number of electrons = Z
Application 4:
Consider the following atom:
1. Determine the composition of this atom.
2. Calculate the nuclear charge.
3. Deduce the charge of its electron cloud.
Given: Relative charge of 1 P+= 1+
1.Composition of an atom means the number of protons, neutrons and
electrons
In a neutral atom, number of protons = number of electrons = Z = 13
A= Z + N then N = A – Z = 27 - 13= 14
Number of neutron = 14.
2. Nuclear charge = Q p+ + Qn0
= number of p+ X relative charge of 1 p+
= 13 X 1 + = 13 +
3. Q atom = 0
Then Q electron cloud = - Q nucleus
= - (13 +) = 13 –
Application 5:
The following document shows the atomic structure of sodium atom:
1. referring to the document, indicate the
number of electrons.
2. Determine the atomic number.
3. Knowing that sodium atom has 12 uncharged
particles, calculate its mass number.
4. Write the atomic representation.
5. Calculate the nuclear charge of Na atom.
6. Deduce the charge of its electron cloud.
Given: Relative charge of 1 p+ = 1 +
Relative charge of 1 no = 0
Relative charge of 1 e- = 1
Solution of application 5:
1. Number of electron = 11
2. In a neutral atom, number of protons = number of electrons = Z = 11
3. 12 uncharged particles Neutron = 12
• Mass number is the sum of protons and neutrons in the nucleus (A)
• A = Z + N = 11 + 12 = 23
4. Chemical representation:
5. Nuclear charge = Q p+ + Qn0
= number of p+ X relative charge of 1 p+
= 11 X 1 + = 11 +
6. Q atom = 0
Then Q electron cloud = - Q nucleus
= - (11 +) = 11
Electron configuration:
Electrons are arranged in different energy shells (levels) around the
nucleus.
Number 1 2 3 4
Energy level (shell) K L M N
Max number of
electrons
2 8 8 2
K
L
M N
Correction of homework:
Write the electron configuration of the following atoms:
11Na - 10Ne - 15S - 6C - 9F - 17Cl
In a neutral atom, the number of protons = nb of electrons = Z
For Na: number of e- = 11 Electron configuration: 11Na: K2 L8 M1
For Ne: number of e- = 10 Electron configuration: 10Ne: K2 L8
For S: number of e- = 15 Electron configuration: 15S : K2 L8 M5
For C: number of e- = 6 Electron configuration: 6C : K2 L4
For F: number of e- = 9 Electron configuration: 9F : K2 L7
For Cl: number of e- = 17 Electron configuration: 17Cl: K2 L8 M7
Periodic table:
In the modern periodic table, the elements are arranged in their
increasing atomic number (Z).
The periodic table has 18 columns (vertical lines) and 7 rows (horizontal
rows)
How to determine the location in the periodic table?
Column = Number of valence electrons (In case number of valence
electron is more than 2 then we add 10)
Valence electron = the number of electrons in the outer shell
Row = number of occupied shells or energy levels
Example:
Consider the following atoms:
1. Write the electron configuration of each atom.
In a neutral atom, the number of protons = number of electrons = z
For Li: number of electrons = 3 then the electron configuration is: K2 L1
For P: number of electrons= 15 then P: K2 L8 M5
2. Find the valence electrons of each atom.
Valence electrons = number of electrons on the outer shell: For li: v.e. =
1 and for P: v.e. = 5
3. Determine the location of each atom in the periodic table.
Li is located in column 1 since it has 1 v.e and in row 2 since it has 2
energy shells
P is located in column 15 since it has 5 v.e. and in row 3 since it has 3
energy shells.
Lewis dot symbol:
Chemical symbol of the element surrounded by dots (valence electrons)
Application 7:
Chlorine (Cl) is used as a disinfectant, it is used also to treat drinking
water and swimming pools. A study of chlorine element gave the
following information:
- The relative charge of the electron cloud of chlorine is 17-
- The number of neutrons in the nucleus of the chlorine atom is
greater than the number of protons by 1 (N=Z+1)
1. Determine the number of electrons in chlorine atom, knowing that
the relative charge of an electron is (1-).
2. Deduce the atomic number of chlorine.
3. Calculate the mass number of chlorine.
4. Write its atomic representation.
5. Write its electron configuration.
6. Determine the location of chlorine in the periodic table.
7. Write the Lewis dot structure of chlorine.
Solution:
1. Q e- cloud = Q e-
17 - = number of electrons x relative charge of 1electron
17 - = number of electrons x 1-
Number of electrons = 𝟏𝟕 −
𝟏− = 𝟏𝟕
2. In a neutral atom, number of protons = number of electrons = Z =
17
3. A = Z + N
Given N= Z + 1 = 17 +1= 18
Then A = 17 + 18 = 35
4.
5. Number of electrons = 17
17Cl: K 2 L8 M7
6. Since Cl has 3 energy shells then it is located in row 3
Since Cl has 5 valence electrons then it is located in column 17
7.
Application 8:
Silicon of symbol Si is a metalloid used in fabrication of solar cells and
transistors. It is prepared from pure sand.
Silicon has 4 valence electrons and is located in row 3 in the periodic
table.
The number of nucleons in silicon atom is 28
1. Write its Lewis dot symbol.
2. Write the electron configuration of Si. Justify.
3. Determine its atomic number.
4. Calculate the number of uncharged particles in Si.
5. Determine the atomic number of the element just above Si in the
periodic table.
Solution:
1.
2. Since Si has 4 v.e. then the number of electrons in the last shell = 4
Since Si is located in row 3 then it has 3 occupied energy shells
Then the electron configuration of Si: K 2 L8 M4
3. Number of electrons = 2 + 8+ 4=14
In a neutral atom the number of electrons =number of protons = Z=14
4. Number of nucleons = Mass number = 28
A = Z + N then
N = A – Z = 28 -14
= 14
5. Element just above Si then it is located in column 14, row 2
Its electron configuration is K 2 L4
Then number of electron= 2 + 4 = 6,
In a neutral atom, nb of protons = nb of electrons = Z = 6