Askiitians Chemistry Test207 Solutions

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  • 8/13/2019 Askiitians Chemistry Test207 Solutions

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    Trans Web Educational Services Pvt. LtdB 147,1st Floor, Sec-6,NOIDA, UP-201301

    Website: www.askiitians.com Email. [email protected] Tel:0120-4616500 Ext - 204

    Solutions

    Code - AC207SECTION I

    1. (b)

    400 =

    c = 20 105

    N

    BaSO 4 Ba 2+ + SO 4 2

    Ksp = s 2 = = 1 10 8 M2 /L 2

    2. (c)

    P =

    3. (d)

    V = 3L T = 300 K

    P = 0.2 atm

    PV = RT

    = 0.02436

    Moles of NH 3 = equivalents of NH 3

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    Trans Web Educational Services Pvt. LtdB 147,1st Floor, Sec-6,NOIDA, UP-201301

    Website: www.askiitians.com Email. [email protected] Tel:0120-4616500 Ext - 204

    = 0.02436

    Milliequivalents of NH 3 = 1000 0.02436

    = 24.36

    = N 134

    = 0.18.

    4. (b)

    400 =

    c = 20 10 5 N

    BaSO 4 Ba 2+ + SO 4 2

    Ksp = s 2 = = 1 10 8 M2 /L 2

    5. (a)

    m =

    Tf = K f m = 0.62 oC

    Freezing Point = 0 0.32 = 0.62 oC

    6. (c)

    Rate =

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    Trans Web Educational Services Pvt. LtdB 147,1st Floor, Sec-6,NOIDA, UP-201301

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    Ratio is 1 : 1.25.

    7. (c)

    CH bond in allylic position is weakest because the allylic free radical isthe most stable. Bond between H and sp carbon is stronger than thebond between H and sp3 carbon.

    > 8 > .

    8. (b)

    Aqueous ethanol is a protic solvent while the DMSO is aprotic solvent.The attacking nucleophile is solvated in protic solvent and leastsolvated in aprotic solvent. So, in DMSO, the S N2 substitution takesplace at a faster rate with higher yield.

    9. (a)

    In exothermic reaction,

    Energy of Product < Energy of reactant

    SECTION II

    1. C

    No rearrangement akes place

    2. a

    3. b

    4. d

    SECTION III

    Paragraph

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    Trans Web Educational Services Pvt. LtdB 147,1st Floor, Sec-6,NOIDA, UP-201301

    Website: www.askiitians.com Email. [email protected] Tel:0120-4616500 Ext - 204

    1. (a)

    The base present in DNA is adenine which is held with thyamine usingtwo hydrogen bonds.

    2. (b)

    Adenosine is an example of nucleoside, made up of adenine (base) andribose (sugar moiety).

    3. (c)

    Guanine is not a pyrimidine base. It is actually a purine base.

    Paragraph

    1. (d)

    NF3 is not hydrolysed due to lack of vacant d orbitals in N and F. PF 3 &PF5 are not hydrolysed because P F bond is stronger than P Ocovalent bonds. Hence, NF 3 , PF 3 , and PF 6 are not hydrolyzed.

    2. (d)

    F F F

    Electron densityof N is decreased

    due to high

    electronegativity fluorine.

    3. (b)

    The difference in electronegativities of N and F is lowest, hence NF 3 isleast ionic.

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    The electronegativity difference between Bi and Cl is maximum.Hence, BiCl 3 is most ionic.

    SECTION IV

    1. a r

    b r

    c p

    d q

    2. a rb q, s

    c p

    d q

    3. a r

    b p

    c s

    d q