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Solutions
Code - AC207SECTION I
1. (b)
400 =
c = 20 105
N
BaSO 4 Ba 2+ + SO 4 2
Ksp = s 2 = = 1 10 8 M2 /L 2
2. (c)
P =
3. (d)
V = 3L T = 300 K
P = 0.2 atm
PV = RT
= 0.02436
Moles of NH 3 = equivalents of NH 3
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= 0.02436
Milliequivalents of NH 3 = 1000 0.02436
= 24.36
= N 134
= 0.18.
4. (b)
400 =
c = 20 10 5 N
BaSO 4 Ba 2+ + SO 4 2
Ksp = s 2 = = 1 10 8 M2 /L 2
5. (a)
m =
Tf = K f m = 0.62 oC
Freezing Point = 0 0.32 = 0.62 oC
6. (c)
Rate =
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Ratio is 1 : 1.25.
7. (c)
CH bond in allylic position is weakest because the allylic free
radical isthe most stable. Bond between H and sp carbon is stronger
than thebond between H and sp3 carbon.
> 8 > .
8. (b)
Aqueous ethanol is a protic solvent while the DMSO is aprotic
solvent.The attacking nucleophile is solvated in protic solvent and
leastsolvated in aprotic solvent. So, in DMSO, the S N2
substitution takesplace at a faster rate with higher yield.
9. (a)
In exothermic reaction,
Energy of Product < Energy of reactant
SECTION II
1. C
No rearrangement akes place
2. a
3. b
4. d
SECTION III
Paragraph
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1. (a)
The base present in DNA is adenine which is held with thyamine
usingtwo hydrogen bonds.
2. (b)
Adenosine is an example of nucleoside, made up of adenine (base)
andribose (sugar moiety).
3. (c)
Guanine is not a pyrimidine base. It is actually a purine
base.
Paragraph
1. (d)
NF3 is not hydrolysed due to lack of vacant d orbitals in N and
F. PF 3 &PF5 are not hydrolysed because P F bond is stronger
than P Ocovalent bonds. Hence, NF 3 , PF 3 , and PF 6 are not
hydrolyzed.
2. (d)
F F F
Electron densityof N is decreased
due to high
electronegativity fluorine.
3. (b)
The difference in electronegativities of N and F is lowest,
hence NF 3 isleast ionic.
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The electronegativity difference between Bi and Cl is
maximum.Hence, BiCl 3 is most ionic.
SECTION IV
1. a r
b r
c p
d q
2. a rb q, s
c p
d q
3. a r
b p
c s
d q
