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AP Calculus I Notes 3.1 The Derivative and the Tangent Line Problem Essentially, the problem of finding the tangent line at a point P boils down to the problem of finding the slope of the tangent line at point P. You can approximate this slope using the secant line (not the trig): This is also known as the ______________________________________. Slope of the Secant line: 1

AP Calculus I - FCPS · Web viewAP Calculus I Notes 3.1 The Derivative and the Tangent Line Problem Essentially, the problem of finding the tangent line at a point P boils down to

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AP Calculus I

AP Calculus I

Notes 3.1

The Derivative and the Tangent Line Problem

Essentially, the problem of finding the tangent line at a point P boils down to the problem of finding the slope of the tangent line at point P. You can approximate this slope using the secant line (not the trig):

Slope of the Secant line:

This is also known as the ______________________________________.

What if we wanted to find the slope of the line at a single point, instead of two? Let’s try to find a method that can tell us the slope at any single point using the slope formula:

Definition of Tangent Line with Slope m:

If is defined on an open interval containing c, and if the limit exists, then the line passing through the point with slope m is the tangent line to the graph of at the point .

The slope of the tangent line to the graph of at the point is also called the slope of the graph of at .

Ex. 1:Find the slope of the graph of at the point .

Why does this answer make sense?

Ex. 2:Find the slopes of the tangent lines to the graph of at the points and .

The Derivative of a Function

The limit used to define the slope of a tangent line is also used to define one of the two fundamental operations of calculus – DIFFERENTIATION

Definition of the Derivative of a Function

The derivative of at is given by

provided the limit exists

The process of finding the derivative of a function is called differentiation. A function is differentiable at if its derivative exists at and differentiable on an open interval if it is differentiable at every point in that interval

.

Notations used to Denote the Derivative of

1. 2. 3. 4.

The notation is read as “the derivative of with respect to .”

Ex. 3:Find the derivative of

This means that…. ____________________________________________________________________

____________________________________________________________________

____________________________________________________________________

Ex. 4: Find the derivative of . Then find the slope of the graph of at the points and . Discuss the behavior of at .

Ex. 5: Find the derivative with respect to for the function .

What is the equation of the tangent line at ?

Differentiability and Continuity

Another alternate limit form of the derivative is: provided this limit exists

The existence of the limit in this alternative form requires that the one-sided limits of:

and

are equal. These one-sided limits are called the derivatives from the left and from the right.

We say that is differentiable on the closed interval if it is differentiable on and if the derivative from the right of and the left of both exist.

Illustration

Sketch a graph of each function. Determine the intervals in which the function is continuous and the intervals in which the functions are differentiable.

1.

2.

3.

4.

Theorem – If is _____________________ at , then is ____________________ at

Summary:

1)

If a function is ___________________ at , then it is ____________________ at . Thus differentiability implies continuity

2) It is possible for a function to be __________________ at and not be _________________ at . Thus continuity does not imply differentiability.

AP Calculus I

Notes 3.2

Basic Differentiation Rules and Rates of Change

The Constant Rule

Ex. 1:Use the definition of a derivative to find the derivative of y = 7.

So, the Constant Rule is the derivative of a constant function is ______

Find the derivative of: f(x) = 7 ______ s(t) = -3 ______ y = kπ2_______

The Power Rule

Ex. 2: Use the definition of a derivative to find the derivative of each of the following:

a) b) c)

So, the Power Rule is if n is a rational number, then the derivative of a function is ___________

Ex. 3: Use the derivative rules to find the derivative of each of the following:

a) b) c)

Ex. 4: Find an equation of the tangent line to the graph of when .

**What two things do we need to write the equation of a line? ___________ and __________

The Constant Multiple Rule

Ex. 5: Use the definition of a derivative to find the derivative of

So, the Constant Multiple Rule is if is a differentiable function and c is a real number, the derivative of a function is _____________

Ex. 6: Find the derivative of each of the following.

a) b) c) y = -

d) y = e) f)

The Sum and Difference Rules

The derivative of the sum (or difference) of two differentiable functions is differentiable and is the sum (or difference) of their derivatives.

Ex. 7: Find the derivative of each of the following:

a) b) c)

3.2 – Derivatives ( Day 2 )

Derivatives of Sine and Cosine Functions

Proofs: Graphically:

Graph of Graph of

Graph of Graph of

Derivative Rules of Sine and Cosine Functions

Ex. 8:

Find the derivative of the following:

a) y = 2 sin xb) y = 2x – cos xc) y = x2 + cos x

Evaluate the following:

d) e)

Derivative of the Natural Exponential Function

Ex. 9: Find the derivative of the following functions:

a) b)

Ex. 10: Determine the points on the curve at which the slope is horizontal or vertical.

a)

b)

Ex. 11: Find the average rate of change over the interval from of the function and then find the instantaneous rate of change at each of the endpoints.

Derivative Worksheet

Find the derivatives of the following functions

1)2)

3)4)

5)6)

7)8)

9)10)

11)12)

13)14)

15)16)

17)18)

19)20)

AP Calculus I

Notes 3.3

The Product/Quotient Rules and Higher-Order Derivatives

Need for More Rules

1)

Given the function , find the derivative of by taking the derivative of both terms, then simplify by multiplying the two answers.

2)

Next, go back to and start by multiplying the terms and then differentiate.

3)

Is it true that ?

The Product Rule:

Ex. 1: Find the derivative of each of the following:

a) b)

c) d)

Need for MORE Rules

1)

Given the function , find the derivative taking the derivative of both functions, then simplify by dividing the two answers.

2) Next, simplify the expression, then differentiate.

3)

Is it true that ?

The Quotient Rule:

Ex. 2: Find each derivative:

a) b) c)

Ex. 3: Assume that and are differentiable functions about which we know information about a few discrete data points. The information we know is summarized in the table below:

-2

4

-1

5

6

-1

3

-5

1

7

0

-6

-3

8

-5

1

1

6

2

3

2

-1

5

1

?

Use your differentiation rules to determine each of the following.

a)

If find b) If find

c) If find d) If , find

Derivatives of Trigonometric Functions/Proofs Using Quotient Rule

Ex. 4:Find the derivative of each function.

a) b)

Higher Order Derivatives

The second derivative is the derivative of the first derivative.

Ex. 5: Find the first, second, third, and fourth derivatives of the function

Worksheet Derivatives 2: Finding derivatives and tangent lines

Find the derivative of each of the following:

1)

2)

3)4)

5)6)

7)8)

9)Find the equation of the tangent line to at .

Rates of Change

Since derivative determines slope, it also determines the rate of change of one variable with respect to another. There are many applications of this concept: population growth rates, production rates, water flow rates, velocity, acceleration, etc.

Recall that The average velocity is

Ex. 1:If a billiard ball is dropped from a height of 100 feet, its height s at time t is given by the position function where s is measured in feet and t is measured in seconds. Find the average velocity over each of the following time intervals.

1.

2.

3.

Position / Velocity / Acceleration

You can obtain a velocity function by differentiating a position function.

You can obtain an acceleration function by then differentiating a velocity function.

Suppose that in the last example we wanted to find the instantaneous velocity of the object when .

The velocity of the object at time t is the derivative of the position function.

The position of a free-falling object (neglecting air resistance) under the influence of gravity can be represented by the equation

is the initial height of the object, is the initial velocity of the object,

g is the acceleration due to gravity

Ex. 2: At time t = 0, a diver jumps from a diving board that is 32 feet above the water. The position of the diver is given by , where s is measured in feet and t is measured in seconds.

a. When does the diver hit the water?

b. What is the diver’s velocity at impact?

c. What is the diver’s acceleration at impact?

Ex. 3: A silver dollar is dropped from the top of the Empire State Building, which is tall. Given the position function is . (feet) or (meters)

a. Determine the position and velocity functions for the coin

b.

Determine the average velocity on the interval .

c.

Find the instantaneous velocity when and .

d. Find the time required for the coin to hit the ground.

e. Find the velocity of the dollar just before it hits the ground.

Ex. 4:A projectile is shot upward from the surface of the earth with an initial velocity of 120 meters per second. What is its velocity after 5 seconds? 10 seconds? What is it’s acceleration at the same time periods?

39

Position/Velocity/Acceleration - Worksheet

·

Position equation, s, is given by the equation .

· Velocity is the derivative of position ( Speed is absolute value of velocity )

· Acceleration is the derivative of Velocity

Practice Problems:

1. Bugs Bunny has been captured by Yosemite Sam and forced to walk the plank. Instead of waiting for Yosemite Sam to finish cutting the board from underneath him, Bugs finally decides just to jump. Bugs’ jumps up at 16 ft/sec from a plank 320 feet high.

a. What is the position equation and velocity equation?

b. When will Bugs hit the ground?

c. What is Bugs’ velocity at impact?

d. What is Bugs’ speed at impact?

e. When does Bugs reach a maximum height?

f. What is Bugs’ maximum height?

g. Find Bugs’ velocity at 1 second.

h. Find Bugs’ average velocity from the time he jumped until the time he landed.

i. What is Bug’s acceleration at 1 second.

2. Spider-Man goes to the top of a building 320 feet high to prevent Dr. Octopus from destroying the Earth. He knocks Dr. Octopus unconscious and throws him up in the air at 128 ft/sec.

a. Find the position, velocity, and acceleration as functions of time.

b. How long will it take for Dr. Octopus to reach his maximum height?

c. What is the maximum height that Dr. Octopus reaches?

d. When does Dr. Octopus hit the ground?

e. With what velocity does Dr. Octopus hit the ground?

f. What was his acceleration at the time of impact?

3. A student throws his Calculus book straight up from the ground at 490 m/sec.

a. Find the position, velocity, and acceleration as functions of time.

b. How long will it take the book to reach its maximum height?

c. What is the maximum height the book goes?

d. When does the book hit the ground?

e. With what velocity does the book hit the ground?

f. With what acceleration does the book hit the ground?

4. A student drops his graphing calculator from the top level of the parking garage 64 feet high.

a. Find the position, velocity, and acceleration as functions of time.

b. When does the calculator hit the ground?

c. With what velocity does the calculator hit the ground?

d. What was the calculator’s average velocity from the time it was dropped until it hit the ground?

e. What was the acceleration of the book half way down

Particle Motion

In discussing motion, there are three closely related concepts that you need to keep straight. There are:

Ex. 1: If represents the position of a particle along the x-axis at any time t , then this means…

1) “Initially” means when __________=0.

2) “At the origin” means _______________=0.

3) “At rest” means _______________=0.

4) If the velocity of the particle is positive, then the particle is moving to the ____________.

5) If the velocity of the particle is ________________, then the particle is moving to the left.

6) To find the average velocity over a time interval, divide the change in ______________ by the change in time.

7) Instantaneous velocity is the velocity at a single moment (instant!) in time.

8) If the acceleration of the particle is positive, then the _________________ is increasing.

9) If the acceleration of the particle is ________________, then the velocity is decreasing.

10) In order for a particle to change direction, the _________________ must change signs.

Particle Motion

Velocity GraphRepresentation of the particle’s movement along the x axis.

6

7

5

7

6

5

5

4

4

4

2

1

3

3

1

1

2

1. The particle is moving left and speeding up since velocity is negative and the acceleration is also negative.

2. The particle is moving left at a constant speed ( at that instant ) since velocity is negative and acceleration is 0.

3. The particle is moving left and slowing down since velocity is negative and acceleration is positive.

4. The particle is at rest since velocity is 0 even though acceleration is positive.

5. The particle is moving right and speeding up since velocity is positive and acceleration is also positive.

6. The particle is moving right at a constant speed since velocity is positive and acceleration is 0.

7. The particle is moving right and slowing down since velocity is positive and acceleration is negative.

Ex. 2: The data in the table below give selected values for the velocity, in meters/minute, of a particle moving along the x-axis. The velocity v is a differentiable function of time t.

Time t (min)

0

2

5

6

8

12

Velocity (meters/min)

-3

2

3

5

7

5

1)

At , is the particle moving to the right or to the left? Explain your answer.

2)

Is there a time during minutes when the particle is at rest? Explain your answer.

3)

Use data from the table to find an approximation for and explain the meaning of in terms of the motion of the particle. Show the computation that lead to your answer and indicate units of measure.

4)

Let denote the acceleration of the particle at time . Is there guaranteed to be a time in the interval such that ? Justify your answer.

Ex. 3: The graph below represents the velocity , in feet per second, of a particle moving along the x-axis over the time interval seconds.

1)

At seconds, is the particle moving to the right or the left? Explain your answer.

2) Over what time interval is the particle moving to the left? Explain your answer.

3)

At seconds, is the acceleration of the particle positive or negative? Explain your answer.

4)

What is the average acceleration of the particle over the interval ? Show the computations that lead to your answer and indicate units or measure.

5)

Is there guaranteed to be a time t from such that ? Justify your answer.

Ex. 4: A particle moves along the x-axis so that at time t seconds its position in meters is given by:

1)

At , is the particle moving to the right or to the left? Explain your answer.

2)

At , is the velocity of the particle increasing or decreasing? Explain your answer.

3)

Find all the values of for which the particle is moving to the left.

4) Find the velocity of the particle when the acceleration is 0.

Ex. 5: A particle moves along the x-axis such that its position in feet can be modeled by the equation , where represents the time in seconds, .

a) Find the velocity and acceleration function.

b) Find the initial position, velocity and acceleration of the particle.

c) What is the velocity of the particle when the acceleration is zero?

d) When is the particle moving to the right? Justify your answer.

HW – Particle Motion 1 and 2 (Calculator may be used)

1) The position of a particle (in inches) moving along the x-axis after t seconds have elapsed is given by the following equation:

s = f(t) = t4 – 2t3 – 6t2 + 9t

a) Calculate the velocity of the particle at time t.

b) Compute the particle's velocity at t = 1, 2, and 4 seconds.

c) When is the particle at rest?

d) When is the particle moving in the forward (positive) direction?

e) Calculate the acceleration of the particle after 4 seconds.

2.)The motion of a grizzly bear stalking its prey, walking left and right of a fixed point in feet per second, can be modeled by the motion of a particle moving left and right along the x-axis, with a position equation of:

s (t) = sin t - t2

a) Identify the velocity equation that represents the bear's motion.

b) Determine how fast the bear was traveling at t = 7 seconds.

c) In what direction is the bear traveling at t = 5 seconds?

d) How fast is the bear accelerating at a time of 2 seconds?

AP Calculus I

Notes 3.4

The Chain Rule

Exploration

1)

Use the basic power rule to find given . Next, multiply out and then differentiate. Do you notice any similarities or differences?

2)

Now, use the basic power rule to find given . Next, multiply out and then differentiate. Do you notice any similarities or differences?

3)

Next, use the basic power rule to find given . Next, multiply out and then differentiate. Do you notice any similarities or differences?

4)

Next, use the basic power rule to find given . Next, multiply out and then differentiate. Do you notice any similarities or differences?

When differentiating functions with inside parts and outside parts, we must use The Chain Rule.

The Chain Rule

If is a differentiable function of u and is a differentiable function of x, then is a differentiable function of x and

or

Ex. 1:Use the Chain Rule to find the derivative:

a) b) c)

d) e)

The General Power Rule

If , where u is a differentiable function of x and n is a rational number, then

Ex. 2:Find all points on the graph of for which and those for which does not exist. Then graph to verify your answers.

Ex. 3: Find the derivative of each of the following:

a) b)

Ex. 4: Find the second derivative of the following:

a) b)

Ex. 5: Find the derivative of each of the following:

a) y = tan 3xb) f ( x ) = cos ( x2 – 1 )

c) d)

f) e)

Theorem – Derivative of the Natural Logarithmic Function

Let be a differentiable function of .

1)2)

Ex. 6: Differentiate each of the following logarithmic functions

a)b)

c)d)

Ex. 7: Use logarithmic properties to differentiate the following functions.

a)b)

Because the natural logarithm is undefined for negative numbers, you will often encounter expressions of the form . When you differentiate functions in the form , do everything as usual.

Ex. 8: Find the equation of the tangent line for at .

Theorem – Derivatives for Bases Other than e

Let a be a positive real number () and let u be a differentiable function of x.

1) 2)

3) 4)

Ex. 9: Find the derivative of each of the following:

a) b) c)

AP Calculus I

Notes 3.5

Implicit Differentiation

So far, most functions have been expressed in explicit form. Some, however, are defined implicitly.

For example:

Implicit FormExplicit FormDerivative

It is not always possible, however, to solve for y explicitly. For example, . In these cases, we must use implicit differentiation.

The key to finding implicitly is understanding that the differentiation is happening with respect to x.

· When you differentiate terms involving x alone, you can differentiate as usual.

· When you differentiate terms involving y, you must apply the Chain Rule.

Ex. 1: Differentiate each of the following:

a) b)

c) d)

Guidelines for Implicit Differentiation

1. Differentiate both sides of the equation with respect to x.

2.

Collect all terms involving on the left side of the equation and move all other terms to the right side of the equation.

3.

Factor out of the left side of the equation.

4.

Solve for by dividing both sides of the equation by the left-hand factor that does not contain .

Ex. 2: Find given that .

Ex. 3: Find all points of horizontal and vertical tangencies for the graph of .

Ex. 4: Determine the slope of the tangent line to the graph of at the point (,).

Ex. 5: Determine the slope of the normal line of at the point .

Ex. 6: Find :

Ex. 7: Given , find .

Ex. 8: Given , find .

AP Calculus I

Notes 3.6

Inverse Trigonometric Functions and Differentiation

Ex. 1: Evaluate each of the following:

a) b) c)

d) e) f)

Ex. 2: Use right triangles to evaluate the following expressions:

a) Given , find b) Given , find

Derivatives of Inverse Trigonometric Functions

Proof:

Let be a differentiable function of .

Ex. 3: Differentiate each of the following:

a) b) c)

Ex. 4: Differentiate

Ex. 5: Write the equation of the tangent line to at .

AP Calculus

Notes 3.6

Inverse Functions

A function can be written as a set of ordered pairs:

FunctionInverse Function

Definition of Inverse Function

A function is the inverse of the function if:

for each in the domain of and for each in the domain of

Ex. 1: Show that the functions are inverses of each other

and

Ex. 2: Find the inverse of

Derivative of an Inverse Function Investigation:

1. Graph the functions (for ) and .

2. Verify that the two functions are inverses:

3. Write the ordered pair for at and determine the inverse point on .

4. Using the feature on the calculator to determine the slope at the ordered pairs found in the step above. Is there any relationship between the two slopes?

5. Repeat the step above for the ordered pairs a) and then b) . Is there any relationship between and , which is the same as ?

a)

b)

6. Make a conjecture about the derivative of inverse functions:

Derivative of an Inverse Function:

Let be the inverse of , a differentiable function:.

Ex. 3: Let a)

What is the value of when

b)

What is the value of when

Ex. 4:

AP Calculus I

Notes 3.7

Related Rates

Another important use of The Chain Rule is to find the rates of change of two or more related variables that are changing with respect to time.

For example, when a balloon is inflated, there are numerous characteristics (variables) of the balloon that are changing as time goes on. Here are a few:

Ex. 1: Suppose x and y are both differentiable functions of t and are related by the equation . Find when x= 1, given that = 2 when x = 1.

Guidelines for Solving Related Rate Problems

1. Identify all given quantities and quantities to be determined. Make a sketch and label.

2. Write an equation involving the variables whose rates are given or are to be determined.

3. Using the Chain Rule, implicitly differentiate both sides of the equation with respect to time t.

4. After completing Step 3, substitute into the resulting equation all known values for the variables and their rates of change. Then solve for the required rate of change.

Ex. 2: A pebble is dropped into a calm pond, causing ripples in the form of concentric circles. The radius r of the outer ripple is increasing at a constant rate of 1 foot per second. When the radius is 4 feet, at what rate is the total area A of the disturbed water changing?

Ex. 3:Air is being pumped into a spherical balloon at a rate of 4.5 cubic inches per minute. Find the rate of change of the radius when the radius is 2 inches.

Ex. 4:The radius, r, of a circle is increasing at a rate of 2cm per minute. At the instant the radius of the circle is 6cm, find:

a) The rate of change of the area.

b)The rate of change of the circumference.

Ex. 5:A television camera at ground level is filming the lift-off of a space shuttle that is rising according to the position equation , where s is in feet and t is in seconds. The camera is 2000 feet from the launch. Find the rate of change in the angle of elevation of the camera 10 seconds after lift-off.

Ex. 6:Liquid is dripping into a conical cup at the rate of 2.5 cubic inches per minute. The cup has a height that is always twice the radius. How fast is the liquid level rising in the cup when the liquid is 2 inches deep?

CALCULUS AB Name ________________________

Related Rate Problems

Solve the following related rates problems. Show all work and circle your answer.

1. Air is leaking out of a spherical balloon at the rate of 3 cubic inches per minute. When the radius is 5 inches, how fast is the radius decreasing?

2. A cone-shaped paper cup is being filled with water at the rate of 3 cubic centimeters per second. The height of the cup is 10 cm and the radius of the base is 5 cm. How fast is the water level rising when the level is 4 cm?

3. A 25-foot ladder leans against a vertical wall. If the bottom of the ladder is slipping away from the base of the wall at the rate of 1 foot per second, how fast is the top of the ladder moving down the wall when the bottom of the ladder is 7 feet from the base?

4.

A cylindrical tank of radius 10 feet is being filled with wheat at the rate of 314 cubic feet per minute. How fast is the depth of the wheat increasing? (Think about what is for a cylinder)

5. Oil from an uncapped oil well in the ocean is radiating outward in the form of a circular film on the surface of the water. If the radius of the circle is increasing at the rate of 2 meters per minute, how fast is the area of the oil film growing when the radius reaches 100 meters?

6. A conical tank is dripping oil into a cylindrical tank. The cone has a diameter of 6cm and a height of 7cm.

a. Find the rate in which oil is leaving the conical tank when the height is 2.4 cm and is decreasing at a rate of 0.18 cm/min.

b. Find the rate in which the height of the cylindrical tank is increasing given the tank has a radius of 5cm and a height of 4 cm. (Think about how the radius is changing over time in a cylinder)

Calculus - Chapter 3 Review

Evaluate the following:

1.2.

Use the derivative rules to find the derivative of each of the following functions.

3.4.

5.6.

7.An ice cube is melting at a constant rate such that it’s sides are changing at . Find the rate in which the volume is decreasing at the instant the side length is .

8.Find all the points on the graph of where there is a horizontal and a vertical tangent line.

Find each derivative.

9.10.Find

11.12.Find :

13.Find the equation of the tangent line to at .

CALCULATOR PAGE - Use the chart and the functions below to find the derivatives.

14.15.

Find the intervals of differentiability:

16.17.18.

19. The temperature T of food put in a freezer is where t is in hours. Find the rate of change of the temperature after 3 hours.

20. If and , then what is ?

For questions 21 – 23: A particle is moving along the x-axis where, for all values of time t for , the position can be modeled by the function . Determine the following:

21.Find the velocity and acceleration at time .

22.What is the average velocity of the particle between the two times in which the acceleration is zero?

23.What is the position when the velocity is first zero?

24. Sand is being poured onto the ground in the shape of a cone whose height is always twice the radius.

When , what is the rate of change of the height if sand is poured at a rate of 16 cubic feet per minute? The volume of a cone is .

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2

,

0

[

x

e

x

x

h

+

=

2

)

(

()17

fx

=

3

()

5

x

gx

=

73

()510

fxxx

=-

5

7

()

gxx

=

2

()1617200

sttt

=-+-

2

()2(53)

gxxx

=-

2

()

grr

p

=

xc

=

2

10

()

7

fx

x

=

(

)

2

10

()

7

fx

x

=

7531

2222

()23

gxxxxx

=-++

5

2

2

()

5

fx

x

=

32

369

()

3

tt

gt

+-

=

3

4

()

fpppp

=++

2

()2

gxx

x

=+

3

()25cos

fxxxx

=--+

1

()

gx

x

=

()2sin5

fxx

=-

()23

fxx

=-

()(3)(21)

fxxx

=+-

51

2

4

3

()101

3

x

gxx

x

-

=++-

32

3

()

xxx

gx

x

++

=

(

)

(

)

4

2

)

(

x

x

x

f

=

)

(

x

f

)

(

x

f

[

]

)

(

'

)

(

'

)

(

)

(

x

g

x

f

x

g

x

f

dx

d

=

[

]

__

__________

__________

__________

)

(

)

(

=

x

g

x

f

dx

d

2

()(32)(54)

hxxxx

=-+

(2,1)

3

sin

3

2

-

+

=

x

e

x

y

x

h(x) = (x2 + 4x)cos x

h(x)=(x

2

+4x)cosx

(

)

(

)

2

6

)

(

x

x

x

f

=

)

(

'

)

(

'

)

(

)

(

x

g

x

f

x

g

x

f

dx

d

=

ú

û

ù

ê

ë

é

=

ú

û

ù

ê

ë

é

)

(

)

(

x

g

x

f

dx

d

2

52

()

1

x

fx

x

-

=

+

2

3

42

()

4

xx

fx

x

--

=

+

h

x

e

h

x

e

x

h

x

h

-

+

+

®

0

lim

()

fx

()

gx

2

()1

fxx

=+

x

'()

fx

'()

gx

()(),

pxxfx

=

'(2).

p

()3()(),

qxfxgx

=

'(2).

q

-

(0,1)

()

(),

5()

fx

rx

gx

=

'(0).

r

)

(

)

(

3

)

(

2

x

f

x

g

x

x

m

=

)

1

(

'

-

m

[

]

=

x

dx

d

tan

[

]

=

x

dx

d

cot

[

]

=

x

dx

d

sec

(1,2)

-

[

]

=

x

dx

d

csc

2

6

csc

x

x

y

=

sec

yxx

=

[

]

()()

d

fxfx

dx

¢¢¢

=

[

]

[

]

)

(

'

)

(

'

'

)

(

'

'

'

2

2

x

f

dx

d

x

f

dx

d

x

f

=

=

43

()321

fxxxx

=-+-

2

()(34)(21)

fxxxx

=-+-

()(34)(2tan5)

fxxx

=-+

32

()(1)

fxxx

=-

(

)

2

()4csc(27)

fxxx

=-

f

5

()

1

x

fx

x

-

=

-

2

6

()

4

fx

x

=

-

2

21

()

1

xx

fx

x

-+

=

-

cos

()

2

xx

fx

x

=

+

()

4

x

fx

x

=

-

8

x

=

distance

Rate=

time

change in distance

change in time

s

t

D

=

D

2

16100

st

=-+

[1,2]

x

[1,1.5]

[1,1.1]

1

t

=

()()

vtst

¢

=

2

00

1

()

2

stgtvts

=++

0

s

0

v

2

()161632

sttt

=-++

1453

ft

2

00

()16

sttvts

=-++

0

()()

'()lim

x

fxxfx

fx

x

+D-

=

D

s(t) = −4.9t2 + v0t + s0

s(t)=-4.9t

2

+v

0

t+s

0

1

t

=

2

t

=

0

0

2

2

1

s

t

v

gt

s

+

+

=

)

(

t

x

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1

2

–1

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v(t)

01234560–1–2–3–4

)

(

t

v

0

=

t

12

0

£

£

t

)

10

(

'

v

)

10

(

'

v

)

(

t

a

t

c

t

=

0

)

(

=

c

a

)

(

t

v

9

0

£

£

t

12345678910t

1

2

3

4

5

6

7

8

9

10

11

–1

–2

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v(t)

4

=

t

(,)

ab

4

=

t

4

2

£

£

t

4

2

£

£

t

2

2

3

)

(

'

s

ft

t

v

-

=

11

9

6

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(

2

3

+

+

-

=

t

t

t

t

x

0

=

t

1

=

t

t

t

e

t

t

t

x

-

+

=

9

3

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(

2

t

()

yfx

=

0

³

t

)

(

'

x

f

2

)

3

(

)

(

+

=

x

x

f

)

(

'

x

g

2

)

1

2

(

)

(

-

=

x

x

g

)

(

'

x

h

2

2

)

1

3

(

)

(

+

=

x

x

h

)

(

'

x

m

2

3

)

(

)

(

x

x

x

m

+

=

()

yfu

=

'()

fx

()

ugx

=

(())

yfgx

=

[

]

(())(())()

d

fgxfgxgx

dx

¢¢

=

()

yfuu

¢¢¢

23

()(32)

fxxx

=-

2

1

yx

=+

(

)

h

h

h

h

p

p

p

p

cos

cos

lim

0

-

+

+

®

2

7

()

(23)

gt

t

-

=

-

3

2

)

1

3

(

)

5

(

)

(

+

-

=

x

x

x

f

(

)

n

yux

=

éù

ëû

dy

dx

1

nn

d

unuu

dx

-

¢

éù

=

ëû

(

)

2

2

3

()1

fxx

=-

()0

fx

¢

=

()

fx

¢

3

2

()

4

x

fx

x

=

+

2

2

31

3

x

y

x

-

æö

=

ç÷

+

èø

8

2

)

3

5

(

+

=

x

y

q

sin

e

y

=

)

2

3

cos(

2

+

=

x

y

x

x

y

csc

3

+

=

'

y

(

)

x

xe

y

2

sin

sec

=

3

()sin4

ftt

=

u

x

[

]

1

ln,0

=>

d

xx

dxx

[

]

'

ln,0

==>

dduu

uu

dxuu

[

]

x

dx

d

ln

(

)

2

ln1

éù

+

ëû

d

x

dx

[

]

ln

d

xx

dx

(

)

3

ln

éù

ëû

d

x

dx

[()]

d

fx

dx

1

2

ln

+

=

x

y

22

3

(1)

()ln

21

+

=

-

xx

fx

x

ln

u

ln

=

yu

3

2

sin

2

ln

)

(

+

=

x

x

f

0

=

x

1

a

¹

(ln)

xx

d

aaa

dx

éù

=

ëû

(ln)

uu

ddu

aaa

dxdx

éù

=

ëû

[

]

1

log

(ln)

a

d

x

dxax

=

[

]

1

log

(ln)

a

ddu

u

dxaudx

=

3

2

x

y

=

32

(12)

x

d

dx

éù

-=

ëû

4

4

x

d

x

dx

éù

=

ëû

1

xy

=

y

23

242

xyy

-+=

dy

dx

3

d

dx

x

éù

ëû

3

d

dx

y

éù

ëû

[

]

3

d

dx

xy

+

2

d

dx

xy

éù

ëû

322

54

yyyx

+--=-

x

22

1

xy

+=

22

44

xy

+=

2

1

2

-

222

3()100

xyxy

+=

(3,1)

dt

dw

2

cos

sin

2

p

=

t

w

22

25

xy

+=

2

2

dy

dx

()

fxx

=

5

2

=

+

xy

x

÷

ø

ö

ç

è

æ

-

2

1

arcsin

(

)

0

arccos

(

)

3

arctan

(

)

2

sec

arc

(

)

2

csc

arc

(

)

1

cot

-

arc

x

y

arcsin

=

y

cos

÷

÷

ø

ö

ç

ç

è

æ

=

2

5

sec

arc

y

()

fx

y

tan

[

]

=

u

dx

d

arcsin

u

x

[

]

=

u

dx

d

arcsin

[

]

=

u

dx

d

arccos

[

]

=

u

dx

d

arctan

[

]

=

u

arc

dx

d

cot

[

]

=

u

arc

dx

d

sec

[

]

=

u

arc

dx

d

csc

(1,1)

[

]

x

dx

d

3

arctan

[

]

x

dx

d

arcsin

[

]

x

e

arc

dx

d

2

sec

2

1

arcsin

x

x

x

y

-

+

=

x

e

y

arctan

=

1

=

x

{

}

)

7

,

4

(

,

)

6

,

3

(

,

)

5

,

2

(

),

4

,

1

(

=

f

=

-

1

f

g

f

(4,2)

x

x

g

f

=

))

(

(

x

g

x

x

f

g

=

))

(

(

x

1

2

)

(

3

-

=

x

x

f

3

2

1

)

(

+

=

x

x

g

3

2

)

(

-

=

x

x

f

2

)

(

x

x

f

=

f

0

³

x

x

x

g

=

)

(

)

(

x

f

3

=

x

)

(

x

g

_

__________

)

3

(

'

:

=

f

m

m : f −1( ) '(x) = g '(9) = ___________

m:f

-1

()

'(x)=g'(9)=___________

)

5

.

1

(

f

)

2

(

f

)

2

(

'

f

(0,0)

)

4

(

'

g

(

)

)

4

(

'

1

-

f

_

__________

)

(

'

:

=

x

f

m

m : f −1( ) '(x) = g '(x) = ___________

m:f

-1

()

'(x)=g'(x)=___________

_

__________

)

(

'

:

=

x

f

m

m : f −1( ) '(x) = g '(x) = ___________

m:f

-1

()

'(x)=g'(x)=___________

1

-

f

f −1( ) '(x) = 1f '( f −1(x))

f

-1

()

'(x)=

1

f'(f

-1

(x))

5

4

2

)

(

2

3

-

+

-

=

x

x

x

x

f

)

(

1

x

f

-

t

3

=

x

f −1( ) '(x)

f

-1

()

'(x)

2

3

yx

=+

dy

dt

dx

dt

2

50

t

s

=

dr

dt

h

h

h

÷

ø

ö

ç

è

æ

-

÷

ø

ö

ç

è

æ

+

®

4

sin

4

sin

lim

0

p

p

2

y

t

=

(

)

(

)

x

x

x

x

x

x

x

x

D

-

-

D

+

+

D

+

®

D

5

3

5

3

lim

2

2

0

8

4

65

()7

8

fxx

x

x

=-+

(

)

(

)

2

5

sec

cot

3

)

(

x

x

x

f

=

10

5

3

2

)

(

x

e

x

g

x

+

=

(

)

x

x

g

ln

sin

)

(

2

=

min

5

mm

s

=

mm

s

8

=

3

2

yxx

=+

y

x

x

x

2

cos

4

ln

4

-

=

)

3

tan(

:

2

2

x

y

dx

y

d

=

(1,2)

x

e

y

2

2

arctan

=

2

2

dy

dx

22

3410

xy

-=

3

2

arcsin

+

=

x

y

0

=

x

(1)11

f

=

(1)25

f

¢

=

(1)2

g

=

(1)4

g

¢

=

(1)13

h

=-

()()

'()lim

xc

fxfc

fc

xc

®

-

=

-

(1)9

h

¢

=

(2)3

f

=-

(2)7

f

¢

=-

(2)4

g

=-

(2)5

g

¢

=

(2)6

h

=-

(2)8

h

¢

=

(3)1

f

=

(3)6

f

¢

=

(3)14

g

=-

()()

lim

xc

fxfc

xc

+

®

-

-

1

2

(3)

g

¢

=

(3)0

h

=

(3)10

h

¢

=-

))

(

(

)

(

)

3

(

'

x

f

g

x

K

if

K

=

(1)if()ln(())

HHxgx

¢

=

4

1

2

+

-

=

x

x

y

4

)

(

2

-

=

x

x

f

ï

î

ï

í

ì

³

+

<

-

=

0

1

ln

0

2

sin

2

)

(

2

t

t

t

t

t

t

g

10

4

700

3

+

-

=

t

t

t

T

4

)

(

3

-

=

x

x

f

()()

lim

xc

fxfc

xc

-

®

-

-

)

(

)

(

1

x

f

x

g

-

=

)

4

(

'

g

p

2

0

<

£

t

t

t

t

x

sin

4

6

)

(

2

+

-

=

2

=

t

3

=

h

h

r

V

2

3

1

p

=

f

[,]

ab

(,)

ab

a

b

x

y

x

x

f

1

)

(

=

()2

fxx

=-

1

3

()

fxx

=

î

í

ì

³

+

-

<

-

=

2

6

2

2

3

)

(

x

x

x

x

x

f

f